CBSE Class 12 2025 Mathematics Set-1 (Available): Download Answer Key and Solution PDF

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Sahaj Anand

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The CBSE Class 12th Board Mathematics exam was conducted on 8th March 2025 from 10:30 AM to 1:30 PM.

The Mathematics theory paper is worth 80 marks, and the internal assessment is worth 20 marks. The exam included key topics like algebra, calculus, probability, linear programming, vectors, and Three-Dimensional Geometry, which needed a solid conceptual understanding and problem-solving strategy.

Mathematics question paper includes MCQs (1 mark each), short-answer type questions (2 & 3 marks each), and long-answer type questions (4 & 6 marks each) making up 80 marks.

The examination tests analytical skills, logical reasoning, and problem-solving ability based on application.

The question paper and solution PDF will be available for download soon

CBSE Class 12 Mathematics Question Paper (65/2/1) with Solution PDF

CBSE Class 12 2025 Mathematics (65/2/1) Question Paper With Answer Key  download iconDownload Check Solution


Question 1:

The projection vector of vector \( \vec{a} \) on vector \( \vec{b} \) is:

  • (A) \( \left( \frac{\vec{a} \cdot \vec{b}}{|\vec{b}|^2} \right) \vec{b} \)
  • (B) \( \frac{\vec{a} \cdot \vec{b}}{|\vec{b}|} \)
  • (C) \( \frac{\vec{a} \cdot \vec{b}}{|\vec{a}|} \)
  • (D) \( \left( \frac{\vec{a} \cdot \vec{b}}{|\vec{a}|^2} \right) \vec{b} \)
Correct Answer: (1) \( \left( \frac{\vec{a} \cdot \vec{b}}{|\vec{b}|^2} \right) \vec{b} \)
View Solution

Question 2:

The function \( f(x) = x^2 - 4x + 6 \) is increasing in the interval:

  • (A) \( (0,2) \)
  • (B) \( (-\infty,2] \)
  • (C) \( [1,2] \)
  • (D) \( [2,\infty) \)
Correct Answer: (4) \( [2, \infty) \)
View Solution

Question 3:

If \( f(2a - x) = f(x) \), then \( \int_{0}^{2a} f(x) \,dx \) is:

  • (A) \( \int_{0}^{2a} f\left(\frac{x}{2}\right) dx \)
  • (B) \( \int_{0}^{a} f(x) dx \)
  • (C) \( 2 \int_{a}^{0} f(x) dx \)
  • (D) \( 2 \int_{0}^{a} f(x) dx \)
Correct Answer: (4) \( 2 \int_{0}^{a} f(x) dx \)
View Solution

Question 4:

If  is a symmetric matrix, then \( 2x + y \) is:

  • (A) \(-8\)
  • (B) \(0\)
  • (C) \(6\)
  • (D) \(8\)
Correct Answer: (2) \( 0 \)
View Solution

Step 1: Understanding Symmetric Matrices

A matrix \( A \) is symmetric if:
\[ A^T = A \]

which means that the elements across the main diagonal are equal:
\[ A_{ij} = A_{ji}. \]

Step 2: Equating Corresponding Elements

The given matrix:


is symmetric, so we equate corresponding elements:

1. \( A_{12} = A_{21} \Rightarrow 12 = 6x \)

\[ 6x = 12 \quad \Rightarrow \quad x = 2. \]

2. \( A_{13} = A_{31} \Rightarrow 4y = 8x \)

Substituting \( x = 2 \):

\[ 4y = 8(2) = 16. \]

\[ y = \frac{16}{4} = 4. \]

Step 3: Compute \( 2x + y \)
\[ 2x + y = 2(2) + 4 = 4 + 4 = 8. \]

Thus, the correct answer is: 8 Quick Tip: For a symmetric matrix \( A \), the condition \( A_{ij} = A_{ji} \) helps in finding unknown variables. Always check elements across the main diagonal.


