Dielectric Constant: Formula, Units, & Values

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Jasmine Grover

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Dielectric Constant is the ratio of the substance’s electric permittivity to the electric permittivity of the free space. A dielectric is a material that has poor electrical conductivity but can store an electric charge due to Dielectric polarization. Therefore, showing only displacement current makes it an ideal choice for building a capacitor (to store and return electrical energy). The dielectric constant is denoted by the greek letter ‘κ’ (kappa). The formula of Dielectric constant can be represented by:

Dielectric Constant, \(K = \frac {\epsilon}{\epsilon_0}\) 

Here, 

  • κ = Dielectric Constant
  • ε = Permittivity of the substance
  • ε0 = Permittivity of the free space

Dielectric constant is also known as electric permittivity or simply permittivity. Dielectric constant is also called relative permittivity since it is measured relatively from the permittivity of free space (ε0). Dielectric constant depicts the ability of plastics to preserve electrical energy. 

Read More: Capacitance Formula

Key Terms: Dielectric Constant, Electric Flux, Electric Permittivity, Capacitance, Electric Charge, Electric Potential, Permittivity, Electric Field

What is Dielectric Constant?

[Click Here for Previous Year Questions] 

The ratio of the substance’s permittivity to the permittivity of the free space is defined as the dielectric constant of a substance. The dielectric constant shows the extent to which a material can hold electric flux in it.

Dielectric constant, also called relative permittivity or specific inductive capacity, is a property of an electrically insulating material equivalent to the ratio of the capacitance of a capacitor filled with the respective material to the capacitance of one identical capacitor present in vacuum without the dielectric material.

Dielectric Constant Formula

Dielectric Constant formula can be expressed as:

Dielectric Constant, \(K = \frac {\epsilon}{\epsilon_0}\) 

Where,

  • κ = Dielectric Constant
  • ε = Permittivity of the substance
  • ε0 = Permittivity of the free space

Dielectric Constant Unit

The dielectric constant is the ratio of two like entities, therefore it is a unit-less and dimensionless quantity.

Dielectric Constant Symbol

Dielectric constant symbol can be expressed using the Greek letter kappa ‘κ’. The relative permittivity of a dielectric substance can also be referred to as Dielectric Constant.

Solved Examples

Ques. Define the basic difference between active and passive dielectrics. (2 marks)

Ans. The key difference between active and passive dielectrics is that dielectrics that typically adapt easily for electrical energy storage are called active dielectrics. On the other hand, the dielectrics which are seen to restrict electrical energy storage are called passive dielectrics. An example of active dielectric is Piezoelectric, while glass is one of the major examples of passive dielectric.

Ques. Define pyro-electricity. (1 mark)

Ans. Pyro-electricity can be expressed as the creation of electronic polarization by thermal stress.

Read More:


Dielectric Constant Theory 

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Dielectric constant is the relative permittivity of a dielectric substance and is abbreviated as ‘κ’ (kappa). The dielectric constant is an important parameter to define a capacitor.

  • A capacitor is a type of electronic component that is used to store electric charge.
  • It can be constructed by sandwiching a dielectric insulating plate in between the metal conducting plates.
  • How effectively a capacitor can store charge depends upon the layer of dielectric material.

Capacitor

Capacitor

Hence, it is important to choose the correct dielectric material. The expression can be written as:

κ = Eo/E

Here,

  • The value of E0 is always greater than or equal to E.
  • Therefore, the value of a dielectric constant is always greater than 1.
  • The greater the value of κ the more will be the charge stored in a capacitor.

In the capacitor, the capacitance is given by:

C = κC0

In the parallel plate capacitor, the capacitance is given by:

C = κε0A/d

Where,

  • C = Capacitance of the parallel plate capacitor
  • κ = Dielectric Constant
  • ε0 = Permittivity of the free space
  • A = Area of parallel conducting plates
  • D = Separation between parallel conducting plates

Dielectric permittivity

Dielectric Permittivity

The value of capacitance can be increased by increasing the value of the dielectric constant and decreasing the separation between the parallel conducting plates.


