Atoms MCQ: Introduction & Explanation

Collegedunia Team logo

Collegedunia Team Content Curator

Content Curator

Atoms are the smallest and elementary unit of any ordinary matter. Every atom has a nucleus in the centre and one or more electrons revolving around it in energy shells. One or more protons and several neutrons make up the nucleus. The protons have a positive charge, while the electrons have a negative charge and the neutrons have none. The atom is electrically neutral if the number of protons and electrons is equal and thus nullifies each other. 

Structure of atoms

Structure of Atom

When an atom contains more or fewer electrons than protons, it has a negative or positive overall charge accordingly and is called an ion. The electromagnetic force attracts electrons to its protons in the nucleus. The number of protons in the nucleus is the atomic number and it determines the chemical properties the atom belongs to.

The following are the five atomic models:

Read More:

Multiple Choice Questions

Ques 1. Which of the following correctly represents the electronic distribution in the Mg atom?

(a) 3, 8, 1

(b) 2, 8, 2

(c) 1, 8, 3

(d) 8, 2, 2

Click here for the answer

Ans. (b) 2, 8, 2

Explanation: Atomic number and the number of electrons in a magnesium atom is 12.

So, electronic configuration is 2, 8, 2 (as 12 = 2 + 8 + 2).

The maximum electrons on the K shell are 2 and the maximum electrons in the L shell are 8.

Ques 2. A sample of NH3 molecules irrespective of source contains 82.35% Nitrogen and 17.65% of Hydrogen by mass. This data supports:

(a) Law of Conservation of Mass

(b) Law of Multiple Proportions

(c) Law of Definite Proportions

(d) Avogadro’s Law

Click here for the answer

Ans. (c) Law of Definite Proportions

Explanation: According to the law of definite proportions, or ratio, the mass proportion of components in a compound's samples will always be the same.

The law of proportions, also known as the law of fixed constant, holds that the proportions of the constituent components that make up a chemical compound or composition will always be the same.

Ques 3. What is the molecular formula of potassium nitrate?

(a) KNO3

(b) KNO

(c) KNO2

(d) KON

Click here for the answer

Ans. (a) KNO3

Explanation: Potassium Nitrate is a crystalline salt with strong oxidizing powers. They are used in the manufacture of gunpowder, fertilizer, and in medicine. Potassium nitrate is the inorganic nitrate salt of potassium. K is the chemical representation of potassium and NO3 is the chemical representation of nitrate.

Ques 4. Molecular mass is defined as the:

(a) Mass of one molecule of any substance compared with the mass of one atom of C – 12

(b) Mass of one atom in comparison with the mass of one atom of hydrogen

(c) Mass of one atom in comparison with the mass of one molecule

(d) None of the above

Click here for the answer

Ans. (a) Mass of one molecule of any substance compared with the mass of one atom of C – 12

Explanation: The sum of all atoms' weight in a molecule is calculated using a scale with hydrogen, carbon, nitrogen, and oxygen atomic masses of 1, 12, 14, and 16, respectively. Water, for example, has a molecular mass of 18 (i.e. 2 + 16) since it contains two hydrogen atoms and one oxygen atom. Also known as molecular mass.

Ques 5. The number of moles in 46g of sodium with atomic number 23 is equal to.

(a) 4

(b) 2

(c) 0

(d) ½

Click here for the answer

Ans. (b) 2

Explanation: It is given that,

Atomic Mass of Sodium or molar mass = 23 

A number of moles in 46 g of Na is.

No. of moles = Given Mass/ Molar Mass

by substituting the value we get

No. of Moles = 46/23

No. of Moles = 2

Ques 6. Which of the following represents a correct chemical formula?

(a) CaCl

(b) BiPO4

(c) NaSO4

(d) NaS

Click here for the answer

Ans. (b) BiPO4

Explanation: BiPO4 is the only one of these compounds with the exact chemical formula. Bismuth orthophosphate is a compound containing bismuth. The valencies of all the elements are not satisfied in the other compounds. Calcium chloride (CaCl2), sodium sulfate (Na2SO4), and sodium sulphide (Na2S) are the correct chemical composition representations.

Ques 7. What is the formula mass unit of ZnO?

