Two copper wires, of 1 m and 9 m respectively, have same resistance. Find their diameters in ratio.

The electrical resistance an electrical conductor has is known as the resistance to the passage of electric current via it.

  • A wire’s resistance is inversely proportional to area of the wire’s cross-section. It is also directly proportional to the wire’s length.
  • In case the diameter of wire increases, while length of the wire decreases, then the resistance of the wire lowers. Thus, as the diameter of the wire decreases while length of the wire increases, then the resistance of the wire increases.

The resistance of the conductor can be expressed as:

R = ρ l/A

Herein, the wire is 9 times longer than the first one. The resistance simultaneously increases as the length expands. Since the diameter of the wire is inversely linked to the resistance, it can be increased in order to maintain equivalent resistance. Now, since the area of the cross-section is considered proportional to the diameter, the resistance will be constant when diameter of the wire will be increased by three times.

Thus, their diameters will be in the 1:3 ratio.


Related Questions

  1. A Closed Coil Has 500 Turns Across Rectangular Frame Of Area 4.0 Cm2 With Resistance Of 500 Ohms. The Coil Is Plane Perpendicular To A Uniform Magnetic Field Of 0.2wb/M2. Find Amount Of Charge Through Coil If Turned Over (180 Degrees Rotation).
  2. If R, C And L Are Fundamental Quantities In A Circuit Like Resistance, Capacitance And Inductance In W, Then Find Dimensional Formula For Resistance And Capacitance.
  3. A Galvanometer Having Resistance 100 Ohms Shows Full Scale Deflection With Current 10 MA. Find Value Of Shunt To Convert It Into An Ammeter Of 10 Ampere Range.
  4. Resistance In Meter Bridge’s Two Arms Are 5 Ohms And R Ohms. When Resistance R Is Shunted With Equal Resistance, New Balance Point Becomes 1.6l1. Calculate R.
  5. In A Graph Between Current I And Voltage V, Find The Portion Corresponding To Negative Resistance.
  6. 1.0 M Rectangular Loop With A Sliding Connector Is In Uniform Magnetic Field 2t Perpendicular To Plane Of Loop. Resistance Is 2 Ohms. Two Resistances, 6 Ohms And 3 Ohms, Are Connected.
  7. A Circuit Consists Of A Battery Of 3 Cells (2 V Each), A Combination Of Three Resistors, 10 Ohm, 20 Ohm And 30 Ohm, Attached Parallelly, With Plug Key And Ammeter (In Series).
  8. To A Resistor With 10 Ohms, Sinusoidal Voltage V = 200 Sin 314t Is Applied. Calculate The Values Below.
  9. Two Identical Resistors With Resistances 15 Ohm Are Connected In Series And Parallel To A Battery Of 6 V. Calculate Ratio Of Power Consumed.
  10. For The Resistor Combination, Find The Equivalent Resistance Between M and N.
  11. Two Concentric Coplanar Circular Loops Of Wire (Resistance Per Unit Length 10 4 Ohms M-1) Have Diameters 0.2 M And 2 M. With Time-Varying Potential Difference Of (4+2.5t) Applied To Larger Loop, Find Current In Smaller One.

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CBSE CLASS XII Related Questions

  • 1.
    A circular coil of 100 turns and radius \( \left(\frac{10}{\sqrt{\pi}}\right) \, \text{cm}\) carrying current of \( 5.0 \, \text{A} \) is suspended vertically in a uniform horizontal magnetic field of \( 2.0 \, \text{T} \). The field makes an angle \( 30^\circ \) with the normal to the coil. Calculate:
    the magnetic dipole moment of the coil, and
    the magnitude of the counter torque that must be applied to prevent the coil from turning.


      • 2.
        Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

          • attract with a force \( \frac{F}{2} \)
          • repel with a force \( \frac{F}{2} \)
          • repel with a force \( F \)
          • attract with a force \( F \)

        • 3.
          Four long straight thin wires are held vertically at the corners A, B, C and D of a square of side \( a \), kept on a table and carry equal current \( I \). The wire at A carries current in upward direction whereas the current in the remaining wires flows in downward direction. The net magnetic field at the centre of the square will have the magnitude:

            • \( \dfrac{\mu_0 I}{\pi a} \) and directed along OC
            • \( \dfrac{\mu_0 I}{\pi a \sqrt{2}} \) and directed along OD
            • \( \dfrac{\mu_0 I \sqrt{2}}{\pi a} \) and directed along OB
            • \( \dfrac{2\mu_0 I}{\pi a} \) and directed along OA

          • 4.
            The energy of an electron in an orbit in hydrogen atom is \( -3.4 \, \text{eV} \). Its angular momentum in the orbit will be:

              • \( \dfrac{3h}{2\pi} \)
              • \( \dfrac{2h}{\pi} \)
              • \( \dfrac{h}{\pi} \)
              • \( \dfrac{h}{2\pi} \)

            • 5.
              The magnetic field in a plane electromagnetic wave travelling in glass (\( n = 1.5 \)) is given by \[ B_y = (2 \times 10^{-7} \text{ T}) \sin(\alpha x + 1.5 \times 10^{11} t) \] where \( x \) is in metres and \( t \) is in seconds. The value of \( \alpha \) is:

                • \( 0.5 \times 10^3 \, \text{m}^{-1} \)
                • \( 6.0 \times 10^2 \, \text{m}^{-1} \)
                • \( 7.5 \times 10^2 \, \text{m}^{-1} \)
                • \( 1.5 \times 10^3 \, \text{m}^{-1} \)

              • 6.
                In a Young's double-slit experiment, two waves each of intensity I superpose each other and produce an interference pattern. Prove that the resultant intensities at maxima and minima are 4I and zero respectively.

                  CBSE CLASS XII Previous Year Papers

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