The CBSE Class 12th Board Mathematics exam was conducted on 8th March 2025 from 10:30 AM to 1:30 PM.
The Mathematics theory paper is worth 80 marks, and the internal assessment is worth 20 marks. The exam included key topics like algebra, calculus, probability, linear programming, vectors, and Three-Dimensional Geometry, which needed a solid conceptual understanding and problem-solving strategy.
Mathematics question paper includes MCQs (1 mark each), short-answer type questions (2 & 3 marks each), and long-answer type questions (4 & 6 marks each) making up 80 marks.
The examination tests analytical skills, logical reasoning, and problem-solving ability based on application.
The question paper and solution PDF will be available for download soon
CBSE Class 12 Mathematics Question Paper (65/2/1) with Solution PDF
| CBSE Class 12 2025 Mathematics (65/2/1) Question Paper With Answer Key | Check Solution |

The projection vector of vector \( \vec{a} \) on vector \( \vec{b} \) is:
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The function \( f(x) = x^2 - 4x + 6 \) is increasing in the interval:
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If \( f(2a - x) = f(x) \), then \( \int_{0}^{2a} f(x) \,dx \) is:
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If
is a symmetric matrix, then \( 2x + y \) is:
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Step 1: Understanding Symmetric Matrices
A matrix \( A \) is symmetric if:
\[ A^T = A \]
which means that the elements across the main diagonal are equal:
\[ A_{ij} = A_{ji}. \]
Step 2: Equating Corresponding Elements
The given matrix:

is symmetric, so we equate corresponding elements:
1. \( A_{12} = A_{21} \Rightarrow 12 = 6x \)
\[ 6x = 12 \quad \Rightarrow \quad x = 2. \]
2. \( A_{13} = A_{31} \Rightarrow 4y = 8x \)
Substituting \( x = 2 \):
\[ 4y = 8(2) = 16. \]
\[ y = \frac{16}{4} = 4. \]
Step 3: Compute \( 2x + y \)
\[ 2x + y = 2(2) + 4 = 4 + 4 = 8. \]
Thus, the correct answer is: 8 Quick Tip: For a symmetric matrix \( A \), the condition \( A_{ij} = A_{ji} \) helps in finding unknown variables. Always check elements across the main diagonal.
If \( y = \sin^{-1}x \), where \( -1 \leq x \leq 0 \), then the range of \( y \) is:
View Solution
Step 1: Understanding the Function
The function \( y = \sin^{-1}x \) is the inverse sine function. The domain of \( \sin^{-1}x \) is:
\[ [-1, 1] \]
Its range is:
\[ \left[ -\frac{\pi}{2}, \frac{\pi}{2} \right] \]
Step 2: Restrict the Domain
In the given problem, the domain is restricted to:
\[ -1 \leq x \leq 0 \]
Step 3: Finding the Range Corresponding to the Given Domain
- At \( x = -1 \), \( y = \sin^{-1}(-1) = -\frac{\pi}{2} \).
- At \( x = 0 \), \( y = \sin^{-1}(0) = 0 \).
Since the sine inverse function is continuous and strictly increasing, the range is:
\[ \left[ -\frac{\pi}{2}, 0 \right] \]
Step 4: Conclusion
The correct answer is:
\[ \left[ -\frac{\pi}{2}, 0 \right] \] Quick Tip: For the inverse sine function \( \sin^{-1}x \): - Domain: \( [-1, 1] \) - Range: \( \left[ -\frac{\pi}{2}, \frac{\pi}{2} \right] \) Be mindful of the given domain to determine the appropriate range.
If a line makes angles of \( \frac{3\pi}{4}, -\frac{\pi}{3} \), and \( \theta \) with the positive directions of \(x\)-, \(y\)-, and \(z\)-axis respectively, then \( \theta \) is:
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If \( E \) and \( F \) are two events such that \( P(E) > 0 \) and \( P(F) \neq 1 \), then \( P(\overline{E}/\overline{F}) \) is:
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Which of the following can be both a symmetric and skew-symmetric matrix?
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The equation of a line parallel to the vector \( 3\hat{i} + \hat{j} + 2\hat{k} \) and passing through the point \( (4, -3, 7) \) is:
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Four friends Abhay, Bina, Chhaya and Devesh were asked to simplify \[ 4AB + 3(AB + BA) - 4BA \]
where \( A \) and \( B \) are both matrices of order \( 2 \times 2 \). It is known that \( A \neq B \neq I \) and \( A^{-1} \neq B \).
Their answers are given as:
- Abhay : \( 6AB \)
- Bina : \( 7AB - BA \)
- Chhaya : \( 8AB \)
- Devesh : \( 7BA - AB \)
Who answered it correctly?