Dielectric Constant Value 

[Click Here for Previous Year Questions]

The following table depicts some important dielectric constant value of dielectric materials:

Dielectric Materials Dielectric Constant Value
Vacuum 1.00
Air 1.00059
Water 80
Paper 3.6

Effect of Dielectric on Capacitance 

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Suppose there is a capacitor with parallel plates of area A and separated by a distance d. Now, for a capacitor with charge Q, the charge on each plate will be +Q and –Q. The area of the plate is A therefore the charge density will be ±σ:

⇒ σ = Q/A

Now, if the two plates have a vacuum between them, the potential energy across the capacitor will be:

⇒ V0 = E0d = V0 σ/ε0 d

Thus, the capacitance of the capacitor will be:

⇒ C0 = Q/V0 = ε0 A/d

Let us take another capacitor with the same specifications as taken earlier. We will insert a dielectric between the plates in such a way that it fully occupies the space between the plates. The dielectric is polarized by the field as it enters the field between the plates and the charges are arranged so that they act as two charged sheets with a surface charge density of σp and – σp. The net surface charge density becomes equal to ±(σ – σp).

Dielectric Inside Parallel Plate Capacitor

Dielectric Inside Parallel Plate Capacitor

And, the potential energy across the capacitor will be,

⇒ V = Ed = (σ – σp / ε0) d

In the case of linear dielectrics, σp is proportional to E0 and therefore it is proportional to σ. Thus, we can say that the value (σ – σp) is also proportional to σ.

⇒ σ − σp = σ/K

Where K is a constant whose value depends upon the selected dielectric medium.

The potential energy across the capacitor will be:

⇒ V = σd/ε0K = Qd/Aε0K

And the capacitance between the plates will be:

⇒ C = Q/V = ε0KA/d

Here ε0K is the permittivity of the medium, which can also be written as,

⇒ ε = ε0K

Here the value K is the permittivity of the medium such that, for a given medium,

⇒ K = ε/ε0

Vacuum Permittivity and Dielectric Permittivity

Vacuum Permittivity and Dielectric Permittivity

What is meant by the polarization of a dielectric material?

The polarization of dielectric material can be expressed as the process of generation of electrical dipoles within the dielectric by the application of an external electrical field.

Name the four polarization mechanisms.

The four polarization mechanisms include:

  • Orientational Polarization
  • Electronic Polarization
  • Ionic Polarization
  • Space-charge Polarization

What are some applications of Relative permittivity?

Some relative permittivity application are:

  • Energy: Relative permittivity is used in the process of designing Capacitors.
  • Communication: Relative permittivity is also used in RF transmission lines.
  • Environment: The air around us is affected by the changes in temperature, humidity and barometric pressure. The changes in the relative permittivity also impacts the changes in capacitance.

Read More:


Factors Affecting Dielectric Constant

[Click Here for Previous Year Questions]

The dielectric constant depends on various factors such as:

  • Frequency: One of the factors that influence the dielectric constant is the frequency of the voltage applied. The value of the dielectric constant becomes non-linear with the increase in the frequency of the applied voltage.
  • Applied voltage: The value of the dielectric constant decreases when we apply direct current voltage and increases when we apply alternating current voltage.
  • Temperature: The molecule alignment in the dielectric material becomes difficult at low temperatures. But when we increase the temperature, the dipoles present in the dielectric material become dominant which results in an increase in the dielectric constant.
  • Humidity and moisture: The strength of the dielectric material decreases with the increase in humidity or moisture.
  • Heating effect: The dielectric loss occurs when the dielectric material is heated. The dissipation of energy in the form of heat when molecules in a material move as it comes in contact with an alternating current voltage is known as dielectric loss.
  • Structure & morphology: The dielectric constant also gets influenced by the structure and morphology of the material.

Previous Year Questions

  1. A spherical drop of capacitance … [KCET 2004]
  2. Two equal capacitors are first connected in series … [JEE Mains 2021]
  3. A point charge +q is placed at the centre of a cube … [NEET 1996]
  4. The energy stored in a capacitor of capacity C and potential V is given by … [NEET 1996]
  5. What is the flux through a cube of side a if a point charge … [NEET 2012]
  6. In a certain region of space with volume … [NEET 2020]
  7. A hollow cylinder has a charge q … [NEET 2007]
  8. What is the effective capacitance between points … [NEET 1999]
  9. When air is replaced by a dielectric medium of constant K … [NEET 1999]
  10. A conducting sphere of radius … [NEET 2004]
  11. In a region, the potential is represented by … [NEET 2014]
  12. The electrostatic force between the metal plate … [NEET 2018]
  13. Three charges, each +q, are placed … [NEET 2011] 
  14. A capacitor of capacitance C [NEET 2002]
  15. A capacitor is charged by a battery … [NEET 2017]

Things to Remember

  • Dielectric Constant is the ratio of the substance’s electric permittivity to the electric permittivity of the free space and it is denoted by ‘κ’ (kappa).
  • Dielectric constant is a dimensionless quantity.
  • The formula for Dielectric Constant is given by, \(K = \frac {\epsilon}{\epsilon_0}\).
  • The factors affecting dielectric constant are frequency, applied voltage, temperature, humidity, moisture, heating effect and structure & morphology.

