Resistance Formula Important Questions

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Resistance formula is defined by Ohm’s Law which states that the voltage drop across a conductor is directly proportional to the current flowing through the electric circuit.  The proportionality constant is known as Resistance. Mathematically, Ohm’s Law can be written as

V ∝ I

V = IR

Where V = Voltage drop in Volts

I = Electric Current in Amperes

R = Resistance in Ohms

Ohms denoted by the letter Ω is the SI unit of resistance. Resistance can also be defined as 1 Volt/ 1 Ampere. Resistance is an important concept covered in the Current Electricity chapter of the latest CBSE Class 12 Physics Syllabus.

The video below explains this:

Resistance Formula Detailed Video Explanation:

Read More: NCERT Solutions for Class 12 Current Electricity 


Very Short Answer Questions (1 mark)

Ques. Plot the graph between current and voltage for GaAs. [Delhi 2014]

Ans. The Current Vs Voltage for GaAs is as Follows:

V-I plot for GaAs

V-I plot for GaAs

Ques. How does resistivity of Cu vary as a function of temperature? [Delhi 2014, All India 2014]

Ans. The resistivity of Cu varies as per the following plot with respect to temperature.

The resistivity of Cu Vs Temperature

The resistivity of Cu Vs Temperature

Read More: Static Electricity

Ques. Plot the resistivity of Silicon with temperature. [Delhi 2014]

Ans. The plot of resistivity of Cu as a function of temperature is:

Si Resistivity Vs Temperature

Si Resistivity Vs Temperature

Ques. Define resistivity and give its Si unit. [All India 2011]

Ans. The resistance offered by unit length of the conductor across an area of 1 m2 is termed as resistivity. The unit is Ohm- meter, denoted by Ωm.

Ques. Give the expression for the resitivity of a conductor with variation shown along a range of temperatures. [Delhi 2008]

Ans. The resistivity for a metallic conductor varying across a range of temperatures is given by the expression:

\(\rho_T=\rho_0[1+\alpha[T-T_0]]\)

Where

T, T0= Temperatures

ρT, ρ= Resistivities at temperatures T and T0

α= Temperature Coefficient of the metallic conductor material

Read More:


Short Answer Questions (2 Marks)

Ques. Differentiate between resistivity and resistance for a conductor. 

Ans. Resistance is the potential drop across the conductor per unit of current flowing through it. Resistivity is the resistance offered by a conductor unit cross-sectional area and unit length of the conductor. 

Ques. Show the variation of resistivity for a conductor and semiconductor concerning temperature change.

Ans. The following is the resistivity vs temperature plot of conductor and semiconductor:

Conductor (left), Semiconductor (Right)- Resistivity vs Temperature Plot

Conductor (left), Semiconductor (Right)- Resistivity vs Temperature Plot

In conductors when temperature is raised, the resistivity increases,as the relaxation time decreases. Whereas in semiconductors, with an increase in temperature,relaxation time is decreased thereby reducing resistivity. 

Ques. A carbon resistor consists of three red colored strips and one gold strip. Determine the resistor value and tolerance.

Ans. For the carbon resistor the color code would be R R R Gold. The resistor value would be 22 x102 Ω ∓ 5 %. i.e. 2200 Ω with  ∓ 5 % tolerance.

Read More: Galvanometer 

Ques. What are ohmic and non-ohmic resistors? Give examples. 

Ans. Materials that obey Ohm’s Law are Ohmic resistors. Examples: Metals

Materials that do not follow Ohm’s Law and have their characteristics are non-ohmic resistors. Example diodes, transistors.

Ques. Why are constantan and manganin used for making resistors?

Ans. High resistivities and low temperature of coefficient resistance are why constantan and manganin alloys are used in resistors. 

Check Out:


Long Answer Questions (3 Marks)

Ques. Why is a potentiometer used to measure the emf in a circuit? 

Ans. Potentiometer works on the principle of null deflection. Therefore, a potentiometer does not draw any current from the circuit. The emf value of a cell is the terminal potential difference when no current flows through the cell. Thus a potentiometer is used in place of a voltmeter to measure the emf of a cell. 

Ques. If V is the potential difference applied across length L of a copper wire and has a diameter D. What is the drift velocity of electrons if:

  1. V is doubled
  2. I is doubled
  3. D is doubled

Ans. Drift velocity is given by Vd

Mathematically,

\(V_d=\frac{V}{R(neA)}\)

Replacing R with \(P \frac{l}{A}\)

\(V_d=\frac{V}{nePl}\)

Thus when the drift velocity gets doubled with a doubled V. Drift velocity gets halved when I is doubled it remains unchanged with a change in diameter. 

Read More: Unit of Voltage MCQs

Ques. What happens to the wire resistance when its length is increased to twice its original length? 

