NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.5

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NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.5 is covered in this article. Exercise 7.5 covers questions on the topic, Integration by Substitution, Integration using Partial Fractions, Integration by Parts. NCERT Solutions for Class 12 Maths Chapter 7 will carry a weightage of around 6-18 marks in the CBSE Term 2 Exam 2022. NCERT has provided a total of 23 problems and solutions based on the important topics.

Download PDF NCER Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.5

NCERT Solutions for Class 12 Maths Chapter 7: Important Topics

Important topics covered in Integrals Chapter are:

Double Integral
Continuous Integration
Properties of Definite Integral
Line Integral
Integrals of Particular Function

Also check: NCERT Solutions for Class 12 Maths Chapter 7 Integrals

CBSE CLASS XII Related Questions

1.
Evaluate: $ \tan^{-1} \left[ 2 \sin \left( 2 \cos^{-1} \frac{\sqrt{3}}{2} \right) \right]$
View Solution
2.
The integrating factor of the differential equation $ (x + 2y^3) \frac{dy}{dx} = 2y $ is:
- $ e^{y^2} $
- $ \frac{1}{\sqrt{y}} $
- $ e^{-\frac{1}{y^2}} $
- $ e^{y^2} $
View Solution
3.
Let $|\vec{a}| = 5 \text{ and } -2 \leq \lambda \leq 1$. Then, the range of $|\lambda \vec{a}|$ is:
- [5, 10]
- [-2, 5]
- [-1, 5]
- [10, 5]
View Solution
4.
If $ \mathbf{a} $ and $ \mathbf{b} $ are position vectors of two points $ P $ and $ Q $ respectively, then find the position vector of a point $ R $ in $ QP $ produced such that \[ QR = \frac{3}{2} QP. \]
View Solution
5.
Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.
View Solution
6.
If $M$ and $N$ are square matrices of order 3 such that $\det(M) = m$ and $MN = mI$, then $\det(N)$ is equal to :
- $-1$
- 1
- $-m^2$
- $m^2$
View Solution

View All

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Mathematics NCERT Solutions

NCERT Solutions For Class 12 Mathematics Chapter 13: Probability

NCERT Solutions For Class 12 Mathematics Chapter 9: Differential Equations

NCERT Solutions For Class 12 Mathematics Chapter 7 Integrals

NCERT Solutions For Class 12 Mathematics Chapter 12: Linear Programming

NCERT Solutions for Class 12 Maths Chapter 3 Matrices

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You can also check

Exercise 7.1 Solutions	22 Questions
Exercise 7.2 Solutions	39 Questions
Exercise 7.3 Solutions	24 Questions
Exercise 7.4 Solutions	25 Questions
Exercise 7.5 Solutions	23 Questions
Exercise 7.6 Solutions	24 Questions
Exercise 7.7 Solutions	11 Questions
Exercise 7.8 Solutions	6 Questions
Exercise 7.9 Solutions	22 Questions
Exercise 7.10 Solutions	10 Questions
Exercise 7.11 Solutions	21 Questions
Miscellaneous Exercise Solutions	44 Questions

Methods of Integration	List of Integral Formulas	Double Integral
Fundamental Theorem of Calculus	Integration by Partial Fractions	Definite Integral Formula
Continuous integration	Properties of Definite Integral	Line Integral
Calculus Formula	Differentiation and Integration Formula	Substitution Method

NCERT Solutions for Class 12 Maths	Maths MCQs	Maths Syllabus
Arithmetic	Calculus	Algebra
Mathematics Notes	Trigonometry	Maths Study Material

NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.5

NCERT Solutions for Class 12 Maths Chapter 7: Important Topics

Other Exercises Solutions of Class 12 Maths Chapter 7 Integrals

CBSE CLASS XII Related Questions

1.
Evaluate: $ \tan^{-1} \left[ 2 \sin \left( 2 \cos^{-1} \frac{\sqrt{3}}{2} \right) \right]$

2.
The integrating factor of the differential equation \( (x + 2y^3) \frac{dy}{dx} = 2y \) is:

3.
Let $|\vec{a}| = 5 \text{ and } -2 \leq \lambda \leq 1$. Then, the range of $|\lambda \vec{a}|$ is:

4.
If \( \mathbf{a} \) and \( \mathbf{b} \) are position vectors of two points \( P \) and \( Q \) respectively, then find the position vector of a point \( R \) in \( QP \) produced such that \[ QR = \frac{3}{2} QP. \]

5.
Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.

6.
If $M$ and $N$ are square matrices of order 3 such that $\det(M) = m$ and $MN = mI$, then $\det(N)$ is equal to :

Similar Mathematics Concepts

Comments

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NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.5

NCERT Solutions for Class 12 Maths Chapter 7: Important Topics

Other Exercises Solutions of Class 12 Maths Chapter 7 Integrals

CBSE CLASS XII Related Questions

1.Evaluate: $ \tan^{-1} \left[ 2 \sin \left( 2 \cos^{-1} \frac{\sqrt{3}}{2} \right) \right]$

2.The integrating factor of the differential equation \( (x + 2y^3) \frac{dy}{dx} = 2y \) is:

3.Let $|\vec{a}| = 5 \text{ and } -2 \leq \lambda \leq 1$. Then, the range of $|\lambda \vec{a}|$ is:

4.If \( \mathbf{a} \) and \( \mathbf{b} \) are position vectors of two points \( P \) and \( Q \) respectively, then find the position vector of a point \( R \) in \( QP \) produced such that \[ QR = \frac{3}{2} QP. \]

5.Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.

6.If $M$ and $N$ are square matrices of order 3 such that $\det(M) = m$ and $MN = mI$, then $\det(N)$ is equal to :

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Evaluate: $ \tan^{-1} \left[ 2 \sin \left( 2 \cos^{-1} \frac{\sqrt{3}}{2} \right) \right]$

2.
The integrating factor of the differential equation \( (x + 2y^3) \frac{dy}{dx} = 2y \) is:

3.
Let $|\vec{a}| = 5 \text{ and } -2 \leq \lambda \leq 1$. Then, the range of $|\lambda \vec{a}|$ is:

4.
If \( \mathbf{a} \) and \( \mathbf{b} \) are position vectors of two points \( P \) and \( Q \) respectively, then find the position vector of a point \( R \) in \( QP \) produced such that \[ QR = \frac{3}{2} QP. \]

5.
Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.

6.
If $M$ and $N$ are square matrices of order 3 such that $\det(M) = m$ and $MN = mI$, then $\det(N)$ is equal to :