JEE Main 2024 question paper pdf with solutions- Download Jan 30 Shift 1 Mathematics Question Paper pdf

Shambhavi's profile photo

Shambhavi

Content Analyst | Updated 3+ months ago

JEE Main 2024 Jan 30 Shift 1 Mathematics question paper with solutions and answers pdf is available here . NTA conducted JEE Main 2024 Jan 30 Shift 1 exam from 9 AM to 12 PM. The Mathematics question paper for JEE Main 2024 Jan 30 Shift 1 includes 30 questions divided into 2 sections, Section 1 with 20 MCQs and Section 2 with 10 numerical questions. Candidates must attempt any 5 numerical questions out of 10. The memory-based JEE Main 2024 question paper pdf for the Jan 30 Shift 1 exam is available for download using the link below.

Related Links:

JEE Main 2024 Jan 30 Shift 1 Mathematics Question Paper PDF Download

JEE Main 2024 Mathematics Question Paper JEE Main 2024 Mathematics Answer Key JEE Main 2024 Mathematics Solution
Download PDF Download PDF Download PDF

JEE Main 2024 Jan 30 Shift 1 Mathematics Questions with Solutions

Question Answer Solution

1. A line passing through the point A(9,0) makes an angle of 30° with the positive direction of the x-axis. If this line is rotated about A through an angle of 15° clockwise, then its equation in the new position is:


(1) y√3 - 2 + x = 9
(2) x√3 - 2 + y = 9
(3) x√3 + 2 + y = 9
(4) y√3 + 2 + x = 9

(1) y√3 - 2 + x = 9 The initial slope of the line is tan(30°) = 1/√3. After rotation, the new slope becomes tan(15°) = 2 - √3. Using the point-slope form, we get y = (2 - √3)(x - 9), leading to the equation y√3 - 2 + x = 9.

2. Let Sn denote the sum of the first n terms in an arithmetic progression. If S20 = 790 and S10 = 145, then S15 - S5 is:

(1) 395
(2) 390
(3) 405
(4) 410

(1) 395 Given S20 = 790 and S10 = 145, solve for a and d in the arithmetic progression. Calculations yield S15 = 405 and S5 = 10, hence S15 - S5 = 395.

3. If z = x + iy, xy = 0, satisfies the equation z² + iz = 0, then |z|² is equal to:
 

(1) 9
(2) 1
(3) 4
(4) 1/4

(2) 1 Substitute z = x + iy and separate real and imaginary parts. Solving for x and y yields |z|² = x² + y² = 1.

4. Let a = a1i + a2j + a3k and b = b1i + b2j + b3k be two vectors such that |a| = 1, a × b = 2, and |b| = 4. If c = 2(a × b) - 3b, then the angle between b and c is equal to:

(1) cos-1(2/√3)
(2) cos-1(-1/√3)
(3) cos-1(-√3/2)
(4) cos-1(2/3)

(3) cos-1(-√3/2) Calculate |a × b| and use c = 2(a × b) - 3b to find the angle between b and c using cos θ = (b · c) / (|b||c|).

5. The maximum area of a triangle whose one vertex is at (0,0) and the other two vertices lie on the curve y = -2x² + 54 at points (x, y) and (-x, y) where y > 0 is:

(1) 88
(2) 122
(3) 92
(4) 108

(4) 108 With the curve y = -2x² + 54, the base of the triangle is 2x and the height is y. Maximizing the area A = x × y gives a maximum area of 108.

6. The value of limn→∞k=1n n3 / (n2 + k2)(n2 + 3k2)) is:

(1) (2√3 + 3)π / 24
(2) 13π / (8(4√3 + 3))
(3) 13(2√3 - 3)π / 8
(4) π / (8(2√3 + 3))

(2) 13π / (8(4√3 + 3)) Rewrite as a Riemann sum and approximate by a definite integral. Simplify and integrate to obtain the result.

7. Let g: R→R be a non-constant twice differentiable function such that g' (1/2) = g' (3/2). If a real-valued function f is defined as f(x) = 1/2 [g(x) + g(2 - x)], then:

(1) f''(x) = 0 for at least two x in (0,2)
(2) f''(x) = 0 for exactly one x in (0,1)
(3) f''(x) = 0 for no x in (0,1)
(4) f' (3/2) + f' (1/2) = 1

(1) f''(x) = 0 for at least two x in (0,2) Since f(x) is symmetric around x = 1, use properties of symmetry and differentiate to show that f''(x) = 0 for at least two values in the interval.