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A cylindrical tank of radius 10 cm is being filled with sugar at the rate of \( 100\pi \) cm\(^3\)/s. The rate at which the height of the sugar inside the tank is increasing is:
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Step 1: Volume of a Cylinder Formula
The volume \( V \) of a cylinder is given by:
\[ V = \pi r^2 h \]
Where:
- \( r = 10 \) cm (radius)
- \( h \) = height of the sugar in the tank (variable)
- \( V \) = volume of the sugar in the tank (dependent on time)
Step 2: Differentiate Both Sides with Respect to Time
Differentiating both sides with respect to \( t \):
\[ \frac{dV}{dt} = \pi r^2 \frac{dh}{dt} \]
Step 3: Substitute Known Values
Since \( \frac{dV}{dt} = 100\pi \) cm\(^3\)/s and \( r = 10 \) cm,
\[ 100\pi = \pi (10)^2 \frac{dh}{dt} \]
\[ 100\pi = 100\pi \frac{dh}{dt} \]
Dividing both sides by \( 100\pi \),
\[ \frac{dh}{dt} = 1 \div 10 = 0.1 \]
Step 4: Conclusion
The correct answer is:
\[ \textbf{(A) 0.1 cm/s} \] Quick Tip: In rate of change problems involving geometric shapes: - Differentiate the volume formula with respect to time. - Carefully substitute known values and solve for the required rate.
Let \( \vec{p} \) and \( \vec{q} \) be two unit vectors and \( \alpha \) be the angle between them. Then \( (\vec{p} + \vec{q}) \) will be a unit vector for what value of \( \alpha \)?
View Solution
Step 1: Calculate the Magnitude of \( \vec{p} + \vec{q} \)
Given that \( \vec{p} \) and \( \vec{q} \) are unit vectors, we use the identity:
\[ |\vec{p} + \vec{q}|^2 = |\vec{p}|^2 + |\vec{q}|^2 + 2 |\vec{p}| |\vec{q}| \cos \alpha \]
Since \( |\vec{p}| = 1 \) and \( |\vec{q}| = 1 \),
\[ |\vec{p} + \vec{q}|^2 = 1^2 + 1^2 + 2(1)(1)\cos \alpha \]
\[ |\vec{p} + \vec{q}|^2 = 2 + 2\cos \alpha \]
Step 2: Condition for a Unit Vector
For \( \vec{p} + \vec{q} \) to be a unit vector,
\[ |\vec{p} + \vec{q}|^2 = 1 \]
Equating both expressions:
\[ 2 + 2\cos \alpha = 1 \]
\[ 2\cos \alpha = -1 \]
\[ \cos \alpha = -\frac{1}{2} \]
Step 3: Finding \( \alpha \)
From standard trigonometric values,
\[ \cos \frac{2\pi}{3} = -\frac{1}{2} \]
Thus,
\[ \alpha = \frac{2\pi}{3} \]
Step 4: Conclusion
The correct answer is:
\[ \textbf{(D) } \frac{2\pi}{3} \] Quick Tip: For two unit vectors \( \vec{p} \) and \( \vec{q} \), the relation \[ |\vec{p} + \vec{q}| = 1 \] leads to \( \cos \alpha = -\frac{1}{2} \), implying \( \alpha = \frac{2\pi}{3} \).
The line \( x = 1 + 5\mu, \, y = -5 + \mu, \, z = -6 - 3\mu \) passes through which of the following points?
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If \( A \) denotes the set of continuous functions and \( B \) denotes the set of differentiable functions, then which of the following depicts the correct relation between set \( A \) and \( B \)?
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The area of the shaded region (figure) represented by the curves \(y = x^2\), \(0 \leq x \leq 2\), and the y-axis is given by:
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A factory produces two products X and Y. The profit earned by selling X and Y is represented by the objective function \( Z = 5x + 7y \), where \( x \) and \( y \) are the number of units of X and Y respectively sold. Which of the following statement is correct?
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If \( A \) and \( B \) are square matrices of order \( m \) such that \( A^2 - B^2 = (A - B)(A + B) \), then which of the following is always correct?
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If \( p \) and \( q \) are respectively the order and degree of the differential equation
\[ \frac{d}{dx} \left( \frac{dy}{dx} \right)^3 = 0 \]
then \( (p - q) \) is:
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Assertion (A): \( A = diag [3, 5, 2] \) is a scalar matrix of order \( 3 \times 3 \).
Reason (R): If a diagonal matrix has all non-zero elements equal, it is known as a scalar matrix.
