NCERT Solutions For Class 12 Physics Chapter 9: Ray Optics and Optical Instruments

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NCERT Solutions for Class 12 Physics Chapter 9 Ray Optics and Optical Instruments are provided in this article. Optics helps us study the properties and behaviour of light. In Ray Optics, the light travels in a straight line stating that there is an image for each and every object. The optical devices made utilising reflecting and refracting properties of lenses, mirrors and prisms known as Optical instruments.

Class 12 Physics Chapter 9 is a part of Unit 6 Optics which along with Unit 5 Electromagnetic Waves has a weightage of 18 marks in the CBSE Class 12 Board exam.  The NCERT Solutions for Class 12 Physics Chapter 9 covers concepts of refractionSnell’s Law, and total internal reflection

Download PDF: NCERT Solutions for Class 12 Physics Chapter 9 Ray Optics and Optical Instruments


NCERT Solutions for Class 12 Physics Chapter 9

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Class 12 Physics Chapter 9 – Important Topics Covered

  • Ray Optics is the branch of physics that deals with the behaviour of light as a ray which travels in a straight line.
Light always travels in a straight line. It does not require any medium to travel
  • Reflection is the phenomenon wherein light changes its path without any change in the medium.

Laws of Reflection

  1. The angle of incidence, represented as i is equal to the angle of reflection, represented as r.
    ∠i = ∠r.
  2. The incident ray, the reflected ray and the normal to the reflecting surface at the incidence point, all lie in the same plane.
  • The mirror formula represents a relation between the focal length of the mirror and the distances of objects and images from the mirror.
\({1 \over v} + {1 \over u} = {1 \over f} \)
  • Linear Magnification: The ratio of the size of the image that is formed by a spherical mirror I to the size of the object O is known as linear magnification.
\(m={I \over O}={-v \over u}\)
  • Refraction is the phenomenon of change in the path of light as it goes from one medium to another.

Laws of Refraction

  1. The incident ray, refracted ray and the normal to the refracting surface at the point of incidence, all lie in the same plane.
  2. The ratio of the sin of the angle of incidence to the sin of the angle of refraction is constant for any two given mediums. This constant is the relative refractive index.

n = sin i/sin r (Snell’s law)

where, n is the refractive index of the second medium when first medium is air.
 


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CBSE CLASS XII Related Questions

  • 1.
    A part of a wire carrying \( 2.0 \, \text{A} \) current and bent at \( 90^\circ \) at two points is placed in a region of uniform magnetic field \( \vec{B} = -0.50 \, \hat{k} \, \text{T} \), as shown in the figure. Calculate the magnitude of the net force acting on the wire.


      • 2.
        In a Young's double-slit experiment, two waves each of intensity I superpose each other and produce an interference pattern. Prove that the resultant intensities at maxima and minima are 4I and zero respectively.


          • 3.
            The energy of an electron in an orbit in hydrogen atom is \( -3.4 \, \text{eV} \). Its angular momentum in the orbit will be:

              • \( \dfrac{3h}{2\pi} \)
              • \( \dfrac{2h}{\pi} \)
              • \( \dfrac{h}{\pi} \)
              • \( \dfrac{h}{2\pi} \)

            • 4.
              A ray of light MN is incident normally on the face corresponding with side AB of a prism with an isosceles right-angled triangular base ABC. Trace the path of the ray as it passes through the prism when the refractive index of the prism material is \( \sqrt{2} \), and \( \sqrt{3} \).


                • 5.
                  A 500 nm photon is incident normally on a perfectly reflecting surface and is reflected. The value of momentum transferred to the surface is:

                    • \( 3.87 \times 10^{-43} \, \text{kg} \, \text{ms}^{-1} \)
                    • \( 2.5 \times 10^{-30} \, \text{kg} \, \text{ms}^{-1} \)
                    • \( 2.65 \times 10^{-27} \, \text{kg} \, \text{ms}^{-1} \)
                    • \( 1.33 \times 10^{-27} \, \text{kg} \, \text{ms}^{-1} \)

                  • 6.
                    The magnetic field in a plane electromagnetic wave travelling in glass (\( n = 1.5 \)) is given by \[ B_y = (2 \times 10^{-7} \text{ T}) \sin(\alpha x + 1.5 \times 10^{11} t) \] where \( x \) is in metres and \( t \) is in seconds. The value of \( \alpha \) is:

                      • \( 0.5 \times 10^3 \, \text{m}^{-1} \)
                      • \( 6.0 \times 10^2 \, \text{m}^{-1} \)
                      • \( 7.5 \times 10^2 \, \text{m}^{-1} \)
                      • \( 1.5 \times 10^3 \, \text{m}^{-1} \)
                    CBSE CLASS XII Previous Year Papers

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