A galvanometer can be defined as a device used for the detection of small electric current or to measure its magnitude. In general, the current and its intensity is shown by the movement of a magnetic needle or a coil in a magnetic field. When current IG flows via the galvanometer, the current through the shunt resistance can be expressed by IS = I – IG. The voltages across the galvanometer and shunt resistance are equivalent to one another due to the parallel nature of their connection.
Therefore, RG.IG = (I – IG).Rs
Here,
- RG = Resistance of galvanometer
- G = Galvanometer coil
- I = Total current via circuit
- IG = Total current via galvanometer that corresponds to full-scale reading
- Rs = Value of shunt resistance
Step-1: Solution
As per the given question, the following can be determined:
I = 10A
Ig = 10 mA = 0.010 A
Rg = 100 Ω
Thus, with the given condition, we can obtain:
| I = Ig + Is |
⇒ (I − Ig)Rs = IgRg
By replacing the known values, we can get:
(10 − 0.010)Rs = 0.010 × 100
⇒ Rs = 0.1
Also Read: NCERT Solutions for Class 6 to 12
Related Questions
- In A Graph Between Current I And Voltage V, Find The Portion Corresponding To Negative Resistance.
- 1.0 M Rectangular Loop With A Sliding Connector Is In Uniform Magnetic Field 2t Perpendicular To Plane Of Loop. Resistance Is 2 Ohms. Two Resistances, 6 Ohms And 3 Ohms, Are Connected.
- Resistance In Meter Bridge’s Two Arms Are 5 Ohms And R Ohms. When Resistance R Is Shunted With Equal Resistance, New Balance Point Becomes 1.6l1. Calculate R.
- A Closed Coil Has 500 Turns Across Rectangular Frame Of Area 4.0 Cm2 With Resistance Of 500 Ohms. The Coil Is Plane Perpendicular To A Uniform Magnetic Field Of 0.2wb/M2. Find Amount Of Charge Through Coil If Turned Over (180 Degrees Rotation).
- If R, C And L Are Fundamental Quantities In A Circuit Like Resistance, Capacitance And Inductance In W, Then Find Dimensional Formula For Resistance And Capacitance.
- To A Resistor With 10 Ohms, Sinusoidal Voltage V = 200 Sin 314t Is Applied. Calculate The Values Below.
- Two Identical Resistors With Resistances 15 Ohm Are Connected In Series And Parallel To A Battery Of 6 V. Calculate Ratio Of Power Consumed.
- For The Resistor Combination, Find The Equivalent Resistance Between M and N.
- A Circuit Consists Of A Battery Of 3 Cells (2 V Each), A Combination Of Three Resistors, 10 Ohm, 20 Ohm And 30 Ohm, Attached Parallelly, With Plug Key And Ammeter (In Series).
- Two Concentric Coplanar Circular Loops Of Wire (Resistance Per Unit Length 10 4 Ohms M-1) Have Diameters 0.2 M And 2 M. With Time-Varying Potential Difference Of (4+2.5t) Applied To Larger Loop, Find Current In Smaller One.
- Three Incandescent Bulbs (Each 100 W) Are Attached In Series. In Another Circuit, Three More Bulbs Of Same Wattage Are Attached Parallelly To An Equal Source.
Read More:





Comments