A wheel starts rotating at 10 rad/sec and attains the angular velocity of 100 rad/sec in 15 seconds. What is the angular acceleration in rad/sec2? A. 10 B. 110/15 C. 100/15 D. 6

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The Correct answer is (D)

The equation of rotational motion for constant angular acceleration is given by

ω_f = ω_i + αt

⇒ α = \(\frac{\omega_f - \omega_i}{t}\)

Where,

ω_f = final angular velocity
ω_i = initial angular velocity
α = angular acceleration
t = time taken to reach final angular velocity from initial angular velocity.

Given,

Initial angular velocity, ω_i = 10 rad/s

final angular velocity, ω_f = 100 rad/s

Time taken, t = 15 sec

Using the equation of rotational motion, angular acceleration (α) of the wheel, is given by

α = \(\frac{100-10}{15} = \frac{90}{15}\)

⇒ α = 6 rad/sec²

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A wheel starts rotating at 10 rad/sec and attains the angular velocity of 100 rad/sec in 15 seconds. What is the angular acceleration in rad/sec2? A. 10 B. 110/15 C. 100/15 D. 6

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2.The electric field at a point in a region is given by \( \vec{E} = \alpha \frac{\hat{r}}{r^3} \), where \( \alpha \) is a constant and \( r \) is the distance of the point from the origin. The magnitude of potential of the point is:

4.Two point charges \( q_1 = 16 \, \mu C \) and \( q_2 = 1 \, \mu C \) are placed at points \( \vec{r}_1 = (3 \, \text{m}) \hat{i}\) and \( \vec{r}_2 = (4 \, \text{m}) \hat{j} \). Find the net electric field \( \vec{E} \) at point \( \vec{r} = (3 \, \text{m}) \hat{i} + (4 \, \text{m}) \hat{j} \).

5.A current carrying circular loop of area A produces a magnetic field \( B \) at its centre. Show that the magnetic moment of the loop is \( \frac{2BA}{\mu_0} \sqrt{\frac{A}{\pi}} \).

6.The ends of six wires, each of resistance R (= 10 \(\Omega\)) are joined as shown in the figure. The points A and B of the arrangement are connected in a circuit. Find the value of the effective resistance offered by it to the circuit.

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Comments

SUBSCRIBE TO OUR NEWS LETTER

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