8. The area (in square units) of the region bounded by the parabola y² = 4(x - 2) and the line y = 2x - 8 is:

(1) 8
(2) 9
(3) 6
(4) 7

(2) 9 Find points of intersection and set up an integral for the area between the curves from y = -2 to y = 4. Evaluate to find the area as 9 square units.

9. Let y = y(x) be the solution of the differential equation sec(x) dy + {2(1 - x) tan(x) + x(2 - x)} dx = 0 such that y(0) = 2. Then y(2) is equal to:

(1) 2
(2) 2{1 - sin(2)}
(3) 2{sin(2) + 1}
(4) 1

(1) 2 Solve the differential equation by separation of variables and apply the initial condition y(0) = 2 to solve for the constant. Calculate y(2) to get 2.

10. Let (α, β, γ) be the foot of the perpendicular from the point (1,2,3) on the line x/5 = (y - 1)/2 = (z + 4)/3. Then 19(α + β + γ) is equal to:

(1) 102
(2) 101
(3) 99
(4) 100

(2) 101 Parameterize the line and use perpendicularity conditions to solve for the foot of the perpendicular. Calculate α + β + γ, and then find 19(α + β + γ) = 101.

11. Two integers x and y are chosen with replacement from the set {0,1,2,...,10}. Then the probability that |x - y| > 5 is:

(1) 30/121
(2) 62/121
(3) 60/121
(4) 31/121

(1) 30/121 Count all pairs where |x - y| > 5 by analyzing possible values for each integer x. Add favorable outcomes and divide by total outcomes (121) to get the probability.

12. If the domain of the function f(x) = cos⁻¹(2 - |x|) / 4 is [−α, β) − {γ}, then α + β + γ is equal to:

(1) 12
(2) 9
(3) 11
(4) 8

(3) 11 Solve for the domain by setting -1 ≤ (2 - |x|) / 4 ≤ 1 and solving inequalities. Identify α, β, and γ values to find α + β + γ = 11.

13. Consider the system of linear equations x + y + z = 4μ, x + 2y + 2z = 10μ, x + 3y + 4λz = μ² + 15. Which one of the following statements is NOT correct?

(1) The system has a unique solution if λ = 1/2 and μ = 1
(2) The system is inconsistent if λ = 1/2 and μ = 1
(3) The system has an infinite number of solutions if λ = 1/2 and μ = 15
(4) The system is consistent if λ = 1/2

(2) The system is inconsistent if λ = 1/2 and μ = 1 Write the system in matrix form, calculate the determinant, and check the conditions for unique and infinite solutions to verify the statements.

14. If the circles (x + 1)² + (y +2)² = r² and x² + y² - 4x - 4y + 4 = 0 intersect at exactly two distinct points, then:

(1) 5 < r < 9
(2) 0 < r < 7
(3) 3 < r < 7
(4) 1/2 < r < 7

(3) 3 < r < 7 Find the center and radius of each circle. Use the condition for intersecting circles, |r₁ - r₂| < d < r₁ + r₂, to solve for r.

15. If the length of the minor axis of an ellipse is equal to half of the distance between the foci, then the eccentricity of the ellipse is:

(1) √5 / 3
(2) √3 / 2
(3) 1 / √3
(4) 2 / √5

(4) 2 / √5 Use the relationships between the semi-major axis, semi-minor axis, and foci of an ellipse to solve for the eccentricity, resulting in e = 2 / √5.

16. Let M denote the median of the following frequency distribution.
Class    Frequency
0-4            3
4-8            9
8-12          10
12-16         8
16-20         6
Then 20M is equal to:

(1) 416
(2) 104
(3) 52
(4) 208

(4) 208 Calculate the cumulative frequency and identify the median class. Use the median formula, substitute values, and calculate 20 times the median.

17. If f(x) = 2cos⁴x / (3 + 2cos⁴x) + 2sin⁴x / (3 + 2sin⁴x), then 1/5 f'(0) is equal to:

 (1) 0
(2) 1
(3) 2
(4) 6

(1) 0 Simplify the expression for f(x) using trigonometric identities to find that f(x) is constant, implying f'(x) = 0.

18. Let A(2,3,5) and C(−3,4,−2) be opposite vertices of a parallelogram ABCD. If the diagonal BD = i + 2j + 3k, then the area of the parallelogram is equal to:

(1) 1/2 √410
(2) 1/2 √474
(3) 1/2 √586
(4) 1/2 √306

(2) 1/2 √474 Calculate the vectors AC and BD, find their cross product, and use the formula for the area of a parallelogram.

