NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.4

Namrata Das logo

Namrata Das

Exams Prep Master

NCERT Solutions for Class 12 Maths Chapter 7 Integrals contains the solutions for all Exercise 7.4 questions. Exercise 7.4 is based on the Integrals of Some Particular Functions. NCERT Solutions for Class 12 Maths Chapter 7 will carry a weightage of around 6-18 marks in the CBSE Term 2 Exam 2022. NCERT has provided a total of 25 problems and solutions based on the important topics.

Download PDF NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.4

NCERT Solutions for Class 12 Maths Chapter 7: Important Topics

Important topics covered in Integrals Chapter are:

  • Double Integral
  • Continuous Integration
  • Properties of Definite Integral
  • Line Integral
  • Integrals of Particular Function

Also check: NCERT Solutions for Class 12 Maths Chapter 7 Integrals 

Other Exercises Solutions of Class 12 Maths Chapter 7 Integrals

Chapter 7 Integrals Topics:

CBSE Class 12 Mathematics Study Guides:

CBSE CLASS XII Related Questions

  • 1.

    Solve the differential equation \( (x+y)\,dy + (x-y)\,dx = 0 \), given that \( y(1) = 1 \).


      • 2.

        Find the value of \(x\) if \(A = B\), where

        \[ A = \begin{bmatrix} 6 & 3x \\ 8 & -6 \end{bmatrix} \text{ and } B = \begin{bmatrix} 6 & x^2+2 \\ 8 & x^2-5x \end{bmatrix}. \]


          • 3.

            \( \int e^{x}\left( \frac{2+\sin 2x}{1+\cos 2x} \right) dx \) is equal to :

              • \( \log \cos 2x + C \)
              • \( \sec^{2} 2x + C \)
              • \( e^{x}\tan x + C \)
              • \( e^{x}\cot x + C \)

            • 4.

              For the following Linear Programming Problem, shade the feasible region on the graph and find the coordinates of its corner points :

              Minimize \(Z = 18x + 10y\)

              subject to constraints

              \[ \begin{aligned} 4x + y &\ge 20 \\ 2x + 3y &\ge 30 \\ x, y &\ge 0. \end{aligned} \]


                • 5.

                  For events A and B, if \(P(B)=\frac{3}{5}\), \(P(A/B)=\frac{1}{2}\) and \(P(A\cup B)=\frac{4}{5}\), then \(P(A)\) is :

                    • \(\frac{1}{2}\)
                    • \(\frac{3}{5}\)
                    • \(\frac{1}{5}\)
                    • \(\frac{3}{10}\)

                  • 6.

                    The motion of a particle is described as \( S = 2t^{3} - 6t^{2} + 8 \). Its velocity \( \frac{dS}{dt} \), when the acceleration \( \frac{d^{2}S}{dt^{2}} \) vanishes is :

                      • \( -6 \) unit/sec
                      • \( 0 \) unit/sec
                      • \( 18 \) unit/sec
                      • \( 6 \) unit/sec
                    CBSE CLASS XII Previous Year Papers

                    Comments


                    No Comments To Show