Define gravitational flux in analogy to electric flux. How does gravitational flux differ from electric flux?

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Gravitational flux is a measure of the amount of gravitational field passing through a given area, just as electric flux is a measure of the amount of electric field passing through a given area. It is similar to electric flux in that it is a measure of the strength of the field at a point, and is calculated by taking the dot product of the field vector and the area vector.

However, gravitational flux differs from the electric flux in a few key ways.

Firstly, while electric fields can be both positive and negative, gravitational fields are always attractive, meaning that they are always directed towards the source of the field.
This means that the gravitational flux through a closed surface is always negative, while the electric flux can be either positive or negative.
Another key difference is that while electric fields are generated by charges, gravitational fields are generated by masses.
This means that the gravitational flux through a given area is dependent on the mass of the object generating the field, as well as the distance between the object and the area.

Gravitational Flux = \(\overrightarrow{g}.\overrightarrow{A}\)

Electric flux = \(\overrightarrow{E}.\overrightarrow{A}\)

Magnetic flux = \(\overrightarrow{B}.\overrightarrow{A}\)

Both gravitational flux and electric flux have similar formulas. They are measures of the strength of a field passing through a given area. Gravitational flux is always negative and depends on the mass of the object generating the field. The electric flux can be positive or negative and depends on the charges generating the field.

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CBSE CLASS XII Related Questions

1.
Two slits 0.1 mm apart are arranged 1.20 m from a screen. Light of wavelength 600 nm from a distant source is incident on the slits.

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2.
Two point charges Q and \( -q \) are held \( r \) distance apart in free space. A uniform electric field \( \vec{E} \) is applied in the region perpendicular to the line joining the two charges. Which one of the following angles will the direction of the net force acting on charge \( -q \) make with the line joining Q and \( -q \)?

\( \tan^{-1} \left( \frac{4\pi \epsilon_0 E r^2}{Q} \right) \)
\( \cot^{-1} \left( \frac{4\pi \epsilon_0 E r^2}{Q} \right) \)
\( \tan^{-1} \left( \frac{QE}{4\pi \epsilon_0 r^2} \right) \)
\( \cot^{-1} \left( \frac{QE}{4\pi \epsilon_0 r^2} \right) \)

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3.
In a compound microscope, an object is placed at a distance of 1.5 cm from the objective of focal length 1.25 cm. The eyepiece has a focal length of 5 cm. The final image is formed at infinity. Calculate the distance between the objective and the eyepiece.

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4.
A particle of charge \( q \) is moving with a velocity \( \vec{v} \) at a distance \( d \) from a long straight wire carrying a current \( I \) as shown in the figure. At this instant, it is subjected to a uniform electric field \( \vec{E} \) such that the particle keeps moving undeviated. In terms of unit vectors \( \hat{i}, \hat{j}, \) and \( \hat{k} \), find:
the magnetic field \( \vec{B} \),
the magnetic force \( \vec{F}_m \), and
the electric field \( \vec{E} \) acting on the charge.

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5.
In a Young’s double-slit experiment, two light waves, each of intensity \( I_0 \), interfere at a point, having a path difference \( \frac{\lambda}{8} \) on the screen. Find the intensity at this point.

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6.
The ends of six wires, each of resistance R (= 10 \(\Omega\)) are joined as shown in the figure. The points A and B of the arrangement are connected in a circuit. Find the value of the effective resistance offered by it to the circuit.

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Define gravitational flux in analogy to electric flux. How does gravitational flux differ from electric flux?

CBSE CLASS XII Related Questions

1.
Two slits 0.1 mm apart are arranged 1.20 m from a screen. Light of wavelength 600 nm from a distant source is incident on the slits.

3.
In a compound microscope, an object is placed at a distance of 1.5 cm from the objective of focal length 1.25 cm. The eyepiece has a focal length of 5 cm. The final image is formed at infinity. Calculate the distance between the objective and the eyepiece.

5.
In a Young’s double-slit experiment, two light waves, each of intensity \( I_0 \), interfere at a point, having a path difference \( \frac{\lambda}{8} \) on the screen. Find the intensity at this point.

6.
The ends of six wires, each of resistance R (= 10 \(\Omega\)) are joined as shown in the figure. The points A and B of the arrangement are connected in a circuit. Find the value of the effective resistance offered by it to the circuit.

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Define gravitational flux in analogy to electric flux. How does gravitational flux differ from electric flux?

CBSE CLASS XII Related Questions

1.Two slits 0.1 mm apart are arranged 1.20 m from a screen. Light of wavelength 600 nm from a distant source is incident on the slits.

3.In a compound microscope, an object is placed at a distance of 1.5 cm from the objective of focal length 1.25 cm. The eyepiece has a focal length of 5 cm. The final image is formed at infinity. Calculate the distance between the objective and the eyepiece.

5.In a Young’s double-slit experiment, two light waves, each of intensity \( I_0 \), interfere at a point, having a path difference \( \frac{\lambda}{8} \) on the screen. Find the intensity at this point.

6.The ends of six wires, each of resistance R (= 10 \(\Omega\)) are joined as shown in the figure. The points A and B of the arrangement are connected in a circuit. Find the value of the effective resistance offered by it to the circuit.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Two slits 0.1 mm apart are arranged 1.20 m from a screen. Light of wavelength 600 nm from a distant source is incident on the slits.

3.
In a compound microscope, an object is placed at a distance of 1.5 cm from the objective of focal length 1.25 cm. The eyepiece has a focal length of 5 cm. The final image is formed at infinity. Calculate the distance between the objective and the eyepiece.

5.
In a Young’s double-slit experiment, two light waves, each of intensity \( I_0 \), interfere at a point, having a path difference \( \frac{\lambda}{8} \) on the screen. Find the intensity at this point.

6.
The ends of six wires, each of resistance R (= 10 \(\Omega\)) are joined as shown in the figure. The points A and B of the arrangement are connected in a circuit. Find the value of the effective resistance offered by it to the circuit.