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Assertion (A): Every point of the feasible region of a Linear Programming Problem is an optimal solution.
Reason (R): The optimal solution for a Linear Programming Problem exists only at one or more corner point(s) of the feasible region.
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A vector \( \vec{a} \) makes equal angles with all the three axes. If the magnitude of the vector is \( 5\sqrt{3} \) units, then find \( \vec{a} \).
If \( \vec{a} \) and \( \vec{b} \) are position vectors of two points \( P \) and \( Q \) respectively, then find the position vector of a point \( R \) in \( QP \) produced such that \( QR = \frac{3}{2} QP \).
Evaluate:
\[ \int_{0}^{\pi/4} \sqrt{1 + \sin 2x} \, dx \]
View Solution
Step 1: Trigonometric Identity Transformation
We know the identity:
\[ \sin 2x = 2\sin x \cos x \]
Using the identity for \( \sin 2x \) in the integrand:
\[ \sqrt{1 + \sin 2x} = \sqrt{1 + 2\sin x \cos x} \]
Also, recall that:
\[ 1 + \sin 2x = (\sin x + \cos x)^2 \]
Thus,
\[ \sqrt{1 + \sin 2x} = |\sin x + \cos x| \]
Since in the given interval \( [0, \pi/4] \), both \( \sin x \) and \( \cos x \) are positive, the absolute value is not needed. Therefore,
\[ \sqrt{1 + \sin 2x} = \sin x + \cos x \]
Step 2: Integrating the Expression
Now,
\[ I = \int_{0}^{\pi/4} (\sin x + \cos x) \, dx \]
Breaking the integral:
\[ I = \int_{0}^{\pi/4} \sin x \, dx + \int_{0}^{\pi/4} \cos x \, dx \]
Both integrals are straightforward:
\[ \int \sin x \, dx = -\cos x \quad and \quad \int \cos x \, dx = \sin x \]
Now evaluate each term:
\[ I = \left[ -\cos x \right]_{0}^{\pi/4} + \left[ \sin x \right]_{0}^{\pi/4} \]
\[ I = \left( -\cos \frac{\pi}{4} + \cos 0 \right) + \left( \sin \frac{\pi}{4} - \sin 0 \right) \]
\[ I = \left( -\frac{1}{\sqrt{2}} + 1 \right) + \left( \frac{1}{\sqrt{2}} - 0 \right) \]
\[ I = \left( 1 - \frac{1}{\sqrt{2}} \right) + \frac{1}{\sqrt{2}} \]
The negative and positive terms cancel:
\[ I = 1 \]
Step 3: Conclusion
The evaluated integral is:
\[ \int_{0}^{\pi/4} \sqrt{1 + \sin 2x} \, dx = 1 \] Quick Tip: For integrals involving \( \sqrt{1 + \sin 2x} \), always try using the identity: \[ 1 + \sin 2x = (\sin x + \cos x)^2 \] This simplifies the expression effectively.
Find the values of \( a \) for which \( f(x) = \sin x - ax + b \) is increasing on \( \mathbb{R} \).
If \( \vec{a} \) and \( \vec{b} \) are two non-collinear vectors, then find \( x \) such that \( \vec{v} = (x - 2) \vec{a} + \vec{b} \) and \( \vec{p} = (3 + 2x) \vec{a} - 2\vec{b} \) are collinear.
If \( x = e^{\frac{x}{y}} \), then prove that \( \frac{dy}{dx} = \frac{x - y}{x \log x} \).
If \( f(x) = \begin{cases} 2x - 3 & if \, -3 \leq x \leq -2
x + 1 & if \, -2 < x \leq 0 \end{cases} \)
Check the differentiability of \( f(x) \) at \( x = -2 \).
Solve the differential equation \( 2(y + 3) - xy \frac{dy}{dx} = 0 \); given \( y(1) = -2 \).
Solve the following differential equation:
\[ (1 + x^2) \frac{dy}{dx} + 2xy = 4x^2 \]
Let \( R \) be a relation defined over \( \mathbb{N} \), where \( \mathbb{N} \) is the set of natural numbers, defined as " \( m R n \) if and only if \( m \) is a multiple of \( n \)", where \( m, n \in \mathbb{N} \). Find whether \( R \) is reflexive, symmetric, and transitive or not.
