Expected Percentile for JEE Main April 5 2026 Shift 1 Score 150 marks

150 marks in April 5th shift 1 is likely to give 97-98 percentile. Your expected rank for ‌150 marks is expected to be around 25,000-40,000.

Based on the April shift’s analysis, we can expect the April 5th Shift 1 paper to be moderate overall. Mathematics is more likely to remain the toughest, and Chemistry to be a easy section.
150 marks in JEE Main 2026 April session can qualify for JEE Advanced 2026.
You have strong chances of getting core branches such as Electrical, ECE, Mechanical, or Civil at mid-tier NITs like Jalandhar, Raipur, and Hamirpur.

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Expected Percentile for JEE Main April 5 2026 Shift 1 Score 150 marks

Expected Difficulty Level for JEE Main April 5, 2026 Shift 1

By analysing the previous shifts of JEE Main 2026 April sessions, all papers have had a moderate paper. We can expect the same trend for April 5th Shift 1 as well.

Mathematics is expected to be the toughest section among the 3 sections. It is expected to have questions that require heavy calculations.
The physics paper is expected to be moderate. The questions are more likely to be a mix of both conceptual and formula-based questions.
Chemistry is more likely to be an easier section. The questions can be expected to be more direct and NCERT-based.

Subject	Difficulty level of April 5 Shift 1 (Expected)
Physics	Moderate
Chemistry	Easy to Moderate
Mathematics	Moderate to tough
Overall	Moderate

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Check: Expected JEE Main Cutoff Percentile for General Category to qualify for NITs

Expected Percentile for 150 Marks in JEE Main 2026 April 5 Shift 1

Based on the April shifts’ papers analysis, 150 marks in JEE Main 2026 April 5 shift 1 is likely to result in a 97-98 percentile.

With 150 marks in the JEE Main April session, you can get rank among 25,000-40,000 students.
You can qualify for JEE Advanced 2026 with 150 marks in JEE Main 2026 comfortably.

JEE Main Marks	Expected JEE Main Percentile (Approx)
170-172	99
150-152	98
138-140	97
128-130	96
120-122	95

Expected Percentile for 150 Marks in JEE Main 2026 April 5 Shift 1

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Ques. What rank can I expect with score of 150 in JEE Main 2026 April Shifts?

Ans. Your AIR is more likely to fall between 25,000 - 40,000. If the shift is on tougher side, you can expect around 18,000-35,000 ranks for 150 marks.

Ques. Is 150 marks enough to qualify for JEE Advanced?

Ans. Yes, 150 marks is typically more than enough to qualify for JEE Advanced. The qualifying cutoff for JEE Advanced is usually between 93-94 percentile (general category), whereas 150 marks usually results 97-98 percentile.

Check:

120 Marks in JEE Main Percentile	190 Marks in JEE Main Percentile
250 Marks in JEE Main Percentile	200 Marks in JEE Main Percentile
240 Marks in JEE Main Percentile	180 Marks in JEE Main Percentile

What do 150 Marks in JEE Main 2026 in the April Session Mean for College Admission?

150 marks in the April session is considered strong performance. You can get admission chances at many colleges, including NITs, IIITs, and GFTIs.

97-98 percentile is typically ‌not enough for CSE at NIT Trichy or Surathkal; however, you can get Civil or Mechanical Engineering at these NITs.
If you want CSE at any IIT, you have chances at North-East NITs like NIT Meghalaya, or Mizoram with 150 marks.
You can get Core branches like ECE, Mechanical, or Electrical at Mid-tier NITs.

College Tier	Example Colleges	Likely Branches	Admission chances
Top-Tier NITs	NIT TrichyNIT SurathkalNIT Warangal	CivilMetallurigal ChemicalMechanical (rarely)	Possible for core / lower branches. CSE/ECE is difficult for general OS candidate
Mid-tier NITs	NIT JalandharNIT RaipurNIT Silchar	Electrical, Mechanical, ECE, Civil	Strong chances for core branches. CSE is possible for Home state candidate
New NITs	NIT MeghalayaNIT MizoramNIT Manipur	CSE, IT, ECE	HIgh probability for top branches like CSE or IT
Top IIITs	IIIT LucknowIIITM GwaliorIIIT Pune	ECE, IT	Strong chance for specialised branches. Good chance for ECE.
GFTIs	BIT MesraPEC ChandigarhIIEST Shibpur	ECE, Mechanical	Very good chances for preferred branches in top GFTIs

Also Read:

List of Colleges Accepting JEE Mains 2026 Score in Tami Nadu

Ques. Which NITs can I get into with 150 Marks?

Ans. With 150 marks in JEE Main, you have strong chances of getting ECE, Electrical, or other core branches at IIT Jalandhar, Hamirpur, Raipur, or other mid-tier NITs. CSE is typically difficult with 150 marks, especially for general category.