Question 5:

If \( y = \sin^{-1}x \), where \( -1 \leq x \leq 0 \), then the range of \( y \) is:

  • (A) \( \left( -\frac{\pi}{2}, 0 \right) \)
  • (B) \( \left[ -\frac{\pi}{2}, 0 \right] \)
  • (C) \( \left[ -\frac{\pi}{2}, 0 \right) \)
  • (D) \( \left( -\frac{\pi}{2}, 0 \right] \)
Correct Answer: (2) \( \left[ -\frac{\pi}{2}, 0 \right] \)
View Solution

Step 1: Understanding the Function

The function \( y = \sin^{-1}x \) is the inverse sine function. The domain of \( \sin^{-1}x \) is:
\[ [-1, 1] \]

Its range is:
\[ \left[ -\frac{\pi}{2}, \frac{\pi}{2} \right] \]

Step 2: Restrict the Domain

In the given problem, the domain is restricted to:
\[ -1 \leq x \leq 0 \]

Step 3: Finding the Range Corresponding to the Given Domain

- At \( x = -1 \), \( y = \sin^{-1}(-1) = -\frac{\pi}{2} \).
- At \( x = 0 \), \( y = \sin^{-1}(0) = 0 \).

Since the sine inverse function is continuous and strictly increasing, the range is:
\[ \left[ -\frac{\pi}{2}, 0 \right] \]

Step 4: Conclusion

The correct answer is:
\[ \left[ -\frac{\pi}{2}, 0 \right] \] Quick Tip: For the inverse sine function \( \sin^{-1}x \): - Domain: \( [-1, 1] \) - Range: \( \left[ -\frac{\pi}{2}, \frac{\pi}{2} \right] \) Be mindful of the given domain to determine the appropriate range.


Question 6:

If a line makes angles of \( \frac{3\pi}{4}, -\frac{\pi}{3} \), and \( \theta \) with the positive directions of \(x\)-, \(y\)-, and \(z\)-axis respectively, then \( \theta \) is:

  • (A) \( -\frac{\pi}{3} \) only
  • (B) \( \frac{\pi}{3} \) only
  • (C) \( \frac{\pi}{6} \)
  • (D) \( \pm \frac{\pi}{3} \)
Correct Answer: (D) \( \pm \frac{\pi}{3} \)
View Solution

Question 7:

If \( E \) and \( F \) are two events such that \( P(E) > 0 \) and \( P(F) \neq 1 \), then \( P(\overline{E}/\overline{F}) \) is:

  • (A) \( \frac{P(\overline{E})}{P(\overline{F})} \)
  • (B) \( 1 - P(\overline{E}/F) \)
  • (C) \( 1 - P(E/F) \)
  • (D) \( \frac{1 - P(E \cup F)}{P(\overline{F})} \)
Correct Answer: (C) \( 1 - P(E/F) \)
View Solution

Question 8:

Which of the following can be both a symmetric and skew-symmetric matrix?

  • (A) Unit Matrix
  • (B) Diagonal Matrix
  • (C) Null Matrix
  • (D) Row Matrix
Correct Answer: (C) Null Matrix
View Solution

Question 9:

The equation of a line parallel to the vector \( 3\hat{i} + \hat{j} + 2\hat{k} \) and passing through the point \( (4, -3, 7) \) is:

  • (A) \( x = 4t + 3, \, y = -3t + 1, \, z = 7t + 2 \)
  • (B) \( x = 3t + 4, \, y = t + 3, \, z = 2t + 7 \)
  • (C) \( x = 3t + 4, \, y = t - 3, \, z = 2t + 7 \)
  • (D) \( x = 3t + 4, \, y = -t + 3, \, z = 2t + 7 \)
Correct Answer: (C) \( x = 3t + 4, \, y = t - 3, \, z = 2t + 7 \)
View Solution

Question 10:

Four friends Abhay, Bina, Chhaya and Devesh were asked to simplify \[ 4AB + 3(AB + BA) - 4BA \]

where \( A \) and \( B \) are both matrices of order \( 2 \times 2 \). It is known that \( A \neq B \neq I \) and \( A^{-1} \neq B \).

Their answers are given as:

- Abhay : \( 6AB \)

- Bina : \( 7AB - BA \)

- Chhaya : \( 8AB \)

- Devesh : \( 7BA - AB \)

Who answered it correctly?

