CUET 2026 May 15 Shift 1 Environmental Science Question Paper with Solutions is available for download here. NTA conducted the CUET 2026 exam from 11th May to 31st May in two shifts.

  • CUET 2026 Environmental Science exam consists of 50 questions for 250 marks to be attempted in 60 minutes.
  • As per the marking scheme, 5 marks are awarded for each correct answer, and 1 mark is deducted for incorrect answer.

Candidates can download CUET 2026 May 15 Shift 1 Environmental Science Question Paper with Answer Key and Solution PDF from links provided below.

CUET 2026 Environmental Science May 15 Shift 1 Question Paper with Solution PDF

CUET May 15 Shift 1 Environmental Science Question Paper 2026 Download PDF Check Solutions

Question 1:

Match the LIST-I with LIST-II
1

Choose the correct answer from the options given below:

  • (A) A - I, B - II, C - III, D - IV
  • (B) A - III, B - II, C - I, D - IV
  • (C) A - III, B - I, C - II, D - IV
  • (D) A - I, B - III, C - II, D - IV
Correct Answer: (C) A - III, B - I, C - II, D - IV
View Solution

Concept:
The Sustainable Development Goals (SDGs) represent a universal call to action adopted by the United Nations General Assembly in 2015 under the 2030 Agenda for Sustainable Development.
The framework comprises 17 interconnected goals, 169 targets, and 232 unique indicators designed to end poverty, protect the planet, and ensure peace and prosperity globally.
Environmental management requires a precise understanding of the thematic scope and statutory targets designated under each numbered goal.

Step 1: Detailed Analysis of Individual Goals:
Each numbered goal possesses a distinct mandate:
1. SDG 10 (Ten) - Reduced Inequalities: This goal focuses on reducing income inequalities and disparities based on age, sex, disability, race, ethnicity, origin, religion, or economic status. Thus, item A matches with objective III.
2. SDG 14 (Fourteen) - Life Below Water: This goal is committed to the conservation and sustainable utilization of oceans, seas, and marine resources to mitigate marine pollution, ocean acidification, and overfishing. Thus, item B matches with objective I.
3. SDG 15 (Fifteen) - Life on Land: This goal seeks to protect, restore, and promote sustainable use of terrestrial ecosystems, sustainably manage forests, combat desertification, and halt land degradation and biodiversity loss. Thus, item C matches with objective II.
4. SDG 16 (Sixteen) - Peace, Justice and Strong Institutions: This goal aims to promote peaceful and inclusive societies, provide access to justice for all, and build effective, accountable, and inclusive institutions at all levels. Thus, item D matches with objective IV.

Step 2: Synthesis and Code Alignment:
Mapping each listed item to its correct roman numeral:
A matches with III.
B matches with I.
C matches with II.
D matches with IV.
The resulting configuration is A - III, B - I, C - II, D - IV.

Final Answer:
The correct matching corresponds to option (C).

Quick Tip: Chronological mnemonic for environmental SDGs:
Goal 13 \(\rightarrow\) Climate Action (Air/Atmosphere).
Goal 14 \(\rightarrow\) Life Below Water (Hydrosphere).
Goal 15 \(\rightarrow\) Life on Land (Lithosphere/Biosphere).
Goal 16 \(\rightarrow\) Peace, Justice and Strong Institutions (Anthroposphere).

Question 2:

Match the LIST-I with LIST-II
2

Choose the correct answer from the options given below:

  • (A) A - I, B - II, C - IV, D - III
  • (B) A - II, B - III, C - I, D - IV
  • (C) A - III, B - IV, C - II, D - I
  • (D) A - IV, B - III, C - II, D - I
Correct Answer: (C) A - III, B - IV, C - II, D - I
View Solution

Concept:
Environmental ethics and political ecology evaluate how diverse human philosophical frameworks influence societal interactions with the natural biosphere.
These philosophies vary across a spectrum ranging from anthropocentric resource conservation to systemic sociopolitical critiques of ecological degradation.

Step 1: Ideological Characterization of Each School of Thought:
1. Stewardship of land (A): Stewardship is rooted in the ethical premise that humans are trustees rather than absolute owners of the Earth. It calls for responsible planning and management of resources to safeguard biodiversity and soil health for future generations. Hence, A corresponds to III.
2. Shallow Ecology (B): Conceptualized by Norwegian philosopher Arne Naess, shallow ecology is fundamentally anthropocentric and technocentric. It advocates environmental conservation primarily to prevent resource depletion, minimize pollution for human welfare, and conserve environment only to meet human needs. Hence, B corresponds to IV.
3. Social Ecology (C): Advanced by Murray Bookchin, social ecology asserts that ecological crises are symptoms of underlying societal pathologies. It argues that the psychological urge to dominate nature stems directly from the domination of human by human, asserting that hierarchical and class systems are responsible for environmental degradation. Hence, C corresponds to II.
4. Socialist Ecology (D): Also referred to as eco-socialism, this perspective integrates Marxist political economy with ecological science. It maintains that capitalism is the real cause of environmental degradation because the profit motive and endless capital expansion inherently deplete natural sinks and commodify nature. Hence, D corresponds to I.

Step 2: Correlating Terms with Descriptions:
Matching the items systematically:
A corresponds to III.
B corresponds to IV.
C corresponds to II.
D corresponds to I.
This establishes the sequence: A - III, B - IV, C - II, D - I.

Final Answer:
The matching combination is represented by option (C).

Quick Tip: Associate foundational theorists with their frameworks:
Arne Naess \(\rightarrow\) Shallow Ecology (utilitarian, anthropocentric).
Murray Bookchin \(\rightarrow\) Social Ecology (social hierarchies and class domination).
Karl Marx / Eco-socialists \(\rightarrow\) Socialist Ecology (capitalist accumulation).
Aldo Leopold \(\rightarrow\) Land Ethic and Land Stewardship.

Question 3:

First "Earth Day" was celebrated on ...................

  • (A) April 20, 1970
  • (B) April 22, 1970
  • (C) April 20, 1972
  • (D) April 22, 1972
Correct Answer: (B) April 22, 1970
View Solution

Concept:
Earth Day is a globally recognized annual event observed to demonstrate civic commitment to ecological conservation, combat climate change, and demand statutory enforcement of environmental protection policies.
It marks the inception of the modern public environmental movement and the mobilization of grassroots eco-activism.

Step 1: Historical Genesis and Catalyzing Events:
In January 1969, an oil well blowout occurred off the coast of Santa Barbara, California, discharging more than three million gallons of crude oil into the Pacific Ocean.
The ensuing environmental destruction killed thousands of sea birds, dolphins, and seals, sparking outrage across the United States.
Senator Gaylord Nelson of Wisconsin resolved to harness the growing public concern by organizing an environmental "teach-in" across American university campuses.

Step 2: Mobilization and Selection of Date:
Senator Nelson recruited young activist Denis Hayes to coordinate national efforts and broaden the campaign beyond academic institutions to include labor unions, schools, and civic communities.
The organizers selected April 22, 1970, because it was a weekday falling between spring break and final college exams, thereby optimizing student attendance.
On that historic day, roughly 20 million Americans (nearly 10 percent of the total United States population at the time) took to the streets to peacefully protest industrial pollution, smog, oil spills, and toxic dumps.

Step 3: Legislative Legacy and Global Expansion:
The widespread success of the April 22, 1970 demonstration led directly to the establishment of the United States Environmental Protection Agency (US EPA) in December 1970.
It also facilitated the passage of landmark legislation including the Clean Air Act of 1970, the Clean Water Act of 1972, and the Endangered Species Act of 1973.
In 1990, Denis Hayes took the campaign global, mobilizing 200 million people across 141 nations.

Final Answer:
The first Earth Day was celebrated on April 22, 1970, which corresponds to option (B).

Quick Tip: Key environmental dates:
- Earth Day: April 22 (first held in 1970).
- World Environment Day: June 5 (Stockholm Conference, 1972).
- International Day for Biological Diversity: May 22.
- World Ozone Day: September 16.

Question 4:

Which of the following issue is NOT addressed by Eco-feminism?

  • (A) Animal rights
  • (B) Agriculture development
  • (C) Air Pollution
  • (D) Nuclear weapon policies
Correct Answer: (C) Air Pollution
View Solution

Concept:
Ecofeminism is an interdisciplinary branch of environmental philosophy and feminist theory that developed in the late 1970s.
It asserts that a direct ideological and structural connection exists between the patriarchal oppression of women and the mechanistic exploitation of nature.
It deconstructs hierarchical dualisms (culture/nature, male/female, reason/emotion) that justify the domination of living systems.

Step 1: Evaluation of Core Thematic Areas in Ecofeminism:
1. Animal Rights: Ecofeminist scholars such as Carol J. Adams (author of The Sexual Politics of Meat) and Marti Kheel directly link speciesism with sexism. They argue that the exploitation, commodification, and consumption of animal bodies mirror the patriarchal subordination and bodily objectification of women. Animal liberation is therefore a key pillar of ecofeminism.
2. Agriculture Development: Prominent ecofeminist thinkers like Vandana Shiva have written extensively on how modern industrial agriculture undermines traditional farming communities. Monocultures and corporate intellectual property rights over seeds marginalize rural women, who have historically been the primary conservators of indigenous agro-biodiversity.
3. Nuclear Weapon Policies: The historical origins of ecofeminist activism are deeply linked to the anti-nuclear and peace movements, such as the Women’s Pentagon Action (1980) and the Greenham Common Women’s Peace Camp in the United Kingdom. Ecofeminists criticize nuclear testing, militarism, and weapons of mass destruction as patriarchal expressions of technological domination over life.

Step 2: Identification of Non-Thematic Issue:
Air Pollution: While ecofeminists oppose environmental degradation generally, air pollution is treated primarily as a physical, atmospheric, and chemical engineering problem. It is addressed through emission limits, monitoring protocols, and air quality standards rather than as a core philosophical subject of ecofeminist critique.

Final Answer:
Air pollution is not an issue distinctively addressed as a foundational focus of ecofeminism, corresponding to option (C).

Quick Tip: Ecofeminist issues target the patriarchal domination triad:
1. Domination of female and non-human bodies (Animal rights).
2. Destruction of traditional, female-led biodiversity systems (Agriculture/Seeds).
3. Aggressive military and technological destruction (Nuclear weapons).
Technical pollution issues (such as air pollution monitoring) belong to physical environmental engineering.

Question 5:

Which of the following formula is correct to calculate "the average rate of change in the number of organisms per time, per organisms", in population growth rate ?

Where, N represent the number of organisms and t is the time.

  • (A) \(\Delta N\)
  • (B) \(\frac{\Delta N}{N \Delta t}\)
  • (C) \(\frac{\Delta N}{\Delta t}\)
  • (D) \(\frac{\Delta t}{N \Delta N}\)
Correct Answer: (B) \(\frac{\Delta N}{N \Delta t}\)
View Solution

Concept:
Population dynamics involves quantifying changes in population size over space and time.
In population ecology, demographic rates can be expressed either as absolute changes across the whole population or as specific per capita rates normalized per individual organism.

Step 1: Derivation of Absolute Population Growth Rate:
Let \(N\) denote the initial population size (number of organisms).
Let \(\Delta N\) denote the change in the total number of individuals over a specified time interval \(\Delta t\).
The absolute rate of population growth describes the number of individuals added or lost per unit of time:
\[ \text{Absolute Growth Rate} = \frac{\Delta N}{\Delta t} \]

Step 2: Derivation of Per Capita Growth Rate:
The problem specifies the rate of change:
- "per time" \(\implies\) divided by \(\Delta t\)
- "per organisms" \(\implies\) divided by the number of individuals \(N\)
Normalizing the absolute growth rate to a single individual basis yields the average per capita rate of change:
\[ \text{Per Capita Growth Rate} = \frac{1}{N} \left( \frac{\Delta N}{\Delta t} \right) = \frac{\Delta N}{N \Delta t} \] In continuous differential notation, this corresponds to the specific growth rate:
\[ r = \frac{1}{N} \frac{dN}{dt} \] where \(r\) is the intrinsic rate of natural increase.

Step 3: Examination of Incorrect Formulations:
- Option (A), \(\Delta N\), is simply the absolute net increment in individual counts.
- Option (C), \(\frac{\Delta N}{\Delta t}\), represents the absolute population growth rate per unit time, but is not normalized per organism.
- Option (D), \(\frac{\Delta t}{N \Delta N}\), is dimensionally inverted.

