NCERT Solutions For Class 12 Physics Chapter 2: Electrostatic Potential and Capacitance

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NCERT Solutions for Class 12 Physics Chapter 2 Electrostatic Potential and Capacitance are provided in this article. The chapter provides good weightage to derivations and numerical problems related to the concepts covered in the chapter. The NCERT Solutions for Class 12 Physics Chapter 2 covers concepts of electrostatic potential, equipotential surfaces, parallel plate capacitors, etc.

The derivation of topics like potential due to an electric dipole, energy stored in the capacitor and potential energy of the system of charges, is frequently asked in the examination. Numerical problems based on the concepts of the effective capacitance of a combination of capacitors are asked regularly in the exams. 

Download PDF: NCERT Solutions for Class 12 Physics Chapter 2


NCERT Solutions for Class 12 Physics Chapter 2

NCERT Solutions for Electrostatic Potential and Capacitance are as given below – 

NCERT Solutions Physics NCERT Solutions Physics NCERT Solutions Physics NCERT Solutions Physics NCERT Solutions Physics NCERT Solutions Physics NCERT Solutions Physics NCERT Solutions Physics NCERT Solutions Physics NCERT Solutions Physics NCERT Solutions Physics NCERT Solutions Physics NCERT Solutions Physics NCERT Solutions Physics

Electrostatic Potential and Capacitance Important Topics

  • Electrostatic Potential is the amount of work done to move a unit charge from a reference point to a specific point inside the electric field without producing an acceleration.

The electrostatic potential of the system is given by the formula:

U = 1/(4πεº) × [q1q2/d]

  • Capacitance is the ratio of change in the electric charge of a system, to the corresponding change in the electric potential.

The formula for capacitance is given by:

\(\begin{array}{l}C=\frac{Q}{V}\end{array}\)

The total energy extracted from a fully charged capacitor is given by the following equation:

\(\begin{array}{l}U=\frac{1}{2}CV^2\end{array}\)

  • Electrostatic Potential of a Charge: When a charge, q, is placed in an electric field E, it experiences a force proportional to the magnitude of the charge equal to q × E. If the resultant work done is then divided by the magnitude of charge, it becomes independent of the charge. 

The work done by an external force in bringing a unit positive charge from a point A to point B is given by,

\(V_B -V_A={U_B-U_A \over q}\)


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CBSE CLASS XII Related Questions

  • 1.

    Assertion (A): The deflection in a galvanometer is directly proportional to the current passing through it. 

    Reason (R): The coil of a galvanometer is suspended in a uniform radial magnetic field.

      • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A)
      • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
      • Assertion (A) is true, but Reason (R) is false.
      • Assertion (A) is false and Reason (R) is also false.

    • 2.
      In the given figure, three identical bulbs P, Q, and S are connected to a battery.
      three identical bulbs P, Q, and S

      [(i)] Compare the brightness of bulbs P and Q with that of bulb S when key K is closed.

      [(ii)] Compare the brightness of the bulbs S and Q when the key K is opened.
      Justify your answer in both cases.


        • 3.
          A metal rod of length 50 cm is held vertically and moved with a velocity in a magnetic field at the place of 0.4 G. The emf induced across the ends of the rod is:

            • 0.1 mV
            • 0.2 mV
            • 0.8 mV
            • 1.6 mV

          • 4.
            Define 'Mass defect' and 'Binding energy' of a nucleus. Describe the 'Fission process' on the basis of binding energy per nucleon.


              • 5.

                A battery of emf \( E \) and internal resistance \( r \) is connected to a rheostat. When a current of 2A is drawn from the battery, the potential difference across the rheostat is 5V. The potential difference becomes 4V when a current of 4A is drawn from the battery. Calculate the value of \( E \) and \( r \).


                  • 6.
                    In the figure, curved lines represent equipotential surfaces. A charge \( Q \) is moved along different paths A, B, C, and D. The work done on the charge will be maximum along the path:
                     curved lines represent equipotential surfaces

                      • A
                      • B
                      • C
                      • D
                    CBSE CLASS XII Previous Year Papers

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