NCERT Solutions For Class 12 Physics Chapter 4: Moving Charges and Magnetism

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NCERT Solutions for Class 12 Physics Chapter 4 Moving Charges and Magnetism are provided in this article. Moving charges generate an electric field. The rate of flow of electric charge is known as current. Magnetism is caused due to the current. Magnetic fields exert forces on the magnets and the moving charges.  

Class 12 Physics Chapter 4 along with Chapter 5 Magnetism and Matter belongs to Unit 3 which has a weightage of 17 marks with Unit 4 Electromagnetic Induction and Alternating Currents. Along with the elementary concepts, mathematical treatment of the magnetic field produced due to a current element (Biot Savart Law), ampere’s circuital law and the concept of solenoid and toroids are covered in the Class 12 NCERT Solutions for NCERT Solutions for Class 12 Physics Chapter 4. 

Download PDF: NCERT Solutions for Class 12 Physics Chapter 4


NCERT Solutions for Class 12 Physics Chapter 4

The NCERT solutions for class 12 physics chapter 4: Moving Charges and Magnetism are provided below. 

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS


Class 12 Physics Chapter 4 – Important Concepts

  • The region in space where a Magnet has its magnetic effect is known as the Magnetic field of the Magnet.
F = q [E(r) + v × B(r)] = EElectric + Fmagnetic 
  • Magnetism is a property displayed by Magnets and produced by the moving charges. This results in the objects being attracted or pushed away.
The relation between a moving charge and magnetism is that Magnetism is caused due to the movement of charges.
  • Lorentz Force is the total force on a given charge c, moving with a velocity v, in the presence of electric field E and magnetic field B. (This force acts normal to v and the work done by it is zero)

F = q(v x B + E)

  • Magnetic Force on a Current-Carrying Conductor: Due to the motion of charges in a conductor, each charge experiences a force. When current is passed through a magnetic field, the magnetic field exerts a force on the wire in a perpendicular direction to the current and the magnetic field as well.

 \(F= I (I \times B ) or |F | = I |I||B| sin \theta \)


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CBSE CLASS XII Related Questions

  • 1.
    An alpha particle and a deuterium ion are accelerated through the same potential difference. These are then directed towards a target nucleus to make a head-on collision. It is observed that their distance of closest approach is the same. Justify it theoretically.


      • 2.
        Answer the following giving reason:
        (a) All the photoelectrons do not eject with the same kinetic energy when monochromatic light is incident on a metal surface.
        (b) The saturation current in case (a) is different for different intensity.
        (c) If one goes on increasing the wavelength of light incident on a metal sur face, keeping its intensity constant, emission of photoelectrons stops at a certain wavelength for this metal.


          • 3.
            A beam of red light and a beam of blue light have equal intensities. Which of the following statements is true?

              • The blue beam has more number of photons than the red beam.
              • The red beam has more number of photons than the blue beam.
              • Wavelength of red light is lesser than wavelength of blue light.
              • The blue light beam has lesser energy per photon than that in the red light beam.

            • 4.
              A charge \( -6 \mu C \) is placed at the center B of a semicircle of radius 5 cm, as shown in the figure. An equal and opposite charge is placed at point D at a distance of 10 cm from B. A charge \( +5 \mu C \) is moved from point ‘C’ to point ‘A’ along the circumference. Calculate the work done on the charge.
              work done on the charge


                • 5.
                  A rectangular glass slab ABCD (refractive index 1.5) is surrounded by a transparent liquid (refractive index 1.25) as shown in the figure. A ray of light is incident on face AB at an angle \(i\) such that it is refracted out grazing the face AD. Find the value of angle \(i\).
                  A rectangular glass slab ABCD (refractive index 1.5)


                    • 6.
                      A small spherical shell \( S_1 \) has point charges \( q_1 = -3 \, \mu C \), \( q_2 = -2 \, \mu C \) and \( q_3 = 9 \, \mu C \) inside it. This shell is enclosed by another big spherical shell \( S_2 \). A point charge \( Q \) is placed in between the two surfaces \( S_1 \) and \( S_2 \). If the electric flux through the surface \( S_2 \) is four times the flux through surface \( S_1 \), find charge \( Q \).

                        CBSE CLASS XII Previous Year Papers

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