Final Answer:
The correct mathematical formulation is \(\frac{\Delta N}{N \Delta t}\), corresponding to option (B).

Quick Tip: Dimensional check for demographic rates:
"Per unit time" requires \(\Delta t\) in the denominator.
"Per organism" requires \(N\) in the denominator.
Net change \(\Delta N\) is in the numerator, yielding \(\frac{\Delta N}{N \Delta t}\) with units of \(\text{time}^{-1}\).

Question 6:

Arrange the following forest types according to latitudinal zonation from equator towards poles
A. Deciduous Forest
B. Coniferous Forest
C. Grassland
D. Tundra Forest
E. Tropical rain Forest

Choose the correct answer from the options given below:

  • (A) C, E, B, A, D
  • (B) C, E, A, B, D
  • (C) E, C, A, B, D
  • (D) E, C, B, A, D
Correct Answer: (C) E, C, A, B, D
View Solution

Concept:
Latitudinal zonation describes the predictable distribution of terrestrial biomes across the Earth from the equator (\(0^\circ\)) to the polar regions (\(90^\circ\)).
This distribution is determined by incoming solar radiation, temperature gradients, and global atmospheric circulation cells, which dictate precipitation patterns.

Step 1: Spatial Characterization of Biomes from Low to High Latitude:
1. Tropical Rain Forest (E): Situated directly along the equatorial belt (\(0^\circ\) to approximately \(10^\circ-15^\circ\) North and South). These forests experience high temperatures, intense insolation, and abundant year-round precipitation.
2. Grasslands (C): Positioned immediately poleward of the wet equatorial forests (\(15^\circ\) to \(30^\circ\) North and South), transitioning into tropical savannas and subtropical grasslands where precipitation becomes distinctly seasonal.
3. Temperate Deciduous Forest (A): Occurring in the mid-latitudes (\(35^\circ\) to \(50^\circ-55^\circ\) North), characterized by four distinct seasons, moderate rainfall, and broadleaf trees that shed their foliage annually.
4. Coniferous Forest (B): Also known as the Boreal forest or Taiga, this biome occupies the sub-arctic latitudinal belt (\(55^\circ\) to \(65^\circ-70^\circ\) North). It is dominated by evergreen gymnosperms (spruce, fir, pine) adapted to long, freezing winters.
5. Tundra (D): Located at the highest latitudes (\(> 65^\circ-70^\circ\) North) bordering the Arctic ocean, characterized by permafrost, low growing seasons, and dwarf shrubby vegetation.

Step 2: Sequential Ordering from Equator to Pole:
Ordering these biomes from the lowest latitude (equator) to the highest latitude (poles):
\[ \text{E (Tropical Rain Forest)} \rightarrow \text{C (Grassland)} \rightarrow \text{A (Deciduous Forest)} \rightarrow \text{B (Coniferous Forest)} \rightarrow \text{D (Tundra)} \]

Final Answer:
The correct latitudinal sequence is E, C, A, B, D, which corresponds to option (C).

Quick Tip: Latitudinal zonation parallels altitudinal zonation:
Equator \(\rightarrow\) Tropical Rainforest.
Subtropics \(\rightarrow\) Grassland/Savanna.
Mid-latitudes \(\rightarrow\) Temperate Deciduous Forest.
High-latitudes \(\rightarrow\) Coniferous Forest (Taiga).
Polar margins \(\rightarrow\) Tundra.

Question 7:

Arrange the following ecological succession in the lithosphere (rocks) from final to initial succession stage
A. Moss stage
B. Foliose - lichens stage
C. Herbaceous stage
D. Crustose - lichens Stage
E. Shrub stage

Choose the correct answer from the options given below:

  • (A) E, C, D, A, B
  • (B) E, C, B, A, D
  • (C) E, C, A, B, D
  • (D) E, C, A, D, B
Correct Answer: (C) E, C, A, B, D
View Solution

Concept:
Primary ecological succession on a bare, subaerial rock substrate is designated as a lithosere (a type of xerosere).
Through progressive pedogenesis and microclimatic modifications, pioneer organisms gradually alter the hostile rock environment, allowing more complex plant forms to colonize the substrate over time.

Step 1: Normal Chronological Stages of a Lithosere (Pioneer to Climax):
1. Crustose Lichen Stage (D): Pioneer colonizers (such as Rhizocarpon and Lecanora) adhere tightly to bare rock surfaces, secreting carbonic and lichenic acids that etch rock minerals to form the first traces of mineral dust.
2. Foliose Lichen Stage (B): Leaf-like lichens with protruding thalli (such as Parmelia and Dermatocarpon) establish themselves over the crustose crust, accumulating wind-blown dust and organic detritus.
3. Moss Stage (A): Xerophytic mosses (such as Grimmia and Polytrichum) overgrow the decaying lichens, forming thick rhizoid mats that retain moisture and accelerate substrate weathering.
4. Herbaceous Stage (C): Deeper organic matter supports the germination of annual and perennial herbs, whose penetrating root systems break open rock crevices.
5. Shrub Stage (E): Shrubs (such as Rhus and Rubus) shade out herbaceous species, providing conditions for tree saplings to develop toward the climax woodland community.

Step 2: Reverse Ordering (Final to Initial):
The question explicitly demands ordering from the final to the initial succession stage:
- Final stage among the options: Shrub stage (E)
- Preceding stage: Herbaceous stage (C)
- Preceding stage: Moss stage (A)
- Preceding stage: Foliose lichens stage (B)
- Pioneer/Initial stage: Crustose lichens stage (D)
The resulting sequence is E \(\rightarrow\) C \(\rightarrow\) A \(\rightarrow\) B \(\rightarrow\) D.

Final Answer:
The reverse sequence corresponds to option (C).

Quick Tip: Always check the direction requested:
- Forward (Initial to Final): Crustose (D) \(\rightarrow\) Foliose (B) \(\rightarrow\) Moss (A) \(\rightarrow\) Herb (C) \(\rightarrow\) Shrub (E).
- Backward (Final to Initial): Shrub (E) \(\rightarrow\) Herb (C) \(\rightarrow\) Moss (A) \(\rightarrow\) Foliose (B) \(\rightarrow\) Crustose (D).
Reversing the order is a common trap in succession questions.

Question 8:

Which of the following ecological pyramid is always inverted?

  • (A) Pyramid of Number in Grassland ecosystem
  • (B) Pyramid of Number in Parasitic food chain
  • (C) Pyramid of Biomass in forest ecosystem
  • (D) Pyramid of energy in grassland ecosystem
Correct Answer: (B) Pyramid of Number in Parasitic food chain
View Solution

Concept:
Ecological pyramids, introduced by Charles Elton, graphically depict the trophic structure of an ecosystem across successive feeding levels.
They illustrate the distribution of numbers, dry biomass, or energy flow from primary producers (\(T_1\)) to apex predators (\(T_n\)).
An upright pyramid has a wide base tapering toward the top, whereas an inverted pyramid has a narrow base that broadens at higher trophic levels.

Step 1: Evaluation of Each Ecological Pyramid Option:
1. Pyramid of Number in Grassland ecosystem: Upright. Millions of individual grass plants form a broad base supporting thousands of herbivorous insects, which in turn support smaller numbers of insectivorous birds and apex raptors.
2. Pyramid of Biomass in forest ecosystem: Upright. The standing crop biomass of massive perennial trees (wood, roots, foliage) is far greater than the biomass of herbivorous animals, which exceeds that of top carnivores.
3. Pyramid of Energy in grassland ecosystem: Always upright. Under the Second Law of Thermodynamics and Lindeman’s 10% law, energy is dissipated as metabolic heat at each transfer, so energy content declines at every successive trophic level across all ecosystems without exception.
4. Pyramid of Number in Parasitic food chain: Always inverted. A single primary producer (e.g., an oak tree) acts as host to hundreds of herbivorous birds or mammals. Each bird hosts thousands of ectoparasites and endoparasites (lice, ticks, and helminths), and each parasite can harbor millions of hyperparasitic bacteria and protozoa. The count of individuals increases at each successive trophic step.

Step 2: Conclusion on Shape Inversion:
Because individual organism counts continuously multiply as one moves up a parasitic food chain, its pyramid of numbers is consistently inverted.

Final Answer:
The pyramid of numbers in a parasitic food chain is always inverted, corresponding to option (B).

Quick Tip: Pyramid Inversion Rules:
- Pyramid of Energy: Never inverted (always upright).
- Pyramid of Numbers: Inverted in parasitic food chains; spindle-shaped in a tree ecosystem.
- Pyramid of Biomass: Inverted in aquatic ecosystems (phytoplankton vs. fish).

Question 9:

Diversity of habitat over the total landscape or geographical area is referred to as ..................

  • (A) Genetic diversity
  • (B) Alfa diversity
  • (C) Beta diversity
  • (D) Gamma diversity
Correct Answer: (D) Gamma diversity
View Solution

Concept:
Biodiversity can be evaluated across multiple biological scales, ranging from allelic variations within a single population to regional landscape heterogeneity.
In 1960, ecologist Robert H. Whittaker formulated a spatial hierarchy of species diversity comprising alpha (\(\alpha\)), beta (\(\beta\)), and gamma (\(\gamma\)) diversity components.

Step 1: Characterization of Diversity Scales:
1. Genetic Diversity: Quantifies the heritable nucleotide and allelic variations present among individuals within a single species population or across different populations of that species.
2. Alpha (\(\alpha\)) Diversity: Refers to local diversity, representing species richness within a single homogenous community, site, or discrete ecosystem.
3. Beta (\(\beta\)) Diversity: Represents differentiation diversity, measuring the rate of species turnover or degree of change in taxonomic composition between distinct habitats or along an environmental gradient.
4. Gamma (\(\gamma\)) Diversity: Represents regional diversity. It measures the overall diversity of species and habitats across an entire geographical region or landscape. It integrates both the local alpha richness of individual patches and the beta turnover occurring between those patches:
\[ \gamma = \bar{\alpha} \times \beta \]

Step 2: Assessment of the Problem Statement:
The question explicitly asks for the metric that captures the "diversity of habitat over the total landscape or geographical area."
By Whittaker’s definition, the total diversity assessed at the landscape or macro-geographical scale is gamma (\(\gamma\)) diversity.

Final Answer:
The total landscape or regional scale diversity is Gamma diversity, corresponding to option (D).

Quick Tip: Whittaker’s Biodiversity Scales:
- \(\alpha\)-diversity \(\rightarrow\) Point/local scale (within a single habitat).
- \(\beta\)-diversity \(\rightarrow\) Gradient scale (turnover between two habitats).
- \(\gamma\)-diversity \(\rightarrow\) Landscape/regional scale (total geographic pool).

Question 10:

Parasites, that feed on external surface of the host organism are called ...................

  • (A) Endo parasites
  • (B) Brood parasites
  • (C) Ecto parasites
  • (D) Commens parasites
Correct Answer: (C) Ecto parasites
View Solution

Concept:
Parasitism is an interspecific interaction (+, -) where one organism (the parasite) obtains nourishment and shelter by living on or inside another living organism (the host), typically compromising the host’s fitness without causing immediate death.
Parasites are classified based on their anatomical location relative to the host’s body.

Step 1: Classification of Parasites by Location and Mode:
1. Ectoparasites: Parasitic organisms that attach to, reside on, and feed upon the external surface (skin, hair, feathers, gills) of the host organism. Common examples include human head lice (Pediculus humanus), ticks (Ixodes spp.) on dogs, marine copepods on fish, and the stem holoparasite Cuscuta (dodder) growing over host foliage.
2. Endoparasites: Organisms that live internally within host tissues, blood vessels, or lumen organs (e.g., Plasmodium inside liver cells and erythrocytes, Ascaris lumbricoides inside human intestines, and liver flukes inside the bile duct).
3. Brood Parasites: A specialized avian reproductive strategy where the parasite deposits eggs in the nest of another bird species, leaving parental care and incubation entirely to the host (e.g., the Asian Koel laying eggs in a Crow’s nest).
4. Commensalism: A non-parasitic symbiotic relationship (+, 0) where the commensal benefits while the host remains unaffected.

Step 2: Matching with the Question Statement:
The question asks for parasites that feed on the external surface of the host organism.
By biological definition, these organisms are termed ectoparasites.

Final Answer:
Parasites feeding on the external surface of the host are ectoparasites, corresponding to option (C).

