JEE Main PYQs on Electric and Magnetic Fields: JEE Main Questions for Practice with Solutions

Shivam Yadav's profile photo

Shivam Yadav

Educational Content Expert | Updated on - Aug 25, 2025

The JEE Main 2026 exam requires a perfect balance of speed, accuracy, and a solid understanding of the key concepts in Electric and Magnetic Fields. This article provides a set of Multiple Choice Questions (MCQs) on Electric and Magnetic Fields, designed to help you master the topic, enhance your problem-solving skills, and build conceptual clarity. These skills are crucial for excelling in the JEE Main 2026 exam.

Whether you're revisiting fundamental concepts, practicing advanced problems, or testing your knowledge, these JEE Main PYQs will serve as a valuable resource to boost your preparation and confidence.

With the JEE Main 2026 exam approaching, practicing these PYQs and reviewing detailed solutions will help you tackle the exam with confidence, improving your chances of securing a high rank. Make sure you stay ahead in your JEE Main 2026 preparation with these focused and structured questions.

Also Read

JEE Main Questions

  • 1.
    Let \( B_1 \) be the magnitude of magnetic field at the center of a circular coil of radius \( R \) carrying current \( I \). Let \( B_2 \) be the magnitude of magnetic field at an axial distance \( x \) from the center. For \( x : R = 3 : 4 \), \( \frac{B_2}{B_1} \) is:

      • 4 : 5
      • 16 : 25
      • 64 : 125
      • 25 : 16

    • 2.
      A proton is moving undeflected in a region of crossed electric and magnetic fields at a constant speed of \( 2 \times 10^5 \, \text{m/s} \). When the electric field is switched off, the proton moves along a circular path of radius 2 cm. The magnitude of electric field is \( x \times 10^4 \, \text{N/C} \). The value of \( x \) is \_\_\_\_\_. (Take the mass of the proton as \( 1.6 \times 10^{-27} \, \text{kg} \)).


        • 3.
          Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R).
          Assertion (A): A magnetic monopole does not exist.
          Reason (R): Magnetic lines are continuous and form closed loops.
          In the light of the above statements, choose the correct answer from the options below:

            • (A) is false but (R) is true
            • (A) is true but (R) is false
            • Both (A) and (R) are true but (R) is NOT the correct explanation of (A)
            • Both (A) and (R) are true and (R) is the correct explanation of (A)

          • 4.

            Uniform magnetic fields of different strengths $ B_1 $ and $ B_2 $, both normal to the plane of the paper, exist as shown in the figure. A charged particle of mass $ m $ and charge $ q $, at the interface at an instant, moves into region 2 with velocity $ v $ and returns to the interface. It continues to move into region 1 and finally reaches the interface. What is the displacement of the particle during this movement along the interface?

            Consider the velocity of the particle to be normal to the magnetic field and  $ B_2 > B_1 $.

              • \( \frac{mv}{qB_1} \left( 1 - \frac{B_2}{B_1} \right) \times 2 \)
              • \( \frac{mv}{qB_1} \left( 1 - \frac{B_1}{B_2} \right) \)
              • \( \frac{mv}{qB_1} \left( 1 - \frac{B_2}{B_1} \right) \)
              • \( \frac{mv}{qB_1} \left( 1 - \frac{B_1}{B_2} \right) \times 2 \)

            • 5.
              The figure shows a circular portion of radius \( \frac{R}{2} \) removed from a disc of mass \( m \) and radius \( R \). The moment of inertia about an axis passing through the centre of mass of the disc and perpendicular to the plane is:

                • \( \frac{13}{32} mR^2 \)
                • \( \frac{mR^2}{2} \)
                • \( \frac{mR^2}{4} \)
                • \( \frac{13}{64} mR^2 \)

              • 6.
                A monochromatic light is incident on a metallic plate having work function \( \phi \). An electron, emitted normally to the plate from a point A with maximum kinetic energy, enters a constant magnetic field, perpendicular to the initial velocity of the electron. The electron passes through a curve and hits back the plate at a point B. The distance between A and B is:

                  • \( \sqrt{\frac{2m \left( \frac{hc}{\lambda} - \phi \right)}{eB}} \)
                  • \( \frac{m \left( \frac{hc}{\lambda} - \phi \right)}{eB} \)
                  • \( \sqrt{8m \left( \frac{hc}{\lambda} - \phi \right)} \div eB \)
                  • \( 2 \frac{m \left( \frac{hc}{\lambda} - \phi \right)}{eB} \)

                Fees Structure

                Structure based on different categories

                CategoriesState
                General1000
                Women800
                sc500
                pwd500
                Others900

                Note: The application fee for choosing exam centers in India and countries other than India varies.

                In case of any inaccuracy, Notify Us! 

                Comments


                No Comments To Show