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JEE Main Questions

1.
If \( x_1, x_2, \dots, x_{25} \) be 25 observations such that \( \sum_{i=1}^{25} (x_i + 5)^2 = 2500 \) and \( \sum_{i=1}^{25} (x_i - 5)^2 = 1000 \). Then, the ratio of Mean and Standard deviation of the given observations is:

\( \dfrac{1}{4} \)
\( \dfrac{1}{2} \)
\( \dfrac{2}{3} \)
\( \dfrac{1}{5} \)

View Solution

2.
Consider the reaction:
Find the number of moles of benzene formed if the efficiency of reaction is 60%.

0.05
0.06
0.03
0.04

View Solution

3.
An object is placed in air (\(n_1 = 1\)) at a distance \(4R\) from a spherical refracting surface that separates air from a medium of refractive index \(n_2 = 1.4\). The surface has a radius of curvature \(R\), with its centre lying in the second medium. Find the magnitude of magnification of the image formed.

\( \dfrac{5}{3} \)
\( \dfrac{3}{5} \)
\( \dfrac{7}{5} \)
\( \dfrac{5}{7} \)

View Solution

4.
The value of \( 1^3 - 2^3 + 3^3 - 4^3 + \dots + 15^3 \) is equal to:

1856
1854
1786
1826

View Solution

5.
Sucrose hydrolyses in acidic medium to form glucose and fructose which follows first order kinetics. If the half-life of sucrose is 3 hrs, find the % of sucrose left after 6 hrs.

View Solution

6.
Given below are two statements:

Both Statement I and Statement II are correct
Statement I is incorrect, Statement II is correct
Statement I is correct, Statement II is incorrect
Both Statement I and Statement II are incorrect

View Solution

Expected Percentile for JEE Main April 5 2026 Shift 1 Score 150 marks

Expected Difficulty Level for JEE Main April 5, 2026 Shift 1

Expected Percentile for 150 Marks in JEE Main 2026 April 5 Shift 1

What do 150 Marks in JEE Main 2026 in the April Session Mean for College Admission?

JEE Main Questions

1.
If \( x_1, x_2, \dots, x_{25} \) be 25 observations such that \( \sum_{i=1}^{25} (x_i + 5)^2 = 2500 \) and \( \sum_{i=1}^{25} (x_i - 5)^2 = 1000 \). Then, the ratio of Mean and Standard deviation of the given observations is:

2.
Consider the reaction:
Find the number of moles of benzene formed if the efficiency of reaction is 60%.

4.
The value of \( 1^3 - 2^3 + 3^3 - 4^3 + \dots + 15^3 \) is equal to:

5.
Sucrose hydrolyses in acidic medium to form glucose and fructose which follows first order kinetics. If the half-life of sucrose is 3 hrs, find the % of sucrose left after 6 hrs.

6.
Given below are two statements:

Comments

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Expected Difficulty Level for JEE Main April 5, 2026 Shift 1

Expected Percentile for 150 Marks in JEE Main 2026 April 5 Shift 1

What do 150 Marks in JEE Main 2026 in the April Session Mean for College Admission?

JEE Main Questions

1.If \( x_1, x_2, \dots, x_{25} \) be 25 observations such that \( \sum_{i=1}^{25} (x_i + 5)^2 = 2500 \) and \( \sum_{i=1}^{25} (x_i - 5)^2 = 1000 \). Then, the ratio of Mean and Standard deviation of the given observations is:

2.Consider the reaction: Find the number of moles of benzene formed if the efficiency of reaction is 60%.

4.The value of \( 1^3 - 2^3 + 3^3 - 4^3 + \dots + 15^3 \) is equal to:

5.Sucrose hydrolyses in acidic medium to form glucose and fructose which follows first order kinetics. If the half-life of sucrose is 3 hrs, find the % of sucrose left after 6 hrs.

6.Given below are two statements:

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
If \( x_1, x_2, \dots, x_{25} \) be 25 observations such that \( \sum_{i=1}^{25} (x_i + 5)^2 = 2500 \) and \( \sum_{i=1}^{25} (x_i - 5)^2 = 1000 \). Then, the ratio of Mean and Standard deviation of the given observations is:

2.
Consider the reaction:
Find the number of moles of benzene formed if the efficiency of reaction is 60%.

4.
The value of \( 1^3 - 2^3 + 3^3 - 4^3 + \dots + 15^3 \) is equal to:

5.
Sucrose hydrolyses in acidic medium to form glucose and fructose which follows first order kinetics. If the half-life of sucrose is 3 hrs, find the % of sucrose left after 6 hrs.

6.
Given below are two statements: