NCERT Solutions for Class 12 Maths Chapter 1 Relations and Functions Exercise 1.2

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NCERT Solutions for Class 12 Maths Chapter 1 Relations and Functions Exercise 1.2 is mainly based on types of relations.

NCERT maths chapter 1 relation and functions carry a weightage of around 6 to 8 marks in the CBSE term 2 exams 2022.
NCERT Exercise 1.2 has provided around 11 problems and solutions based on relations, types of relations, types of functions and binary operations.

Check NCERT Solution for Class 12 Maths Chapter 1 relations and functions Exercise 1(PDF Link)

Check Class 12 NCERT Maths Chapter 1 Relations and Functions Exercises:

Read More:

Relation & Functions	Difference between Relations & Functions	Binary Addition
Modulus Function	Onto Function	Signum Function

CBSE Class 12 Mathematics Study Guide:

Math Study Notes	Math MCQs	NCERT Solutions for Class 12 Maths
Trigonometry	Algebra	Difference between in Maths

CBSE CLASS XII Related Questions

1.
Sports car racing is a form of motorsport which uses sports car prototypes. The competition is held on special tracks designed in various shapes. The equation of one such track is given as

(i) Find \(f'(x)\) for \(0<x>3\).
(ii) Find \(f'(4)\).
(iii)(a) Test for continuity of \(f(x)\) at \(x=3\).
OR
(iii)(b) Test for differentiability of \(f(x)\) at \(x=3\).
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2.
A line passing through the points \(A(1,2,3)\) and \(B(6,8,11)\) intersects the line \[ \vec r = 4\hat i + \hat j + \lambda(6\hat i + 2\hat j + \hat k) \] Find the coordinates of the point of intersection. Hence write the equation of a line passing through the point of intersection and perpendicular to both the lines.
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3.
Find the domain of \(p(x)=\sin^{-1}(1-2x^2)\). Hence, find the value of \(x\) for which \(p(x)=\frac{\pi}{6}\). Also, write the range of \(2p(x)+\frac{\pi}{2}\).
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4.
Evaluate : \[ \int_{\frac{1}{12}}^{\frac{5}{12}} \frac{dx}{1+\sqrt{\cot x}} \]
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5.
Find : \[ \int \frac{2x+1}{\sqrt{x^2+6x}}\,dx \]
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6.
If \[ P = \begin{bmatrix} 1 & -1 & 0 \\ 2 & 3 & 4 \\ 0 & 1 & 2 \end{bmatrix} \quad \text{and} \quad Q = \begin{bmatrix} 2 & 2 & -4 \\ -4 & 2 & -4 \\ 1 & -1 & 5 \end{bmatrix} \] find \( QP \) and hence solve the following system of equations using matrix method:
\[ x - y = 3,\quad 2x + 3y + 4z = 13,\quad y + 2z = 7 \]
View Solution

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