19. If 2sin³x + sin²x cosx + 4sinⁿx − 4 = 0 has exactly 3 solutions in the interval (0, nπ/2), n ∈ N, then the roots of the equation x² + nx + (n−3) = 0 belong to:

(1) (0, ∞)
(2) (−∞, 0)
(3) −√17/2, √17/2
(4) Z

(2) (−∞, 0) Rewrite and solve the given equation by analyzing solution intervals to find values of n for which the quadratic equation has roots in the specified interval.

20. Let f : −π/2, π/2 → R be a differentiable function such that f(0) = 1/2. If the limit lim(x→0) ∫(0 to x) f(t)dt / (e^(x²) - 1) = α, then 8α² is equal to:

(1) 16
(2) 2
(3) 1
(4) 4

(2) 2 Rewrite the limit as a Riemann sum and use Taylor series expansion for simplification. Then solve for α and find 8α².

21. A group of 40 students appeared in an examination of 3 subjects - Mathematics, Physics, Chemistry. It was found that all students passed in at least one of the subjects, 20 students passed in Mathematics, 25 in Physics, and 16 in Chemistry. At most 11 students passed in both Mathematics and Physics, 15 in both Physics and Chemistry, and 10 in both Mathematics and Chemistry. The maximum number of students passed in all three subjects is:

10 Use the principle of inclusion-exclusion to solve for the number of students passing all three subjects.
22. If d1 is the shortest distance between the lines x+1/2 = y-1/-12 = z/1 and x-1/-7 = y+8/2 = z-4/5, and d2 is the shortest distance between the lines x-1/2 = y-2/1 = z-6/-3 and x/1 = y+2/1 = z-1/6, then the value of 32√3d1/d2 is:  16 Calculate the shortest distances d1 and d2 using the formula for skew lines, then find the ratio 32√3d1/d2.
23. Let the latus rectum of the hyperbola x²/9 - y²/b² = 1 subtend an angle of π/3 at the center of the hyperbola. If b² is equal to 1/m(1+√n), where l and m are co-prime numbers, then l²+m²+n² is equal to:   182 Use the eccentricity relation for a hyperbola and solve the system of equations to find b² and calculate l² + m² + n².
24. Let A = {1,2,3,...,7} and let P(1) denote the power set of A. If the number of functions f : A → P(A) such that a ∈ f(a), ∀a ∈ A is mn, and m and n are least, then m + n is equal to:   44 Identify subsets containing element a, calculate total functions, and simplify mn, finding the minimum m + n = 44.

25. The value of ∫(0 to 9) 10x / (x+1) dx is:

(1) (2√3+3)π/24
(2) 13π/8(4√3+3)
(3) 13(2√3−3)π/8
(4) π/8(2√3+3)

(2) 13π/8(4√3+3) Rewrite as a Riemann sum, simplify with partial fraction decomposition, and integrate to obtain the answer.
26. Number of integral terms in the expansion of (√7z + 1/(6√z))^824 is equal to:  (1) 138 Calculate general term in the expansion, ensure integer power, and count the terms where the exponent is an integer.
27. Let y = y(x) be the solution of the differential equation (1 − x²)dy = xy + x³ + 2√1−x² dx, with y(0) = 0. If y(1/2) = m/n, where m and n are co-prime numbers, then m + n is equal to:  (1) 97 Solve the differential equation by separation of variables, and calculate m + n.
28. Let α, β ∈ N be roots of the equation x² − 70x + λ = 0, where λ/2, λ/3 ∉ N. If λ assumes the minimum possible value, then √α−1+√β−1(λ+35)/|α−β| is equal to:  (1) 60 Find λ, α, β that meet the conditions and use them to calculate the expression.

29. If the function f(x) = { 1/|x| , |x| ≥ 2
                                            ax² + 2b , |x| < 2 }

is differentiable on R, then 48(a + b) is equal to:

15 To ensure differentiability and continuity, calculate the values of a and b. The solution involves applying continuity and differentiability conditions at x = 2. Finally, compute 48(a + b).
30. Let α = 1² + 4² + 8² + 13² + 19² + 26² + ... up to 10 terms and β = Σ₁₀n=1 n⁴. If 4α - β = 55k + 40, then k is equal to: 353 Calculate the sum of squares of terms in an AP for α and use the sum of fourth powers for β. Then, solve for k using the given equation.


Also Check:

JEE Main 2024 Jan 30 Shift 1 Mathematics Question Paper by Coaching Institute

Coaching Institutes Question Paper with Solutions PDF
Aakash BYJUs To be updated
Reliable Institute To be updated
Resonance To be updated
Vedantu To be updated
Sri Chaitanya To be updated
FIIT JEE To be updated

JEE Main 2024 Jan 30 Shift 1 Mathematics Paper Analysis

JEE Main 2024 Jan 30 Shift 1 Mathematics paper analysis is updated here with details on the difficulty level of the exam, topics with the highest weightage in the exam, section-wise difficulty level, etc. 