  • (A) Abhay
  • (B) Bina
  • (C) Chhaya
  • (D) Devesh
Correct Answer: (B) Bina
View Solution

Question 11:

A cylindrical tank of radius 10 cm is being filled with sugar at the rate of \( 100\pi \) cm\(^3\)/s. The rate at which the height of the sugar inside the tank is increasing is:

  • (A) 0.1 cm/s
  • (B) 0.5 cm/s
  • (C) 1 cm/s
  • (D) 1.1 cm/s
Correct Answer: (A) 0.1 cm/s
View Solution

Step 1: Volume of a Cylinder Formula

The volume \( V \) of a cylinder is given by:
\[ V = \pi r^2 h \]

Where:
- \( r = 10 \) cm (radius)
- \( h \) = height of the sugar in the tank (variable)
- \( V \) = volume of the sugar in the tank (dependent on time)


Step 2: Differentiate Both Sides with Respect to Time

Differentiating both sides with respect to \( t \):
\[ \frac{dV}{dt} = \pi r^2 \frac{dh}{dt} \]


Step 3: Substitute Known Values

Since \( \frac{dV}{dt} = 100\pi \) cm\(^3\)/s and \( r = 10 \) cm,
\[ 100\pi = \pi (10)^2 \frac{dh}{dt} \]
\[ 100\pi = 100\pi \frac{dh}{dt} \]

Dividing both sides by \( 100\pi \),
\[ \frac{dh}{dt} = 1 \div 10 = 0.1 \]


Step 4: Conclusion

The correct answer is:
\[ \textbf{(A) 0.1 cm/s} \] Quick Tip: In rate of change problems involving geometric shapes: - Differentiate the volume formula with respect to time. - Carefully substitute known values and solve for the required rate.


Question 12:

Let \( \vec{p} \) and \( \vec{q} \) be two unit vectors and \( \alpha \) be the angle between them. Then \( (\vec{p} + \vec{q}) \) will be a unit vector for what value of \( \alpha \)?

  • (A) \( \frac{\pi}{4} \)
  • (B) \( \frac{\pi}{3} \)
  • (C) \( \frac{\pi}{2} \)
  • (D) \( \frac{2\pi}{3} \)
Correct Answer: (B) \( \frac{\pi}{3} \)
View Solution

Step 1: Calculate the Magnitude of \( \vec{p} + \vec{q} \)

Given that \( \vec{p} \) and \( \vec{q} \) are unit vectors, we use the identity:
\[ |\vec{p} + \vec{q}|^2 = |\vec{p}|^2 + |\vec{q}|^2 + 2 |\vec{p}| |\vec{q}| \cos \alpha \]

Since \( |\vec{p}| = 1 \) and \( |\vec{q}| = 1 \),
\[ |\vec{p} + \vec{q}|^2 = 1^2 + 1^2 + 2(1)(1)\cos \alpha \]
\[ |\vec{p} + \vec{q}|^2 = 2 + 2\cos \alpha \]


Step 2: Condition for a Unit Vector

For \( \vec{p} + \vec{q} \) to be a unit vector,
\[ |\vec{p} + \vec{q}|^2 = 1 \]

Equating both expressions:
\[ 2 + 2\cos \alpha = 1 \]
\[ 2\cos \alpha = -1 \]
\[ \cos \alpha = -\frac{1}{2} \]


Step 3: Finding \( \alpha \)

From standard trigonometric values,
\[ \cos \frac{2\pi}{3} = -\frac{1}{2} \]

Thus,
\[ \alpha = \frac{2\pi}{3} \]


Step 4: Conclusion

The correct answer is:
\[ \textbf{(D) } \frac{2\pi}{3} \] Quick Tip: For two unit vectors \( \vec{p} \) and \( \vec{q} \), the relation \[ |\vec{p} + \vec{q}| = 1 \] leads to \( \cos \alpha = -\frac{1}{2} \), implying \( \alpha = \frac{2\pi}{3} \).


Question 13:

The line \( x = 1 + 5\mu, \, y = -5 + \mu, \, z = -6 - 3\mu \) passes through which of the following points?

  • (A) \( (1, -5, 6) \)
  • (B) \( (1, 5, 6) \)
  • (C) \( (1, -5, -6) \)
  • (D) \( (-1, -5, 6) \)
Correct Answer: (C) \( (1, -5, -6) \)
View Solution

Question 14:

If \( A \) denotes the set of continuous functions and \( B \) denotes the set of differentiable functions, then which of the following depicts the correct relation between set \( A \) and \( B \)?

