When magnetic field lines are close, the magnetic field is?

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Jasmine Grover

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Magnetic field lines are used to visualize and represent the direction and strength of the magnetic field in a given region of space.

  • The closer the field lines are to each other, the stronger the magnetic field is in that region.
  • This is because the density of magnetic field lines represents the strength of the magnetic field.
  • If the field lines are close together, it means that the magnetic field is changing rapidly, and there is a large magnetic force acting in the region.
  • In contrast, if the field lines are far apart, the magnetic field is weaker because there is less force acting in that region.
Magnetic field lines

In other words, the magnetic field lines behave like a map that tells us about the strength and direction of the magnetic field. When the field lines are close together, they indicate that the magnetic field is strong, and when they are far apart, they indicate that the magnetic field is weak. Therefore, the density of the magnetic field lines provides a visual representation of the strength of the magnetic field.

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CBSE CLASS XII Related Questions

  • 1.
    An astronomical telescope consists of two converging lenses. One of them of large aperture and large focal length is called objective lens and the other one, of smaller focal length and smaller aperture is called the eyepiece. It is used to see distant objects which are not seen clearly with naked eyes. The image formed by the objective lens acts as an object for the eyepiece and the final image produced by the eyepiece is magnified.


      • 2.
        When a dielectric is placed in an external electric field, the electric field inside the dielectric is less than that outside it.Explain


          • 3.
            An inductor of \(\frac{5}{\pi}\,H\), a capacitor of \(\frac{50}{\pi}\,\mu F\) and a resistor of \(400\,\Omega\) are connected in series across an ac voltage \[ v = 140 \sin(100\pi t)\,V. \] Calculate:
            • (I) impedance of the circuit
            • (II) rms value of current in the circuit} (Take \(\sqrt{2}=1.4\))


              • 4.
                Derive the relation for the refractive index ($\mu$) of a prism in terms of angle of minimum deviation ($\delta_m$) and angle of prism ($A$).

                  • $\mu = \frac{\sin\left(\frac{A + \delta_m}{2}\right)}{\sin\left(\frac{A}{2}\right)}$
                  • $\mu = \frac{\cos\left(\frac{A + \delta_m}{2}\right)}{\cos\left(\frac{A}{2}\right)}$
                  • $\mu = \frac{\sin\left(\frac{A - \delta_m}{2}\right)}{\sin\left(\frac{A}{2}\right)}$
                  • $\mu = \frac{\tan\left(\frac{A + \delta_m}{2}\right)}{\tan\left(\frac{A}{2}\right)}$

                • 5.
                  A student sets up the circuit as shown in the figure to find the value of unknown resistance X and records a set of readings of the voltmeter and the ammeter by using the rheostat.


                    • 6.
                      Draw a labelled diagram of a step-up transformer. Obtain the ratio of secondary voltage to primary voltage in terms of number of turns in the two coils.

                        CBSE CLASS XII Previous Year Papers

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