Check Important Handwritten Notes:


Sample Questions

Ques. What is the polarization of a dielectric material? (1 mark) 

Ans. The process of creating electrical dipoles within the dielectric by applying an external electric field is known as the polarization of a dielectric material.

Ques. Name the four polarization mechanisms?  (2 marks) 

Ans. Given below are the four polarization mechanisms:

  • Electronic polarization
  • Orientational polarization
  • Ionic polarization
  • Space-charge polarization

Ques. What is the difference between active and passive dielectrics?  (2 marks) 

Ans. Some of the key differences between active and passive dielectrics are:

Active Dielectrics Passive Dielectrics
The dielectrics that can easily adapt to the storage of electrical energy are called active dielectrics. The dielectrics that restrict the storage of electrical energy are called passive dielectrics.
Example: Piezoelectric Example: Glass

Ques. What is the Dielectric Constant of water? (1 mark) 

Ans. The dielectric constant of water is 80.

Ques. What are the different breakdown mechanisms in dielectrics? (2 marks) 

Ans. Here are the various breakdown mechanisms in dielectrics:

  • Intrinsic & Avalanche Breakdown
  • Chemical & Electrochemical Breakdown
  • Thermal Breakdown
  • Defect Breakdown
  • Discharge Breakdown

Ques. Define the dielectric constant of a medium. What is its unit? (2 marks) 

Ans. Dielectric When a dielectric slab is introduced between the plates of a charged capacitor or in the region of the electric field, an electric field EP induces inside the dielectric due to induced charge on dielectric in a direction opposite to the direction of the applied external electric field. Hence, the net electric field inside the dielectric gets reduced to £0 – £P, where £0 is an external electric field. The ratio of applied external electric field and a reduced electric field is known as dielectric constant K of the dielectric medium, i.e.

K= E0 / E0 – EP

Ques. What is a Parallel Plate Capacitor? (3 marks) 

Ans. The most common among all capacitors is parallel plate capacitor. It comprises two metal plates of area A and separated by distance d filled with air or some other dielectric medium. The capacitance of air filled parallel plate capacitor is given by C0 = ε0 / d

Parallel Plate Capacitor

When a dielectric of dielectric constant K is filled fully between the plates, then C= KAε0 / d = KC0

Ques. Define the dielectric strength of a dielectric. (1 mark) 

Ans. The dielectric strength of a dielectric is the maximum value of the applied electric field required to just breakdown of the dielectric material.

Ques. The figure shows two identical capacitors C1 and C2 each of 1.5 µF capacitance, connected to a battery of 2 V. Initially switch ‘S’ is closed. After sometime ‘S’ is left open and dielectric slabs of dielectric constant K = 2 are inserted to fill completely the space between the plates of the two capacitors. How will the
(i) charge and
(ii) potential difference between the plates of the capacitors be affected after the slabs are inserted?  (3 marks) 
The figure shows two identical capacitors C1 and C2 each of 1.5 µF capacitance, connected to a battery of 2 V. Initially switch ‘S’ is closed

Ans. (i) When switch S is open and dielectric is introduced, charge on each capacitor, will be

q1 = C1V,

q2 = C2V,

q1 = 2CV = 2 × 1.5 × 2 = 6 µC, q2 = 6 µC

Charge on each capacitor will become twice.

(ii) P.d. across C1 is still 2V and across C2,

q = (2C) V’

∴ V’ = V/2 = 2/2 = 1V

Ques. A parallel plate capacitor is charged by a battery. After some time the battery is disconnected and a dielectric slab of dielectric constant K is inserted between the plates. How would
(i) the capacitance,
(ii) the electric field between the plates and
(iii) the energy stored in the capacitor, be affected? Justify your answer.  (3 marks) 

Ans. Let C be the capacitance and V be the potential difference.

The charge on the capacitor plates will then be Q = CV.

The electric field between the plates, 

E = V/d

 and the energy stored,

En = Q2 / 2C or ½ CV

As the dielectric (K) is introduced after disconnecting the battery

We have the new values of charge, Q’ = Q Capacitance C’ = KC

Potential V’ = Q/KC=V/K

(i) New capacitance is K times its original.

 the electric field between the plates and (iii) the energy stored in the capacitor, be affected? Justify your answer

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                      CBSE CLASS XII Previous Year Papers

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