JEE Main 2026 April 2 Shift 1 Analysis: Was the Paper Tough

According to the experts analysis and students reaction who appeared in the JEE Main 2026 April Shift 1 exam, the question paper was moderate to tough. NTA has conducted JEE Main 2026 April Shift 1 exam at 9:00 AM to 12:00 PM (IST). Candidate who appeared in the exam have shared their reaction on various coaching platforms such as CollegeDunia.

Some students mentioned that 200+ marks is needed to score around 99 percentile.
Other students mentioned that 170 - 180 marks are required for 99 percentile.
Maths was not tough but the calculations were lengthy and includes 2 questions from Vector 3D.
Physics was durable and high weightage that includes 2-3 questions from Modern Physics and 2 -3 from Electrostatics.
Chemistry was easy and simple that includes mixed questions of Inorganic and Physical Chemistry, specially from co-ordination compound.

Students who are supposed to appear in the upcoming shift must focus on clearing the concept and revise all formulas.

Also Check:

JEE Main 2026 April 2 Shift 1 Analysis: Was the Paper Tough

Check JEE Main 2026 2nd April Detailed Analysis by CollegeDunia

JEE Main 2026 April 2 Shift 1 Overall Difficulty Level

As per the students reactions shared by CollegeDunia, the JEE Main 2026 April 2 Shift 1 question paper was moderate. Students mentioned that it was easy in comparison to the January paper.

Subject-Wise JEE Main 2026 April 2 Shift 1 Analysis

The JEE Main 2026 April 2 Shift 1 paper shows variation in Physics, Chemistry, and Mathematics. Every subject has a different difficulty level and impact on performance.

JEE Main 2026: April 2 Shift 1 Physics Analysis

Difficulty: Moderate

Key Topics & Weightage:

Mechanics (basic concepts and application-based questions)
Electrostatics and Current Electricity
Modern Physics
Thermodynamics

Student Reactions:

Questions were mostly formula-based with some conceptual application
Not very tricky, but need clear understanding of fundamentals
Considered balanced and manageable by most students

JEE Main 2026: April 2 Shift 1 Chemistry Analysis

Difficulty: Easy to Moderate (Easiest Section)

Key Topics & Weightage:

Inorganic Chemistry (NCERT-based questions)
Physical Chemistry (basic numerical questions)
Organic Chemistry (standard reactions and concepts)

Student Reactions:

Majority of questions were direct and NCERT-based
Required less time compared to other subjects
Helped students boost their overall score easily

JEE Main 2026: April 2 Shift 1 Mathematics Analysis

Difficulty: Moderate to Tough

Key Topics & Weightage:

Calculus (Integration, Differentiation)
Algebra (Matrices, Determinants)
Coordinate Geometry
Vectors and 3D Geometry

Student Reactions:

Questions were lengthy and calculation-intensive
Most time-consuming section of the paper
Many students found it difficult to complete on time

Check: Predict Your College Chances As Per Your JEE Main 2026 Marks

Student Reactions & Feedback on JEE Main 2026 April 2 Shift 1

Students coming out of the exam centre mentioned EE Main 2026 April 2 Shift 1 paper to be moderate and balanced.

Time Management: Time management was a major challenge in the paper especially because of lengthy Mathematics questions.
Subject-wise: Students found Chemistry was easiest, Physics was moderate, and Mathematics was the most time-consuming and difficult section.
Overall Sentiment: Most students felt the paper was moderate but lengthy, where performance was mostly depended on speed and accuracy and not difficulty level.

Aspect	Student Feedback	Approx. Percentage of Students
Overall Difficulty	Moderate	75%
Time Management	Challenging (due to Maths)	85%
Physics Section	Moderate, concept-based	75%
Chemistry Section	Easy to Moderate, NCERT-based	80%
Mathematics Section	Lengthy and time-consuming	90%
Paper Nature	Balanced but Lengthy	80%

Also Read: JEE Main 2026 April 2 Shift 1 Answer Key

Key Takeaways & Preparation Tips for Remaining JEE Main 2026 April Shifts

Prioritize Chemistry first during the exam to secure quick and easy marks.
Attempt Physics next, focusing on formula-based and direct questions.
Keep Mathematics for last, and avoid spending too much time on one question.

