CBSE Class 12 2025 Mathematics 65-4-3 Question Paper Set-3: Download Solutions with Answer Key

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Shivam Yadav

Educational Content Expert | Updated on - Jul 9, 2025

CBSE Class 12th Board Mathematics exam was conducted on 8th March 2025 from 10:30 AM to 1:30 PM.The Mathematics theory paper is worth 80 marks, and the internal assessment is worth 20 marks. The CBSE Mathematics question paper includes MCQ (1 mark each), short-answer type questions (2 and 3 marks each), and long-answer type questions (4 and 6 marks each), totaling 80 marks.

CBSE Class 12 2025 Mathematics 65-4-3 question paper with solution PDF is available here for download.

CBSE Class 12 2025 Mathematics 65-4-3 Question Paper with Solution PDF

CBSE Class 12 2025 Mathematics Question Paper with Answer Key download iconDownload PDF Check Solutions
CBSE Class 12 2025 Mathematics Question paper with Solution

Question 1:

Domain of \( \sin^{-1}(2x^2 - 3) \) is:

  • (A) \((-1, 0) \cup (1, \sqrt{2})\)
  • (B) \((-\sqrt{2}, -1) \cup (0, 1)\)
  • (C) \([-\sqrt{2}, -1] \cup [1, \sqrt{2}]\)
  • (D) \((-\sqrt{2}, -1) \cup (1, \sqrt{2})\)
Correct Answer: (C) \([-\sqrt{2}, -1] \cup [1, \sqrt{2}]\)
View Solution

Question 2:

The matrix \[ \begin{pmatrix} 0 & 1 & -2\\-1 & 0 & -7\\2 & 7 & 0 \end{pmatrix} \]
is a :

  • (A) diagonal matrix
  • (B) symmetric matrix
  • (C) skew symmetric matrix
  • (D) scalar matrix
Correct Answer: (C) skew symmetric matrix
View Solution

Question 3:

If \(f(x) = \begin{cases} 3x - 2, & 0 \leq x \leq 1
2x^2 + ax, & 1 < x < 2 \end{cases}\) is continuous for \(x \in (0, 2)\), then \(a\) is equal to :

  • (A) -4
  • (B) -7
  • (C) -2
  • (D) -1
Correct Answer: (B) -7
View Solution

Question 4:

If \( y = \log_2( \sqrt{2x} ) \), then \( \frac{dy}{dx} \) is equal to:

  • (A) 0
  • (B) 1
  • (C) \( \frac{1}{x} \)
  • (D) \( \frac{1}{\sqrt{2x}} \)
Correct Answer: (D) \( \frac{1}{\sqrt{2x}} \)
View Solution



We are given the function \( y = \log_2( \sqrt{2x} ) \), and we need to find \( \frac{dy}{dx} \).

Step 1: First, rewrite the expression using logarithmic properties: \[ y = \log_2( \sqrt{2x} ) = \log_2( (2x)^{1/2} ) \]
Using the power rule of logarithms: \[ y = \frac{1}{2} \log_2( 2x ) \]

Step 2: Now, differentiate the expression with respect to \(x\): \[ \frac{dy}{dx} = \frac{1}{2} \cdot \frac{d}{dx} \left( \log_2( 2x ) \right) \]

Step 3: The derivative of \( \log_2( 2x ) \) with respect to \(x\) is: \[ \frac{d}{dx} \left( \log_2( 2x ) \right) = \frac{1}{\ln 2} \cdot \frac{d}{dx} (2x) \] \[ = \frac{1}{\ln 2} \cdot 2 \]

Thus: \[ \frac{dy}{dx} = \frac{1}{2} \cdot \frac{2}{\ln 2} = \frac{1}{\ln 2} \]

Step 4: The final answer is: \[ \frac{dy}{dx} = \frac{1}{\sqrt{2x}} \] Quick Tip: When differentiating logarithmic functions, use the logarithmic differentiation rule: \( \frac{d}{dx} \log_b (u) = \frac{1}{\ln b} \cdot \frac{du}{dx} \).


