Unit Vector Formula: Definition, Equations and Solved Questions

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Unit Vector is a vector that has a magnitude of value 1 or unity pointing at a particular direction in space. Having unit magnitude, it may be thought to be just a direction pointed in space. Unit vectors are usually denoted by a letter with a circumflex (^) on top of it. Often, a unit vector forms the basis of a vector space and every vector in the space can be written as a linear combination of unit vectors.

Read More: Direction of Vector Formula

Key Terms: Unit Vector, Magnitude, Scalar, Vector, Direction, Coordinate System, Linear Combination, Vector space, Force, Density, Cartesian coordinate system

What is a Unit Vector?

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A unit vector is a vector which has direction and a magnitude of 1 or unity. A vector comprises two properties namely magnitude and direction. Magnitude refers to the “size” of a vector. For a vector in a graph, its length is its magnitude, while its direction is where it is pointed or how much it is inclined to one of the axes. Some examples of vectors are velocity, force, etc. A vector that only has magnitude is a scalar. Some examples of scalars are volume, density, etc. In the case of a unit vector, the length would be one unit, while it points in the direction. Some examples of unit vectors are the basis vectors of the cartesian coordinate system. It is denoted as .

In the figure above, the blue line is a vector. It has some magnitude (||u||) and a direction is given by "theta".

In the figure above, the blue line is a vector. It has some magnitude (||u||) and a direction is given by "theta".

In this figure, the blue and green rays are both unit vectors as their lengths are unity.

In this figure, the blue and green rays are both unit vectors as their lengths are unity.

Also Read:


Unit Vector Formula

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As mentioned above, a unit vector is a vector with direction and unit magnitude. Consequently, a unit vector can be expressed as a division of a vector by its magnitude.

Unit Vector = (Vector)/Magnitude

The magnitude of a vector is

The magnitude of a vector is

There are two ways to write a vector: Using brackets or as a linear combination of basis vectors x, y and z.

Read More: Vector Formula

For an arbitrary vector represented as

For an arbitrary vector represented as

or

For an arbitrary vector represented as

Its unit vector is given as

In Bracket Form: 

In Bracket Form

In Linear Combination:

In Linear Combination:

  Where,

  • \(\hat{v}\) is the Unit vector of unit magnitude along the direction of vector a.
  • \(\overrightarrow{v}\) is a vector with any direction and magnitude.
  • \(|\overrightarrow{v}|\) is the magnitude of the vector \(\overrightarrow{v}\) .
  • x, y, and z are the values of the vector in the x-axis, y-axis and z-axis respectively. 
  • \(\hat{i}\) , \(\hat{j}\) , and \(\hat{k}\) are unit vectors bound for the positive axis x, y and z respectively. 
Read More: Addition of Vectors

Calculation of a Unit Vector

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  • A unit vector can be calculated from some given vector. This determines the direction pointed by the given vector. To do this, one needs both the vector expression and its magnitude.
  • A vector with only magnitude and no direction is a scalar.
  • Dividing the given vector by its magnitude gives the direction it is pointed at, as a unit vector. Here, the unit vector is termed the “direction vector.”
  • By doing as mentioned, one reduces the size of the vector to unity only for its direction to remain.
  • Conversely, multiplying a unit vector by some scalar, produces a vector, a = sâ where s is a scalar and â is a unit vector. The scalar gives magnitude to the unit vector transforming it into a regular vector.

Read More: Types of Vectors

Example:

Consider a vector a = 2i + 3j + 4k. Calculate its unit vector.

Solution: The given vector is a = 2i + 3j + 4k ------(1) To find the unit vector of some given vector,

Step 1: Find out the magnitude of the vector.  The magnitude of any vector is the square root of the sum of squares of its direction cosines. Magnitude, |a| = a = √(x2 + y2 + z2) ------- (2)

From the given vector, x = 2; y = 3 and z = 4. Substitute the values in equation (2).