Aspect	Key Takeaway	Preparation Tip
Overall Paper Level	Moderate but lengthy	Focus on speed + accuracy, not just difficulty
Mathematics	Most time-consuming and rank-deciding	Attempt selective questions, avoid getting stuck
Physics	Moderate, formula + concept-based	Revise formulas and practice application-based questions
Chemistry	Easiest and scoring (NCERT-based)	Prioritize NCERT revision and attempt first in exam
Time Management	Biggest challenge in the paper	Follow fixed order: Chemistry - Physics - Maths
Attempt Strategy	Not all questions are doable	Skip lengthy questions initially, attempt later
Revision Focus	Important topics repeated	Revise PYQs and short notes regularly
Competition Level	Very high, small mistakes matter	Focus on accuracy to avoid negative marking

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4ADFK1

1.
For tetrahedral complex, the correct order of energy of \(d\)-orbitals is:

\(d_{xy} = d_{xz}>d_{x^2-y^2}\)
\(d_{xy} = d_{yz}>d_{zx}\)
\(d_{x^2-y^2}>d_{z^2}>d_{xz}\)
\(d_{x^2-y^2} = d_{z^2}<d_{xy} = d_{yz} = d_{xz}\)

View Solution

2.
In the expansion of \( (1 + \alpha x)^{26} \) and \( (1 - \alpha x)^{28} \), the coefficient of the middle term is the same, then the value of \( \alpha \) is:

\( \dfrac{7}{22} \)
\( \dfrac{7}{27} \)
\( \dfrac{5}{27} \)
\( \dfrac{5}{22} \)

View Solution

3.
In an AC series circuit supply voltage \(V_{\text{rms}} = 100\) volts; \(R = 80\,\Omega\), \(X_L = 80\,\Omega\) and source frequency is \(f = 50\) Hz. Find the power factor.

\( \dfrac{1}{\sqrt{2}} \)
\( \dfrac{1}{2} \)
\( \dfrac{3}{4} \)
\( \dfrac{\sqrt{3}}{2} \)

View Solution

4.
Electric field at the centre of a semi-circular ring of radius \(10\,\text{cm}\) is \(100\,\text{V/m}\). Find the charge on the ring if the charge distribution is uniform.

\(4\varepsilon_0\)
\(20\varepsilon_0\)
\(25\varepsilon_0\)
\(30\varepsilon_0\)

View Solution

5.
If \( x_1, x_2, \dots, x_{25} \) be 25 observations such that \( \sum_{i=1}^{25} (x_i + 5)^2 = 2500 \) and \( \sum_{i=1}^{25} (x_i - 5)^2 = 1000 \). Then, the ratio of Mean and Standard deviation of the given observations is:

\( \dfrac{1}{4} \)
\( \dfrac{1}{2} \)
\( \dfrac{2}{3} \)
\( \dfrac{1}{5} \)

View Solution

6.
Consider the reaction:
Find the number of moles of benzene formed if the efficiency of reaction is 60%.

0.05
0.06
0.03
0.04

View Solution

JEE Main 2026 April 2 Shift 1 Analysis: Was the Paper Tough

JEE Main 2026 April 2 Shift 1 Overall Difficulty Level

Subject-Wise JEE Main 2026 April 2 Shift 1 Analysis

JEE Main 2026: April 2 Shift 1 Physics Analysis

JEE Main 2026: April 2 Shift 1 Chemistry Analysis

JEE Main 2026: April 2 Shift 1 Mathematics Analysis

Student Reactions & Feedback on JEE Main 2026 April 2 Shift 1

Key Takeaways & Preparation Tips for Remaining JEE Main 2026 April Shifts

4ADFK1

1.
For tetrahedral complex, the correct order of energy of \(d\)-orbitals is:

2.
In the expansion of \( (1 + \alpha x)^{26} \) and \( (1 - \alpha x)^{28} \), the coefficient of the middle term is the same, then the value of \( \alpha \) is:

3.
In an AC series circuit supply voltage \(V_{\text{rms}} = 100\) volts; \(R = 80\,\Omega\), \(X_L = 80\,\Omega\) and source frequency is \(f = 50\) Hz. Find the power factor.