Solve the following linear programming problem graphically:
Minimise \( Z = x - 5y \)
Subject to the constraints:
\[ x - y \geq 0 \]
\[ -x + 2y \geq 2 \]
\[ x \geq 3, \quad y \leq 4, \quad y \geq 0 \]
If \( y = \log \left( \sqrt{x} + \frac{1}{\sqrt{x}} \right)^2 \), then show that
\[ x(x + 1)^2 y_2 + (x + 1)^2 y_1 = 2 \]
If \( x \sqrt{1 + y} + y \sqrt{1 + x} = 0 \), where \( -1 < x < 1 \) and \( x \neq y \), then prove that
\[ \frac{dy}{dx} = -\frac{1}{(1 + x)^2} \]
A die with numbers 1 to 6 is biased such that \( P(2) = \frac{3}{10} \) and the probability of other numbers is equal. Find the mean of the number of times number 2 appears on the dice if the dice is thrown twice.
Two dice are thrown. Defined are the following two events A and B:
\[ A = \{ (x, y) : x + y = 9 \} \quad and \quad B = \{ (x, y) : x \neq 3 \} \]
Where \( (x, y) \) denotes a point in the sample space.
Check if events A and B are independent or mutually exclusive.
Find:
\[ \int \frac{1}{x} \sqrt{\frac{x + a}{x - a}} \, dx \]
Using integration, find the area of the region bounded by the line \( y = 5x + 2 \), the \( x \)-axis, and the ordinates \( x = -2 \) and \( x = 2 \).
Find:
\[ I = \int \frac{x^2 + x + 1}{(x+2)(x^2+1)} \, dx \]
Find the shortest distance between the lines:
\[ \frac{x + 1}{2} = \frac{y - 1}{1} = \frac{z - 9}{-3} \]
and \[ \frac{x - 3}{2} = \frac{y + 15}{-7} = \frac{z - 9}{5} \]
Find the image \( A' \) of the point \( A(2, 1, 2) \) in the line
\[ \ell : \vec{r} = 4 \hat{i} + 2 \hat{j} + 2 \hat{k} + \lambda \left( \hat{i} - \hat{j} - \hat{k} \right) \]
Also, find the equation of the line joining \( A \) and \( A' \). Find the foot of the perpendicular from point A on the line \( \ell \).
Given

Find \( AB \). Hence, solve the system of linear equations:
\[ x - y + z = 4 \] \[ x - 2y - 2z = 9 \] \[ 2x + y + 3z = 1 \]
Given

Find \( A^{-1} \). Hence, solve the system of linear equations:
\[ x - 2y = 10 \] \[ 2x - y - z = 8 \] \[ -2y + z = 7 \]
A school is organizing a debate competition with participants as speakers \( S = \{S_1, S_2, S_3, \dots, S_n\} \) and these are judged by judges \( J = \{J_1, J_2, J_3, \dots, J_m\} \). Each speaker can be assigned one judge. Let \( R \) be a relation from set \( S \) to \( J \) defined as \( R = \{(x, y): x \in S, \, y \in J\} \) such that speaker \( x \) is judged by judge \( y \), where \( x \in S \) and \( y \in J \).
Based on the above, answer the following:
(i) How many relations can there be from \( S \) to \( J \)?
(ii) A student identifies a function from \( S \) to \( J \) as \( f = \{(S_1, J_1), (S_2, J_2), \dots, (S_n, J_n)\} \). Check if it is bijective.
(iii) (a) How many one-to-one functions can there be from set \( S \) to set \( J \)?
OR
(iii) (b) Another student considers a relation \( R_1 = \{(S_1, S_2), (S_3, S_4), \dots\} \) in set \( S \). Write minimum ordered pairs to be included in \( R_1 \) so that \( R_1 \) is reflexive but not symmetric.
Three persons viz. Amber, Bonzi and Comet are manufacturing cars which run on petrol and on battery as well. Their production share in the market is 30%, 30% and 10% respectively. Of their respective production capacities, 20%, 10% and 5% cars respectively are electric (or battery operated).
Based on the above, answer the following:
(i) (a) What is the probability that a randomly selected car is an electric car?
OR
(i) (b) What is the probability that a randomly selected car is a petrol car?
(ii) A car is selected at random and is found to be electric. What is the probability that it was manufactured by Comet?
(iii) A car is selected at random and is found to be electric. What is the probability that it was manufactured by Amber or Bonzi?
A small town is analyzing the pattern of a new street light installation. The lights are set up in such a way that the intensity of light at any point \( x \) metres from the start of the street can be modelled by \( f(x) = e^x \sin x \), where \( x \) is in metres.
Based on the above, answer the following:
(i) Find the intervals on which the function \( f(x) \) is increasing or decreasing, \( x \in [0, \pi] \).
(ii) Verify whether each critical point when \( x \in [0, \pi] \) is a point of local maximum, local minimum, or a point of inflection.



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