CBSE Class 12 Physics Compartment Question Paper 2025 (Available):Download Solution with Answer Key

CBSE CLASS XII Questions

• 1.

  A charged particle is moving in a circular path with velocity \( V \) in a uniform magnetic field \( \vec{B} \). It is made to pass through a sheet of lead and as a consequence, it looses one half of its kinetic energy without change in its direction. How will (1) the radius of its path change? (2) its time period of revolution change?

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• 2.

  Two conductors A and B of the same material have their lengths in the ratio 1:2 and radii in the ratio 2:3. If they are connected in parallel across a battery, the ratio \( \frac{v_A}{v_B} \) of the drift velocities of electrons in them will be:

  • 2
    
  • \( \frac{1}{2} \)
    
  • \( \frac{3}{2} \)
    
  • \( \frac{8}{9} \)
    
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• 3.

  A proton moving with velocity \( V \) in a non-uniform magnetic field traces a path as shown in the figure. The path followed by the proton is always in the plane of the paper. What is the direction of the magnetic field in the region near points P, Q, and R? What can you say about relative magnitude of magnetic fields at these points?
  

  

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• 4.

  A current carrying circular loop of area A produces a magnetic field \( B \) at its centre. Show that the magnetic moment of the loop is \( \frac{2BA}{\mu_0} \sqrt{\frac{A}{\pi}} \).

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• 5.

  In a circular loop of radius \( R \), current \( I \) enters at point \( A \) and exits at point \( B \), as shown in the figure. The value of the magnetic field at the centre \( O \) of the loop is:

  

  • \( \dfrac{\mu_0 I}{R} \)
  • zero
  • \( \dfrac{\mu_0 I}{2R} \)
  • \( \dfrac{\mu_0 I}{4R} \)
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• 6.

  Derive an expression for the torque acting on a rectangular current loop suspended in a uniform magnetic field.

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