Quick Tip: Anatomical prefixes for parasites:
"Ecto-" = External / Outside (Ectoparasite: lice, ticks, fleas, leeches).
"Endo-" = Internal / Inside (Endoparasite: tapeworms, roundworms, malaria parasite).

Question 11:

Commensalism is a kind of population interaction, in which ...................

  • (A) Both the species are benenfitted.
  • (B) One species is benefitted and other is harmed.
  • (C) One species is benefitted and other is unaffected.
  • (D) Both the species are harmed.
Correct Answer: (C) One species is benefitted and other is unaffected.
View Solution

Concept:
Population interactions describe the ecological relationships established between individuals of different species living together in a biological community.
These biotic interactions are classified based on whether the association increases (+), decreases (-), or has no measurable impact (0) on the fitness, growth, and survival of the interacting species.

Step 1: Systematic Overview of Interspecific Interactions:
1. Mutualism (+, +): An obligate or facultative association where both species derive mutual physiological or nutritional benefits (e.g., lichens, rhizobium-legume symbiosis, pollination vectors).
2. Parasitism and Predation (+, -): Detrimental associations where one species benefits at the expense of the other, which is either harmed or consumed.
3. Competition (-, -): Interaction where both species experience reduced fitness due to mutually limited access to shared essential resources (light, water, food, nesting space).
4. Amensalism (-, 0): Association where one species is inhibited or harmed, while the other species remains completely unaffected (e.g., Penicillium secreting an antibiotic that kills nearby bacteria).
5. Commensalism (+, 0): An interaction where one species derives nutritional, transport, or shelter benefits, while the second species remains unaffected (neither harmed nor benefitted).

Step 2: Ecological Examples of Commensalism:
- An epiphytic orchid growing on the branch of a large mango tree obtains sunlight and anchorage without absorbing nutrients or damaging the host tree.
- Cattle egrets foraging beside grazing herbivores feed on insects stirred up by the livestock’s movement, while the cattle remain unaffected.
- Barnacles attached to the skin of a whale receive constant water flow and planktonic food without causing metabolic harm or benefit to the whale.

Final Answer:
In commensalism, one species is benefitted and the other is unaffected, corresponding to option (C).

Quick Tip: Sign conventions for ecological interactions:
- Mutualism: (+, +)
- Commensalism: (+, 0)
- Amensalism: (-, 0)
- Predation / Parasitism: (+, -)
- Competition: (-, -)

Question 12:

Which of the following are criteria air pollutants under NAAQS in India?
A. CO
B. \(\text{CO}_2\)
C. \(\text{NO}_2\)
D. \(\text{SO}_2\)
E. Pb

Choose the correct answer from the options given below:

  • (A) A, B, C and D only
  • (B) B, C, D and E only
  • (C) A, C, D and E only
  • (D) A, C and E only
Correct Answer: (C) A, C, D and E only
View Solution

Concept:
National Ambient Air Quality Standards (NAAQS) are statutory limits notified by the Central Pollution Control Board (CPCB) under the provisions of the Air (Prevention and Control of Pollution) Act, 1981.
These standards establish maximum permissible ambient concentrations for designated "criteria pollutants" to protect public health and the environment.

Step 1: Analysis of the 12 Mandated NAAQS Pollutants:
In November 2009, the Ministry of Environment, Forest and Climate Change revised the NAAQS to mandate regulatory limits for 12 key ambient air pollutants:
1. Sulphur Dioxide (\(\text{SO}_2\))
2. Nitrogen Dioxide (\(\text{NO}_2\))
3. Particulate Matter (\(\text{PM}_{10}\))
4. Fine Particulate Matter (\(\text{PM}_{2.5}\))
5. Ozone (\(\text{O}_3\))
6. Lead (\(\text{Pb}\))
7. Carbon Monoxide (\(\text{CO}\))
8. Ammonia (\(\text{NH}_3\))
9. Benzene (\(\text{C}_6\text{H}_6\))
10. Benzo(a)pyrene (BaP)
11. Arsenic (\(\text{As}\))
12. Nickel (\(\text{Ni}\))

Step 2: Evaluation of Options Provided in the Question:
- A. CO (Carbon Monoxide): Included under NAAQS (8-hour standard of \(2.0\text{ mg/m}^3\)).
- B. \(\text{CO}_2\) (Carbon Dioxide): Not a criteria pollutant under Indian NAAQS. Although it is the major greenhouse gas driving global climate change, it is non-toxic at normal atmospheric concentrations and is not regulated as a conventional urban criteria air pollutant under NAAQS.
- C. \(\text{NO}_2\) (Nitrogen Dioxide): Included under NAAQS (annual standard of \(40\,\mu\text{g/m}^3\)).
- D. \(\text{SO}_2\) (Sulphur Dioxide): Included under NAAQS (annual standard of \(50\,\mu\text{g/m}^3\)).
- E. Pb (Lead): Included under NAAQS (annual standard of \(0.50\,\mu\text{g/m}^3\)).
Therefore, items A, C, D, and E are criteria air pollutants, while item B is not.

Final Answer:
The criteria air pollutants are A, C, D, and E only, corresponding to option (C).

Quick Tip: Do not confuse Greenhouse Gases with Criteria Air Pollutants:
\(\text{CO}_2\) is a greenhouse gas, but NOT a NAAQS criteria air pollutant in India.
The toxic carbon oxide regulated under NAAQS is Carbon Monoxide (\(\text{CO}\)).

Question 13:

Arrange the following in increasing order of their sand content
A. Sandy soil
B. Silty Soil
C. Clayey soil
D. Loamy soil

Choose the correct answer from the options given below:

  • (A) C, D, B, A
  • (B) C, B, D, A
  • (C) A, D, B, C
  • (D) B, C, D, A
Correct Answer: (B) C, B, D, A
View Solution

Concept:
Soil texture is defined by the relative proportions of three primary mineral size separates: sand (coarse, \(0.05\) to \(2.0\text{ mm}\)), silt (medium, \(0.002\) to \(0.05\text{ mm}\)), and clay (colloidal, \(< 0.002\text{ mm}\)).
Soil classification schemes (such as the USDA textural triangle) delineate soil textural classes based on the relative weight percentages of these three mineral components.

Step 1: Quantitative Evaluation of Sand Percentage in Major Soil Classes:
1. Clayey Soil (C): Dominated by fine, cohesive clay colloids (\(> 40-50\%\) clay content). Its sand content is typically the lowest among major classes, generally remaining below \(15-20\%\) by weight.
2. Silty Soil (B): Dominated by silt particles (\(> 80\%\) silt). Sand particles typically constitute only about \(10-20\%\) of pure silt soils.
3. Loamy Soil (D): An agricultural soil blend comprising approximately equal influence of sand, silt, and clay. A standard loam contains approximately \(40-50\%\) sand, \(30-40\%\) silt, and \(10-20\%\) clay.
4. Sandy Soil (A): Characterized by high porosity, low water-holding capacity, and large particle diameters. By definition, sandy soil consists of at least \(70-85\%\) sand particles by weight.

Step 2: Arranging in Increasing Order (Lowest to Highest):
Ordering the soils by increasing sand fraction:
\[ \text{Clayey soil (C)} < \text{Silty soil (B)} < \text{Loamy soil (D)} < \text{Sandy soil (A)} \] This yields the sequence: C, B, D, A.

Final Answer:
The correct increasing order of sand content is C, B, D, A, which corresponds to option (B).

Quick Tip: Sand Content Hierarchy:
Clay (\(< 20\%\)) \(<\) Silt (\(10-20\%\)) \(<\) Loam (\(40-50\%\)) \(<\) Sand (\(> 70-85\%\)).
Clay holds water best because it has the lowest sand and finest pore spaces, while sandy soil drains rapidly due to its dominant coarse sand content.

Question 14:

Which of the following soil horizon of a typical soil profile will have the highest abudance of organic matter?

  • (A) C horizon
  • (B) A horizon
  • (C) B horizon
  • (D) R horizon
Correct Answer: (B) A horizon
View Solution

Concept:
A soil profile is a vertical cross-section of the regolith from the surface down to unweathered bedrock, displaying distinct parallel layers called master horizons (O, A, E, B, C, and R).
These horizons develop over centuries through physical weathering, chemical leaching, and the biological breakdown of plant and animal matter.

Step 1: Structural Differentiation of Soil Horizons:
1. A Horizon (Topsoil): The uppermost mineral horizon, often referred to as the topsoil. It is characterized by an accumulation of humified organic matter thoroughly mixed with fine mineral particles. The decomposition of surface litter by earthworms, fungi, and bacteria enriches this layer with dark, fertile humus, giving it the highest organic matter content among the given options.
2. B Horizon (Subsoil): The zone of illuviation (accumulation), where silicate clays, iron, and aluminium oxides leached from overlying horizons precipitate. It contains significantly less organic matter than the topsoil.
3. C Horizon (Parent Material): A substratum composed of partially disintegrated and weathered parent rock. It is devoid of biological humification and contains negligible organic matter.
4. R Horizon (Bedrock): The bottom layer of consolidated, unweathered solid rock (such as granite, basalt, limestone, or sandstone) with no organic content.

Step 2: Comparison and Conclusion:
Although a dedicated organic O horizon exists in undisturbed forest soils, among the standard mineral horizons listed in the options (A, B, C, and R), the A horizon contains the highest abundance of organic matter.

Final Answer:
The soil horizon with the highest organic matter content among the choices is the A horizon, corresponding to option (B).

Quick Tip: Master Soil Horizons from top to bottom:
- O \(\rightarrow\) Organic surface litter.
- A \(\rightarrow\) Topsoil (maximum humus and biological activity).
- E \(\rightarrow\) Zone of eluviation (bleached/leached).
- B \(\rightarrow\) Subsoil (zone of illuviation/accumulation).
- C \(\rightarrow\) Weathered parent rock.
- R \(\rightarrow\) Consolidated bedrock.

Question 15:

Which of the following can directly cause eutrophication in lakes?
A. Sewage waste
B. Acidic precipitation
C. Agriculture runoff
D. Sulfur rich effluent from thermal power plant
E. Municipal waste water

Choose the correct answer from the options given below:

  • (A) A, C and D only
  • (B) B, D and E only
  • (C) B, C and D only
  • (D) A, C and E only
Correct Answer: (D) A, C and E only
View Solution

Concept:
Eutrophication refers to the accelerated nutrient enrichment of aquatic systems, primarily by nitrogen (\(\text{N}\)) and phosphorus (\(\text{P}\)).
This influx stimulates rapid blooms of algae and cyanobacteria, which subsequently decompose, depleting dissolved oxygen and causing fish kills.

Step 1: Detailed Examination of Potential Sources:
- A. Sewage waste: Untreated domestic sewage is rich in organic nitrogen, urea, proteins, and phosphates from human excreta and detergents. Its discharge directly enriches aquatic systems, driving rapid eutrophication.
- B. Acidic precipitation: Acid rain contains sulphuric and nitric acids resulting from \(\text{SO}_2\) and \(\text{NO}_x\) emissions. It lowers the pH of lakes and leaches toxic aluminium ions, causing lake acidification rather than nutrient enrichment.
- C. Agriculture runoff: Farmland runoff carries dissolved inorganic fertilizers (synthetic urea, ammonium nitrate, and superphosphates). These are primary drivers of cultural eutrophication in surface water bodies worldwide.
- D. Sulfur-rich effluent from thermal power plants: Discharges sulphates, heavy metals, and warm cooling water (thermal pollution). It does not provide the limiting nitrogen and phosphorus nutrients required to stimulate algal blooms.
- E. Municipal waste water: Municipal wastewater contains greywater loaded with synthetic detergents, surfactants, and phosphates, directly adding nutrients to receiving water bodies.

Step 2: Synthesizing the Direct Drivers:
The sources that directly supply limiting plant nutrients (N and P) and trigger algal blooms are:
- Sewage waste (A)
- Agriculture runoff (C)
- Municipal waste water (E)
Items B and D contribute to acidification and industrial chemical pollution rather than eutrophication.

Final Answer:
The sources that directly cause eutrophication are A, C, and E only, corresponding to option (D).

Quick Tip: Remember: Eutrophication is driven by excess Nitrogen (\(\text{N}\)) and Phosphorus (\(\text{P}\)).
Look for agricultural runoff (fertilizers) and domestic sewage/wastewater (detergents and excreta).
Acid rain and sulfur effluents cause lake acidification, not eutrophication.