Ans. \(R=\rho \frac {l}{A}\)

⇒ \(R=\rho \frac {l}{\pi r^2}\)

When the length l1= 2l the radius changes from r to r1.

⇒ πr2l = πr12l1

⇒ r12= r2/2

Substituting for new resistance we get

\(R'=\rho \frac {l_1}{\pi r_1^2} \)

\(R'=\rho \frac {2l}{\pi \frac{r^2} {2}} \)

⇒ \(R'=\rho \frac {4l}{\pi r^2} \)

Hence the resistance increases by four times in doubling the length.


Very Long Answer Questions (5 Marks)

Ques. What is the expression for current density of a conductor in terms of drift speed of electrons? 

Ans. Let V be the potential difference applied across the conductor and E be the electric field produced inside the conductor. 

The derivation for the current density is as follows:

The derivation for the current density is as follows

The derivation for the current density is as follows

Read More: SI unit of Electric Current

Ques. If three resistors are combined in parallel and value at 2, 4, and 5 Ω respectively. Determine the total resistance of the combination. When connected to a 20 V emf battery and there is negligible internal resistance in the circuit, calculate the current through each resistor and the total current drawn from the battery. 

Ans. Let R1, R2, and R3 be the three resistors.

When connected in parallel, the total resistance = \(\frac{1}{R}= \frac{1}{R_1}+ \frac{1}{R_2}+\frac{1}{R_3}\)

= \(\frac{1}{2}+\frac{1}{4}+\frac{1}{5}\)

= 20/ 19 Ω

EMF, V =20 V

Current I1 through R1 is 20/2 =10 A

Current I2 through R2= 20/4 =5A

Current I3 through R3= 20/5 =4A

Therefore, Total current = I1+I2+I3

= 10+5+4=19 A

Discover about the Chapter video:

Current Electricity Detailed Video Explanation:

For Latest Updates on Upcoming Board Exams, Click Here: https://t.me/class_10_12_board_updates


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CBSE CLASS XII Related Questions

  • 1.
    A current carrying circular loop of area A produces a magnetic field \( B \) at its centre. Show that the magnetic moment of the loop is \( \frac{2BA}{\mu_0} \sqrt{\frac{A}{\pi}} \).


      • 2.
        (a) Consider the so-called ‘D-T reaction’ (Deuterium-Tritium reaction).
        In a thermonuclear fusion reactor, the following nuclear reaction occurs: \[ \ ^{2}_1 \text{H} + \ ^{3}_1 \text{H} \longrightarrow \ ^{4}_2 \text{He} + \ ^{1}_0 \text{n} + Q \] Find the amount of energy released in the reaction.
        % Given data Given:
        \( m\left(^{2}_1 \text{H}\right) = 2.014102 \, \text{u} \)
        \( m\left(^{3}_1 \text{H}\right) = 3.016049 \, \text{u} \)
        \( m\left(^{4}_2 \text{He}\right) = 4.002603 \, \text{u} \)
        \( m\left(^{1}_0 \text{n}\right) = 1.008665 \, \text{u} \)
        \( 1 \, \text{u} = 931 \, \text{MeV}/c^2 \)


          • 3.
            Write the mathematical forms of three postulates of Bohr’s theory of the hydrogen atom. Using them prove that, for an electron revolving in the \( n \)-th orbit,
            (a) the radius of the orbit is proportional to \( n^2 \), and
            (b) the total energy of the atom is proportional to \( \frac{1}{n^2} \).


              • 4.
                The electric field at a point in a region is given by \( \vec{E} = \alpha \frac{\hat{r}}{r^3} \), where \( \alpha \) is a constant and \( r \) is the distance of the point from the origin. The magnitude of potential of the point is:

                  • \( \frac{\alpha}{r} \)
                  • \( \frac{\alpha r^2}{2} \)
                  • \( \frac{\alpha}{2r^2} \)
                  • \( -\frac{\alpha}{r} \)

                • 5.
                  Two point charges \( q_1 = 16 \, \mu C \) and \( q_2 = 1 \, \mu C \) are placed at points \( \vec{r}_1 = (3 \, \text{m}) \hat{i}\) and \( \vec{r}_2 = (4 \, \text{m}) \hat{j} \). Find the net electric field \( \vec{E} \) at point \( \vec{r} = (3 \, \text{m}) \hat{i} + (4 \, \text{m}) \hat{j} \).


                    • 6.
                      In the circuit, three ideal cells of e.m.f. \( V \), \( V \), and \( 2V \) are connected to a resistor of resistance \( R \), a capacitor of capacitance \( C \), and another resistor of resistance \( 2R \) as shown in the figure. In the steady state, find (i) the potential difference between P and Q, (ii) the potential difference across capacitor C.
                      potential difference across capacitor C

                        CBSE CLASS XII Previous Year Papers

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