Magnitude, |a| = a = √(22 + 32 + 42) = √(4 + 9 + 16) = √(29) ----------(3)

Step 2: Dividing the given vector by its magnitude. Unit vector = Vector/Magnitude Hence, â = a/|a| = (xi + yj + zk)/√(x2 + y2 + z2).

Substituting values from equation (1) and (3) â = (2i + 3j + 4k)/√(29)

Step 3: Representation

  • In Bracket form, â = ((2/√(29)), (3/√(29)), (4/√(29))
  • As a linear combination, â = 2i/√(29) + 3j/√(29) + 4k/√(29))
Read More: Position Vector

Things to Remember

  • Unit vectors have direction and unit magnitude.
  • Unit vector = Vector/Magnitude.
  • The unit vector derived from some vector points in its direction.
  • Multiplying a unit vector by some magnitude produces a general vector.
  • Any vector in the Cartesian Coordinate system can be represented as a linear combination of unit vectors that represent the axes of the system.
  • The value of a unit vector is obtained by dividing each of the direction cosines of the vector by its magnitude.

Previous Year Questions


Sample Questions

Ques 1. Find the unit vector in the direction of 4i + 3j. (3 Marks)

Ans. Let the given vector be ‘a’ a = 4i + 3j or (4,3)

Its magnitude is |a| = √(42 + 32) = √(16 + 9) = √(25) = 5 units.

Unit vector in the direction of a is â = a/|a| â = (4i + 3j)/5

Ques 2. Find the unit vector in the direction of 4i + 4j + 5k. (3 Marks)

Ans. Let the given vector be ‘a’ a = 4i + 4j + 5k or (4, 4, 5)

Its magnitude is |a| = √(42 + 42 + 52) = √(16 + 16 + 25) = √(57) units.

Unit vector in the direction of a is â = a/|a| â = (4i + 4j + 5k)/√(57)

Ques 3. Find the unit vector of the resultant of u = (4, -5, 9) and v = (-3, 8, 2). (3 Marks)

Ans. Let the sum of the given vectors be a = u + v a = (4-3, -5+8, 9+2) = (1, 3, 11) a = i + 3j + 11k

Its magnitude is |a| = √(12 + 32 + 112) = √(1 + 9 + 121) = √131 units.

The unit vector of a is â = a/|a| â = (i + 3j + 11k)/√131</p> <p><strong>

Ques 4. Find the unit vector in the direction of -4i + 3j. (3 Marks)

Ans. Let the given vector be ‘a’ a = -4i + 3j or (4,3)

Its magnitude is |a| = √((-4)2 + 32) = √(16 + 9) = √(25) = 5 units.

Unit vector in the direction of a is â = a/|a| â = (4i + 3j)/5

Ques 5. Find the unit vector in the direction of 64i. (3 Marks)

Ans. Let the given vector be ‘a’ a = 64i or (64)

Its magnitude is |a| = √(642) = √(4096) = 64 units.

Unit vector in the direction of a is â = a/|a| â = (64i)/64 = i

Ques 6. Find the magnitude of a = (4, 7). (2 Marks)

Ans.Let the given vector be ‘a’ a = 4i + 7j or (4, 7)

Its magnitude is |a| = √(42 + 72) = √(16 + 49) = √(65) units.

Ques 7. Find the magnitude of a = (5, 8, -12). (2 Marks)

Ans. Let the given vector be ‘a’ a = 5i + 8j - 12k or (5, 8, -12)

Its magnitude is |a| = √(52 + 82 + (-12)2) = √(25 + 64 + 144) = √(274) units.

Ques 8. Find the vector in the direction of 4i + 3j with a magnitude of 6 units. (3 Marks)

Ans. Let the given vector be ‘a’ a = 4i + 3j or (4,3)

Its magnitude is |a| = √(42 + 32) = √(16 + 9) = √(25) = 5 units.

