CUET 2026 Physics May 31 Shift 2 Question Paper- Download Answer Key and Solution PDF

Step 1: Recall Coulomb's law. \[ F=\frac{kq_1q_2}{r^2} \]
Given: \[ q_1=4\times10^{-6}C \] \[ q_2=9\times10^{-6}C \] \[ r=3m \]

Step 2: Substitute the values.
\[ F= \frac{(9\times10^9)(4\times10^{-6})(9\times10^{-6})} {3^2} \] \[ F= \frac{9\times36\times10^{-3}} {9} \] \[ F=36\times10^{-3} \] \[ F=0.036N \]

Step 3: Choose the correct option.
\[ \boxed{F=0.036N} \]

Therefore, \[ \boxed{(B)} \]
is the correct answer. Quick Tip: Coulomb's Law: \[ \boxed{F=\frac{kq_1q_2}{r^2}} \] Important: \[ F\propto q_1q_2 \] \[ F\propto \frac{1}{r^2} \] Doubling distance reduces force by a factor of 4.

Step 1: Examine the Assertion.

For a pure inductor: \[ V=L\frac{dI}{dt} \]
Current lags behind voltage by: \[ \boxed{90^\circ} \]
Hence, \[ \boxed{Assertion (A) is True} \]

Step 2: Examine the Reason.

An inductor produces self-induced emf which opposes any change in current. \[ \boxed{Reason (R) is True} \]

Step 3: Determine the relationship.

Because the inductor opposes change in current, the current cannot rise instantly and hence lags the voltage.

Thus, Reason correctly explains Assertion.

Therefore, \[ \boxed{Both A and R are true and R is the correct explanation of A} \]
Hence, \[ \boxed{(A)} \]
is the correct answer. Quick Tip: Phase Difference in AC Circuits: \boxed{Resistor \rightarrow 0^\circ} \boxed{Inductor \rightarrow 90^\circ} \boxed{Capacitor \rightarrow 90^\circ}
Remember: \boxed{Current lags in Inductor} \boxed{Current leads in Capacitor}

Step 1: Recall Ohm's Law. \[ V=IR \]
Therefore, \[ I=\frac{V}{R} \]
Step 2: Substitute the given values. \[ I=\frac{10}{20} \] \[ I=0.5\,A \]
Step 3: Identify the correct option. \[ \boxed{I=0.5\,A} \]
Therefore, \[ \boxed{(B)} \]
is the correct answer. Quick Tip: Ohm's Law: \[ \boxed{V=IR} \] Useful forms: \[ \boxed{I=\frac{V}{R}} \] \[ \boxed{R=\frac{V}{I}} \] One of the most important formulas in Current Electricity.

Step 1: Recall the functions of semiconductor devices. \[ LED \rightarrow Light Emission \] \[ Zener Diode \rightarrow Voltage Regulation \] \[ Photodiode \rightarrow Light Detection \] \[ Solar Cell \rightarrow Converts Solar Energy into Electrical Energy \]
Step 2: Match the columns. \[ A \rightarrow II \] \[ B \rightarrow I \] \[ C \rightarrow III \] \[ D \rightarrow IV \]
Step 3: Choose the correct option. \[ \boxed{A-II,\;B-I,\;C-III,\;D-IV} \]
Therefore, \[ \boxed{(A)} \]
is the correct answer. Quick Tip: Important Semiconductor Devices: \[ \boxed{LED \rightarrow Light Emitting Diode} \] \[ \boxed{Zener Diode \rightarrow Voltage Regulator} \] \[ \boxed{Photodiode \rightarrow Light Sensor} \] \[ \boxed{Solar Cell \rightarrow Photovoltaic Device} \]

Step 1: Recall Bohr's energy formula. \[ E_n=\frac{-13.6}{n^2}\;eV \]
For the third orbit: n=3

Step 2: Substitute the value of \(n\). \[ E_3=\frac{-13.6}{3^2} \] \[ E_3=\frac{-13.6}{9} \] \[ E_3=-1.51\,eV \]
Step 3: Choose the correct option. \[ \boxed{E_3=-1.51\,eV} \]
Therefore, \[ \boxed{(A)} \]
is the correct answer. Quick Tip: Bohr Energy Formula: \[ \boxed{E_n=\frac{-13.6}{n^2}\;eV} \] For hydrogen atom: \[ E_1=-13.6\,eV \] \[ E_2=-3.4\,eV \] \[ E_3=-1.51\,eV \] Frequently asked CUET numerical.

Step 1: Examine the Assertion.

Electromagnetic waves do not require any material medium for propagation.

Hence they can travel through vacuum. \[ \boxed{Assertion (A) is True} \]
Step 2: Examine the Reason.