4.
Electric field at the centre of a semi-circular ring of radius \(10\,\text{cm}\) is \(100\,\text{V/m}\). Find the charge on the ring if the charge distribution is uniform.

5.
If \( x_1, x_2, \dots, x_{25} \) be 25 observations such that \( \sum_{i=1}^{25} (x_i + 5)^2 = 2500 \) and \( \sum_{i=1}^{25} (x_i - 5)^2 = 1000 \). Then, the ratio of Mean and Standard deviation of the given observations is:

6.
Consider the reaction:
Find the number of moles of benzene formed if the efficiency of reaction is 60%.

Comments

dOGVmW

JEE Main 2026 April 2 Shift 1 Overall Difficulty Level

Subject-Wise JEE Main 2026 April 2 Shift 1 Analysis

JEE Main 2026: April 2 Shift 1 Physics Analysis

JEE Main 2026: April 2 Shift 1 Chemistry Analysis

JEE Main 2026: April 2 Shift 1 Mathematics Analysis

Student Reactions & Feedback on JEE Main 2026 April 2 Shift 1

Key Takeaways & Preparation Tips for Remaining JEE Main 2026 April Shifts

4ADFK1

1.For tetrahedral complex, the correct order of energy of \(d\)-orbitals is:

2.In the expansion of \( (1 + \alpha x)^{26} \) and \( (1 - \alpha x)^{28} \), the coefficient of the middle term is the same, then the value of \( \alpha \) is:

3.In an AC series circuit supply voltage \(V_{\text{rms}} = 100\) volts; \(R = 80\,\Omega\), \(X_L = 80\,\Omega\) and source frequency is \(f = 50\) Hz. Find the power factor.

4.Electric field at the centre of a semi-circular ring of radius \(10\,\text{cm}\) is \(100\,\text{V/m}\). Find the charge on the ring if the charge distribution is uniform.

5.If \( x_1, x_2, \dots, x_{25} \) be 25 observations such that \( \sum_{i=1}^{25} (x_i + 5)^2 = 2500 \) and \( \sum_{i=1}^{25} (x_i - 5)^2 = 1000 \). Then, the ratio of Mean and Standard deviation of the given observations is:

6.Consider the reaction: Find the number of moles of benzene formed if the efficiency of reaction is 60%.

Comments

dOGVmW

1.
For tetrahedral complex, the correct order of energy of \(d\)-orbitals is:

2.
In the expansion of \( (1 + \alpha x)^{26} \) and \( (1 - \alpha x)^{28} \), the coefficient of the middle term is the same, then the value of \( \alpha \) is:

3.
In an AC series circuit supply voltage \(V_{\text{rms}} = 100\) volts; \(R = 80\,\Omega\), \(X_L = 80\,\Omega\) and source frequency is \(f = 50\) Hz. Find the power factor.

4.
Electric field at the centre of a semi-circular ring of radius \(10\,\text{cm}\) is \(100\,\text{V/m}\). Find the charge on the ring if the charge distribution is uniform.

5.
If \( x_1, x_2, \dots, x_{25} \) be 25 observations such that \( \sum_{i=1}^{25} (x_i + 5)^2 = 2500 \) and \( \sum_{i=1}^{25} (x_i - 5)^2 = 1000 \). Then, the ratio of Mean and Standard deviation of the given observations is:

6.
Consider the reaction:
Find the number of moles of benzene formed if the efficiency of reaction is 60%.