NCERT Solutions For Class 12 Physics Chapter 3: Current Electricity

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NCERT Solutions for Class 12 Physics Chapter 3 Current Electricity are given in this article. Current electricity is the electricity that powers our homes and electrical devices. Current electricity is named for the way electrons move. They “flow” in one direction- like a river current. The study of electrons in motion like this is called Electrodynamics.

The chapter along with the unit Electrostatics has a weightage of 16 marks in CBSE Class 12 Physics exams. The NCERT Solutions for Class 12 Physics Chapter 3 covers concepts of electric current, Ohm’s law, emf, cells in series and parallel, Kirchhoff’s Rules, etc.

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NCERT Solutions for Class 12 Physics Chapter 3

The NCERT Solutions for class 12 physics chapter 3: Current Electricity is as given below.

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Chapter 3 Physics Class 12 Important Topics

Current electricity is the flow of electrons from one section of the circuit to the another.

There are two types of Current Electricity –

Direct Current is the current electricity whose direction stays the same. It is the constant flow of electrons from a high electron density region to a region of low electron density.
Alternating Current is the current electricity that keeps changing the direction of the charge flow.

When 2 bodies at different potentials are linked with a wire, the free electrons move from Point 1 to Point 2, until both objects reach the same potential. The current stops flowing after that.

Electromotive Force: Electromotive force is the electric potential that is either produced by an electrochemical cell or produced by changing the magnetic field.
Voltage: Voltage is the electric potential difference between any two points.

Ohm’s Law states that the electric current flowing through a conductor is directly proportional to the potential difference (V) applied across its ends.

It can be represented as

V = IR

Electrical Resistance is the obstruction that is offered by a conductor in the path of the flow of current.

The formula of electrical resistance is R = V/l.

Electrical resistance of a conductor R = ρl/A

where l = length of the conductor,

A = cross-section area, and

ρ = resistivity of the material of a conductor.

The current electricity can be generated through various methods.
- Both alternating and direct current can be generated by moving a metal wire through a magnetic field.
- Direct Current can be generated by a battery through chemical reactions.

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CBSE CLASS XII Related Questions

1.
An electric dipole consists of charges \(\pm 4 \mu C\) separated by a distance of \(6\,cm\). Calculate the electric field at a point on the axial line at a distance \(20\,cm\) from its center.
View Solution
2.
State any three characteristics of electromagnetic waves.
View Solution
3.
In his experiment on photoelectric effect, Robert A. Millikan found the slope of the cut-off voltage versus frequency of incident light plot to be \( 4.12 \times 10^{-15} \, \text{Vs} \). Calculate the value of Planck’s constant from it.
View Solution
4.
A thin plano-concave lens with its curved face of radius of curvature R is made of glass of refractive index \( n_1 \). It is placed coaxially in contact with a thin equiconvex lens of same radius of curvature of refractive index \( n_2 \). Obtain the power of the combination lens.
View Solution
5.
The ends of six wires, each of resistance R (= 10 \(\Omega\)) are joined as shown in the figure. The points A and B of the arrangement are connected in a circuit. Find the value of the effective resistance offered by it to the circuit.
View Solution
6.
Two wires of the same material and the same radius have their lengths in the ratio 2:3. They are connected in parallel to a battery which supplies a current of 15 A. Find the current through the wires.
View Solution

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NCERT Solutions For Class 12 Physics Chapter 3: Current Electricity

NCERT Solutions for Class 12 Physics Chapter 3

Chapter 3 Physics Class 12 Important Topics

CBSE CLASS XII Related Questions

1.
An electric dipole consists of charges \(\pm 4 \mu C\) separated by a distance of \(6\,cm\). Calculate the electric field at a point on the axial line at a distance \(20\,cm\) from its center.

2.
State any three characteristics of electromagnetic waves.

3.
In his experiment on photoelectric effect, Robert A. Millikan found the slope of the cut-off voltage versus frequency of incident light plot to be \( 4.12 \times 10^{-15} \, \text{Vs} \). Calculate the value of Planck’s constant from it.

4.
A thin plano-concave lens with its curved face of radius of curvature R is made of glass of refractive index \( n_1 \). It is placed coaxially in contact with a thin equiconvex lens of same radius of curvature of refractive index \( n_2 \). Obtain the power of the combination lens.

5.
The ends of six wires, each of resistance R (= 10 \(\Omega\)) are joined as shown in the figure. The points A and B of the arrangement are connected in a circuit. Find the value of the effective resistance offered by it to the circuit.

6.
Two wires of the same material and the same radius have their lengths in the ratio 2:3. They are connected in parallel to a battery which supplies a current of 15 A. Find the current through the wires.

Similar Physics Concepts

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NCERT Solutions For Class 12 Physics Chapter 3: Current Electricity

NCERT Solutions for Class 12 Physics Chapter 3

Chapter 3 Physics Class 12 Important Topics

CBSE CLASS XII Related Questions

1.An electric dipole consists of charges \(\pm 4 \mu C\) separated by a distance of \(6\,cm\). Calculate the electric field at a point on the axial line at a distance \(20\,cm\) from its center.

2. State any three characteristics of electromagnetic waves.

3.In his experiment on photoelectric effect, Robert A. Millikan found the slope of the cut-off voltage versus frequency of incident light plot to be \( 4.12 \times 10^{-15} \, \text{Vs} \). Calculate the value of Planck’s constant from it.

4.A thin plano-concave lens with its curved face of radius of curvature R is made of glass of refractive index \( n_1 \). It is placed coaxially in contact with a thin equiconvex lens of same radius of curvature of refractive index \( n_2 \). Obtain the power of the combination lens.

5.The ends of six wires, each of resistance R (= 10 \(\Omega\)) are joined as shown in the figure. The points A and B of the arrangement are connected in a circuit. Find the value of the effective resistance offered by it to the circuit.

6. Two wires of the same material and the same radius have their lengths in the ratio 2:3. They are connected in parallel to a battery which supplies a current of 15 A. Find the current through the wires.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
An electric dipole consists of charges \(\pm 4 \mu C\) separated by a distance of \(6\,cm\). Calculate the electric field at a point on the axial line at a distance \(20\,cm\) from its center.

2.
State any three characteristics of electromagnetic waves.

3.
In his experiment on photoelectric effect, Robert A. Millikan found the slope of the cut-off voltage versus frequency of incident light plot to be \( 4.12 \times 10^{-15} \, \text{Vs} \). Calculate the value of Planck’s constant from it.

4.
A thin plano-concave lens with its curved face of radius of curvature R is made of glass of refractive index \( n_1 \). It is placed coaxially in contact with a thin equiconvex lens of same radius of curvature of refractive index \( n_2 \). Obtain the power of the combination lens.

5.
The ends of six wires, each of resistance R (= 10 \(\Omega\)) are joined as shown in the figure. The points A and B of the arrangement are connected in a circuit. Find the value of the effective resistance offered by it to the circuit.

6.
Two wires of the same material and the same radius have their lengths in the ratio 2:3. They are connected in parallel to a battery which supplies a current of 15 A. Find the current through the wires.