NCERT Solutions for Class 12 Maths Chapter 6 Applications of Derivatives Exercise 6.4

Jasmine Grover logo

Jasmine Grover

Education Journalist | Study Abroad Lead

Class 12 Maths NCERT Solutions Chapter 6 Applications of Derivatives Exercise 6.4 is provided in this article. Chapter 6 Exercise 6.4 includes questions that deal with concepts of applications of derivatives and approximations. The exercise includes a total of 9 questions with 7 short questions and 2 MCQs.

Download PDF: NCERT Solutions for Class 12 Maths Chapter 6 Exercise 6.4

Check out Class 12 Maths NCERT solutions chapter 6 Applications of Derivatives Exercise 6.4:

Read More: NCERT Solutions For Class 12 Mathematics Chapter 6 Applications of Derivatives

Check out other exercise solutions of Class 12 Maths Chapter 6 Applications of Derivatives:

Class 12 Chapter 6 Applications of Derivatives Topics:

CBSE Class 12 Mathematics Study Guides:

CBSE CLASS XII Related Questions

  • 1.
    Find:

    The shortest distance between the lines: \[ \vec{r}=(4+\lambda)\hat{i}+(2\lambda-1)\hat{j}-3\lambda\hat{k} \] and \[ \vec{r}=(1+2\mu)\hat{i}+(4\mu-1)\hat{j}+(2-5\mu)\hat{k} \]


      • 2.
        Find the vector and cartesian equations of the line passing through the point of intersection of the lines \( \vec{r} = (\hat{i} + \hat{j} - \hat{k}) + \lambda(3\hat{i} - \hat{j}) \) and \( \vec{r} = (4\hat{i} - \hat{k}) + \mu(2\hat{i} + 3\hat{k}) \) and parallel to the line \( \frac{x - 1}{-2} = \frac{7 - y}{-3} = z \).


          • 3.
            Using integration, find the area of the region bounded by the curve \( y = x|x| \), the x-axis, and the vertical lines \( x = -2 \) and \( x = 2 \).


              • 4.
                A relation $R$ on set $A=\{1,2,3\}$ defined as $R=\{(1,2),(2,1),(2,2)\}$ is

                  • Reflexive only
                  • Reflexive and Transitive
                  • Symmetric and Transitive
                  • Symmetric only

                • 5.
                  Which of the following equations is NOT a Linear Differential Equation?

                    • \((1 + x^2) \, dy + 2xy \, dx = \cot x \, dx\)
                    • \(y + \frac{d}{dx}(xy) = x(\sin x + \log x)\)
                    • \(x(1 + y^2) \, dx - y(1 + x^2) \, dy = 0\)
                    • \(y \, dx - (x + 3y^2) \, dy = 0\)

                  • 6.

                    A carpenter needs to design a wooden box in the shape of a cuboid such that the sum of its length and breadth is 3 cm more than its height. Twice of its length, thrice of its breadth and its height add up to 10 cm. Its breadth added to 7 times its height is 1 cm less than 3 times its length. 

                      CBSE CLASS XII Previous Year Papers

                      Comments


                      No Comments To Show