What is the importance of the universal law of Gravitation?

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According to the Universal Law of Gravitation, every particle of matter in the universe attracts every other particle with a force that is directly proportional to the product of the masses of the particles and inversely proportional to the square of the distance between them.

The importance of the Universal Law of Gravitation is as follows:

It explains the phenomenon of revolutions of heavenly bodies: All heavenly bodies or celestial bodies like planets and satellites move in an elliptical orbit due to gravitational force.
It tells us about the force that is responsible for binding us to the earth: The gravitational force of attraction between the earth and us helps to keep us on the ground. Since the mass of the earth is very large compared to us, so we are attracted to the earth.
It explains the formation of tidal waves: Ocean tides result from the rise and fall of water levels due to the gravitational force exerted by both the sun and moon.
A planet's orbit around the sun, a moon's orbit around the Earth, and an artificial satellite's orbit around the Earth are all explained by the law of gravitation.
Rainfall, snowfall, and the flow of water in rivers on the planet are also explained by the universal law of gravitation.

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Related Topics
Weightlessness	Neptune	Relation between G and g
Density of Air	Specific Gravity	Value of g on Moon
Archimedes Principle	Central Force	Global Positioning System
Earth satellites	Escape speed	Gravitational potential energy

CBSE CLASS XII Related Questions

1.
A current carrying circular loop of area A produces a magnetic field \( B \) at its centre. Show that the magnetic moment of the loop is \( \frac{2BA}{\mu_0} \sqrt{\frac{A}{\pi}} \).

View Solution

2.
Three batteries E1, E2, and E3 of emfs and internal resistances (4 V, 2 \(\Omega\)), (2 V, 4 \(\Omega\)) and (6 V, 2 \(\Omega\)) respectively are connected as shown in the figure. Find the values of the currents passing through batteries E1, E2, and E3.

View Solution

3.
Assertion (A): The deflection in a galvanometer is directly proportional to the current passing through it.
Reason (R): The coil of a galvanometer is suspended in a uniform radial magnetic field.

Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A)
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false and Reason (R) is also false.

View Solution

4.
The electric field (\( \vec{E} \)) and electric potential (\( V \)) at a point inside a charged hollow metallic sphere are respectively:

\( E = 0, \quad V = 0 \)
\( E = 0, \quad V = V_0 \text{ (a constant)} \)
\( E \ne 0, \quad V \ne 0 \)
\( E = E_0 \text{ (a constant)}, \quad V = 0 \)

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5.
The distance of an object from the first focal point of a biconvex lens is \( X_1 \) and distance of the image from second focal point is \( X_2 \). The focal length of the lens is:

\( X_1 X_2 \)
\( \sqrt{X_1 + X_2} \)
\( \sqrt{X_1 X_2} \)
\( \frac{X_2}{X_1} \)

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6.
Two slits 0.1 mm apart are arranged 1.20 m from a screen. Light of wavelength 600 nm from a distant source is incident on the slits. How far apart will adjacent bright interference fringes be on the screen?

View Solution

What is the importance of the universal law of Gravitation?

CBSE CLASS XII Related Questions

1.
A current carrying circular loop of area A produces a magnetic field \( B \) at its centre. Show that the magnetic moment of the loop is \( \frac{2BA}{\mu_0} \sqrt{\frac{A}{\pi}} \).

2.
Three batteries E1, E2, and E3 of emfs and internal resistances (4 V, 2 \(\Omega\)), (2 V, 4 \(\Omega\)) and (6 V, 2 \(\Omega\)) respectively are connected as shown in the figure. Find the values of the currents passing through batteries E1, E2, and E3.

3.
Assertion (A): The deflection in a galvanometer is directly proportional to the current passing through it.
Reason (R): The coil of a galvanometer is suspended in a uniform radial magnetic field.

4.
The electric field (\( \vec{E} \)) and electric potential (\( V \)) at a point inside a charged hollow metallic sphere are respectively:

5.
The distance of an object from the first focal point of a biconvex lens is \( X_1 \) and distance of the image from second focal point is \( X_2 \). The focal length of the lens is:

6.
Two slits 0.1 mm apart are arranged 1.20 m from a screen. Light of wavelength 600 nm from a distant source is incident on the slits. How far apart will adjacent bright interference fringes be on the screen?

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What is the importance of the universal law of Gravitation?

CBSE CLASS XII Related Questions

1.A current carrying circular loop of area A produces a magnetic field \( B \) at its centre. Show that the magnetic moment of the loop is \( \frac{2BA}{\mu_0} \sqrt{\frac{A}{\pi}} \).

2.Three batteries E1, E2, and E3 of emfs and internal resistances (4 V, 2 \(\Omega\)), (2 V, 4 \(\Omega\)) and (6 V, 2 \(\Omega\)) respectively are connected as shown in the figure. Find the values of the currents passing through batteries E1, E2, and E3.

3.Assertion (A): The deflection in a galvanometer is directly proportional to the current passing through it. Reason (R): The coil of a galvanometer is suspended in a uniform radial magnetic field.

4.The electric field (\( \vec{E} \)) and electric potential (\( V \)) at a point inside a charged hollow metallic sphere are respectively:

5.The distance of an object from the first focal point of a biconvex lens is \( X_1 \) and distance of the image from second focal point is \( X_2 \). The focal length of the lens is:

6.Two slits 0.1 mm apart are arranged 1.20 m from a screen. Light of wavelength 600 nm from a distant source is incident on the slits. How far apart will adjacent bright interference fringes be on the screen?

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
A current carrying circular loop of area A produces a magnetic field \( B \) at its centre. Show that the magnetic moment of the loop is \( \frac{2BA}{\mu_0} \sqrt{\frac{A}{\pi}} \).

2.
Three batteries E1, E2, and E3 of emfs and internal resistances (4 V, 2 \(\Omega\)), (2 V, 4 \(\Omega\)) and (6 V, 2 \(\Omega\)) respectively are connected as shown in the figure. Find the values of the currents passing through batteries E1, E2, and E3.

3.
Assertion (A): The deflection in a galvanometer is directly proportional to the current passing through it.
Reason (R): The coil of a galvanometer is suspended in a uniform radial magnetic field.

4.
The electric field (\( \vec{E} \)) and electric potential (\( V \)) at a point inside a charged hollow metallic sphere are respectively:

5.
The distance of an object from the first focal point of a biconvex lens is \( X_1 \) and distance of the image from second focal point is \( X_2 \). The focal length of the lens is:

6.
Two slits 0.1 mm apart are arranged 1.20 m from a screen. Light of wavelength 600 nm from a distant source is incident on the slits. How far apart will adjacent bright interference fringes be on the screen?