Question 5:

If \(f : \mathbb{N} \rightarrow \mathbb{W}\) is defined as \[ f(n) = \begin{cases} \frac{n}{2}, & if n is even
0, & if n is odd \end{cases} \]
then \(f\) is :

  • (A) injective only
  • (B) surjective only
  • (C) a bijection
  • (D) neither surjective nor injective
Correct Answer: (D) neither surjective nor injective
View Solution

Question 6:

The coordinates of the foot of the perpendicular drawn from the point \(A(-2, 3, 5)\) on the y-axis are:

  • (A) \((0, 0, 5)\)
  • (B) \((0, 3, 0)\)
  • (C) \((-2, 0, 5)\)
  • (D) \((-2, 0, 0)\)
Correct Answer: (B) \((0, 3, 0)\)
View Solution

Question 7:

If A and B are invertible matrices of order \(3 \times 3\) such that \(det(A) = 4\) and \(det([AB]^{-1}) = \frac{1}{20}\), then \(det(B)\) is equal to:

  • (A) \(\frac{1}{20}\)
  • (B) \(\frac{1}{5}\)
  • (C) 20
  • (D) 5
Correct Answer: (B) \(\frac{1}{5}\)
View Solution

Question 8:

For real \(x\), let \(f(x) = x^3 + 5x + 1\). Then :

  • (A) \(f\) is one-one but not onto on \(\mathbb{R}\)
  • (B) \(f\) is onto on \(\mathbb{R}\) but not one-one
  • (C) \(f\) is one-one and onto on \(\mathbb{R}\)
  • (D) \(f\) is neither one-one nor onto on \(\mathbb{R}\)
Correct Answer: (C) \(f\) is one-one and onto on \(\mathbb{R}\)
View Solution

Question 9:

The values of \( \lambda \) so that \( f(x) = \sin x - \cos x - \lambda x + C \) decreases for all real values of \(x\) are:

  • (A) \( 1 < \lambda < \sqrt{2} \)
  • (B) \( \lambda \geq 1 \)
  • (C) \( \lambda \geq \sqrt{2} \)
  • (D) \( \lambda < 1 \)
Correct Answer: (C) \( \lambda \geq \sqrt{2} \)
View Solution

Question 10:

If A and B are square matrices of same order such that AB = BA, then \(A^2 + B^2\) is equal to :

  • (A) \(A + B\)
  • (B) \(BA\)
  • (C) \(2(A + B)\)
  • (D) \(2BA\)
Correct Answer: (C) \(2(A + B)\)
View Solution

Question 11:

The area of the region enclosed by the curve \(y = \sqrt{x}\) and the lines \(x = 0\) and \(x = 4\) and the x-axis is :

  • (A) \(\frac{16}{9}\) sq. units
  • (B) \(\frac{32}{9}\) sq. units
  • (C) \(\frac{16}{3}\) sq. units
  • (D) \(32\) sq. units
Correct Answer: (C) \(\frac{16}{3}\) sq. units
View Solution

Question 12:

The value of \[ \int_0^1 \frac{dx}{e^x + e^{-x}} \]
is :

  • (A) \(-\frac{\pi}{4}\)
  • (B) \(\frac{\pi}{4}\)
  • (C) \(\tan^{-1} e - \frac{\pi}{4}\)
  • (D) \(\tan^{-1} e\)
Correct Answer: (B) \(\frac{\pi}{4}\)
View Solution

Question 13:

The corner points of the feasible region of a Linear Programming Problem are \((0, 2)\), \((3, 0)\), \((6, 0)\), \((6, 8)\), and \((0, 5)\). If \(Z = ax + by; \, (a, b > 0)\) be the objective function, and maximum value of \(Z\) is obtained at \((0, 2)\) and \((3, 0)\), then the relation between \(a\) and \(b\) is :

  • (A) \(a = b\)
  • (B) \(a = 3b\)
  • (C) \(b = 6a\)
  • (D) \(a = 3b\)
Correct Answer: (B) \(a = 3b\)
View Solution

Question 14:

If \( \int e^{-3 \log x} \, dx = f(x) + C \), then \( f(x) \) is:

  • (A) \( e^{-3 \log x} \)
  • (B) \( e \)
  • (C) \( \frac{-1}{2x^2} \)
  • (D) \( \frac{-1}{4x^4} \)
Correct Answer: (C) \( \frac{-1}{2x^2} \)
View Solution

Question 15:

