Jasmine Grover Content Strategy Manager
Content Strategy Manager
NCERT Solutions for Class 12 Physics Chapter 2 Electrostatic Potential and Capacitance are provided in this article. The chapter provides good weightage to derivations and numerical problems related to the concepts covered in the chapter. The NCERT Solutions for Class 12 Physics Chapter 2 covers concepts of electrostatic potential, equipotential surfaces, parallel plate capacitors, etc.
The derivation of topics like potential due to an electric dipole, energy stored in the capacitor and potential energy of the system of charges, is frequently asked in the examination. Numerical problems based on the concepts of the effective capacitance of a combination of capacitors are asked regularly in the exams.
Download PDF: NCERT Solutions for Class 12 Physics Chapter 2
NCERT Solutions for Class 12 Physics Chapter 2
NCERT Solutions for Electrostatic Potential and Capacitance are as given below –
Electrostatic Potential and Capacitance Important Topics
- Electrostatic Potential is the amount of work done to move a unit charge from a reference point to a specific point inside the electric field without producing an acceleration.
| The electrostatic potential of the system is given by the formula: U = 1/(4πεº) × [q1q2/d] |
- Capacitance is the ratio of change in the electric charge of a system, to the corresponding change in the electric potential.
| The formula for capacitance is given by: \(\begin{array}{l}C=\frac{Q}{V}\end{array}\) |
- Energy stored in a capacitor: Once the opposite charges are placed on either side of a parallel-plate capacitor, the charges can be allowed to move towards each other through a circuit.
| The total energy extracted from a fully charged capacitor is given by the following equation: \(\begin{array}{l}U=\frac{1}{2}CV^2\end{array}\) |
- Electrostatic Potential of a Charge: When a charge, q, is placed in an electric field E, it experiences a force proportional to the magnitude of the charge equal to q × E. If the resultant work done is then divided by the magnitude of charge, it becomes independent of the charge.
| The work done by an external force in bringing a unit positive charge from a point A to point B is given by, \(V_B -V_A={U_B-U_A \over q}\) |
Also Read:
Check-Out:
Comments