NCERT Solutions for class 12 Chemistry Chapter 1: The Solid State

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NCERT Solutions for class 12 Chemistry Chapter 1 The Solid State are provided in this article. Some of the important concepts covered in this topic include:

As this chapter has been omitted in the new CBSE Class 12 Syllabus, it does not have any weightage but is useful in preparing for competitive exams.

Download PDF: NCERT Solutions for Class 12 Chemistry Chapter 1 pdf

NCERT Solutions for Class 12 Chemistry Chapter 1

NCERT Solutions for Class 12 Chemistry Chapter 1 Solid State is given below.

Class 12 Chemistry Chapter 1: Solid State – Important Topics

Some of the important topics in Class 12 Chemistry Chapter 1: Solid State is given below

Types of Solids – Crystalline and Amorphous Solids

Properties of Crystalline Solids:

They have fixed geometrical shapes.
Crystalline solids have their constituent particles arranged in long-range order.
They have a fixed melting point.
They have fixed heat of fusion.
They are anisotropic.
They are considered as true solids.

Properties of Amorphous Solids:

They have an irregular shape.
Amorphous solids have their constituent particles arranged in short-range order.
When heated, they soften and do not have a sharp melting point.
They do not have a sharp melting point.
They are isotropic.
They are considered as pseudo solids or super cooled liquids.

Solid State

Solid State

Types of Bonding – Ionic Bond, Covalent Bond

Ionic Bond: Ionic bond is formed by the exchange of electrons between two reacting molecules. It usually occurs between metals and non metals (eg: Sodium and Chlorine) where there is an interchange of oppositely charged particles.

Covalent Bond: Covalent Bond is the sharing of electrons between two molecules to form a new product. This types of bonding is not as strong as Ionic bonds.

Some of the factors which determine the type of Bonding are called as Bond parameters. They include:

Bond Length
Bond Angle
Bond Enthalpy
Bond Order
Resonance Structures

Lattice Enthalpy: It is the amount of energy required to separate one mole of crystalline ionic compounds from its constituent gaseous ions.

Also Read:

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CBSE CLASS XII Related Questions

1.
Calculate the freezing point of a solution when 10.5 g of MgBr$_2$ was dissolved in 250 g of water, assuming MgBr$_2$ undergoes complete dissociation. Given: \[ \text{Molar mass of MgBr}_2 = 184 \, g\,mol^{-1} \] \[ K_f \text{ for water} = 1.86 \, K\,kg\,mol^{-1} \] (ii) Write two differences between ideal and non-ideal solutions.

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2.
State Faraday’s second law of electrolysis.

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3.
Answer the following: (I) Which isomer of C$_4$H$_9$Br is most reactive towards S$_N$1 reaction? (II) Predict the alkene that would be formed by dehydrohalogenation of 1-Bromo-1-methylcyclohexane. (III) Although chlorine shows strong $-I$ effect, yet it is ortho/para-directing in electrophilic aromatic substitution reactions. Why? (ii) Write the major product in the following reactions: (I)
(II)

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4.
How many Faradays are required to reduce 1 mol of $Cr_2O_7^{2-}$ to $Cr^{3+}$ in acidic medium ?

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5.
(I) Why do transition metals show variable oxidation states? (II) Out of Mn$^{2+}$ and Ti$^{2+}$ which will be more paramagnetic and why? Atomic No.: Ti = 22, Mn = 25 (III) Which ion is the strongest oxidising agent in the options given below: \[ Cr^{3+},\ V^{3+},\ Mn^{3+} \] Atomic No.: Cr = 24, V = 23, Mn = 25 (ii) Complete and balance the following equations: (I) \[ 2MnO_2+4KOH+O_2\rightarrow ? \] (II) \[ 5C_2O_4^{2-}+2MnO_4^-+16H^+\rightarrow ? \]

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6.
The half-life periods of decomposition of $\mathrm{NH_3}$ for different initial pressures are given below :

The order of the reaction is :

zero order
first order
0·5
second order

View Solution

NCERT Solutions for class 12 Chemistry Chapter 1: The Solid State

Download PDF: NCERT Solutions for Class 12 Chemistry Chapter 1 pdf

NCERT Solutions for Class 12 Chemistry Chapter 1

Class 12 Chemistry Chapter 1: Solid State – Important Topics

CBSE CLASS XII Related Questions

2.
State Faraday’s second law of electrolysis.

4.
How many Faradays are required to reduce 1 mol of \(Cr_2O_7^{2-}\) to \(Cr^{3+}\) in acidic medium ?

6.
The half-life periods of decomposition of $\mathrm{NH_3}$ for different initial pressures are given below :

The order of the reaction is :

Similar Chemistry Concepts

Comments

dOGVmW

NCERT Solutions for class 12 Chemistry Chapter 1: The Solid State

Download PDF: NCERT Solutions for Class 12 Chemistry Chapter 1 pdf

NCERT Solutions for Class 12 Chemistry Chapter 1

Class 12 Chemistry Chapter 1: Solid State – Important Topics

CBSE CLASS XII Related Questions

2.State Faraday’s second law of electrolysis.

4.How many Faradays are required to reduce 1 mol of \(Cr_2O_7^{2-}\) to \(Cr^{3+}\) in acidic medium ?

6.The half-life periods of decomposition of $\mathrm{NH_3}$ for different initial pressures are given below :The order of the reaction is :

Similar Chemistry Concepts

Comments

dOGVmW

2.
State Faraday’s second law of electrolysis.

4.
How many Faradays are required to reduce 1 mol of \(Cr_2O_7^{2-}\) to \(Cr^{3+}\) in acidic medium ?

6.
The half-life periods of decomposition of $\mathrm{NH_3}$ for different initial pressures are given below :

The order of the reaction is :