  • (A) \( B \subset A \) (Differentiable functions are inside Continuous functions)
  • (B) \( A \subset B \) (Continuous functions are inside Differentiable functions)
  • (C) \( A \cap B \) (Intersection of Continuous and Differentiable)
  • (D) \( A \) and \( B \) are Disjoint Sets
Correct Answer: (A) \( B \subset A \)
View Solution

Question 15:

The area of the shaded region (figure) represented by the curves \(y = x^2\), \(0 \leq x \leq 2\), and the y-axis is given by:

  • (A) \( \int_{0}^{2} x^2 \, dx \)
  • (B) \( \int_{0}^{2} \sqrt{y} \, dy \)
  • (C) \( \int_{0}^{4} x^2 \, dx \)
  • (D) \( \int_{0}^{4} \sqrt{y} \, dy \)
Correct Answer: (D) \( \int_{0}^{4} \sqrt{y} \, dy \)
View Solution

Question 16:

A factory produces two products X and Y. The profit earned by selling X and Y is represented by the objective function \( Z = 5x + 7y \), where \( x \) and \( y \) are the number of units of X and Y respectively sold. Which of the following statement is correct?

  • (A) The objective function maximizes the difference of the profit earned from products X and Y.
  • (B) The objective function measures the total production of products X and Y.
  • (C) The objective function maximizes the combined profit earned from selling X and Y.
  • (D) The objective function ensures the company produces more of product X than product Y.
Correct Answer: (C) The objective function maximizes the combined profit earned from selling X and Y.
View Solution

Question 17:

If \( A \) and \( B \) are square matrices of order \( m \) such that \( A^2 - B^2 = (A - B)(A + B) \), then which of the following is always correct?

  • (A) \( A = B \)
  • (B) \( AB = BA \)
  • (C) \( A = 0 or B = 0 \)
  • (D) \( A = I or B = I \)
Correct Answer: (B) \( AB = BA \)
View Solution

Question 18:

If \( p \) and \( q \) are respectively the order and degree of the differential equation
\[ \frac{d}{dx} \left( \frac{dy}{dx} \right)^3 = 0 \]

then \( (p - q) \) is:

  • (A) 0
  • (B) 1
  • (C) 2
  • (D) 3
Correct Answer: (B) 1
View Solution

Question 19:

Assertion (A): \( A = diag [3, 5, 2] \) is a scalar matrix of order \( 3 \times 3 \).

Reason (R): If a diagonal matrix has all non-zero elements equal, it is known as a scalar matrix.

Correct Answer: (C) Assertion (A) is true but Reason (R) is false.
View Solution

Question 20:

Assertion (A): Every point of the feasible region of a Linear Programming Problem is an optimal solution.

Reason (R): The optimal solution for a Linear Programming Problem exists only at one or more corner point(s) of the feasible region.

Correct Answer: (C) Assertion (A) is false but Reason (R) is true.
View Solution

Question 21 (a):

A vector \( \vec{a} \) makes equal angles with all the three axes. If the magnitude of the vector is \( 5\sqrt{3} \) units, then find \( \vec{a} \).


OR Question 21 (b):

If \( \vec{a} \) and \( \vec{b} \) are position vectors of two points \( P \) and \( Q \) respectively, then find the position vector of a point \( R \) in \( QP \) produced such that \( QR = \frac{3}{2} QP \).


Question 22:

Evaluate:
\[ \int_{0}^{\pi/4} \sqrt{1 + \sin 2x} \, dx \]

View Solution

Step 1: Trigonometric Identity Transformation

We know the identity:
\[ \sin 2x = 2\sin x \cos x \]

Using the identity for \( \sin 2x \) in the integrand:
\[ \sqrt{1 + \sin 2x} = \sqrt{1 + 2\sin x \cos x} \]

Also, recall that:
\[ 1 + \sin 2x = (\sin x + \cos x)^2 \]

Thus,
\[ \sqrt{1 + \sin 2x} = |\sin x + \cos x| \]

Since in the given interval \( [0, \pi/4] \), both \( \sin x \) and \( \cos x \) are positive, the absolute value is not needed. Therefore,
\[ \sqrt{1 + \sin 2x} = \sin x + \cos x \]


Step 2: Integrating the Expression

Now,
\[ I = \int_{0}^{\pi/4} (\sin x + \cos x) \, dx \]

Breaking the integral:
\[ I = \int_{0}^{\pi/4} \sin x \, dx + \int_{0}^{\pi/4} \cos x \, dx \]

Both integrals are straightforward:
\[ \int \sin x \, dx = -\cos x \quad and \quad \int \cos x \, dx = \sin x \]