Question 16:

Choose the correct statement about water pollution?
A. Dissolved oxygen is inversely proportional to BOD in waste water.
B. Dissolved ion increases turbidity of water.
C. Turbidity is a measure of transparency of water.
D. Alkalinity is caused by carbonate, bicarbonate and hydroxides.
E. Alkalinity is base neutralising capacity of water.

Choose the correct answer from the options given below:

  • (A) A, B, C and D Only
  • (B) A, B, C and E Only
  • (C) A, C and D Only
  • (D) A, C, D and E Only
Correct Answer: (C) A, C and D Only
View Solution

Concept:
Water quality assessment requires monitoring physical, chemical, and biological parameters.
Key indicators include Biochemical Oxygen Demand (BOD), Dissolved Oxygen (DO), Turbidity, and Alkalinity.

Step 1: Statement-by-Statement Scientific Verification:
- Statement A: Biochemical Oxygen Demand (BOD) measures the amount of dissolved oxygen consumed by aerobic bacteria to break down biodegradable organic matter. As organic waste increases, microbial consumption of DO rises, driving ambient DO down. Hence, DO is inversely related to BOD in wastewater. (Correct)
- Statement B: Turbidity is caused by suspended and colloidal solids (such as clay, silt, and finely divided organic matter) that scatter light. Dissolved ions (e.g., \(\text{Na}^+\), \(\text{Cl}^-\), \(\text{Ca}^{2+}\)) do not scatter light; they contribute to Total Dissolved Solids (TDS) and electrical conductivity. (Incorrect)
- Statement C: Turbidity quantifies the cloudiness or haze of a liquid, providing an optical measure of its light penetration and loss of transparency. (Correct)
- Statement D: Alkalinity in natural waters is predominantly produced by three chemical bases: bicarbonate ions (\(\text{HCO}_3^-\)), carbonate ions (\(\text{CO}_3^{2-}\)), and hydroxide ions (\(\text{OH}^-\)). (Correct)
- Statement E: Alkalinity is defined as the capacity of water to neutralize acids (acid-neutralizing capacity). Conversely, acidity is the base-neutralizing capacity of water. (Incorrect)

Step 2: Aggregation of Valid Statements:
The valid statements are A, C, and D. Statements B and E are scientifically incorrect.

Final Answer:
The correct option is A, C and D Only, corresponding to option (C).

Quick Tip: Key definitions for water chemistry:
- Alkalinity = Acid-neutralizing capacity (buffering power against acids).
- Acidity = Base-neutralizing capacity.
- Turbidity = Caused by suspended particles, NOT dissolved ions.
- High BOD \(\implies\) Low Dissolved Oxygen (DO).

Question 17:

Which of the following is NOT an air pollution control measure/ technique?

  • (A) Bag houses
  • (B) Electrostatic Precipitators
  • (C) High Volume Air Sampler
  • (D) Cyclone Chambers
Correct Answer: (C) High Volume Air Sampler
View Solution

Concept:
Industrial air pollution management relies on engineering devices designed to capture, separate, or neutralize particulate matter and gaseous pollutants from industrial flue gas emissions before they are discharged through stacks.
In contrast, environmental monitoring instruments are used to measure the concentration of ambient pollutants in the atmosphere.

Step 1: Evaluation of Air Pollution Control Technologies:
1. Bag houses (Fabric Filters): Industrial particulate control units containing long, tubular fabric filter bags. When dust-laden flue gas passes through the fabric, particulate matter is retained on the bag surface, achieving capture efficiencies exceeding \(99\%\) for fine particles.
2. Electrostatic Precipitators (ESP): Filtration devices that use high-voltage electrode wires to ionize incoming gas streams and charge passing particles. The negatively charged particles are then attracted to grounded collecting plates, effectively removing fly ash from coal-fired power plants.
3. Cyclone Chambers (Centrifugal Collectors): Inertial separators that utilize centrifugal force generated by a vortex flow to separate heavier particulates (\(> 10\,\mu\text{m}\)) from flue gas streams.

Step 2: Identification of Monitoring Equipment:
High Volume Air Sampler (HVAS): This is an analytical sampling instrument used in ambient air quality stations. It draws a measured volume of ambient air through a pre-weighed glass-fiber filter at a rate of \(1.1\) to \(1.7\text{ m}^3/\text{min}\) over a 24-hour period to measure the concentration of Suspended Particulate Matter (SPM and \(\text{PM}_{10}\)).
The High Volume Air Sampler is a measuring instrument used for ambient air analysis, not an industrial abatement or control device.

Final Answer:
A High Volume Air Sampler is an air quality monitoring instrument rather than a pollution control technique, corresponding to option (C).

Quick Tip: Particulate control devices remove pollutants from flue gas:
- Gravity settling chambers
- Cyclone separators
- Baghouse fabric filters
- Electrostatic precipitators (ESP)
- Venturi scrubbers
Samplers (e.g., High Volume Sampler) only measure pollutants; they do not control emissions.

Question 18:

Arrange the following steps involved in the sewage treatment in correct order from initial to the last.
A. Coagulation and Flocculation
B. Chemical disinfection
C. Screening
D. Distribution of treated water
E. Sediment and filtration

Choose the correct answer from the options given below:

  • (A) E, C, B, A, D
  • (B) C, E, B, A, D
  • (C) C, E, A, B, D
  • (D) C, A, B, E, D
Correct Answer: (C) C, E, A, B, D
View Solution

Concept:
Sewage and wastewater treatment comprises sequential stages: preliminary, primary, secondary, and tertiary treatments.
These stages progressively remove large floating solids, settleable organic sludge, colloidal matter, and pathogenic organisms before the treated effluent is redistributed or discharged.

Step 1: Step-by-Step Wastewater Treatment Process:
1. Screening (C): The initial preliminary physical step. Raw influent passes through coarse and fine bar screens to intercept large floating debris, plastics, and rags to prevent clogging of downstream pumps.
2. Sedimentation and Filtration (E): In primary treatment, wastewater enters primary settling basins where gravity settling separates settleable suspended organic solids as primary sludge, followed by filtration to remove coarse particulate matter.
3. Coagulation and Flocculation (A): Chemical coagulants (such as alum or ferric chloride) are mixed into the water to destabilize colloidal charges, followed by gentle flocculation to form settleable flocs.
4. Chemical Disinfection (B): Disinfectants such as chlorine gas, sodium hypochlorite, or ozone are added to destroy pathogenic bacteria, viruses, and parasites before water release.
5. Distribution of Treated Water (D): The final step where treated, disinfected water is pumped through pipelines for municipal reuse, agricultural irrigation, or safely returned to water networks.

Step 2: Chronological Sequence of Operations:
Arranging these operational stages in order:
C (Screening) → E (Sediment and filtration) → A (Coagulation and Flocculation) → B (Chemical disinfection) → D (Distribution)

Final Answer:
The correct operational order is C, E, A, B, D, which corresponds to option (C).

Quick Tip: Standard wastewater treatment sequence:
1. Screening (preliminary physical removal).
2. Primary sedimentation (gravity settling).
3. Secondary/tertiary coagulation and flocculation.
4. Disinfection (chlorination to kill pathogens).
5. Effluent distribution or reuse.

Question 19:

Gandhiji’s concept of development is Sarvodaya which can be achieved through ..................

  • (A) Navodaya
  • (B) Suryaodaya
  • (C) Antyodaya
  • (D) Sampuranodaya
Correct Answer: (C) Antyodaya
View Solution

Concept:
Mahatma Gandhi’s economic philosophy proposed an alternative paradigm to centralized industrial development, emphasizing moral progress, decentralized village economies (Gram Swaraj), and self-reliance.
His overarching developmental vision was termed Sarvodaya, which he coined in 1908 while paraphrasing John Ruskin’s treatise Unto This Last.

Step 1: Philosophical Framework of Sarvodaya:
- Sarvodaya translates to "universal upliftment" or the "welfare and progress of all".
- Gandhi argued that unlike Western utilitarianism, which seeks "the greatest good of the greatest number," a just society must ensure the welfare of every individual without exception.
- True development cannot be achieved through aggregate economic indices if the poorest individuals remain destitute and marginalized.

Step 2: The Operational Mechanism of Antyodaya:
- To realize Sarvodaya, Gandhi introduced the principle of Antyodaya, which translates to the "upliftment of the last person".
- According to this principle, any development initiative must begin by uplifting the most impoverished and marginalized individual in the community.
- As Gandhi famously stated in his talisman, one should test any policy by asking whether it will restore the poorest and weakest person to control over their own life and destiny.
- Thus, Antyodaya serves as the practical method and prerequisite for achieving Sarvodaya.

Final Answer:
Gandhiji’s concept of Sarvodaya is achieved through Antyodaya, corresponding to option (C).

Quick Tip: Gandhian developmental concepts:
- Sarvodaya = Universal progress / Welfare of All (The Goal).
- Antyodaya = Uplift of the last, poorest person first (The Method).
- Both were inspired by John Ruskin’s book Unto This Last.

Question 20:

Which of the following is not considered as a typical case of migration?

  • (A) Forceful migration due to terrorism.
  • (B) Nomadic movements without any intent.
  • (C) Migration to urban areas for search of jobs.
  • (D) Voluntary migration within one’s region or country.
Correct Answer: (B) Nomadic movements without any intent.
View Solution

Concept:
In demography and human geography, migration is defined as the geographic movement of people across a defined administrative boundary to establish a new permanent or semi-permanent residence.
It involves an origin, a destination, and an intention to change one’s regular place of abode.

Step 1: Analysis of Recognized Typologies of Migration:
1. Forced Migration due to Terrorism (A): Recognized as forced or involuntary displacement, producing refugees and internally displaced persons (IDPs) fleeing violence.
2. Rural-to-Urban Migration for Employment (C): A classic form of voluntary economic migration driven by urban employment opportunities.
3. Voluntary Internal Migration (D): Relocation within national boundaries where individuals change their permanent residence voluntarily.

Step 2: Examination of Nomadic Mobility:
Nomadic Movements (B): Pastoral nomadism consists of cyclical, routine, or seasonal movements of pastoralist communities alongside their livestock in search of fresh grazing pasture and water.
Because nomads do not relocate with the intention of establishing a fixed, permanent residence at a destination, their movement is classified demographically as circulation or transhumance, rather than true migration.

Final Answer:
Nomadic movements without intent to establish permanent residence do not constitute a typical case of migration, corresponding to option (B).

Quick Tip: Key criteria for demographic migration:
1. Crossing an administrative boundary.
2. Change of permanent or semi-permanent residence.
Cyclical pastoralism and seasonal nomadic wandering lack permanent settlement intent, classifying them as circulation rather than migration.

Question 21:

Which of the following species is also called as the "Terror of Bengal"?

  • (A) Clarias gariepinus
  • (B) Tectona grandis
  • (C) Eichhornia crassipes
  • (D) Tamarix dioica
Correct Answer: (C) Eichhornia crassipes
View Solution

Concept:
Invasive alien species are non-indigenous organisms introduced into new habitats outside their natural geographical range.
Lacking native predators and pathogens, they proliferate rapidly, outcompeting native taxa and disrupting ecosystem stability.

Step 1: Botanical and Historical Identity of the Species:
- Eichhornia crassipes (commonly known as Water Hyacinth) is a free-floating aquatic macrophyte native to the tropical Amazon Basin in South America.
- It was introduced into Bengal, India, in the late 19th century as an ornamental garden plant due to its distinctive mauve-blue flowers and bulbous leaves.

Step 2: Ecological Impact in Bengal:
- Reproducing rapidly through vegetative offsets and stolons, the weed colonized rivers, drainage canals, lakes, and wetlands across Bengal.
- It forms dense, interlocking surface mats that block sunlight from penetrating the water column, preventing photosynthesis in submerged aquatic flora.
- When these large masses of water hyacinth die and decay, aerobic decomposers rapidly consume dissolved oxygen, creating hypoxic conditions that lead to widespread fish mortality.
- Because fish and rice are dietary and economic staples in Bengal, the widespread destruction of freshwater fisheries earned Eichhornia crassipes the title "Terror of Bengal".

Step 3: Verification of Other Options:
- Clarias gariepinus is the invasive African Sharptooth Catfish.
- Tectona grandis is Teak, a valuable deciduous timber tree.
- Tamarix dioica is a riverine shrub adapted to saline soils.

Final Answer:
The species known as the "Terror of Bengal" is Eichhornia crassipes, corresponding to option (C).