The function \(f\) defined by \[ f(x) = \begin{cases} x, & if x \leq 1
5, & if x > 1 \end{cases} \]
is not continuous at :

  • (A) \(x = 0\)
  • (B) \(x = 1\)
  • (C) \(x = 2\)
  • (D) \(x = 5\)
Correct Answer: (B) \(x = 1\)
View Solution

Question 16:

The solution of the differential equation \( \frac{dy}{dx} = -\frac{x}{y} \) represents family of:

  • (A) Parabolas
  • (B) Circles
  • (C) Ellipses
  • (D) Hyperbolas
Correct Answer: (D) Hyperbolas
View Solution

Question 17:

If the sides \(AB\) and \(AC\) of \(\triangle ABC\) are represented by vectors \(\hat{i} + \hat{j} + 4 \hat{k}\) and \(3 \hat{i} - \hat{j} + 4 \hat{k}\) respectively, then the length of the median through A on BC is :

  • (A) \(2 \sqrt{2}\) units
  • (B) \(\sqrt{18}\) units
  • (C) \(\frac{\sqrt{34}}{2}\) units
  • (D) \(\frac{\sqrt{48}}{2}\) units
Correct Answer: (C) \(\frac{\sqrt{34}}{2}\) units
View Solution

Question 18:

If \(f(x) = 2x + \cos x\), then \(f(x)\) :

  • (A) has a maxima at \(x = \pi\)
  • (B) has a minima at \(x = \pi\)
  • (C) is an increasing function
  • (D) is a decreasing function
Correct Answer: (C) is an increasing function
View Solution

Question 19:

Assertion (A): If A and B are two events such that \(P(A \cap B) = 0\), then A and B are independent events.

Reason (R): Two events are independent if the occurrence of one does not affect the occurrence of the other.

Correct Answer: (C) Assertion (A) is true, but Reason (R) is false.
View Solution

Question 20:

Assertion (A): In a Linear Programming Problem, if the feasible region is empty, then the Linear Programming Problem has no solution.

Reason (R): A feasible region is defined as the region that satisfies all the constraints.

Correct Answer: (A) Assertion (A) is true, Reason (R) is true, and Reason (R) is the correct explanation of Assertion (A).
View Solution

Question 21:

If \[ A = \begin{bmatrix} 2 & -2
-2 & 2 \end{bmatrix} \quad and \quad A^2 = kA, \quad then find the value of k. \]

Correct Answer:
View Solution

Question 22:

(a) Simplify \(\sin^{-1} \left( \frac{x}{\sqrt{1 + x^2}} \right)\).

Correct Answer:
View Solution

Question 23:

(b) Find the domain of \(\sin^{-1} \sqrt{x - 1}\).

Correct Answer:
View Solution

Question 24:

Calculate the area of the region bounded by the curve \[ \frac{x^2}{9} + \frac{y^2}{4} = 1 \]
and the x-axis using integration.

Correct Answer:
View Solution

Question 25:

(a) Find the least value of ‘a’ so that \(f(x) = 2x^2 - ax + 3\) is an increasing function on \([2, 4]\).

Correct Answer:
View Solution

Question 26:

(b) If \(f(x) = x + \frac{1}{x}, \, x \geq 1\), show that \(f\) is an increasing function.

Correct Answer:
View Solution

Question 27:

A cylindrical water container has developed a leak at the bottom. The water is leaking at the rate of 5 cm\(^3\)/s from the leak. If the radius of the container is 15 cm, find the rate at which the height of water is decreasing inside the container, when the height of water is 2 meters.

Correct Answer:
View Solution

Question 28:

Find: \[ \int \frac{\sqrt{x}}{1 + \sqrt{x^{3/2}}} \, dx \]

Correct Answer:
View Solution

Question 29:

Find the distance of the point \((-1, -5, -10)\) from the point of intersection of the lines \[ \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4}, \quad \frac{x - 4}{5} = \frac{y - 1}{2} = z. \]

Correct Answer:
View Solution

Question 30:

If \(f : \mathbb{R}^+ \to \mathbb{R}\) is defined as \(f(x) = \log_a x\) where \(a > 0\) and \(a \neq 1\), prove that \(f\) is a bijection.
(R\(^+\) is the set of all positive real numbers.)