Now evaluate each term:
\[ I = \left[ -\cos x \right]_{0}^{\pi/4} + \left[ \sin x \right]_{0}^{\pi/4} \]
\[ I = \left( -\cos \frac{\pi}{4} + \cos 0 \right) + \left( \sin \frac{\pi}{4} - \sin 0 \right) \]
\[ I = \left( -\frac{1}{\sqrt{2}} + 1 \right) + \left( \frac{1}{\sqrt{2}} - 0 \right) \]
\[ I = \left( 1 - \frac{1}{\sqrt{2}} \right) + \frac{1}{\sqrt{2}} \]

The negative and positive terms cancel:
\[ I = 1 \]


Step 3: Conclusion

The evaluated integral is:
\[ \int_{0}^{\pi/4} \sqrt{1 + \sin 2x} \, dx = 1 \] Quick Tip: For integrals involving \( \sqrt{1 + \sin 2x} \), always try using the identity: \[ 1 + \sin 2x = (\sin x + \cos x)^2 \] This simplifies the expression effectively.


Question 23:

Find the values of \( a \) for which \( f(x) = \sin x - ax + b \) is increasing on \( \mathbb{R} \).


Question 24:

If \( \vec{a} \) and \( \vec{b} \) are two non-collinear vectors, then find \( x \) such that \( \vec{v} = (x - 2) \vec{a} + \vec{b} \) and \( \vec{p} = (3 + 2x) \vec{a} - 2\vec{b} \) are collinear.


Question 25 (a):

If \( x = e^{\frac{x}{y}} \), then prove that \( \frac{dy}{dx} = \frac{x - y}{x \log x} \).


OR Question 25 (b):

If \( f(x) = \begin{cases} 2x - 3 & if \, -3 \leq x \leq -2
x + 1 & if \, -2 < x \leq 0 \end{cases} \)

Check the differentiability of \( f(x) \) at \( x = -2 \).


Question 26 (a):

Solve the differential equation \( 2(y + 3) - xy \frac{dy}{dx} = 0 \); given \( y(1) = -2 \).


OR Question 26 (b):

Solve the following differential equation:
\[ (1 + x^2) \frac{dy}{dx} + 2xy = 4x^2 \]


Question 27:

Let \( R \) be a relation defined over \( \mathbb{N} \), where \( \mathbb{N} \) is the set of natural numbers, defined as " \( m R n \) if and only if \( m \) is a multiple of \( n \)", where \( m, n \in \mathbb{N} \). Find whether \( R \) is reflexive, symmetric, and transitive or not.


Question 28:

Solve the following linear programming problem graphically:

Minimise \( Z = x - 5y \)

Subject to the constraints:
\[ x - y \geq 0 \]
\[ -x + 2y \geq 2 \]
\[ x \geq 3, \quad y \leq 4, \quad y \geq 0 \]


Question 29 (a):

If \( y = \log \left( \sqrt{x} + \frac{1}{\sqrt{x}} \right)^2 \), then show that
\[ x(x + 1)^2 y_2 + (x + 1)^2 y_1 = 2 \]


OR Question 29 (b):

If \( x \sqrt{1 + y} + y \sqrt{1 + x} = 0 \), where \( -1 < x < 1 \) and \( x \neq y \), then prove that
\[ \frac{dy}{dx} = -\frac{1}{(1 + x)^2} \]


Question 30 (a):

A die with numbers 1 to 6 is biased such that \( P(2) = \frac{3}{10} \) and the probability of other numbers is equal. Find the mean of the number of times number 2 appears on the dice if the dice is thrown twice.


OR Question 30 (b):

Two dice are thrown. Defined are the following two events A and B:
\[ A = \{ (x, y) : x + y = 9 \} \quad and \quad B = \{ (x, y) : x \neq 3 \} \]

Where \( (x, y) \) denotes a point in the sample space.
Check if events A and B are independent or mutually exclusive.


Question 31:

Find:
\[ \int \frac{1}{x} \sqrt{\frac{x + a}{x - a}} \, dx \]


Question 32:

Using integration, find the area of the region bounded by the line \( y = 5x + 2 \), the \( x \)-axis, and the ordinates \( x = -2 \) and \( x = 2 \).