Quick Tip: Prominent invasive plant species in India:
- Eichhornia crassipes (Water Hyacinth) = "Terror of Bengal".
- Parthenium hysterophorus (Carrot grass) = Imported with PL-480 wheat from the US.
- Lantana camara = Invasive ornamental shrub choking forest understories.

Question 22:

Which of the following process of safe disposal of waste will require least amount of energy input?

  • (A) Incineration
  • (B) Pyrolysis
  • (C) Composting
  • (D) Plasma Arc
Correct Answer: (C) Composting
View Solution

Concept:
Solid waste management uses both thermal and biological technologies to treat municipal solid waste.
Thermal processes require substantial auxiliary energy inputs to sustain elevated temperatures, whereas biological methods rely on natural microbial metabolic processes.

Step 1: Energy Inputs of Thermal Waste Technologies:
1. Plasma Arc Gasification (D): Directs waste into an insulated vessel where an electric plasma torch generates temperatures exceeding \(3000^\circ\text{C}\) to \(10000^\circ\text{C}\). This requires massive external electrical energy to break chemical bonds into vitrified slag and syngas.
2. Incineration (A): Controlled combustion of solid waste at \(850^\circ\text{C}\) to \(1100^\circ\text{C}\). It requires auxiliary fuels (diesel or natural gas) to maintain furnace temperatures, alongside forced-draft air blowers and emission scrubbers.
3. Pyrolysis (B): Endothermic thermal degradation of carbonaceous waste in an oxygen-free atmosphere at \(400^\circ\text{C}\) to \(800^\circ\text{C}\), demanding sustained external heat input to convert waste into bio-oil, syngas, and biochar.

Step 2: Energy Inputs of Biological Treatment:
Composting (C): A natural biological decomposition of organic solid wastes carried out by indigenous aerobic or anaerobic micro-organisms (bacteria, actinomycetes, and fungi).
The process is biologically driven and self-heating due to microbial metabolism. External energy input is minimal, limited to occasional physical turning or passive aeration in windrow piles.

Final Answer:
Composting relies on natural biological breakdown and requires the least amount of energy input, corresponding to option (C).

Quick Tip: Energy input hierarchy in waste processing:
Plasma Arc (\(> 3000^\circ\text{C}\)) \(\gg\) Incineration/Pyrolysis (\(400-1100^\circ\text{C}\)) \(\gg\) Composting (ambient biological process).
Biological processes use natural microbial metabolism and consume the least external energy.

Question 23:

Choose the correct statements about natural and organic farming
A. Natural farming is an example of closed system of farming
B. No human supplied artificial inputs are used in natural farming
C. Traditional farming promotes polyculture
D. Organic farming combines scientific knowledge with traditional farming practices
E. Organic farming relies on growing multiple crops on same space

Choose the correct answer from the options given below:

  • (A) A, B, C, D and E
  • (B) B, C, D and E only
  • (C) A, B, C and E only
  • (D) A, B, D and E only
Correct Answer: (A) A, B, C, D and E
View Solution

Concept:
Sustainable agriculture encompasses ecological farming practices such as natural farming, organic farming, and traditional polyculture systems.
These practices maintain soil fertility, protect agro-biodiversity, and avoid synthetic chemical fertilizers and pesticides.

Step 1: Systematic Evaluation of Each Statement:
- Statement A: Natural farming (such as Masanobu Fukuoka’s natural farming and Zero Budget Natural Farming) operates as a closed ecological system. All nutrient cycles, mulching, and pest management are derived internally from on-farm biological resources without purchasing outside inputs. (True)
- Statement B: Natural farming strictly avoids synthetic fertilizers, commercial chemical pesticides, and artificial soil additives, relying entirely on local cow dung, urine, and natural microbial formulations (such as Jeevamrit). (True)
- Statement C: Traditional indigenous agriculture historically emphasizes polyculture, mixed cropping, and agroforestry to enhance resilience against pest outbreaks and climate variations. (True)
- Statement D: Modern organic farming integrates scientific research on soil microbiology, compost formulation, and integrated pest management (IPM) with traditional crop rotation practices. (True)
- Statement E: Organic farming relies on spatial and temporal biodiversity, utilizing companion planting, polyculture, and intercropping on the same land to maintain soil health. (True)

Step 2: Conclusion:
All five statements (A, B, C, D, and E) are accurate descriptions of natural, organic, and traditional agriculture.

Final Answer:
All statements A, B, C, D, and E are correct, which corresponds to option (A).

Quick Tip: Distinguishing Ecological Farming Terms:
- Natural Farming: Minimal tillage, completely closed-loop on-farm inputs, no external commercial inputs.
- Organic Farming: Avoids synthetic agrochemicals, but uses certified organic inputs and scientific composting.
- Traditional Farming: Historic polyculture systems adapted to local ecosystems.

Question 24:

Which of the following does not apply to High Yielding Varieties (HYVs) of crops?

  • (A) They are semi-dwarf and are protected from strong winds.
  • (B) They mature early and save time for raising other crops in same field.
  • (C) They are disease resistant and does not require pesticides.
  • (D) They require better input like water and fertilisers.
Correct Answer: (C) They are disease resistant and does not require pesticides.
View Solution

Concept:
The Green Revolution introduced High Yielding Varieties (HYVs) of semi-dwarf wheat and rice developed through selective breeding by Norman Borlaug at CIMMYT and breeders at the International Rice Research Institute (IRRI).
These varieties responded well to chemical fertilizers, significantly boosting crop yields per hectare.

Step 1: Agronomic Characteristics of HYV Crops:
1. Semi-Dwarf Architecture (A): Incorporating dwarf genes (such as Norin-10 in wheat and Dee-geo-woo-gen in rice) produced short, thick stalks that prevented lodging (bending or breaking under heavy grain weight or strong winds).
2. Short Duration and Early Maturity (B): HYVs have shorter vegetative periods and mature quickly, allowing farmers to cultivate two or three crops annually on the same plot.
3. High Input Responsiveness (D): HYVs require managed irrigation and heavy applications of synthetic inorganic fertilizers (nitrogen, phosphorus, potassium) to achieve their yield potential.

Step 2: Analysis of Disease and Pest Resistance:
- Pesticide Requirement (C): It is incorrect to claim that HYVs "do not require pesticides."
- Because HYVs were bred from a narrow genetic base and planted in dense monocultures, they were often highly susceptible to pest infestations and fungal diseases (such as stem borer, brown planthopper, and rusts).
- As a result, HYV cultivation required extensive application of chemical insecticides, fungicides, and herbicides.

Final Answer:
The claim that HYVs are disease-resistant and do not require pesticides is incorrect, corresponding to option (C).

Quick Tip: Green Revolution HYV Package:
1. Semi-dwarf non-lodging stalks.
2. High responsiveness to chemical fertilizers.
3. High demand for controlled irrigation.
4. High susceptibility to pests, necessitating regular pesticide use.

Question 25:

Match the LIST-I with LIST-II
25

Choose the correct answer from the options given below:

  • (A) A - I, B - II, C - III, D - IV
  • (B) A - II, B - III, C - I, D - IV
  • (C) A - I, B - III, C - II, D - IV
  • (D) A - IV, B - III, C - I, D - II
Correct Answer: (B) A - II, B - III, C - I, D - IV
View Solution

Concept:
Across India, communities have developed indigenous rainwater harvesting and storage systems adapted to regional rainfall patterns, topography, and soil conditions to provide water security during dry seasons.

Step 1: Regional Mapping of Traditional Water Structures:
1. A. Nadis (Rajasthan): Nadis are traditional village water harvesting ponds constructed in the arid Thar Desert of Rajasthan. Built in natural depressions, they capture surface runoff from surrounding catchments to supply water for rural communities and livestock. Hence, A corresponds to II.
2. B. Bandharas (Maharashtra): Bandharas are traditional check weirs or diversion bunds built across small streams and rivers in Maharashtra. They raise water levels to divert river flow through connected irrigation networks called the phad system. Hence, B corresponds to III.
3. C. Ponds (Jammu and Kashmir): Traditional earthen village ponds and runoff storage tanks have long been constructed in the sub-Himalayan Kandi belt of Jammu and Kashmir to collect seasonal surface runoff for household use and livestock. Hence, C corresponds to I.
4. D. Eris (Tamil Nadu): Eris are ancient tank cascade systems widely used across Tamil Nadu. They capture surface runoff, recharge local aquifers, prevent soil erosion, and historically irrigated roughly one-third of the state’s cropped acreage. Hence, D corresponds to IV.

Step 2: Alignment of Matched Pairs:
Combining these mappings:
A matches II.
B matches III.
C matches I.
D matches IV.
The resulting sequence is A - II, B - III, C - I, D - IV.

Final Answer:
The correct matching corresponds to option (B).

Quick Tip: Traditional Indian Rainwater Harvesting Systems:
- Rajasthan \(\rightarrow\) Nadis, Kunds, Tankas, Khadins.
- Maharashtra \(\rightarrow\) Bandharas and Phad systems.
- Tamil Nadu \(\rightarrow\) Eris (Tank cascades).
- Jammu and Kashmir \(\rightarrow\) Kandi belt Ponds.
- Himachal Pradesh \(\rightarrow\) Kuhls.
- Meghalaya \(\rightarrow\) Bamboo Drip Irrigation.

Question 26:

Which of the following is NOT true for mixed farming?

  • (A) It helps in maintaining soil fertility.
  • (B) It reduces soil erosion.
  • (C) It improves production level and give higher production than monoculture.
  • (D) It provides suitable habitat for birds.
Correct Answer: (D) It provides suitable habitat for birds.
View Solution

Concept:
Mixed farming is an integrated agricultural system in which the cultivation of crops and the rearing of livestock are practiced simultaneously on the same farm.
The biological interaction between plants and animals optimizes nutrient recycling, minimizes financial risk, and promotes agricultural stability.

Step 1: Evaluation of Agronomic Benefits:
1. Soil Fertility Maintenance: Livestock dung and urine provide farmyard manure, enriching soil organic carbon, whereas leguminous forage crops fix atmospheric nitrogen, enhancing natural fertility. Hence, statement (A) is true.
2. Erosion Mitigation: The integration of cover crops, perennial grasses, and rotational pastures protects topsoil from wind and water runoff, substantially reducing erosion compared to continuous tilled monocultures. Hence, statement (B) is true.
3. Enhanced Productivity: By diversifying land use with synergistic enterprise outputs (milk, meat, grain, fiber), mixed farming yields higher total biomass and monetary returns per unit area than conventional monoculture. Hence, statement (C) is true.

Step 2: Assessment of Habitat Provision:
While mixed farming maintains higher agro-biodiversity than intensive monocultures, it is primarily an intensive production landscape shaped by human management, grazing pressure, and crop harvesting.
Such regular anthropogenic disturbances, pesticide/herbicide application, livestock trampling, and harvest operations prevent the establishment of stable, undisturbed breeding and nesting territories for wild birds.
Wild bird conservation relies on undisturbed native grasslands, wetlands, and natural forest corridors rather than working agricultural plots.
Therefore, providing a suitable habitat for wild birds is not an inherent or recognized agronomic objective of mixed farming.

Final Answer:
The statement that is not true regarding mixed farming is option (D).

Quick Tip: Mixed Farming characteristics:
- Simultaneous crop cultivation + livestock rearing.
- High internal resource recycling (dung \(\rightarrow\) manure; crop residue \(\rightarrow\) fodder).
- Primary goals are economic stability and soil conservation, not wild avian habitat conservation.

Question 27:

The measure of number of different food groups consumed over a specific reference period (24 hr/ 8hr/ 7 days) is known as ..............

  • (A) Household food insecurity scale
  • (B) Household dietary diversity scale
  • (C) Household hunger scale
  • (D) Coping strategies index
Correct Answer: (B) Household dietary diversity scale
View Solution

Concept:
Dietary assessment indices are qualitative recall metrics designed by international nutritional agencies to evaluate food access, nutrient adequacy, and household-level food security.
Nutritional quality correlates directly with dietary variety across essential food categories.

Step 1: Defining Dietary Diversity Metrics:
The Household Dietary Diversity Scale (HDDS), standardized by the Food and Agriculture Organization (FAO) and USAID, is a qualitative count metric.
It calculates the total number of distinct nutritional food groups consumed by household members over a specified recall reference window, typically the previous 24 hours, 8 hours, or 7 days.
Standard standardized food groups include cereals, root tubers, vegetables, fruits, meat, eggs, fish, legumes, dairy products, oils/fats, and sugars.

