CBSE Class 12 Physics Set 1 - (55/1/1) Question Paper 2026 with Solution PDF

CBSE CLASS XII Questions

• 1.

  A circular coil of 100 turns and radius \( \left(\frac{10}{\sqrt{\pi}}\right) \, \text{cm}\) carrying current of \( 5.0 \, \text{A} \) is suspended vertically in a uniform horizontal magnetic field of \( 2.0 \, \text{T} \). The field makes an angle \( 30^\circ \) with the normal to the coil. Calculate:
  the magnetic dipole moment of the coil, and
  the magnitude of the counter torque that must be applied to prevent the coil from turning.

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• 2.

  The magnetic field in a plane electromagnetic wave travelling in glass (\( n = 1.5 \)) is given by \[ B_y = (2 \times 10^{-7} \text{ T}) \sin(\alpha x + 1.5 \times 10^{11} t) \] where \( x \) is in metres and \( t \) is in seconds. The value of \( \alpha \) is:

  • \( 0.5 \times 10^3 \, \text{m}^{-1} \)
    
  • \( 6.0 \times 10^2 \, \text{m}^{-1} \)
    
  • \( 7.5 \times 10^2 \, \text{m}^{-1} \)
    
  • \( 1.5 \times 10^3 \, \text{m}^{-1} \)
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• 3.

  A part of a wire carrying \( 2.0 \, \text{A} \) current and bent at \( 90^\circ \) at two points is placed in a region of uniform magnetic field \( \vec{B} = -0.50 \, \hat{k} \, \text{T} \), as shown in the figure. Calculate the magnitude of the net force acting on the wire.

  

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• 4.

  A 500 nm photon is incident normally on a perfectly reflecting surface and is reflected. The value of momentum transferred to the surface is:

  • \( 3.87 \times 10^{-43} \, \text{kg} \, \text{ms}^{-1} \)
    
  • \( 2.5 \times 10^{-30} \, \text{kg} \, \text{ms}^{-1} \)
    
  • \( 2.65 \times 10^{-27} \, \text{kg} \, \text{ms}^{-1} \)
    
  • \( 1.33 \times 10^{-27} \, \text{kg} \, \text{ms}^{-1} \)
    
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• 5.

  Determine the current in the \( 3 \, \Omega \) branch of a Wheatstone Bridge in the circuit shown in the figure.

  

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• 6.

  The energy of an electron in an orbit in hydrogen atom is \( -3.4 \, \text{eV} \). Its angular momentum in the orbit will be:

  • \( \dfrac{3h}{2\pi} \)
    
  • \( \dfrac{2h}{\pi} \)
    
  • \( \dfrac{h}{\pi} \)
    
  • \( \dfrac{h}{2\pi} \)
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