Question 33:

Find:
\[ I = \int \frac{x^2 + x + 1}{(x+2)(x^2+1)} \, dx \]


Question 34 (a):

Find the shortest distance between the lines:
\[ \frac{x + 1}{2} = \frac{y - 1}{1} = \frac{z - 9}{-3} \]
and \[ \frac{x - 3}{2} = \frac{y + 15}{-7} = \frac{z - 9}{5} \]


OR Question 34 (b):

Find the image \( A' \) of the point \( A(2, 1, 2) \) in the line
\[ \ell : \vec{r} = 4 \hat{i} + 2 \hat{j} + 2 \hat{k} + \lambda \left( \hat{i} - \hat{j} - \hat{k} \right) \]

Also, find the equation of the line joining \( A \) and \( A' \). Find the foot of the perpendicular from point A on the line \( \ell \).


Question 35 (a):

Given


Find \( AB \). Hence, solve the system of linear equations:
\[ x - y + z = 4 \] \[ x - 2y - 2z = 9 \] \[ 2x + y + 3z = 1 \]


OR Question 35 (b):

Given


Find \( A^{-1} \). Hence, solve the system of linear equations:
\[ x - 2y = 10 \] \[ 2x - y - z = 8 \] \[ -2y + z = 7 \]


Question 36:

A school is organizing a debate competition with participants as speakers \( S = \{S_1, S_2, S_3, \dots, S_n\} \) and these are judged by judges \( J = \{J_1, J_2, J_3, \dots, J_m\} \). Each speaker can be assigned one judge. Let \( R \) be a relation from set \( S \) to \( J \) defined as \( R = \{(x, y): x \in S, \, y \in J\} \) such that speaker \( x \) is judged by judge \( y \), where \( x \in S \) and \( y \in J \).



Based on the above, answer the following:

(i) How many relations can there be from \( S \) to \( J \)?

(ii) A student identifies a function from \( S \) to \( J \) as \( f = \{(S_1, J_1), (S_2, J_2), \dots, (S_n, J_n)\} \). Check if it is bijective.

(iii) (a) How many one-to-one functions can there be from set \( S \) to set \( J \)?

OR

(iii) (b) Another student considers a relation \( R_1 = \{(S_1, S_2), (S_3, S_4), \dots\} \) in set \( S \). Write minimum ordered pairs to be included in \( R_1 \) so that \( R_1 \) is reflexive but not symmetric.


Question 37:

Three persons viz. Amber, Bonzi and Comet are manufacturing cars which run on petrol and on battery as well. Their production share in the market is 30%, 30% and 10% respectively. Of their respective production capacities, 20%, 10% and 5% cars respectively are electric (or battery operated).




Based on the above, answer the following:

(i) (a) What is the probability that a randomly selected car is an electric car?

OR

(i) (b) What is the probability that a randomly selected car is a petrol car?

(ii) A car is selected at random and is found to be electric. What is the probability that it was manufactured by Comet?

(iii) A car is selected at random and is found to be electric. What is the probability that it was manufactured by Amber or Bonzi?


Question 38:

A small town is analyzing the pattern of a new street light installation. The lights are set up in such a way that the intensity of light at any point \( x \) metres from the start of the street can be modelled by \( f(x) = e^x \sin x \), where \( x \) is in metres.



Based on the above, answer the following:

(i) Find the intervals on which the function \( f(x) \) is increasing or decreasing, \( x \in [0, \pi] \).

(ii) Verify whether each critical point when \( x \in [0, \pi] \) is a point of local maximum, local minimum, or a point of inflection.



CBSE CLASS XII Questions

  • 1.
    The integrating factor of the differential equation \( (x + 2y^3) \frac{dy}{dx} = 2y \) is:

      • \( e^{y^2} \)
      • \( \frac{1}{\sqrt{y}} \)
      • \( e^{-\frac{1}{y^2}} \)
      • \( e^{y^2} \)

    • 2.
      If $M$ and $N$ are square matrices of order 3 such that $\det(M) = m$ and $MN = mI$, then $\det(N)$ is equal to :

        • $-1$
        • 1
        • $-m^2$
        • $m^2$

      • 3.

        Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.


          • 4.
            If \( \mathbf{a} \) and \( \mathbf{b} \) are position vectors of two points \( P \) and \( Q \) respectively, then find the position vector of a point \( R \) in \( QP \) produced such that \[ QR = \frac{3}{2} QP. \]


              • 5.
                Evaluate : \[ I = \int_0^{\frac{\pi}{4}} \frac{dx}{\cos^3 x \sqrt{2 \sin 2x}} \]


                  • 6.
                    Evaluate: $ \tan^{-1} \left[ 2 \sin \left( 2 \cos^{-1} \frac{\sqrt{3}}{2} \right) \right]$

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