Step 2: Analysis of Alternative Nutritional Indices:
1. Household Food Insecurity Access Scale (HFIAS): Measures the degree of anxiety, perceived insufficiency, and behavioral alterations caused by food deprivation.
2. Household Hunger Scale (HHS): A specialized subset of food insecurity metrics focusing solely on severe deprivation (e.g., going entire days without eating).
3. Coping Strategies Index (CSI): Measures adaptive household behaviors (such as borrowing food, rationing meals, or consuming seed stock) during acute economic stress.

Step 3: Verification of the Indicator:
Because the definition provided in the question specifically refers to counting the variety of food groups consumed across a designated reference recall period, it directly matches HDDS.

Final Answer:
The measure of different food groups consumed is the Household dietary diversity scale, corresponding to option (B).

Quick Tip: Nutritional Scale Keywords:
- Count of food groups consumed \(\rightarrow\) Household Dietary Diversity Scale (HDDS).
- Severe deprivation/starvation experiences \(\rightarrow\) Household Hunger Scale (HHS).
- Behavioral responses to crisis \(\rightarrow\) Coping Strategies Index (CSI).

Question 28:

Which of the following is an example of Kharif Crop?

  • (A) Wheat
  • (B) Gram
  • (C) Paddy
  • (D) Mustard
Correct Answer: (C) Paddy
View Solution

Concept:
Indian agriculture is structured around three primary cropping seasons governed by the Southwest monsoon dynamics and temperature variations: Kharif, Rabi, and Zaid.
Crop classification depends on photoperiod requirements, temperature regimes, and moisture availability during vegetative and ripening phases.

Step 1: Characterization of Agricultural Seasons:
1. Kharif Season: Crops sown at the onset of the Southwest monsoon rains (June-July) and harvested during autumn (September-October). These crops require warm temperatures and substantial water availability throughout their active growth cycle.
2. Rabi Season: Crops sown during early winter (October-December) and harvested in spring (March-April). They require cool weather for vegetative growth and dry, warm conditions for seed maturation.
3. Zaid Season: Short duration summer crops grown between Rabi and Kharif (March-June), such as watermelon, cucumber, and fodder crops.

Step 2: Classification of Given Agricultural Crops:
- Paddy (Oryza sativa): A quintessential Kharif wetland cereal crop requiring continuous standing water and high relative humidity during vegetative phases.
- Wheat (Triticum aestivum): A premier temperate Rabi cereal requiring cool temperatures during tillering and warm sunshine during grain filling.
- Gram (Cicer arietinum / Chickpea): A leguminous winter Rabi pulse cultivated under low residual soil moisture.
- Mustard (Brassica juncea): An oilseed grown predominantly during the winter Rabi season.

Final Answer:
Among the given options, Paddy is a Kharif crop, corresponding to option (C).

Quick Tip: Cropping season quick categorization:
- Kharif (Monsoon): Paddy, Maize, Jowar, Bajra, Cotton, Soybean, Groundnut.
- Rabi (Winter): Wheat, Barley, Gram, Mustard, Peas, Linseed.
- Zaid (Summer): Watermelon, Muskmelon, Cucumber, Vegetables.

Question 29:

Which of the following state in India first adopted Green Revolution ?

  • (A) Haryana
  • (B) Punjab
  • (C) Uttar Pradesh
  • (D) Madhya Pradesh
Correct Answer: (B) Punjab
View Solution

Concept:
The Green Revolution in India was launched in the mid-1960s to achieve self-sufficiency in food grain production.
It introduced a technological package featuring High Yielding Varieties (HYVs) of semi-dwarf wheat, assured canal/tube-well irrigation, synthetic chemical fertilizers, and mechanical farm implements.

Step 1: Historical Rollout of the Technology Package:
Under the leadership of agricultural scientist Dr. M. S. Swaminathan and Union Food Minister C. Subramaniam, the Government of India introduced dwarf Mexican wheat varieties bred by Dr. Norman Borlaug (e.g., Sonora 64, Lerma Rojo).
The state selected as the prime pilot testing ground for the initial rollout in 1966-67 was Punjab.

Step 2: Sociological and Geographical Selection Rationale:
Punjab was selected as the first adopter due to several distinct agro-ecological advantages:
1. Existing extensive perennial canal network established during the colonial era, supplemented by rapid rural electrification for tube wells.
2. Fertile alluvial soils deposited by the Indus river system.
3. A enterprising peasantry with relatively larger landholdings capable of investing in mechanization (tractors, threshers) and purchasing synthetic chemical inputs.
The immediate success in Punjab caused wheat yields to jump exponentially, earning the region the reputation of being the "Wheat Granary of India" before the techniques were extended to Haryana and Western Uttar Pradesh.

Final Answer:
The state that first adopted the Green Revolution in India was Punjab, corresponding to option (B).

Quick Tip: Green Revolution Pioneers:
- Global Father: Norman Borlaug (developed dwarf wheat at CIMMYT).
- Indian Father: M. S. Swaminathan.
- First Indian State to Adopt: Punjab (followed by Haryana and Western UP).

Question 30:

Match the LIST-I with LIST-II
30

Choose the correct answer from the options given below:

  • (A) A - II, B - III, C - IV, D - I
  • (B) A - IV, B - III, C - II, D - I
  • (C) A - III, B - II, C - IV, D - I
  • (D) A - IV, B - I, C - II, D - III
Correct Answer: (B) A - IV, B - III, C - II, D - I
View Solution

Concept:
Ecosystem services are the direct and indirect contributions of ecosystems to human well-being.
The Millennium Ecosystem Assessment (MEA, 2005) categorized these ecological functions into four functional classes: Provisioning, Regulating, Cultural, and Supporting services.

Step 1: Systematic Functional Classification:
1. Provisioning Services (A): Material goods obtained directly from ecosystems, such as food, timber, freshwater, biochemicals, and genetic resources including crop improvement and health care. Hence, A pairs with IV.
2. Regulating Services (B): Benefits obtained from the regulation of ecosystem processes, including climate buffering, water purification, flood moderation, and disease vector control. For example, soil erosion is reduced by plants by binding soil particles. Hence, B pairs with III.
3. Cultural Services (C): Non-material benefits people obtain through spiritual enrichment, cognitive development, recreation, and aesthetic experiences, where the ecosystem is a store house of formal and informal education. Hence, C pairs with II.
4. Supporting Services (D): Fundamental ecological processes that are necessary for the production of all other ecosystem services, including nutrient cycling, primary production, and pedogenesis. Hence, D pairs with I.

Step 2: Matching Alignment:
The resulting sequence of pairings is:
A \(\rightarrow\) IV
B \(\rightarrow\) III
C \(\rightarrow\) II
D \(\rightarrow\) I
This establishes the combination A - IV, B - III, C - II, D - I.

Final Answer:
The correct matching sequence corresponds to option (B).

Quick Tip: MEA Ecosystem Services Categories:
- Provisioning \(\rightarrow\) Physical goods extracted (genetic resources, timber).
- Regulating \(\rightarrow\) Natural control systems (erosion control, climate regulation).
- Cultural \(\rightarrow\) Intellectual and spiritual benefits (education, ecotourism).
- Supporting \(\rightarrow\) Foundational life-support cycles (nutrient cycling).

Question 31:

Resources that have been surveyed but cannot used by humans due to lack of technology are known as ..............

  • (A) Potential resources
  • (B) Actual resources
  • (C) Reserve resources
  • (D) Stock resources
Correct Answer: (D) Stock resources
View Solution

Concept:
In resource economics and economic geography, environmental materials are categorized based on their stage of development, survey status, and technological accessibility.
A substance becomes an operational resource only when technical know-how enables human extraction and utilization.

Step 1: Differentiation of Resource Categories:
1. Actual (Developed) Resources: Materials that have been surveyed, quantified in volume and grade, and are actively exploited using current technology (e.g., petroleum extracted from Digboi or Mumbai High).
2. Potential Resources: Materials present in a region that have the potential for future use, but are not yet fully tapped due to capital constraints or infrastructure limitations (e.g., solar and wind energy in Rajasthan and Gujarat).
3. Reserves: The accessible fraction of an identified resource that can be extracted economically and legally using existing technology, but is reserved for future needs (e.g., river water stored behind dams for future generation).
4. Stock Resources: Materials in the environment that possess the intrinsic potential to satisfy human needs, but cannot be utilized due to the lack of appropriate technology.

Step 2: Illustrative Example of Stock:
Water (\(\text{H}_2\text{O}\)) is an abundant chemical compound composed of hydrogen and oxygen.
Hydrogen has extraordinarily high energy density and can serve as a primary clean fuel; however, humans do not yet possess the cost-effective, large-scale industrial technology to commercially split water molecules via catalytic electrolysis for widespread energy use.
Consequently, such surveyed environmental wealth is classified as Stock.

Final Answer:
Resources surveyed but unusable due to lack of technology are stock resources, corresponding to option (D).

Quick Tip: Resource Classification Checklist:
- Present + not fully exploited yet \(\rightarrow\) Potential.
- Surveyed + currently being exploited \(\rightarrow\) Actual/Developed.
- Available + technology exists + saved for future \(\rightarrow\) Reserve.
- Surveyed + NO technology exists to extract \(\rightarrow\) Stock.

Question 32:

Match the LIST-I with LIST-II
32

Choose the correct answer from the options given below:

  • (A) A - III, B - II, C - IV, D - I
  • (B) A - IV, B - III, C - II, D - I
  • (C) A - III, B - IV, C - II, D - I
  • (D) A - I, B - III, C - II, D - IV
Correct Answer: (B) A - IV, B - III, C - II, D - I
View Solution

Concept:
In environmental economics, an externality occurs when the production or consumption activities of one economic agent impart unintended costs (negative externality) or benefits (positive externality) to uncompensated third parties.
When market prices fail to reflect these external social costs or benefits, market failure arises.

Step 1: Systematic Analysis of Externality Types:
1. Negative Production Externality (A): Occurs when an industrial manufacturing activity imposes uncompensated environmental costs on society. A factory discharging untreated chemical effluents into a river damages municipal water supplies and fisheries downstream. Thus, A corresponds to IV.
2. Negative Consumption Externality (B): Arises when an individual’s private consumption of a commodity generates adverse side effects for bystanders. For example, individuals driving private automobiles cause traffic congestion and heighten the accident risk for other commuters. Thus, B corresponds to III.
3. Positive Production Externality (C): Occurs when a firm’s production creates spillover benefits for other enterprises. Constructing an airport improves regional logistical accessibility, which promotes trade, commerce, and tourism for surrounding businesses. Thus, C corresponds to II.
4. Positive Consumption Externality (D): Arises when private consumption confers spillover advantages on neighbors. A homeowner who maintains an architecturally attractive home and garden raises the aesthetic and market valuation of adjacent properties. Thus, D corresponds to I.

Step 2: Compilation of Matched Pairs:
Combining the matched relationships:
A matches with IV.
B matches with III.
C matches with II.
D matches with I.
The resulting configuration is A - IV, B - III, C - II, D - I.

Final Answer:
The correct matching sequence is given by option (B).

Quick Tip: Externality Identification:
- Negative Production \(\rightarrow\) Industrial factory pollution/effluents.
- Negative Consumption \(\rightarrow\) Driving cars causing traffic/accidents, smoking.
- Positive Production \(\rightarrow\) Infrastructure construction (airports, honeybees near orchards).
- Positive Consumption \(\rightarrow\) Home beautification, vaccination.

Question 33:

Which of the following is the correct relationship between Gross Domestic product (GDP), Gross National Product (GNP), Net Income Receipt (X), and Net Outflow to the foreign Assets (Y)?

  • (A) \(\text{GNP} = \text{GDP} - \text{X} + \text{Y}\)
  • (B) \(\text{GNP} = \text{GDP} + \text{X} - \text{Y}\)
  • (C) \(\text{GDP} - \text{X} = \text{GNP} + \text{Y}\)
  • (D) \(\text{GDP} + \text{Y} = \text{GNP} - \text{X}\)
Correct Answer: (B) \(\text{GNP} = \text{GDP} + \text{X} - \text{Y}\)
View Solution

Concept:
National income accounting distinguishes between geographic production boundaries (Gross Domestic Product) and citizenship/ownership production boundaries (Gross National Product).
The mathematical bridge linking domestic production to national output is Net Factor Income from Abroad (NFIA).

