NCERT Solutions for Class 12 Maths Chapter 8 Applications of Integrals Miscellaneous Exercise Solutions

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Class 12 Maths NCERT Solutions Chapter 8 Applications of Integrals Miscellaneous Exercises are provided in the article. Class 12 Chapter 8 Applications of Integrals Miscellaneous Exercises are important for both CBSE Term II exam and for competitive exams. Key topics covered in this chapter are Area Between Two Curves, lines, parabolas; area of circles/ellipses.

Download PDF: NCERT Solutions for Class 12 Maths Chapter 8 Miscellaneous Exercises

Also check other Exercise Solutions of Class 12 Maths Chapter 8 Applications of Integrals

Also Read:

Chapter 8 Applications of Integrals Important Topics
Trapezoidal Rule Formula	Area Under Curve Formula	Trapezoidal Rule
Applications of Integrals Important Questions	SImpsons Rule Formula	Surface Integral

Also Read:

CBSE Class 12 Mathematics Study Guides
Algebra	Arithmetic	Calculus
Mensuration	Trigonometry	Geometry
Permutation and Combination	Math Study Notes	Math MCQs
NCERT Solutions for Class 12 Maths	Math Formula	Difference between in Maths

CBSE CLASS XII Related Questions

1.
Solve the following Linear Programming Problem graphically :
Maximize \( Z = \frac{2x}{5} + \frac{3y}{10} \)
subject to constraints
\( 2x + y \leq 1000 \)
\( x + y \leq 800 \)
\( x, y \geq 0 \).
View Solution
2.
A box contains 6 cards numbered 1 to 6. A student is asked to pick up two cards, one by one after replacement and note down the numbers on the cards. Let A be the event of getting sum of the numbers on two cards as 10, and B, the event of a number other than 4 on the first card selected. Find \( P(A \text{ and } B) \) and find whether the events A and B are independent events or not.
View Solution
3.
Find the differential of \( x^{\cot x} + \frac{2x^2-3}{2x^2-x+2} \) with respect to \( x \).
View Solution
4.
Find the foot of the perpendicular from the point \( (0, 2, 3) \) on the line \( \frac{-x-3}{-5} = \frac{1-y}{-2} = \frac{3z+12}{9} \) and hence find the length of the perpendicular.
View Solution
5.
Sketch the graph defined by \( \left\{ (x, y) : \frac{x^2{25} + \frac{y^2}{25} = 1 \right\} \). Find the area of the region of minor segment cut off by the line \( x = \frac{5}{2} \), using integration.}
View Solution
6.
The volume of a wooden block in the shape of a cube increases at a constant rate as the air becomes moist during the rainy season. Show that the rate of change of its surface area varies inversely as the length of edge of the cube.
View Solution

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You can also check

NCERT Solutions for Class 12 Maths Chapter 8 Applications of Integrals Miscellaneous Exercise Solutions

CBSE CLASS XII Related Questions

1.
Solve the following Linear Programming Problem graphically :
Maximize \( Z = \frac{2x}{5} + \frac{3y}{10} \)
subject to constraints
\( 2x + y \leq 1000 \)
\( x + y \leq 800 \)
\( x, y \geq 0 \).

3.
Find the differential of \( x^{\cot x} + \frac{2x^2-3}{2x^2-x+2} \) with respect to \( x \).

4.
Find the foot of the perpendicular from the point \( (0, 2, 3) \) on the line \( \frac{-x-3}{-5} = \frac{1-y}{-2} = \frac{3z+12}{9} \) and hence find the length of the perpendicular.

5.
Sketch the graph defined by \( \left\{ (x, y) : \frac{x^2{25} + \frac{y^2}{25} = 1 \right\} \). Find the area of the region of minor segment cut off by the line \( x = \frac{5}{2} \), using integration.}

6.
The volume of a wooden block in the shape of a cube increases at a constant rate as the air becomes moist during the rainy season. Show that the rate of change of its surface area varies inversely as the length of edge of the cube.

Similar Mathematics Concepts

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NCERT Solutions for Class 12 Maths Chapter 8 Applications of Integrals Miscellaneous Exercise Solutions

CBSE CLASS XII Related Questions

1.Solve the following Linear Programming Problem graphically : Maximize \( Z = \frac{2x}{5} + \frac{3y}{10} \) subject to constraints \( 2x + y \leq 1000 \) \( x + y \leq 800 \) \( x, y \geq 0 \).

3.Find the differential of \( x^{\cot x} + \frac{2x^2-3}{2x^2-x+2} \) with respect to \( x \).

4.Find the foot of the perpendicular from the point \( (0, 2, 3) \) on the line \( \frac{-x-3}{-5} = \frac{1-y}{-2} = \frac{3z+12}{9} \) and hence find the length of the perpendicular.

5.Sketch the graph defined by \( \left\{ (x, y) : \frac{x^2{25} + \frac{y^2}{25} = 1 \right\} \). Find the area of the region of minor segment cut off by the line \( x = \frac{5}{2} \), using integration.}

6.The volume of a wooden block in the shape of a cube increases at a constant rate as the air becomes moist during the rainy season. Show that the rate of change of its surface area varies inversely as the length of edge of the cube.

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Solve the following Linear Programming Problem graphically :
Maximize \( Z = \frac{2x}{5} + \frac{3y}{10} \)
subject to constraints
\( 2x + y \leq 1000 \)
\( x + y \leq 800 \)
\( x, y \geq 0 \).

3.
Find the differential of \( x^{\cot x} + \frac{2x^2-3}{2x^2-x+2} \) with respect to \( x \).

4.
Find the foot of the perpendicular from the point \( (0, 2, 3) \) on the line \( \frac{-x-3}{-5} = \frac{1-y}{-2} = \frac{3z+12}{9} \) and hence find the length of the perpendicular.

5.
Sketch the graph defined by \( \left\{ (x, y) : \frac{x^2{25} + \frac{y^2}{25} = 1 \right\} \). Find the area of the region of minor segment cut off by the line \( x = \frac{5}{2} \), using integration.}

6.
The volume of a wooden block in the shape of a cube increases at a constant rate as the air becomes moist during the rainy season. Show that the rate of change of its surface area varies inversely as the length of edge of the cube.