JEE Main 2024 Physics Question Paper Pattern

Feature Question Paper Pattern
Examination Mode Computer-based Test
Exam Language 13 languages (English, Hindi, Assamese, Bengali, Gujarati, Kannada, Malayalam, Marathi, Odia, Punjabi, Tamil, Telugu, and Urdu)
Sectional Time Duration None
Total Marks 100 marks
Total Number of Questions Asked 30 Questions
Total Number of Questions to be Answered 25 questions
Type of Questions MCQs and Numerical Answer Type Questions
Section-wise Number of Questions 20 MCQs and 10 numerical type,
Marking Scheme +4 for each correct answer
Negative Marking -1 for each incorrect answer

Read More:

Exam Date and Shift Question Paper PDF
JEE Main 2024 Question Paper Jan 24 Shift 2 Check Here
JEE Main 2024 Question Paper Jan 27 Shift 1 Check Here
JEE Main 2024 Question Paper Jan 27 Shift 2 Check Here
JEE Main 2024 Question Paper Jan 29 Shift 1 Check Here
JEE Main 2024 Question Paper Jan 29 Shift 2 Check Here
JEE Main 2024 Question Paper Jan 30 Shift 1 Check Here
JEE Main 2024 Question Paper Jan 30 Shift 2 Check Here
JEE Main 2024 Question Paper Jan 31 Shift 1 Check Here
JEE Main 2024 Question Paper Jan 31 Shift 2 Check Here
JEE Main 2024 Question Paper Feb 1 Shift 1 Check Here
JEE Main 2024 Question Paper Feb 1 Shift 2 Check Here

JEE Main Previous Year Question Paper

JEE Main Questions

  • 1.
    The sum of the squares of all the roots of the equation \( x^2 + [2x - 3] - 4 = 0 \) is:

      • \(3(2 - \sqrt{2})\)
      • \(6(2 - \sqrt{2})\)
      • \(3(3 - \sqrt{2})\)
      • \(6(3 - \sqrt{2})\)

    • 2.
      Let the arc AC of a circle subtend a right angle at the center O. If the point B on the arc AC divides the arc AC such that: \[ \frac{\text{length of arc AB}}{\text{length of arc BC}} = \frac{1}{5} \] and \[ \overrightarrow{OC} = \alpha \overrightarrow{OA} + \beta \overrightarrow{OB}, \] then \( \alpha = \sqrt{2} (\sqrt{3}-1) \beta \) is equal to:

        • \( 2 - \sqrt{3} \)
        • \( 2 \sqrt{3} \)
        • \( 5 \sqrt{3} \)
        • \( 2 + \sqrt{3} \)

      • 3.
        \[ \sum_{k=1}^{n} \left( \alpha^k + \frac{1}{\alpha^k} \right)^2 = 20, \quad \alpha \text{ is one of the roots of } x^2 + x + 1 = 0, \text{ then } n = ? \]

          • 3
          • 4
          • 5
          • 6

        • 4.
          Let \( \langle a_n \rangle \) be a sequence such that \( a_0 = 0 \), \( a_1 = \frac{1}{2} \), and \( 2a_{n+2} = 5a_{n+1} - 3a_n \).n= 0,1,2,3.... Then \( \sum_{k=1}^{100} a_k \) is equal to:

            • \( 3a_{99} + 100 \)
            • \( 3a_{99} - 100 \)
            • \( 3a_{100} + 100 \)
            • \( 3a_{100} - 100 \)

          • 5.
            Let integers \( a, b \in [-3, 3] \) be such that \( a + b \neq 0 \). \(\text{Then the number of all possible ordered pairs}\) \( (a, b) \), \(\text{for which}\) \[ \left| \frac{z - a}{z + b} \right| = 1 \quad \text{and} \quad \left| \begin{matrix} z + 1 & \omega & \omega^2 \\ \omega^2 & 1 & z + \omega \\ \omega^2 & 1 & z + \omega \end{matrix} \right| = 1, \] \(\text{is equal to:}\) 


              • 6.
                From all the English alphabets, five letters are chosen and are arranged in alphabetical order. The total number of ways, in which the middle letter is ‘M’, is :

                  • 14950
                  • 6084
                  • 4356
                  • 5148

                Fees Structure

                Structure based on different categories

                CategoriesState
                General1000
                Women800
                sc500
                pwd500
                Others900

                Note: The application fee for choosing exam centers in India and countries other than India varies.

                In case of any inaccuracy, Notify Us! 

                Comments


                No Comments To Show