Step 1: Defining GDP and GNP:
- Gross Domestic Product (GDP): The total monetary value of all finished goods and services produced within the geographic boundaries of a nation during a specified financial year.
- Gross National Product (GNP): The total monetary value of all finished goods and services produced by the normal residents and factors of production belonging to a nation, regardless of geographic location.

Step 2: Mathematical Integration of Foreign Factor Flows:
The transition from GDP to GNP requires adjusting for cross-border income flows:
\[ \text{GNP} = \text{GDP} + \text{Net Factor Income from Abroad (NFIA)} \] Let:
- \(X\) = Factor income earned by domestic citizens from foreign assets abroad (receipts).
- \(Y\) = Factor income earned by foreign nationals from domestic assets within the country (outflows/payments).
The Net Factor Income from Abroad is the net difference between inflows and outflows:
\[ \text{NFIA} = X - Y \] Substituting this expression into the primary national income equation:
\[ \text{GNP} = \text{GDP} + X - Y \]

Step 3: Verification of Balance Equation:
Re-arranging the algebraic terms:
\[ \text{GNP} = \text{GDP} + X - Y \] This identity reflects the economic accounting formula relating GDP, GNP, factor receipts, and factor payments.

Final Answer:
The correct relationship is \(\text{GNP} = \text{GDP} + \text{X} - \text{Y}\), corresponding to option (B).

Quick Tip: National Accounting Identity:
\(\text{GNP} = \text{GDP} + \text{NFIA}\)
where \(\text{NFIA} = \text{Income Receipts from Abroad } (X) - \text{Income Payments to Abroad } (Y)\).
Therefore, \(\text{GNP} = \text{GDP} + X - Y\).

Question 34:

Ecological Foot Print (EFP) does not measure-

  • (A) Amount of waste generated by human population
  • (B) Consumption of natural resources by human population
  • (C) Income generated by human population
  • (D) Demand of human from ecosystems
Correct Answer: (C) Income generated by human population
View Solution

Concept:
The Ecological Footprint (EFP) is a resource accounting tool formulated in the 1990s by William Rees and Mathis Wackernagel.
It measures how much biologically productive land and water area an individual, population, or human activity requires to produce the resources it consumes and absorb the wastes it generates.

Step 1: Biophysical Components Measured by EFP:
The ecological footprint quantifies the human demand placed on the planet’s biocapacity, measured in standardized units called global hectares (gha):
1. Demand on Ecosystems (D): Tracks demand across distinct bioproductive surfaces (cropland, grazing land, fishing grounds, and forest land).
2. Resource Consumption (B): Calculates food, timber, pulp, textile fibers, and water extracted to sustain human populations.
3. Waste Assimilation (A): Quantifies the forest area required to absorb emissions, particularly fossil-fuel carbon dioxide emissions (carbon footprint).

Step 2: Identification of Non-Biophysical Parameters:
Income generated by human population (C): Monetary income, gross revenue, and GDP are financial metrics calculated in fiat currencies.
The Ecological Footprint is purely a biophysical accounting metric that does not evaluate personal income, wage levels, or financial earnings.
Economic wealth can correlate with footprint size, but income itself is not an ecological variable measured by the tool.

Final Answer:
The Ecological Footprint does not measure the income generated by human population, corresponding to option (C).

Quick Tip: Ecological Footprint vs. Economic Metrics:
- EFP measures biophysical demand in global hectares (gha).
- It tracks resource consumption and carbon waste absorption.
- It does NOT measure financial variables like income, capital, or monetary wealth.

Question 35:

Agreement between two or more nations to reduce or eliminate tariff and non-tariff barrier on trade is known as:-

  • (A) Free trade agreements
  • (B) Foreign trade agreements
  • (C) Free tariff treaty
  • (D) Custom trade agreements
Correct Answer: (A) Free trade agreements
View Solution

Concept:
International trade governance relies on bilateral and multilateral treaties to regulate the transboundary flow of goods, commodities, and services.
Trade barriers typically include import tariffs (taxes on foreign goods) and non-tariff barriers (import quotas, subsidies, and customs delays).

Step 1: Characterization of Trade Pacts:
1. Free Trade Agreement (FTA): A legally binding international treaty between two or more countries under which member nations agree to reduce or eliminate tariffs, import duties, and non-tariff restrictions on traded goods and services.
Examples include NAFTA (now USMCA) and the ASEAN Free Trade Area.
2. Customs Union: An agreement where member states eliminate internal tariffs and establish a common external tariff applied to non-member nations.
3. Foreign Trade Agreements: A broad, informal term for any external trade accord that does not necessarily eliminate protectionist tariffs.
4. Free Tariff Treaty: A non-standard economic term.

Step 2: Environmental Significance of FTAs:
In environmental studies, Free Trade Agreements are closely scrutinized because trade liberalization can encourage "pollution havens" (where polluting industries migrate to nations with weaker environmental regulations) or accelerate the overexploitation of natural resources.
Consequently, modern FTAs incorporate environmental clauses to ensure trade policies align with environmental protection standards.

Final Answer:
The agreement to reduce or eliminate trade barriers is a Free Trade Agreement, corresponding to option (A).

Quick Tip: Trade Treaty Terminology:
- Free Trade Agreement (FTA): Eliminates tariffs and quotas between member nations.
- Customs Union: FTA + Common external tariff on outside nations.
- Common Market: Customs Union + Free movement of labor and capital.

Question 36:

An international effort "REDD+" was proposed in the year 2005 by developing countries for ...............

  • (A) Reducing CFCs emissions for recovery of ozone layer
  • (B) Reducing deforestation to combat global warming
  • (C) Conserving wetlands for water management
  • (D) Conserving fossil fuel for next generation
Correct Answer: (B) Reducing deforestation to combat global warming
View Solution

Concept:
Forest ecosystems serve as major terrestrial carbon sinks.
Deforestation and forest degradation release stored carbon into the atmosphere, accounting for approximately \(10-15\%\) of anthropogenic greenhouse gas emissions.
REDD+ is an international climate mitigation initiative developed under the United Nations Framework Convention on Climate Change (UNFCCC).

Step 1: Genesis of REDD+ in 2005:
At the 11th Conference of the Parties (COP 11) to the UNFCCC held in Montreal in 2005, the Coalition for Rainforest Nations (led by Papua New Guinea and Costa Rica) submitted a formal proposal entitled "Reducing Emissions from Deforestation in Developing Countries".
This initiative aimed to create financial incentives for developing countries to protect tropical rainforests, thereby preventing carbon emissions and mitigating global warming.

Step 2: Evolution from REDD to REDD+:
The original REDD concept focused exclusively on avoiding deforestation and forest degradation.
Under the Bali Action Plan (COP 13, 2007) and Warsaw Framework (COP 19, 2013), the scope was expanded to REDD+, where the "+" encompasses:
1. Conservation of existing forest carbon stocks.
2. Sustainable management of forests.
3. Enhancement of forest carbon stocks through afforestation and reforestation.

Step 3: Purpose and Core Mechanism:
Developing nations receive verified results-based payments for measurable reductions in carbon emissions achieved through forest conservation.
Its primary objective is reducing deforestation and forest degradation to mitigate global climate change.

Final Answer:
REDD+ was proposed for reducing deforestation to combat global warming, corresponding to option (B).

Quick Tip: Acronym Breakdown:
REDD+ = Reducing Emissions from Deforestation and forest Degradation.
The "+" includes:
- Forest conservation.
- Sustainable forest management.
- Enhancement of forest carbon sinks.

Question 37:

Which of the following are important cycles of catalytic destruction of ozone in stratosphere ?
A. \(\text{CO} / \text{CO}_2\)
B. \(\text{HO} / \text{HO}_2\)
C. \(\text{NO} / \text{NO}_2\)
D. \(\text{Cl} / \text{ClO}\)
E. \(\text{SO} / \text{SO}_2\)

Choose the correct answer from the options given below:

  • (A) A and D only
  • (B) B, C and D only
  • (C) A, C and D only
  • (D) A, D and E only
Correct Answer: (B) B, C and D only
View Solution

Concept:
Stratospheric ozone (\(\text{O}_3\)) is maintained by the Chapman photochemical steady-state mechanism.
However, free radical catalysts (\(X\)) accelerate ozone destruction via homogeneous gas-phase catalytic cycles without being consumed in the process:
\[ X + \text{O}_3 \rightarrow XO + \text{O}_2 \] \[ XO + \text{O} \rightarrow X + \text{O}_2 \] \[ \text{Net Reaction: } \text{O}_3 + \text{O} \rightarrow 2\text{O}_2 \]

Step 1: Examination of Recognized Catalytic Cycles:
1. Hydroxyl Radical Cycle (\(\text{HO}_x\), B): \(\text{OH}\) and \(\text{HO}_2\) radicals originate from the photolytic reaction of excited singlet oxygen \(\text{O}(^1D)\) with water vapor (\(\text{H}_2\text{O}\)) and methane. They are the dominant ozone destruction catalysts in the upper stratosphere.
2. Nitrogen Oxide Cycle (\(\text{NO}_x\), C): Nitric oxide (\(\text{NO}\)) and nitrogen dioxide (\(\text{NO}_2\)), originating from tropospheric nitrous oxide (\(\text{N}_2\text{O}\)), dominate catalytic ozone loss in the middle stratosphere (25-35 km).
3. Chlorine Radical Cycle (\(\text{ClO}_x\), D): Chlorine (\(\text{Cl}\)) and chlorine monoxide (\(\text{ClO}\)) released from anthropogenic chlorofluorocarbons (CFCs) drive ozone depletion, especially over Antarctica.

Step 2: Evaluation of Inactive Species:
- Carbon Oxides (\(\text{CO}/\text{CO}_2\), A): Carbon monoxide and dioxide are stable molecular gases that do not participate in catalytic stratospheric ozone destruction cycles.
- Sulfur Oxides (\(\text{SO}/\text{SO}_2\), E): Sulfur dioxide forms stratospheric aerosol particles (Junge layer of \(\text{H}_2\text{SO}_4\)), providing surfaces for heterogeneous reactions, but \(\text{SO}/\text{SO}_2\) does not act as a gas-phase free radical catalytic cycle.

Step 3: Selection of Valid Radical Cycles:
The established catalytic ozone destruction cycles are the \(\text{HO}_x\) cycle (B), the \(\text{NO}_x\) cycle (C), and the \(\text{ClO}_x\) cycle (D).

Final Answer:
The catalytic cycles responsible for stratospheric ozone destruction are B, C, and D only, corresponding to option (B).

Quick Tip: Stratospheric Ozone Catalysts:
- \(\text{HO}_x\) cycle: \(\text{OH} / \text{HO}_2\)
- \(\text{NO}_x\) cycle: \(\text{NO} / \text{NO}_2\)
- \(\text{ClO}_x\) cycle: \(\text{Cl} / \text{ClO}\)
- \(\text{BrO}_x\) cycle: \(\text{Br} / \text{BrO}\)
Stable oxides (\(\text{CO}_2, \text{SO}_2\)) do not act as gas-phase catalytic radicals.

Question 38:

Which of the following gas is both a green house gas and a criteria air pollutants?

  • (A) Nitrous oxide
  • (B) Carbon dioxide
  • (C) Ozone
  • (D) Sulphur hexafluoride
Correct Answer: (C) Ozone
View Solution

Concept:
Air pollutants can be classified as criteria air pollutants or greenhouse gases (GHGs) based on their environmental impacts:
- Criteria pollutants are regulated based on direct human health toxicity and ambient exposure limits.
- Greenhouse gases trap outgoing terrestrial longwave infrared radiation, contributing to planetary warming.

Step 1: Evaluation of Candidate Gases:
1. Nitrous Oxide (\(\text{N}_2\text{O}\)): A potent greenhouse gas with a global warming potential nearly 300 times that of \(\text{CO}_2\). However, it is non-toxic at ambient concentrations and is not classified as a criteria air pollutant.
2. Carbon Dioxide (\(\text{CO}_2\)): The principal anthropogenic greenhouse gas driving global climate change. However, under the National Ambient Air Quality Standards (NAAQS) of India, it is not designated as a criteria air pollutant.
3. Sulphur Hexafluoride (\(\text{SF}_6\)): A synthetic dielectric greenhouse gas with a high global warming potential (\(\sim 23,500\)), but not a criteria air pollutant.
4. Tropospheric Ozone (\(\text{O}_3\)):
- As a criteria air pollutant: Ground-level ozone is a powerful respiratory irritant that causes coughing, lung damage, and reduces crop yields. It is monitored under both Indian NAAQS and the US EPA.
- As a greenhouse gas: Ozone absorbs longwave infrared radiation near \(9.6\,\mu\text{m}\), making it the third most important greenhouse gas in the troposphere after carbon dioxide and methane.