(a) 18 u

(b) 81 u

(c) 88 u

(d) 188 u

Click here for the answer

Ans. (b) 81 u

Explanation: Atomic mass of Zn = 65u

Atomic mass of O = 16u

Calculating the formula unit masses of them:

ZnO = Zn + O

ZnO = (65 + 16)u = 81u

Ques 8. Atomic models have been improved over the years. Arrange the following atomic models in their chronological order

(i) Rutherford’s atomic model

(ii) Thomson’s atomic model

(ii) Bohr’s atomic model

(a) (i), (ii) and (iii)

(b) (ii), (iii) and (i)

(c) (ii), (i) and (iii)

(d) (iii), (ii) and (i)

Click here for the answer

Ans: (c) (ii), (i) and (iii)

Explanation: The first atomic model was given by J.J. Thomson in 1904. A model of the atom with electrons revolving around the nucleus was proposed by Rutherford in 1911. The final atomic model with improvement came in 1915 by Bohr. The chronological order of the atomic models is (ii) Thomson’s atomic model (i) Rutherford’s atomic model (iii) Bohr’s atomic model.

Ques 9. How many atoms of oxygen are present in 300 grams of CaCO3?

(a) 54.207 × 1023 

(b) 6.207 × 1023 

(c) 12.207 × 1023 

(d) 22.2 × 1023

Click here for the answer

Ans. (a) 54.207 × 1023 

Explanation: Given mass of CaCO3 = 300g

Molar mass of CaCO3 = 40 + 12 + (3 x 16) =100 g mol-¹

Number of moles of CaCO3 = mass / molar mass

= 300g/ 100 g mol-¹

= 3 moles

Number of oxygen atoms in CaCO3 = 3

Number of moles of oxygen atoms = 3 x 3 moles = 9 moles

1 mole of oxygen contains 6.022 x 1023 atoms of oxygen.

Therefore , 9 moles of oxygen contains = 9 x 6.022 x 1023 atoms

=5.4 x 1024 oxygen atoms.

Ques 10. Which of the following represents the correct relation between Avogadro's number (No), number of particles (N), and moles (n)?

(a) n = N / No

(b) n = No / N

(c) n = N No

(d) all are correct

Click here for the answer

Answer. (a) n = N / No

Explanation: The correct relation between Avogadro’s number and the number of particles and moles is given by the formula, n = N / No  where, No is the Avogadro’s number, n is the number of miles and N is the number of particles.

For Latest Updates on Upcoming Board Exams, Click Here: https://t.me/class_10_12_board_updates


Check Also:

CBSE CLASS XII Related Questions

  • 1.
    Answer the following giving reason:
    (a) All the photoelectrons do not eject with the same kinetic energy when monochromatic light is incident on a metal surface.
    (b) The saturation current in case (a) is different for different intensity.
    (c) If one goes on increasing the wavelength of light incident on a metal sur face, keeping its intensity constant, emission of photoelectrons stops at a certain wavelength for this metal.


      • 2.
        Two point charges \( q_1 = 16 \, \mu C \) and \( q_2 = 1 \, \mu C \) are placed at points \( \vec{r}_1 = (3 \, \text{m}) \hat{i}\) and \( \vec{r}_2 = (4 \, \text{m}) \hat{j} \). Find the net electric field \( \vec{E} \) at point \( \vec{r} = (3 \, \text{m}) \hat{i} + (4 \, \text{m}) \hat{j} \).


          • 3.
            A parallel plate capacitor has plate area \( A \) and plate separation \( d \). Half of the space between the plates is filled with a material of dielectric constant \( K \) in two ways as shown in the figure. Find the values of the capacitance of the capacitors in the two cases. parallel plate capacitor


              • 4.
                The resistance of a wire at 25°C is 10.0 \( \Omega \). When heated to 125°C, its resistance becomes 10.5 \( \Omega \). Find (i) the temperature coefficient of resistance of the wire, and (ii) the resistance of the wire at 425°C.


                  • 5.
                    A charge \( -6 \mu C \) is placed at the center B of a semicircle of radius 5 cm, as shown in the figure. An equal and opposite charge is placed at point D at a distance of 10 cm from B. A charge \( +5 \mu C \) is moved from point ‘C’ to point ‘A’ along the circumference. Calculate the work done on the charge.
                    work done on the charge


                      • 6.
                        A small spherical shell \( S_1 \) has point charges \( q_1 = -3 \, \mu C \), \( q_2 = -2 \, \mu C \) and \( q_3 = 9 \, \mu C \) inside it. This shell is enclosed by another big spherical shell \( S_2 \). A point charge \( Q \) is placed in between the two surfaces \( S_1 \) and \( S_2 \). If the electric flux through the surface \( S_2 \) is four times the flux through surface \( S_1 \), find charge \( Q \).

                          CBSE CLASS XII Previous Year Papers

                          Comments


                          No Comments To Show