Expected Percentile for JEE Main April 4 2026 Shift 1 Score 150 marks

Expected percentile for 150 marks in JEE Main 2026 April 4th shift 1 is more likely to be in the range of 97-98.

25,000-40,000 ranks are expected for the students who score 150 marks in April 4th Shift 1.
CSE might be difficult with 150 marks, especially at top NITs like Surathkal, Warangal, or Trichy.
Chances of getting ECE, Electrical, or Mechanical Engineering in NIT Hamirpur, Jalandhar, or Raipur are high.

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Expected Percentile for JEE Main April 4 2026 Shift 1 Score 150 marks

JEE Main 2026 Difficulty Level Analysis of April 4 Shift 1

JEE Main 2026 April 4th Shift 1 continued the trend of previous shifts; paper was overall moderately difficult,

The chemistry section also continued the previous shift’s trends. The paper was balanced overall, and it was easy to score.
The physics section was moderate; the questions were mostly based on the formulas.
Mathematics section was more time-consuming and lengthy. Questions needed heavy calculations.

Subject	Difficulty level of April 4 Shift 1
Physics	Moderate
Chemistry	Easy to Moderate
Mathematics	Moderate to tough
Overall	Moderate

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Ques. How difficult was the April shifts paper compared to January?

Ans. JEE Main April shift papers are considered relatively easy so far, when compared to the January sessions. Mathematics remained lengthy and time-consuming. Physics was moderate, and while chemistry was easy to score.

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Expected Percentile for JEE Main April 4 Shift 1 Score of 150 Marks

150 marks in the April 4 shift 1 is most likely to result in 97-98 percentile.

150 marks in this shift can make you qualify for JEE Advanced 2026 comfortably.
Students with 150 marks in the April 4th shift 1 are more likely to be ranked among 25,000-40,000.
You can get into mid-tier or lower-tier NITs, and you are most likely eligible for core branches.

JEE Main Marks	Expected JEE Main Percentile (Approx)
170-172	99
150-152	98
138-140	97
128-130	96

Expected Percentile for JEE Main April 4 Shift 1 Score of 150 Marks

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Ques. Is 150 marks a good score for the April Session?

Ans. Yes. It is considered a very strong score. It is typically enough to qualify for the JEE Advanced exam. You can get into NITs and IIITs with strong chances of core branches.

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240 Marks in JEE Main Percentile	250 Marks in JEE Main Percentile
200 Marks in JEE Main Percentile	190 Marks in JEE Main Percentile
180 Marks in JEE Main Percentile	120 Marks in JEE Main Percentile

What are Your Admission Chances with 150 Marks in JEE Main April 4 Shift 1?

Your chances of NITs are limited to 150 marks. CSE or any other core branches at the top NITs are usually difficult.

If you want to top NITs, irrespective of branches, you might have to settle for production, chemical, or metallurgical engineering.
You have admission chances to ECE, mechanical, or electrical engineering at mid-tier NITs.
If you want CSE with 150 marks, IIITs might be a good choice.

Tier	Example Colleges	Likely branches
Top-Tier NITs	NIT TrichyNIT SurathkalNIT Warangal	Civil, Metallurgy, Production, Chemical
Mid-tier NITs	NIT JalandharNIT HamirpurNIT Raipur	ECE, Electrical, Mechanical, Civil
Newer NITs	NIT SrinagarNIT AgartalaNIT Nagaland	CSE, IT, ECE
IIIT	IIIT Vadodara	CSE, IT

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Ques. Can I get CSE at NITs if I have a home state quota with 150 marks in JEE Main?

Ans. You have high chances of getting CSE if you have a home state quota in mid-tier NITs with 150 marks. However, the chance of getting CSE at top NITs might be slim even if you have a home state quota.

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4ADFK1

1.
If \( x_1, x_2, \dots, x_{25} \) be 25 observations such that \( \sum_{i=1}^{25} (x_i + 5)^2 = 2500 \) and \( \sum_{i=1}^{25} (x_i - 5)^2 = 1000 \). Then, the ratio of Mean and Standard deviation of the given observations is:

\( \dfrac{1}{4} \)
\( \dfrac{1}{2} \)
\( \dfrac{2}{3} \)
\( \dfrac{1}{5} \)

View Solution

2.
A block of mass \(m\) is released from height \(h\) on a smooth plane. If the normal force on the top of the circular part is \(3mg\), find \(h\).

\(5R\)
\(4R\)
\(3.5R\)
\(3R\)

View Solution

3.
For tetrahedral complex, the correct order of energy of \(d\)-orbitals is:

\(d_{xy} = d_{xz}>d_{x^2-y^2}\)
\(d_{xy} = d_{yz}>d_{zx}\)
\(d_{x^2-y^2}>d_{z^2}>d_{xz}\)
\(d_{x^2-y^2} = d_{z^2}<d_{xy} = d_{yz} = d_{xz}\)

View Solution

4.
In an AC series circuit supply voltage \(V_{\text{rms}} = 100\) volts; \(R = 80\,\Omega\), \(X_L = 80\,\Omega\) and source frequency is \(f = 50\) Hz. Find the power factor.

