NCERT Solutions for class 12 Chemistry Chapter 1: The Solid State

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NCERT Solutions for class 12 Chemistry Chapter 1 The Solid State are provided in this article. Some of the important concepts covered in this topic include:

As this chapter has been omitted in the new CBSE Class 12 Syllabus, it does not have any weightage but is useful in preparing for competitive exams.

Download PDF: NCERT Solutions for Class 12 Chemistry Chapter 1 pdf

NCERT Solutions for Class 12 Chemistry Chapter 1

NCERT Solutions for Class 12 Chemistry Chapter 1 Solid State is given below.

Class 12 Chemistry Chapter 1: Solid State – Important Topics

Some of the important topics in Class 12 Chemistry Chapter 1: Solid State is given below

Types of Solids – Crystalline and Amorphous Solids

Properties of Crystalline Solids:

They have fixed geometrical shapes.
Crystalline solids have their constituent particles arranged in long-range order.
They have a fixed melting point.
They have fixed heat of fusion.
They are anisotropic.
They are considered as true solids.

Properties of Amorphous Solids:

They have an irregular shape.
Amorphous solids have their constituent particles arranged in short-range order.
When heated, they soften and do not have a sharp melting point.
They do not have a sharp melting point.
They are isotropic.
They are considered as pseudo solids or super cooled liquids.

Solid State

Solid State

Types of Bonding – Ionic Bond, Covalent Bond

Ionic Bond: Ionic bond is formed by the exchange of electrons between two reacting molecules. It usually occurs between metals and non metals (eg: Sodium and Chlorine) where there is an interchange of oppositely charged particles.

Covalent Bond: Covalent Bond is the sharing of electrons between two molecules to form a new product. This types of bonding is not as strong as Ionic bonds.

Some of the factors which determine the type of Bonding are called as Bond parameters. They include:

Bond Length
Bond Angle
Bond Enthalpy
Bond Order
Resonance Structures

Lattice Enthalpy: It is the amount of energy required to separate one mole of crystalline ionic compounds from its constituent gaseous ions.

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CBSE CLASS XII Related Questions

1.
Predict the products of electrolysis in each of the following: (i) An aqueous solution of CuCl$_2$ with platinum electrodes. (ii) A concentrated solution of H$_2$SO$_4$ with platinum electrodes.

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2.
The following reactions occur at the anode during the electrolysis of aqueous sodium chloride solution: \[ Cl^-_{(aq)} \rightarrow \frac{1}{2}Cl_2(g)+e^- \qquad E^\circ_{\text{cell}}=1.36\,V \] \[ 2H_2O(l) \rightarrow O_2(g)+4H^+(aq)+4e^- \qquad E^\circ_{\text{cell}}=1.23\,V \] Which reaction is feasible at the anode and why?

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3.
Half-life ($ t_{1/2} $) of a first order reaction is 1386 s. The value of rate constant is:

$0.5 \times 10^{-4} \, \text{s}^{-1}$
$5.0 \times 10^{-4} \, \text{s}^{-1}$
$0.5 \times 10^{-5} \, \text{s}^{-1}$
$0.5 \times 10^{-3} \, \text{s}^{-1}$

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4.
(I) Why do transition metals show variable oxidation states? (II) Out of Mn$^{2+}$ and Ti$^{2+}$ which will be more paramagnetic and why? Atomic No.: Ti = 22, Mn = 25 (III) Which ion is the strongest oxidising agent in the options given below: \[ Cr^{3+},\ V^{3+},\ Mn^{3+} \] Atomic No.: Cr = 24, V = 23, Mn = 25 (ii) Complete and balance the following equations: (I) \[ 2MnO_2+4KOH+O_2\rightarrow ? \] (II) \[ 5C_2O_4^{2-}+2MnO_4^-+16H^+\rightarrow ? \]

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5.
What is meant by lanthanoid contraction? (ii) Why do transition metals form coloured compounds? (iii) Why are $E^\circ_{M^{2+}/M}$ values for Mn and Zn more negative than expected? (iv) Which is the most stable oxidation state of Cu and why? (v) Why is Ce$^{4+}$ in aqueous solution a good oxidising agent?

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6.
State Faraday’s second law of electrolysis.

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NCERT Solutions for class 12 Chemistry Chapter 1: The Solid State

Download PDF: NCERT Solutions for Class 12 Chemistry Chapter 1 pdf

NCERT Solutions for Class 12 Chemistry Chapter 1

Class 12 Chemistry Chapter 1: Solid State – Important Topics

CBSE CLASS XII Related Questions

1.
Predict the products of electrolysis in each of the following: (i) An aqueous solution of CuCl$_2$ with platinum electrodes. (ii) A concentrated solution of H$_2$SO$_4$ with platinum electrodes.

3.
Half-life (\( t_{1/2} \)) of a first order reaction is 1386 s. The value of rate constant is:

6.
State Faraday’s second law of electrolysis.

Similar Chemistry Concepts

Comments

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NCERT Solutions for class 12 Chemistry Chapter 1: The Solid State

Download PDF: NCERT Solutions for Class 12 Chemistry Chapter 1 pdf

NCERT Solutions for Class 12 Chemistry Chapter 1

Class 12 Chemistry Chapter 1: Solid State – Important Topics

CBSE CLASS XII Related Questions

1.Predict the products of electrolysis in each of the following: (i) An aqueous solution of CuCl$_2$ with platinum electrodes. (ii) A concentrated solution of H$_2$SO$_4$ with platinum electrodes.

3.Half-life (\( t_{1/2} \)) of a first order reaction is 1386 s. The value of rate constant is:

6.State Faraday’s second law of electrolysis.

Similar Chemistry Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Predict the products of electrolysis in each of the following: (i) An aqueous solution of CuCl$_2$ with platinum electrodes. (ii) A concentrated solution of H$_2$SO$_4$ with platinum electrodes.

3.
Half-life (\( t_{1/2} \)) of a first order reaction is 1386 s. The value of rate constant is:

6.
State Faraday’s second law of electrolysis.