NCERT Solutions For Class 12 Physics Chapter 3: Current Electricity

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NCERT Solutions for Class 12 Physics Chapter 3 Current Electricity are given in this article. Current electricity is the electricity that powers our homes and electrical devices. Current electricity is named for the way electrons move. They “flow” in one direction- like a river current. The study of electrons in motion like this is called Electrodynamics. 

The chapter along with the unit Electrostatics has a weightage of 16 marks in CBSE Class 12 Physics exams. The NCERT Solutions for Class 12 Physics Chapter 3 covers concepts of electric current, Ohm’s law, emf, cells in series and parallel, Kirchhoff’s Rules, etc.

Download PDF: NCERT Solutions for Class 12 Physics Chapter 3


NCERT Solutions for Class 12 Physics Chapter 3

The NCERT Solutions for class 12 physics chapter 3: Current Electricity is as given below. 

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Chapter 3 Physics Class 12 Important Topics

  • Current electricity is the flow of electrons from one section of the circuit to the another.

There are two types of Current Electricity – 

  1. Direct Current is the current electricity whose direction stays the same. It is the constant flow of electrons from a high electron density region to a region of low electron density.
  2. Alternating Current is the current electricity that keeps changing the direction of the charge flow.
  • When 2 bodies at different potentials are linked with a wire, the free electrons move from Point 1 to Point 2, until both objects reach the same potential. The current stops flowing after that.
  • Electromotive Force: Electromotive force is the electric potential that is either produced by an electrochemical cell or produced by changing the magnetic field.
  • Voltage: Voltage is the electric potential difference between any two points.
    Ohm’s Law states that the electric current flowing through a conductor is directly proportional to the potential difference (V) applied across its ends.

It can be represented as

V = IR

The formula of electrical resistance is R = V/l.

Electrical resistance of a conductor R = ρl/A

where l = length of the conductor,

A = cross-section area, and

ρ = resistivity of the material of a conductor.

  • The current electricity can be generated through various methods.
    • Both alternating and direct current can be generated by moving a metal wire through a magnetic field.
    • Direct Current can be generated by a battery through chemical reactions.

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CBSE CLASS XII Related Questions

  • 1.
    Nuclides with the same number of neutrons are called:

      • Isobars
      • Isotones
      • Isotopes
      • Isomers

    • 2.

      The electric potential (V ) and electric field (⃗ E) are closely related concepts in electrostatics. The electric field is a vector quantity that represents the

        • Production of AC is economical.
        • AC can be easily and efficiently converted from one voltage to another.
        • AC can be transmitted economically over long distances.
        • AC is less dangerous.

      • 3.
        The energy of an electron in an orbit in hydrogen atom is \( -3.4 \, \text{eV} \). Its angular momentum in the orbit will be:

          • \( \dfrac{3h}{2\pi} \)
          • \( \dfrac{2h}{\pi} \)
          • \( \dfrac{h}{\pi} \)
          • \( \dfrac{h}{2\pi} \)

        • 4.
          In a Young's double-slit experiment, two waves each of intensity I superpose each other and produce an interference pattern. Prove that the resultant intensities at maxima and minima are 4I and zero respectively.


            • 5.
              Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

                • attract with a force \( \frac{F}{2} \)
                • repel with a force \( \frac{F}{2} \)
                • repel with a force \( F \)
                • attract with a force \( F \)

              • 6.
                Four long straight thin wires are held vertically at the corners A, B, C and D of a square of side \( a \), kept on a table and carry equal current \( I \). The wire at A carries current in upward direction whereas the current in the remaining wires flows in downward direction. The net magnetic field at the centre of the square will have the magnitude:

                  • \( \dfrac{\mu_0 I}{\pi a} \) and directed along OC
                  • \( \dfrac{\mu_0 I}{\pi a \sqrt{2}} \) and directed along OD
                  • \( \dfrac{\mu_0 I \sqrt{2}}{\pi a} \) and directed along OB
                  • \( \dfrac{2\mu_0 I}{\pi a} \) and directed along OA
                CBSE CLASS XII Previous Year Papers

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