A body rotates about a fixed axis with an angular acceleration of 1 rad/sec2. Through what does it rotate during the time in which its angular velocity increases from 5 rad/s to 15 rad/s?

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The equation of rotational motion for constant angular acceleration is given by

ωf2 = ωi2 + 2αθ

⇒ θ = \(\frac{\omega_f^2 - \omega_i^2}{2 \alpha}\)

Where 

  • ωf = final angular velocity
  • ωi = initial angular velocity
  • α = angular acceleration
  • θ = angular displacement of the body during the time in which its angular velocity

Changes from ωto ωf

Given, 

Initial angular velocity of the fan, ωi = 5 rad/s

final angular velocity of the fan, ωf = 15 rad/s

Angular acceleration, α = 1 rad/sec2

Using the equation of rotational motion, angular displacement of the fan, is given by 

θ = \(\frac{15^2-5^2}{2 \times 1}\) = \(\frac{225-25}{2}\) = 100 rad

Hence, the body rotates angular displacement of 100 rad during the time in which its angular velocity increases from 5 rad/s to 15 rad/s.


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