NCERT Solutions for Class 12 Physics Chapter 13: Nuclei

Jasmine Grover logo

Jasmine Grover

Education Journalist | Study Abroad Strategy Lead

NCERT Solutions for class 12 physics chapter 13 Nuclei are given in this article. Atomic Nucleus is the small, dense and central part of the Atom consisting of Protons, which are positively charged and Neutrons, which are electrically neutral containing more than 99.9% of the mass of an atom and are ten thousand times smaller than an atom.

Unit 8 Atoms and Nuclei along with Unit 7 Dual Nature of Radiation and Matter has a weightage of 12 marks in the CBSE Board examinations. NCERT Solutions Class 12 Physics Chapter 13 covers concepts of Mass-Energy and Nuclear Binding EnergyRadioactive Decay, and Nuclear Energy.

Download PDF: NCERT Solutions for Class 12 Physics Chapter 13


NCERT Solutions for Class 12 Physics Chapter 13

The NCERT solutions for class 12 physics chapter 13: Nuclei are given below.

Ncert solutions

Ncert solutions

Ncert solutions

Ncert solutons

Ncert solutions

Ncert solutions

Ncert solutions

Ncert Solutions

Ncert Solutions

Ncert Solutions

Ncert Solutions

Ncert soluions

Ncert solutions

Ncert solutions

Ncert solutions

Ncert Solutions

Ncert Solutions

Ncert Solutions

Ncert Solutions

Ncert Solutions

Ncert Solutions

Ncert solutions

Ncert solutions

Ncert solutions

Ncert solutions

Ncert solutions


Class 12 Physics Chapter 13 Nuclei – Topics Covered

  • Atomic Mass Unit (amu): The unit used to express atomic masses is known as the atomic mass unit. It is defined as 1/12th of the mass of a Carbon atom (C12).
1 u = 1.660539 x 10-27 kg
  • Atomic number of an element refers to the number of protons that are present inside the nucleus of an atom of an element.
Atomic number = Number of protons = Number of electrons
  • Mass number of an element refers to the total number of protons and neutrons inside the atomic nucleus of the element.
Mass number = Number of protons + Number of neutrons = Number of electrons + Number of neutrons i.e. A = Z + N
  • Size of Nucleus: If R is the radius of the nucleus that has mass number A, then the size of the nucleus can be represented by:
\({4 \over 3} \pi R^3 \propto A => R \propto A^{1/3} => R = R_0A^{1 \over 3}\)
  • Radioactivity Decay Law: According to the Radioactive Decay law, the rate of decay of radioactive atoms at any instant is directly proportional to the number of atoms present at that instant.
\({dN \over dt} \propto N, {dN \over dt}=\ - \lambda N\)

Also Read:

Check-Out: 

CBSE CLASS XII Related Questions

  • 1.
    A 500 nm photon is incident normally on a perfectly reflecting surface and is reflected. The value of momentum transferred to the surface is:

      • \( 3.87 \times 10^{-43} \, \text{kg} \, \text{ms}^{-1} \)
      • \( 2.5 \times 10^{-30} \, \text{kg} \, \text{ms}^{-1} \)
      • \( 2.65 \times 10^{-27} \, \text{kg} \, \text{ms}^{-1} \)
      • \( 1.33 \times 10^{-27} \, \text{kg} \, \text{ms}^{-1} \)

    • 2.
      Suppose a pure Si crystal has \( 5 \times 10^{28} \) atoms per \( \text{m}^3 \). It is doped with \( 5 \times 10^{22} \) atoms per \( \text{m}^3 \) of Arsenic. Calculate majority and minority carrier concentration in the doped silicon. (Given: \( n_i = 1.5 \times 10^{16} \, \text{m}^{-3} \))


        • 3.
          The magnetic field in a plane electromagnetic wave travelling in glass (\( n = 1.5 \)) is given by \[ B_y = (2 \times 10^{-7} \text{ T}) \sin(\alpha x + 1.5 \times 10^{11} t) \] where \( x \) is in metres and \( t \) is in seconds. The value of \( \alpha \) is:

            • \( 0.5 \times 10^3 \, \text{m}^{-1} \)
            • \( 6.0 \times 10^2 \, \text{m}^{-1} \)
            • \( 7.5 \times 10^2 \, \text{m}^{-1} \)
            • \( 1.5 \times 10^3 \, \text{m}^{-1} \)

          • 4.
            A circular coil of 100 turns and radius \( \left(\frac{10}{\sqrt{\pi}}\right) \, \text{cm}\) carrying current of \( 5.0 \, \text{A} \) is suspended vertically in a uniform horizontal magnetic field of \( 2.0 \, \text{T} \). The field makes an angle \( 30^\circ \) with the normal to the coil. Calculate:
            the magnetic dipole moment of the coil, and
            the magnitude of the counter torque that must be applied to prevent the coil from turning.


              • 5.
                Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

                  • attract with a force \( \frac{F}{2} \)
                  • repel with a force \( \frac{F}{2} \)
                  • repel with a force \( F \)
                  • attract with a force \( F \)

                • 6.
                  A ray of light MN is incident normally on the face corresponding with side AB of a prism with an isosceles right-angled triangular base ABC. Trace the path of the ray as it passes through the prism when the refractive index of the prism material is \( \sqrt{2} \), and \( \sqrt{3} \).

                    CBSE CLASS XII Previous Year Papers

                    Comments


                    No Comments To Show