EM waves are produced by mutually perpendicular oscillating electric and magnetic fields. \[ \boxed{Reason (R) is True} \]
Step 3: Determine the relationship.

The changing electric field produces magnetic field and vice versa.

Therefore EM waves are self-propagating and do not require a medium.

Thus Reason correctly explains Assertion.

Hence, \[ \boxed{Both A and R are true and R is the correct explanation of A} \]
Therefore, \[ \boxed{(A)} \]
is the correct answer. Quick Tip: Properties of Electromagnetic Waves: \[ \boxed{Do not require a medium} \] \[ \boxed{Travel with speed c=3\times10^8\,m/s} \] \[ \boxed{E \perp B} \] \[ \boxed{E \perp Direction of Propagation} \]

Step 1: Recall the lens formula. \[ \frac{1}{f}=\frac{1}{v}-\frac{1}{u} \]
Given: \[ f=+20\,cm \] \[ u=-30\,cm \]

Step 2: Substitute the values. \[ \frac{1}{20} = \frac{1}{v} + \frac{1}{30} \] \[ \frac{1}{v} = \frac{1}{20} -\frac{1}{30} \] \[ \frac{1}{v} = \frac{3-2}{60} = \frac{1}{60} \] \[ v=60\,cm \]
Step 3: Choose the correct option. \[ \boxed{v=60\,cm} \]
Therefore, \[ \boxed{(A)} \]
is the correct answer. Quick Tip: Lens Formula: \[ \boxed{\frac{1}{f}=\frac{1}{v}-\frac{1}{u}} \] For a convex lens: \[ \boxed{f>0} \] Always use the Cartesian sign convention.

Step 1: Recall common applications of EM waves. \[ Gamma Rays \rightarrow Cancer Treatment \] \[ X-rays \rightarrow Medical Imaging \] \[ Microwaves \rightarrow Radar Communication \] \[ Radio Waves \rightarrow Broadcasting \]
Step 2: Match the columns. \[ A \rightarrow II \] \[ B \rightarrow III \] \[ C \rightarrow I \] \[ D \rightarrow IV \]
Step 3: Choose the correct option. \[ \boxed{A-II,\;B-III,\;C-I,\;D-IV} \]
Therefore, \[ \boxed{(A)} \]
is the correct answer. Quick Tip: Important EM Wave Applications: \[ \boxed{Radio Waves \rightarrow Broadcasting} \] \[ \boxed{Microwaves \rightarrow Radar} \] \[ \boxed{X-rays \rightarrow Medical Imaging} \] \[ \boxed{Gamma Rays \rightarrow Cancer Therapy} \] Very frequently asked in CUET Physics.

Step 1: Recall the photon energy relation. \[ E=\frac{hc}{\lambda} \]
Given: \[ h=6.63\times10^{-34}\,Js \] \[ c=3\times10^8\,m/s \] \[ \lambda=500\times10^{-9}\,m \]
Step 2: Substitute the values. \[ E= \frac{(6.63\times10^{-34})(3\times10^8)} {500\times10^{-9}} \] \[ E= \frac{19.89\times10^{-26}} {5\times10^{-7}} \] \[ E=3.98\times10^{-19}\,J \]
Step 3: Choose the correct option. \[ \boxed{E=3.98\times10^{-19}\,J} \]
Therefore, \[ \boxed{(B)} \]
is the correct answer. Quick Tip: Photon Energy: \[ \boxed{E=\frac{hc}{\lambda}} \] Useful shortcut: \[ \boxed{E(eV)=\frac{1240}{\lambda(nm)}} \] For shorter wavelength: \[ \boxed{Higher Energy} \]

Step 1: Examine the Assertion.

Control rods are inserted into the reactor core to regulate the chain reaction. \[ \boxed{Assertion (A) is True} \]
Step 2: Examine the Reason.

Control rods made of cadmium or boron absorb excess neutrons. \[ \boxed{Reason (R) is True} \]
Step 3: Determine the relationship.

Since neutrons are responsible for sustaining the chain reaction, absorbing excess neutrons controls the rate of fission.

Thus Reason correctly explains Assertion.

Hence, \[ \boxed{Both A and R are true and R is the correct explanation of A} \]
Therefore, \[ \boxed{(A)} \]
is the correct answer. Quick Tip: Components of a Nuclear Reactor: \[ \boxed{Fuel \rightarrow U^{235}} \] \[ \boxed{Moderator \rightarrow Slows Neutrons} \] \[ \boxed{Control Rods \rightarrow Absorb Neutrons} \] \[ \boxed{Coolant \rightarrow Removes Heat} \] A very important CUET Physics topic.