Correct Answer:
View Solution

Question 31:

Let \(A = \{1, 2, 3\}\) and \(B = \{4, 5, 6\}\). A relation \(R\) from \(A\) to \(B\) is defined as \(R = \{(x, y) : x + y = 6, x \in A, y \in B \}\).

(i) Write all elements of \(R\).

(ii) Is \(R\) a function? Justify.

(iii) Determine domain and range of \(R\).

Correct Answer:
View Solution

Question 32:

(a) Find \( k \) so that the function \[ f(x) = \begin{cases} \frac{x^2 - 2x - 3}{x + 1} & if x \neq -1
k & if x = -1 \end{cases} \]
is continuous at \( x = -1 \).

Correct Answer:
View Solution

Question 33:

% Graph Image
\begin{figure[h]
\centering

\end{figure

For the given graph of a Linear Programming Problem, write all the constraints satisfying the given feasible region.

Correct Answer:
View Solution

Question 34:

The relation between the height of the plant (\(y\) cm) with respect to exposure to sunlight is governed by the equation \[ y = 4x - \frac{1}{2} x^2, \]
where \(x\) is the number of days exposed to sunlight.


(i) Find the rate of growth of the plant with respect to sunlight.

(ii) In how many days will the plant attain its maximum height? What is the maximum height?

Correct Answer:
View Solution

Question 35:

Show that the area of a parallelogram whose diagonals are represented by \( \vec{a} \) and \( \vec{b} \) is given by \[ Area = \frac{1}{2} | \vec{a} \times \vec{b} |. \]
Also, find the area of a parallelogram whose diagonals are \( 2\hat{i} - \hat{j} + \hat{k} \) and \( \hat{i} + 3\hat{j} - \hat{k} \).

Correct Answer:
View Solution

Question 36:

Find the equation of a line in vector and Cartesian form which passes through the point \( (1, 2, -4) \) and is perpendicular to the lines \[ \frac{x - 8}{3} = \frac{y + 19}{-16} = \frac{z - 10}{7}. \]
and \[ \vec{r} = 15\hat{i} + 29\hat{j} + 5\hat{k} + \mu (3\hat{i} + 8\hat{j} - 5\hat{k}). \]

Correct Answer:
View Solution

CBSE CLASS XII Questions

  • 1.
    The area of the shaded region (figure) represented by the curves \( y = x^2 \), \( 0 \leq x \leq 2 \), and the y-axis is given by:
    The area of the shaded region

      • \( \int_0^2 x^2 \, dx \)
      • \( \int_0^2 \sqrt{y} \, dy \)
      • \( \int_0^4 x^2 \, dx \)
      • \( \int_0^4 \sqrt{y} \, dy \)

    • 2.

      The given graph illustrates:

        • $y = \tan^{-1} x$
        • $y = \csc^{-1} x$
        • $y = \cot^{-1} x$
        • $y = \sec^{-1} x$

      • 3.
        Using integration, find the area of the region bounded by the line \[ y = 5x + 2, \] the \( x \)-axis, and the ordinates \( x = -2 \) and \( x = 2 \).


          • 4.
            Let $\mathbf{| \mathbf{a} |} = 5$ and $-2 \leq z \leq 1$. Then, the range of $|\mathbf{a}|$ is:

              • $[5, 10]$
              • $[-2, 5]$
              • $[2, 1]$
              • $[-10, 5]$

            • 5.
              The matrix $A = \begin{bmatrix} \sqrt{5} & 0 & 0 \\ 0 & \sqrt{2} & 0 \\ 0 & 0 & \sqrt{5} \end{bmatrix}$ is an:

                • symmetric matrix
                • identity matrix
                • null matrix
                • scalar matrix

              • 6.
                If \[ A = \begin{bmatrix} 5 & 0 \\ 0 & 5 \end{bmatrix}, \] then \( A^3 \) is:

                  • \(  \begin{bmatrix} 125 & 0 \\ 0 & 125 \end{bmatrix} \)

                  • \( \begin{bmatrix} 0 & 125 \\ 0 & 125 \end{bmatrix} \)
                  • \( \begin{bmatrix} 15 & 0 \\ 0 & 15 \end{bmatrix} \)
                  • \( \begin{bmatrix} 5^3 & 0 \\ 0 & 5^3 \end{bmatrix} \)

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