\( \dfrac{1}{\sqrt{2}} \)
\( \dfrac{1}{2} \)
\( \dfrac{3}{4} \)
\( \dfrac{\sqrt{3}}{2} \)

View Solution

5.
Electric field at the centre of a semi-circular ring of radius \(10\,\text{cm}\) is \(100\,\text{V/m}\). Find the charge on the ring if the charge distribution is uniform.

\(4\varepsilon_0\)
\(20\varepsilon_0\)
\(25\varepsilon_0\)
\(30\varepsilon_0\)

View Solution

6.
Sucrose hydrolyses in acidic medium to form glucose and fructose which follows first order kinetics. If the half-life of sucrose is 3 hrs, find the % of sucrose left after 6 hrs.

View Solution

Expected Percentile for JEE Main April 4 2026 Shift 1 Score 150 marks

JEE Main 2026 Difficulty Level Analysis of April 4 Shift 1

Expected Percentile for JEE Main April 4 Shift 1 Score of 150 Marks

What are Your Admission Chances with 150 Marks in JEE Main April 4 Shift 1?

4ADFK1

1.
If \( x_1, x_2, \dots, x_{25} \) be 25 observations such that \( \sum_{i=1}^{25} (x_i + 5)^2 = 2500 \) and \( \sum_{i=1}^{25} (x_i - 5)^2 = 1000 \). Then, the ratio of Mean and Standard deviation of the given observations is:

2.
A block of mass \(m\) is released from height \(h\) on a smooth plane. If the normal force on the top of the circular part is \(3mg\), find \(h\).

3.
For tetrahedral complex, the correct order of energy of \(d\)-orbitals is:

4.
In an AC series circuit supply voltage \(V_{\text{rms}} = 100\) volts; \(R = 80\,\Omega\), \(X_L = 80\,\Omega\) and source frequency is \(f = 50\) Hz. Find the power factor.

5.
Electric field at the centre of a semi-circular ring of radius \(10\,\text{cm}\) is \(100\,\text{V/m}\). Find the charge on the ring if the charge distribution is uniform.

6.
Sucrose hydrolyses in acidic medium to form glucose and fructose which follows first order kinetics. If the half-life of sucrose is 3 hrs, find the % of sucrose left after 6 hrs.

Comments

dOGVmW

JEE Main 2026 Difficulty Level Analysis of April 4 Shift 1

Expected Percentile for JEE Main April 4 Shift 1 Score of 150 Marks

What are Your Admission Chances with 150 Marks in JEE Main April 4 Shift 1?

4ADFK1

1.If \( x_1, x_2, \dots, x_{25} \) be 25 observations such that \( \sum_{i=1}^{25} (x_i + 5)^2 = 2500 \) and \( \sum_{i=1}^{25} (x_i - 5)^2 = 1000 \). Then, the ratio of Mean and Standard deviation of the given observations is:

2.A block of mass \(m\) is released from height \(h\) on a smooth plane. If the normal force on the top of the circular part is \(3mg\), find \(h\).

3.For tetrahedral complex, the correct order of energy of \(d\)-orbitals is:

4.In an AC series circuit supply voltage \(V_{\text{rms}} = 100\) volts; \(R = 80\,\Omega\), \(X_L = 80\,\Omega\) and source frequency is \(f = 50\) Hz. Find the power factor.

5.Electric field at the centre of a semi-circular ring of radius \(10\,\text{cm}\) is \(100\,\text{V/m}\). Find the charge on the ring if the charge distribution is uniform.

6.Sucrose hydrolyses in acidic medium to form glucose and fructose which follows first order kinetics. If the half-life of sucrose is 3 hrs, find the % of sucrose left after 6 hrs.

Comments

dOGVmW

1.
If \( x_1, x_2, \dots, x_{25} \) be 25 observations such that \( \sum_{i=1}^{25} (x_i + 5)^2 = 2500 \) and \( \sum_{i=1}^{25} (x_i - 5)^2 = 1000 \). Then, the ratio of Mean and Standard deviation of the given observations is:

2.
A block of mass \(m\) is released from height \(h\) on a smooth plane. If the normal force on the top of the circular part is \(3mg\), find \(h\).

3.
For tetrahedral complex, the correct order of energy of \(d\)-orbitals is:

4.
In an AC series circuit supply voltage \(V_{\text{rms}} = 100\) volts; \(R = 80\,\Omega\), \(X_L = 80\,\Omega\) and source frequency is \(f = 50\) Hz. Find the power factor.

5.
Electric field at the centre of a semi-circular ring of radius \(10\,\text{cm}\) is \(100\,\text{V/m}\). Find the charge on the ring if the charge distribution is uniform.

6.
Sucrose hydrolyses in acidic medium to form glucose and fructose which follows first order kinetics. If the half-life of sucrose is 3 hrs, find the % of sucrose left after 6 hrs.