Equipotential Surface: Work Done, Properties & Magnitude

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Equipotential Surface is the surface that has a constant value of the electrical potential at all the points on that surface. The formation of an equipotential surface depends on the type of medium i.e. isotropic, non-isotropic, and the amount of charge distribution.

  • A single-point charge of the equipotential surface is a concentric spherical surface centered at the charge. 
  • An equipotential surface is thus a surface where the potential is the same at every point on the surface.

Read More: Electrostatic Potential and Capacitance

Key Terms: Equipotential, Equipotential Surfaces, Work, Electric Field, Electric Charge, Electric Potential, Work, Electrical potential, Charge


Equipotential Surfaces

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The surface that forms the locus of all points that are at the same potential forms the equipotential surface. To move a charge from one point to another on the equipotential surface, work is not required. For a single charge q, the potential can be calculated using the following formula. Here, V is constant if r is constant. 

Therefore, equipotential surfaces of a single-point charge are concentric spherically centered at the potential charge.

Therefore, equipotential surfaces of a single-point charge are concentric spherically centered at the potential charge.

Equipotential Surface Schematic

Equipotential Surface Schematic

Equipotential Points

Equipotential points are those points in an electric field that are at the same electric potential.

Equipotential Line

When equipotential points are connected by a line or curve, it is called an equipotential line.

Equipotential Surface

When equipotential points lie on a surface, it is called an equipotential surface.

Equipotential Volume

If equipotential points are distributed throughout a space or volume, it is called an equipotential volume.

Equipotential Surfaces for a Uniform Electric Field

The below figure shows equipotential surfaces for a uniform electric field

Equipotential surfaces for a uniform electric field

Equipotential surfaces for a uniform electric field

Equipotential Surfaces for an Isolated Point Charge

The figure below shows Equipotential surfaces for an isolated point charge

Equipotential surfaces for an isolated point charge

Equipotential surfaces for an isolated point charge

Equipotential Surfaces for a Pair of Similar Charge

The figure below shows the equipotential surfaces for a pair of similar charge

Equipotential surfaces for a pair of similar charge

Equipotential surfaces for a pair of similar charge

Equipotential Surfaces for a Pair of Opposite Charge

The equipotential surfaces for two charges of opposite sign are shown below

Equipotential surfaces for an electric dipole

Equipotential surfaces for an electric dipole

Work Done in Equipotential Surface

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The work done in moving a point charge from one point to another in an equipotential surface is zero. If a point charge is moved from point VY to VZ, in an equipotential surface then the work done in the moving point charge can be calculated using the following equation:

W = q0 (VY - Vz)

As the value of VY - Vz is zero, the total work done W = 0.

Work Done in Equipotential Surface

Work Done in Equipotential Surface


Properties of Equipotential Surface

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The properties possessed by equipotential surfaces are mentioned below:

  1. The electric field is always perpendicular to an equipotential surface.
  2. Two equipotential surfaces never intersect each other.
  3. For a point charge, equipotential surfaces are concentric spherical shells.
  4. In a uniform electric field, any plane normal to the field direction is an equipotential surface.
  5. For a uniform electric field, equipotential surfaces are planes normal to the x-axis.
  6. Inside a hollow-charged spherical conductor, the potential remains constant. It can be considered as an equipotential volume. No work is needed to move a point charge from the center to the surface.
  7. The direction of the equipotential surface goes from high potential to low potential.
  8. For an isolated charge, the equipotential surface is a sphere. This means concentric spheres around the charge are different equipotential surfaces.
  9. The space between equipotential surfaces enables us to find regions having a strong and weak field.
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Electric Equipotential Surface

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If electric field lines are present in an n-dimensional space, then the equipotential surface is perpendicular to this plane. This imaginary surface is along the z-axis if the field is set in an X-Y plane.

  • The equipotential surface always remains perpendicular to the electric field lines.
  • It stays at an equal potential as there is no change expected on this surface.

