NCERT Solutions for class 12 Chemistry Chapter 2: Solutions

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NCERT Solutions for class 12 chemistry chapter 2: Solutions are provided in this article which includes important formulas, chemical equations and numericals. Some of the important topics of Class 12 Chemistry Chapter 2 Solutions include:

Expected No. of questions: 2 to 4 questions of 1 to 5 marks

Download PDF: NCERT Solutions for Class 12 Chemistry Chapter 2 pdf

NCERT Solutions for Class 12 Chemistry Chapter 2

The NCERT solutions for class 12 chemistry chapter 2: Solutions is given below in pdf as well as image form.

NCERT Solutions for Class 12 Chemistry Chapter 2: Solutions – Important Topics

A Solution is a homogeneous mixture of two or more chemically non-reacting substances whose composition can be varied within certain limits. A solution is regarded as a simple phase having more than one component.

Types of Solutions: Based on the states of matter, solutions can be divided into solid solutions, liquid solutions and gaseous solutions.

Solid Solutions: The solvent is in solid state

Liquid Solutions: The solvent is in liquid state

Gaseous Solutions: The solvent is in gaseous state

Solubility: The amount of solute that can dissolve in a solvent to form a solution is called solubility. Solubility depends on factors like temperature, pressure, nature of solvent and solute.

Unsaturated Solution: A solution in which more solute can be added at a given temperature.

Saturated Solution: A solution in which no more solute can be added at a given temperature.

Supersaturated solution: A solution in which more solute than the limited amount is present at a given temperature.

Concentration of Solution: The ratio of the solute to the solvent is known as concentration of a solution

Henry’s Law: Henry’s Law states that the partial pressure (p) of the gas in the vapour phase is proportional to the mole fraction (x) of the gas in the solution. Mathematically,

p = K_H. x

Raoult’s Law: Raoult’s Law states that the Partial vapour pressure of every component in a solution is directly proportional to the mole fraction of that component. Mathematically,

P = P₀X

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CBSE CLASS XII Related Questions

1.
Predict the alkene that would be formed by dehydrohalogenation of 1-Bromo-1-methylcyclohexane.

View Solution

2.
Under what condition can a bimolecular reaction become kinetically first order?

View Solution

3.
Explain: (i) Presence of carbonyl group in glucose. (ii) Presence of five $-$OH groups attached to different carbon atoms.

View Solution

4.
Give structures of A, B and C: Aniline $\xrightarrow{Br_2/H_2O}$ A $\xrightarrow{NaNO_2+HCl, 0-5^\circ C}$ B $\xrightarrow{H_3PO_2+H_2O}$ C

View Solution

5.
What happens when acidic solution of potassium permanganate is allowed to stand for sometime ? Give the equation involved. What is this type of reaction called ?

View Solution

6.
61 g benzoic acid (M = 122 g mol$^{-1}$) dissolved in 500 g benzene. Vapour pressure of pure benzene = 66 torr. Assume complete dimerisation. Calculate vapour pressure of solution.

View Solution

NCERT Solutions for class 12 Chemistry Chapter 2: Solutions

Download PDF: NCERT Solutions for Class 12 Chemistry Chapter 2 pdf

NCERT Solutions for Class 12 Chemistry Chapter 2

NCERT Solutions for Class 12 Chemistry Chapter 2: Solutions – Important Topics

CBSE CLASS XII Related Questions

1.
Predict the alkene that would be formed by dehydrohalogenation of 1-Bromo-1-methylcyclohexane.

2.
Under what condition can a bimolecular reaction become kinetically first order?

3.
Explain: (i) Presence of carbonyl group in glucose. (ii) Presence of five $-$OH groups attached to different carbon atoms.

4.
Give structures of A, B and C: Aniline $\xrightarrow{Br_2/H_2O}$ A $\xrightarrow{NaNO_2+HCl, 0-5^\circ C}$ B $\xrightarrow{H_3PO_2+H_2O}$ C

5.
What happens when acidic solution of potassium permanganate is allowed to stand for sometime ? Give the equation involved. What is this type of reaction called ?

6.
61 g benzoic acid (M = 122 g mol$^{-1}$) dissolved in 500 g benzene. Vapour pressure of pure benzene = 66 torr. Assume complete dimerisation. Calculate vapour pressure of solution.

Similar Chemistry Concepts

Comments

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NCERT Solutions for class 12 Chemistry Chapter 2: Solutions

Download PDF: NCERT Solutions for Class 12 Chemistry Chapter 2 pdf

NCERT Solutions for Class 12 Chemistry Chapter 2

NCERT Solutions for Class 12 Chemistry Chapter 2: Solutions – Important Topics

CBSE CLASS XII Related Questions

1.Predict the alkene that would be formed by dehydrohalogenation of 1-Bromo-1-methylcyclohexane.

2.Under what condition can a bimolecular reaction become kinetically first order?

3.Explain: (i) Presence of carbonyl group in glucose. (ii) Presence of five $-$OH groups attached to different carbon atoms.

4.Give structures of A, B and C: Aniline $\xrightarrow{Br_2/H_2O}$ A $\xrightarrow{NaNO_2+HCl, 0-5^\circ C}$ B $\xrightarrow{H_3PO_2+H_2O}$ C

5.What happens when acidic solution of potassium permanganate is allowed to stand for sometime ? Give the equation involved. What is this type of reaction called ?

6.61 g benzoic acid (M = 122 g mol$^{-1}$) dissolved in 500 g benzene. Vapour pressure of pure benzene = 66 torr. Assume complete dimerisation. Calculate vapour pressure of solution.

Similar Chemistry Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Predict the alkene that would be formed by dehydrohalogenation of 1-Bromo-1-methylcyclohexane.

2.
Under what condition can a bimolecular reaction become kinetically first order?

3.
Explain: (i) Presence of carbonyl group in glucose. (ii) Presence of five $-$OH groups attached to different carbon atoms.

4.
Give structures of A, B and C: Aniline $\xrightarrow{Br_2/H_2O}$ A $\xrightarrow{NaNO_2+HCl, 0-5^\circ C}$ B $\xrightarrow{H_3PO_2+H_2O}$ C

5.
What happens when acidic solution of potassium permanganate is allowed to stand for sometime ? Give the equation involved. What is this type of reaction called ?

6.
61 g benzoic acid (M = 122 g mol$^{-1}$) dissolved in 500 g benzene. Vapour pressure of pure benzene = 66 torr. Assume complete dimerisation. Calculate vapour pressure of solution.