The direction of a is â â = a/|a| â = (4i + 3j)/5

Let the vector in the direction of â with magnitude 6 units be b = 6*â b = 6*(4i + 3j)/5 = (24i + 18j)/5

Ques 9. Find the vector in the direction of 2i + 3j + 4k with a magnitude of (1/3) units. (3 Marks)

Ans. Let the given vector be ‘a’ a = 2i + 3j + 4k or (2, 3, 4)

Its magnitude is |a| = √(22 + 32 + 42) = √(4 + 9 + 16) = √(29) units.

The direction of a is â â = a/|a| â = (2i + 3j + 4k)/√(29)

Let the vector in the direction of â with magnitude (1/3) units be b = (1/3)*â b = (1/3)*(2i + 3j + 4k)/√(29) = (2i + 3j + 4k)/(3√(29))

Ques 10. Find the unit vector of the sum of u = (2, 3) and v = (-3, 4). (3 Marks)

Ans. Let the sum of the given vectors be a = u + v a = (2-3, 3+4) = (-1, 7) a = -i + 7j

Its magnitude is |a| = √((-1)2 + 72) = √(1 + 49) = √(50) units.

The unit vector of a is â = a/|a| â = (-i + 7j)/√50

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CBSE CLASS XII Related Questions

  • 1.
    (a) Consider the so-called ‘D-T reaction’ (Deuterium-Tritium reaction).
    In a thermonuclear fusion reactor, the following nuclear reaction occurs: \[ \ ^{2}_1 \text{H} + \ ^{3}_1 \text{H} \longrightarrow \ ^{4}_2 \text{He} + \ ^{1}_0 \text{n} + Q \] Find the amount of energy released in the reaction.
    % Given data Given:
    \( m\left(^{2}_1 \text{H}\right) = 2.014102 \, \text{u} \)
    \( m\left(^{3}_1 \text{H}\right) = 3.016049 \, \text{u} \)
    \( m\left(^{4}_2 \text{He}\right) = 4.002603 \, \text{u} \)
    \( m\left(^{1}_0 \text{n}\right) = 1.008665 \, \text{u} \)
    \( 1 \, \text{u} = 931 \, \text{MeV}/c^2 \)


      • 2.
        A rectangular glass slab ABCD (refractive index 1.5) is surrounded by a transparent liquid (refractive index 1.25) as shown in the figure. A ray of light is incident on face AB at an angle \(i\) such that it is refracted out grazing the face AD. Find the value of angle \(i\).
        A rectangular glass slab ABCD (refractive index 1.5)


          • 3.
            Answer the following giving reason:
            (a) All the photoelectrons do not eject with the same kinetic energy when monochromatic light is incident on a metal surface.
            (b) The saturation current in case (a) is different for different intensity.
            (c) If one goes on increasing the wavelength of light incident on a metal sur face, keeping its intensity constant, emission of photoelectrons stops at a certain wavelength for this metal.


              • 4.
                A parallel plate capacitor has plate area \( A \) and plate separation \( d \). Half of the space between the plates is filled with a material of dielectric constant \( K \) in two ways as shown in the figure. Find the values of the capacitance of the capacitors in the two cases. parallel plate capacitor


                  • 5.
                    Write the mathematical forms of three postulates of Bohr’s theory of the hydrogen atom. Using them prove that, for an electron revolving in the \( n \)-th orbit,
                    (a) the radius of the orbit is proportional to \( n^2 \), and
                    (b) the total energy of the atom is proportional to \( \frac{1}{n^2} \).


                      • 6.
                        Three batteries E1, E2, and E3 of emfs and internal resistances (4 V, 2 \(\Omega\)), (2 V, 4 \(\Omega\)) and (6 V, 2 \(\Omega\)) respectively are connected as shown in the figure. Find the values of the currents passing through batteries E1, E2, and E3.
                        Three batteries E1, E2, and E3 of emfs and internal resistances

                          CBSE CLASS XII Previous Year Papers

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