A wheel starts rotating at 10 rad/sec and attains the angular velocity of 100 rad/sec in 15 seconds. What is the angular acceleration in rad/sec2? A. 10 B. 110/15 C. 100/15 D. 6

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The Correct answer is (D)

The equation of rotational motion for constant angular acceleration is given by

ω_f = ω_i + αt

⇒ α = \(\frac{\omega_f - \omega_i}{t}\)

Where,

ω_f = final angular velocity
ω_i = initial angular velocity
α = angular acceleration
t = time taken to reach final angular velocity from initial angular velocity.

Given,

Initial angular velocity, ω_i = 10 rad/s

final angular velocity, ω_f = 100 rad/s

Time taken, t = 15 sec

Using the equation of rotational motion, angular acceleration (α) of the wheel, is given by

α = \(\frac{100-10}{15} = \frac{90}{15}\)

⇒ α = 6 rad/sec²

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A wheel starts rotating at 10 rad/sec and attains the angular velocity of 100 rad/sec in 15 seconds. What is the angular acceleration in rad/sec2? A. 10 B. 110/15 C. 100/15 D. 6

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4.In a Young's double-slit experiment, two waves each of intensity I superpose each other and produce an interference pattern. Prove that the resultant intensities at maxima and minima are 4I and zero respectively.

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2.
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