Along with the equipotential surface, it is necessary to consider the work done when we move the charge along the surface. In electrostatics, the work done is calculated by:

W = - q × ΔV= - ΔU

Where,

q is the charge

ΔV is the charge in potential

Δis the electric potential energy gained by the charge when it is forced to move in external electric potential.

The work done here is at the expense of electric potential. So W = - ΔU

The charge doesn’t gain any energy, as there is no change in electric potential because the surfaces are equipotential. And as there is no change in energy, no work is done.

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Magnitude of Electric Field on Equipotential Surface

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The value of the electric field in the Equipotential surface direction is zero, this is because the integral line of the electrical field is potential. Therefore, for the potential to remain the same, the electrical field must be zero.

Electrical Field on Equipotential Surface

Electrical Field on Equipotential Surface

Read More: Electric Field and Charge Important Questions


Things to Remember

  • Surface with constant electrostatic potential values is termed as an equipotential surface.
  • Work done in an equipotential field is given by: W = q0 (VY - Vz)
  • The electric field is perpendicular to the surface and the surfaces never intersect one another.
  • Equipotential surfaces are planes normal to the x-axis.
  • In a hollow spherical conductor the potential is zero.
  • The electric field value in an equipotential surface is zero. 

Read More: NCERT Solutions for Class 12 Physics Chapter 2 


Previous Year Questions

  1. A conducting sphere of radius R=20cm is given a charge Q….[JIPMER 2015]
  2. A metallic sphere is placed in a uniform electric field. The line of force follow the path (s) shown in  ….[VITEEE 2018]
  3. On moving a charges , the potential difference between the points is… [VITEEE 2011]
  4. The effective capacitance between two points is….
  5. Voltage rating of a parallel plate capacitor is….[JEE Main 2018]
  6. A bar magnet is10 cm long is kept with its north….[BITSAT 2019]
  7. In the circuit shown, find C if the effective capacitance of the whole circuit is….[JEE Main 2019]
  8. In the figure shown below, the charge on the left plate of the 10μF capacitor is −30μC….[JEE Main 2019]
  9. In The Figure Shown After The Switch S Is Turned from postion a to b….[JEE Main 2019]
  10. The effective capacitance of the whole circuit is to…...[JEE Main 2019]
  11. The dielectric constant of a material which when fully inserted in above capacitor, gives same capacitance….[JEE Main 2019]
  12. A solid conducting sphere, having a charge Q, is surrounded by an uncharged conducting hollow  ….​.[JEE Main 2019]
  13. A Plane Electromagnetic Wave Of Frequency 50 MHz travels in….[JEE Main 2019]
  14. While a capacitor remains connected to a battery, a dielectric slab is slipped between the plates…..[KCET 2001]
  15. The electron is accelerated through a potential difference of 10 V. The additional energy acquired by the electron is…
  16. Watt per ampere is unit of ?
  17. A Parallel Plate Capacitor With Square Plates Is F….[JEE Main 2019]
  18. The energy stored in a capacitor of capacity C and potential V is given by...[NEET 1996]
  19. What is the final potential difference across each capacitor? [KEAM]
  20. As shown in the figure, charges are placed at the vertices…. [VITEEE 2011]

Sample Questions 

Ques. A charged particle q = 1.4 mC, moves a distance of 0.4 m along an equipotential surface of 10 V. Determine the work done by the field during this motion. (2 marks)

Ans.

The work done by the field can be calculated using the expression:

W = - q ΔV

However for equipotential surfaces, ΔV= 0, thus the work done is W = 0.

Ques. An electron of mass m and charge e is released from rest in a uniform electric field of 106 N/C. Find out its acceleration. Also calculate the time taken by the electron to attain a speed of 1.0 c, where c is the velocity of light. (m = 9.1 10-31 Kg, e = 1.6 10-19 Coulomb and c = 3 108 m/s) (3 marks)

Ans.

