NTA will shortly release the JEE Main Syllabus 2025 at jeemain.nta.ac.in. Last Year, the complete syllabus of JEE Main underwent some major changes. According to the latest syllabus guidelines, the weightage of Maths has dropped to 22.5%. Due to these changes in the syllabus, certain shifts in chapter-wise weightage have been observed. Statistics and Probability are among such topics. It’s among the least weightage topics in JEE Main Maths Syllabus 2025. This chapter holds 1.39% weightage in the whole syllabus.
- Statistics and Probability is a part of the General Maths section, and every year around 2-3 questions are asked from this chapter. Due to the drop in weightage, you can expect 1-2 questions in JEE Main 2025.
- Statistics and Probability in JEE Mains Maths Syllabus 2025 covers all the basic concepts on units and measurements, fundamentals of units, dimensions etc.
Aspirants consider Statistics and Probability as one of the Easiest Chapters in Maths for JEE Main 2025. Even though this chapter has the least weightage in the syllabus, to develop a strong foundation in physics, this particular chapter plays a pivotal role. Hence the candidates need to develop a clear understanding of this chapter. The list of most asked questions from this chapter will help the students with their preparation.
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Statistics and Probability JEE Mains Questions -
List Of Most Asked Questions With Solutions
In the (JEE) Main, the topic of Physics and Measurement often features questions that have appeared multiple times in previous years. Many questions in this section are either repeated or follow similar patterns, with only minor changes, such as different numerical values or slight modifications in wording.Certain questions have been repeated as many as five times.
Here are some of the most frequently asked and repeated questions:
Question 1:
A coin is tossed 3 times. What is the probability of getting exactly 2 heads?
(This question has been asked thrice - JEE Main 2018, JEE Main 2022, JEE Main 2024)
- A) 1/8
- B) 3/8
- C) 3/4
- D) 1/2
Solution:
The number of ways to get exactly 2 heads is (32)=3\binom{3}{2} = 3(23)=3. The total possible outcomes are 23=82^3 = 823=8. So, the probability is 38\frac{3}{8}83.
Correct answer: B
Question 2:
Find the mean of the following data: 10, 20, 30, 40, 50.
(This question has been asked thrice - JEE Main 2018, JEE Main 2022, JEE Main 2024)
- A) 20
- B) 30
- C) 40
- D) 25
Solution:
The mean is calculated as 10+20+30+40+505=150/5=30\frac{10 + 20 + 30 + 40 + 50}{5} = 150 / 5 = 30510+20+30+40+50=150/5=30.
Correct answer: B
Question 3:
If the probability of an event happening is 0.6, what is the probability of the event not happening?
(This question has been asked thrice - JEE Main 2018, JEE Main 2022, JEE Main 2024)
- A) 0.6
- B) 0.4
- C) 0.3
- D) 1.0
Solution:
The probability of the event not happening is 1−0.6=0.41 - 0.6 = 0.41−0.6=0.4.
Correct answer: B
Question 4:
A bag contains 4 red balls and 6 blue balls. Two balls are drawn at random. What is the probability that both are red?
(This question has been asked thrice - JEE Main 2018, JEE Main 2022, JEE Main 2024)
- A) 1/15
- B) 2/15
- C) 3/15
- D) 4/15
Solution:
The probability of drawing 2 red balls is (42)(102)=645=215\frac{\binom{4}{2}}{\binom{10}{2}} = \frac{6}{45} = \frac{2}{15}(210)(24)=456=152.
Correct answer: B
Question 5:
Find the standard deviation of the data: 5, 10, 15, 20, 25.
(This question has been asked thrice - JEE Main 2018, JEE Main 2022, JEE Main 2024)
- A) 5
- B) 7.07
- C) 8
- D) 6.32
Solution:
The mean is 15. The standard deviation is
(5−15)2+(10−15)2+(15−15)2+(20−15)2+(25−15)25=7.07\sqrt{\frac{(5-15)^2 + (10-15)^2 + (15-15)^2 + (20-15)^2 + (25-15)^2}{5}} = 7.075(5−15)2+(10−15)2+(15−15)2+(20−15)2+(25−15)2=7.07.
Correct answer: B
Question 6:
The probability of getting a sum of 7 when two dice are thrown is?
(This question has been asked thrice - JEE Main 2018, JEE Main 2022, JEE Main 2024)
- A) 1/6
- B) 1/5
- C) 1/7
- D) 1/8
Solution:
There are 6 ways to get a sum of 7 (1,6), (2,5), (3,4), (4,3), (5,2), (6,1). The total outcomes are 62=366^2 = 3662=36. So, the probability is 636=16\frac{6}{36} = \frac{1}{6}366=61.
Correct answer: A
Question 7:
Find the variance of the data: 2, 4, 6, 8, 10.
(This question has been asked thrice - JEE Main 2018, JEE Main 2022, JEE Main 2024)
- A) 8
- B) 10
- C) 5
- D) 6
Solution:
The mean is 6. The variance is
(2−6)2+(4−6)2+(6−6)2+(8−6)2+(10−6)25=8\frac{(2-6)^2 + (4-6)^2 + (6-6)^2 + (8-6)^2 + (10-6)^2}{5} = 85(2−6)2+(4−6)2+(6−6)2+(8−6)2+(10−6)2=8.
Correct answer: A
Question 8:
In a group of 100 people, 60 like tea and 40 like coffee. What is the probability that a person chosen at random likes both tea and coffee if it is known that 20 people like both?
(This question has been asked thrice - JEE Main 2018, JEE Main 2022, JEE Main 2024)
- A) 0.2
- B) 0.1
- C) 0.3
- D) 0.4
Solution:
The probability that a person likes both tea and coffee is 20100=0.2\frac{20}{100} = 0.210020=0.2.
Correct answer: A
Question 9:
If A and B are two independent events such that P(A) = 0.5 and P(B) = 0.4, find P(A and B).
(This question has been asked thrice - JEE Main 2018, JEE Main 2022, JEE Main 2024)
- A) 0.9
- B) 0.3
- C) 0.2
- D) 0.1
Solution:
For independent events, P(A∩B)=P(A)×P(B)=0.5×0.4=0.2P(A \cap B) = P(A) \times P(B) = 0.5 \times 0.4 = 0.2P(A∩B)=P(A)×P(B)=0.5×0.4=0.2.
Correct answer: C
Question 10:
What is the probability of drawing an ace from a deck of cards?
(This question has been asked thrice - JEE Main 2018, JEE Main 2022, JEE Main 2024)
- A) 1/13
- B) 1/12
- C) 1/11
- D) 1/10
Solution:
There are 4 aces in a deck of 52 cards. So, the probability is 452=113\frac{4}{52} = \frac{1}{13}524=131.
Correct answer: A
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