Define gravitational flux in analogy to electric flux. How does gravitational flux differ from electric flux?

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Gravitational flux is a measure of the amount of gravitational field passing through a given area, just as electric flux is a measure of the amount of electric field passing through a given area. It is similar to electric flux in that it is a measure of the strength of the field at a point, and is calculated by taking the dot product of the field vector and the area vector.

However, gravitational flux differs from the electric flux in a few key ways.

Firstly, while electric fields can be both positive and negative, gravitational fields are always attractive, meaning that they are always directed towards the source of the field.
This means that the gravitational flux through a closed surface is always negative, while the electric flux can be either positive or negative.
Another key difference is that while electric fields are generated by charges, gravitational fields are generated by masses.
This means that the gravitational flux through a given area is dependent on the mass of the object generating the field, as well as the distance between the object and the area.

Gravitational Flux = \(\overrightarrow{g}.\overrightarrow{A}\)

Electric flux = \(\overrightarrow{E}.\overrightarrow{A}\)

Magnetic flux = \(\overrightarrow{B}.\overrightarrow{A}\)

Both gravitational flux and electric flux have similar formulas. They are measures of the strength of a field passing through a given area. Gravitational flux is always negative and depends on the mass of the object generating the field. The electric flux can be positive or negative and depends on the charges generating the field.

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Define gravitational flux in analogy to electric flux. How does gravitational flux differ from electric flux?

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3.
Prove that, in the Bohr model of the hydrogen atom, the time period of revolution of an electron in the \( n \)-th orbit is proportional to \( n^3 \).

4.
A point source is placed at the bottom of a tank containing a transparent liquid (refractive index \( n \)) to a depth H. The area of the surface of the liquid through which light from the source can emerge out is:

5.
A laser beam of wavelength 500 nm and power 5 mW strikes normally on a perfectly reflecting surface of area 1 mm\(^2\) of a body. It rebounds back from the surface. Find the force exerted by the laser beam on the body.

6.
The graph shows the variation of current with voltage for a p-n junction diode. Estimate the dynamic resistance of the diode at \( V = -0.6 \) V.

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Define gravitational flux in analogy to electric flux. How does gravitational flux differ from electric flux?

CBSE CLASS XII Related Questions

3.Prove that, in the Bohr model of the hydrogen atom, the time period of revolution of an electron in the \( n \)-th orbit is proportional to \( n^3 \).

4.A point source is placed at the bottom of a tank containing a transparent liquid (refractive index \( n \)) to a depth H. The area of the surface of the liquid through which light from the source can emerge out is:

5.A laser beam of wavelength 500 nm and power 5 mW strikes normally on a perfectly reflecting surface of area 1 mm\(^2\) of a body. It rebounds back from the surface. Find the force exerted by the laser beam on the body.

6.The graph shows the variation of current with voltage for a p-n junction diode. Estimate the dynamic resistance of the diode at \( V = -0.6 \) V.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

3.
Prove that, in the Bohr model of the hydrogen atom, the time period of revolution of an electron in the \( n \)-th orbit is proportional to \( n^3 \).

4.
A point source is placed at the bottom of a tank containing a transparent liquid (refractive index \( n \)) to a depth H. The area of the surface of the liquid through which light from the source can emerge out is:

5.
A laser beam of wavelength 500 nm and power 5 mW strikes normally on a perfectly reflecting surface of area 1 mm\(^2\) of a body. It rebounds back from the surface. Find the force exerted by the laser beam on the body.

6.
The graph shows the variation of current with voltage for a p-n junction diode. Estimate the dynamic resistance of the diode at \( V = -0.6 \) V.