The force experienced by the electron is 

F = E e

⇒ F = 106 (1.6×10-19)

⇒ F = 1.6×10-13 Newton

The acceleration of the electron is calculated by:

a = F/m= (1.6×10-13 ) ⁄ (9.1×10-31)

a = 1.8×1017 m/s2

The initial velocity = 0

Let t be the time taken by the electron in attaining a final speed of 1.0 c.

Now v = u + a.t or v = a.t

t = v/a= (0.1×c) ⁄ a= (0.1×3.1×108) ⁄ (1.8×1017)

t = 1.7 10-10 sec

Ques. Can two equipotential surfaces intersect with each other? (3 marks)

Ans.

It is not possible for two equipotential surfaces to intersect with each other as this would contradict how an equipotential surface is defined.

Each equipotential surface is defined as the set of all points in a specific region of space that shares a common potential value. If any two of these surfaces intersect, this would indicate that the points of intersection have different potential values, which is pointless.If we have the distributions with two different charges, each with its own set of equipotential surfaces and we bring them close to each other. The surfaces don’t intersect the shift form to reflect the new configuration charge.Hence, no two equipotential surfaces can ever intersect.

Ques. A positive particle having a charge of 1.0 C accelerates in a uniform electric field of 100 V/m. The article has started from rest on an equipotential plane of 50 V. After t = 0.0002 sec, the particle is on the equipotential plane of V = 10 volts. Determine the distance traveled by the particle. (3 marks)

Ans.

Here, the work done in moving a charge in an equipotential surface is given as:

W = - q ΔV

After substituting the values, we get

W = (-1.0 C) (10 V - 50 V)

W = 40 J

We know that, 

The work done in moving a charge in an electric field is:

W = q E d

40 = (1.0) (100) d

d = 0.4 m

Hence, the particle has traveled a 0.4 m distance.

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CBSE CLASS XII Related Questions

1.
(a) A circular coil of 30 turns and radius 8.0 cm carrying a current of 6.0 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.0 T. The field lines make an angle of 60° with the normal of the coil. Calculate the magnitude of the counter torque that must be applied to prevent the coil from turning. 
(b) Would your answer change, if the circular coil in (a) were replaced by a planar coil of some irregular shape that encloses the same area? (All other particulars are also unaltered.)

      2.
      A closely wound solenoid of \(2000 \) turns and area of cross-section \(1.6 × 10^{-4}\  m^2\), carrying a current of \(4.0 \ A\), is suspended through its centre allowing it to turn in a horizontal plane. 
      (a) What is the magnetic moment associated with the solenoid?
      (b) What is the force and torque on the solenoid if a uniform horizontal magnetic field of \(7.5 × 10^{-2}\  T\) is set up at an angle of \(30º\) with the axis of the solenoid?

          3.
          A spherical conductor of radius 12 cm has a charge of 1.6 × 10–7C distributed uniformly on its surface. What is the electric field ?
          1. inside the sphere
          2. just outside the sphere
          3. at a point 18 cm from the centre of the sphere?

              4.
              Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the to charges is the electric potential zero? Take the potential at infinity to be zero.

                  5.

                  In a parallel plate capacitor with air between the plates, each plate has an area of 6 × 10–3 m2 and the distance between the plates is 3 mm. Calculate the capacitance of the capacitor. If this capacitor is connected to a 100 V supply, what is the charge on each plate of the capacitor?

                      6.

                      A parallel plate capacitor made of circular plates each of radius R = 6.0 cm has a capacitance C = 100 pF. The capacitor is connected to a 230 V ac supply with a (angular) frequency of 300 rad s−1.

                      1. What is the rms value of the conduction current?
                      2. Is the conduction current equal to the displacement current?
                      3. Determine the amplitude of B at a point 3.0 cm from the axis between the plates.
                      A parallel plate capacitor made of circular plates

                          CBSE CLASS XII Previous Year Papers

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