Step 2: Conclusion:
Ground-level ozone is the only gas among the choices that belongs to both regulatory categories.

Final Answer:
The gas that is both a greenhouse gas and a criteria air pollutant is Ozone, corresponding to option (C).

Quick Tip: Tropospheric Ozone Dual Identity:
- Criteria Pollutant \(\rightarrow\) Strong oxidant, causes respiratory illness and crop necrosis.
- Greenhouse Gas \(\rightarrow\) Absorbs infrared radiation at \(9.6\,\mu\text{m}\).
"Good up high (stratosphere), bad nearby (troposphere)."

Question 39:

Arrange the following international events in a chronological order starting from old to recent as per their year of enactment.
A. Basel Convention
B. Bamako Convention
C. Paris Agreement on Climate Change
D. Kigali Amendment
E. Kyoto Protocol

Choose the correct answer from the options given below:

  • (A) A, E, C, D, B
  • (B) D, C, B, A, E
  • (C) A, E, B, C, D
  • (D) E, B, A, C, D
Correct Answer: (C) A, E, B, C, D
View Solution

Concept:
Multilateral Environmental Agreements (MEAs) are international legal treaties designed to address environmental issues such as hazardous waste transport, climate change, and stratospheric ozone depletion.
The timeline of an international treaty includes its initial diplomatic adoption and its formal entry into force (enactment) after ratification by a specified quota of sovereign states.

Step 1: Determining Adoption and Enactment Timelines:
1. Basel Convention (A): On the Control of Transboundary Movements of Hazardous Wastes and Their Disposal. Adopted in 1989; enacted and entered into force on May 5, 1992.
2. Kyoto Protocol (E): Adopted in December 1997 under the UNFCCC framework to establish legally binding greenhouse gas reduction targets for Annex-I developed nations.
3. Bamako Convention (B): Adopted by 12 nations of the Organization of African Unity in 1991 to ban the import of hazardous and radioactive wastes into Africa. It achieved sufficient ratifications to enter into force on April 22, 1998.
4. Paris Agreement on Climate Change (C): Adopted in December 2015 at COP 21; entered into force on November 4, 2016.
5. Kigali Amendment to the Montreal Protocol (D): Adopted in October 2016 to mandate the phase-down of hydrofluorocarbons (HFCs); entered into force on January 1, 2019.

Step 2: Chronological Ordering from Oldest to Most Recent:
Tracing the sequence:
- Basel Convention: 1989/1992 (A)
- Kyoto Protocol: 1997 (E)
- Bamako Convention: Enacted 1998 (B)
- Paris Agreement: 2015/2016 (C)
- Kigali Amendment: 2016/2019 (D)
This establishes the sequence: A, E, B, C, D.

Final Answer:
The correct chronological sequence is A, E, B, C, D, corresponding to option (C).

Quick Tip: Chronological Milestones of Key MEAs:
- Basel Convention: 1989 (in force 1992).
- Bamako Convention: 1991 (in force 1998).
- Kyoto Protocol: 1997 (in force 2005).
- Paris Agreement: 2015 (in force 2016).
- Kigali Amendment: 2016 (in force 2019).

Question 40:

Total columnar ozone in the atmosphere is measured in Dobson units. One Dobson unit corresponds to ..............

  • (A) \(\frac{1}{10}\text{ of mm}\)
  • (B) \(\frac{1}{100}\text{ of mm}\)
  • (C) \(\frac{1}{1000}\text{ of mm}\)
  • (D) \(\frac{1}{100}\text{ of cm}\)
Correct Answer: (B) \(\frac{1}{100}\text{ of mm}\)
View Solution

Concept:
Total columnar ozone refers to the total number of ozone molecules present in a vertical atmospheric column extending from the Earth’s surface to the top of the atmosphere.
It is conventionally expressed in Dobson Units (DU), named in honor of Gordon Dobson, who designed the first spectrophotometer to measure stratospheric ozone.

Step 1: Physical Definition of a Dobson Unit:
A Dobson Unit is defined by compressing all ozone molecules in a vertical column of air into a pure, uniform layer at Standard Temperature and Pressure (STP, defined as \(T = 0^\circ\text{C}\) or \(273.15\text{ K}\) and \(P = 1\text{ atm}\) or \(101.325\text{ kPa}\)).
Under these conditions, a layer thickness of \(1\text{ mm}\) of pure ozone corresponds to \(100\text{ DU}\).

Step 2: Mathematical Conversion to Millimeters:
Using this relationship:
\[ 100\text{ DU} = 1\text{ mm of pure ozone at STP} \] Dividing both sides by 100:
\[ 1\text{ DU} = \frac{1}{100}\text{ mm} = 0.01\text{ mm} = 10\,\mu\text{m} \] In terms of molecular areal density, \(1\text{ DU}\) is equivalent to approximately \(2.69 \times 10^{16}\text{ molecules of ozone per square centimeter}\) (\(2.69 \times 10^{20}\text{ molecules/m}^2\)).
For reference, typical atmospheric ozone concentrations average roughly \(300\text{ DU}\), which corresponds to a pure ozone layer only \(3\text{ mm}\) thick at sea-level pressure.

Final Answer:
One Dobson unit corresponds to \(\frac{1}{100}\text{ of mm}\) of pure ozone at STP, which corresponds to option (B).

Quick Tip: Dobson Unit Conversion Formulas:
\(1\text{ DU} = 0.01\text{ mm} = \frac{1}{100}\text{ mm} = 10^{-5}\text{ m}\) (at STP).
\(1\text{ DU} = 2.69 \times 10^{16}\text{ molecules/cm}^2\).
An ozone hole is defined when total ozone levels drop below \(220\text{ DU}\).

Comprehension Passage (Questions 41 to 45):
 



"For any ecosystem, a constant input of energy is the basic requirement for its functioning and sustenance. The productivity of an ecosystem is calculated as the rate of biomass production expressed as gram/square meter/year (\(\text{g}\cdot\text{m}^{-2}\cdot\text{yr}^{-1}\)). The rate of production of organic matter during photosynthesis is called gross primary productivity (GPP). A considerable portion of GPP is consumed and utilized by plants during respiration. Therefore, the biomass available for heterotrophs is known as net primary productivity (NPP). The rate of formation of new organic matter by consumers is known as secondary productivity (SP).
Primary productivity depends on the plants species inhabiting a particular area, availability of nutrients, photosynthetic capacity of plants, and other environmental factors. The annual NPP of whole biosphere is approximately 170 billion tons, out of which, productivity of oceans is around 55 billions tons. In soil, the dead organic matter is converted to humans through humification. Humus undergoes slow degradation and is a reservoir of soil nutrients. Over a period of time, humus is further degraded by microbes and release nutrients by a process called mineralization."

​Question 41:
Annual NPP of land area on the earth is ..............

  • (A) \(< 55\text{ billion tons}\)
  • (B) between 55 to 100 billion tons
  • (C) About 115 billion tons
  • (D) 225 billion tons
Correct Answer: (C) About 115 billion tons
View Solution

Concept:
The biosphere’s Net Primary Productivity (NPP) is partitioned between terrestrial ecosystems (land) and aquatic ecosystems (oceans).
Terrestrial systems generate a disproportionately large share of global primary productivity relative to their surface area due to higher nutrient availability and direct access to sunlight.

Step 1: Extracting Quantitative Parameters from the Passage:
The passage provides the following values:
- Annual Net Primary Productivity (\(\text{NPP}\)) of the entire biosphere:
\[ \text{NPP}_{\text{total}} = 170\text{ billion tons (dry weight)} \] - Annual Net Primary Productivity (\(\text{NPP}\)) of oceanic ecosystems:
\[ \text{NPP}_{\text{oceans}} = 55\text{ billion tons} \]

Step 2: Calculating Terrestrial (Land) Productivity:
The biosphere consists of terrestrial and marine environments:
\[ \text{NPP}_{\text{total}} = \text{NPP}_{\text{land}} + \text{NPP}_{\text{oceans}} \] Rearranging to solve for the terrestrial component:
\[ \text{NPP}_{\text{land}} = \text{NPP}_{\text{total}} - \text{NPP}_{\text{oceans}} \] Substituting the given numbers:
\[ \text{NPP}_{\text{land}} = 170\text{ billion tons} - 55\text{ billion tons} = 115\text{ billion tons} \] Although oceans cover approximately \(70.8\%\) of the Earth’s surface, they contribute only about \(55\text{ billion tons}\) due to light attenuation and nutrient limitation (such as nitrogen and iron).
Land ecosystems cover only \(\sim 29.2\%\) of the surface but generate about \(115\text{ billion tons}\) of biomass annually.

Final Answer:
The annual NPP of the land area on Earth is about 115 billion tons, corresponding to option (C).

Quick Tip: Global Primary Productivity Distribution:
- Entire Biosphere = \(170\text{ billion dry tons/year}\).
- Oceans (\(71\%\) of surface) = \(55\text{ billion tons/year}\) (\(\sim 32\%\)).
- Land (\(29\%\) of surface) = \(115\text{ billion tons/year}\) (\(\sim 68\%\)).
Terrestrial ecosystems produce roughly double the organic biomass of oceans.

Question 42:

Which of the following is not associated with photosynthetic plants?

  • (A) Net primary productivity
  • (B) Gross primary productivity
  • (C) Primary productivity
  • (D) Seconday productivity
Correct Answer: (D) Seconday productivity
View Solution

Concept:
In trophic ecology, productivity describes the rate at which organic biomass is synthesized within an ecosystem.
A functional distinction exists between autotrophic production (primary productivity) and heterotrophic production (secondary productivity).

Step 1: Identifying Plant-Associated Productivity Metrics:
1. Gross Primary Productivity (GPP): The total rate at which photosynthetic autotrophs (green plants, phytoplankton) fix solar energy into organic compounds through photosynthesis.
2. Net Primary Productivity (NPP): The organic biomass that remains after plants meet their own metabolic respiratory requirements (\(R\)):
\[ \text{NPP} = \text{GPP} - R \] 3. Primary Productivity: The broader term for all carbon fixation carried out by autotrophic producers.
All three metrics are direct physiological characteristics of photosynthetic plants.

Step 2: Identifying Heterotrophic Productivity:
Secondary Productivity (SP): As stated in the passage, secondary productivity is "the rate of formation of new organic matter by consumers".
Consumers (herbivores, carnivores, and decomposers) do not perform photosynthesis; they assimilate ingested organic matter into consumer tissues.
Because green plants are autotrophic primary producers, secondary productivity is not associated with photosynthetic plants.

Final Answer:
Secondary productivity is associated with consumers rather than photosynthetic plants, corresponding to option (D).

Quick Tip: Trophic Level Productivity Association:
- Primary Producers (Plants, Algae) \(\rightarrow\) GPP and NPP.
- Consumers (Herbivores, Carnivores) \(\rightarrow\) Secondary Productivity (SP).
Plants do not exhibit secondary productivity.

Question 43:

Choose the correct statement.

  • (A) Annual NPP of land area is higher than oceans.
  • (B) NPP is greater than GPP in terrestrial ecosystems.
  • (C) Secondary productivity is always higher than Primary productivity in Oceanic ecosystem.
  • (D) Primary productivity is unaffected by environmental factors.
Correct Answer: (A) Annual NPP of land area is higher than oceans.
View Solution

Concept:
Evaluating ecosystem energetics requires analyzing how primary and secondary production rates vary between marine and terrestrial biomes under different environmental constraints.

Step 1: Evaluating Statement (A):
From the passage and global ecological data, annual terrestrial Net Primary Productivity is approximately \(115\text{ billion tons}\), whereas oceanic NPP is approximately \(55\text{ billion tons}\).
Consequently, the annual NPP of the land area is substantially higher than that of the oceans, making statement (A) factually and conceptually correct.

Step 2: Evaluating Alternative Statements:
- Statement (B): In terrestrial ecosystems, plants expend a significant fraction of fixed energy (\(20-50\%\)) on cellular respiration (\(R\)).
Because \(\text{NPP} = \text{GPP} - R\), NPP is always less than GPP. Thus, statement (B) is incorrect.
- Statement (C): Under the Second Law of Thermodynamics and Lindeman’s 10% efficiency rule, energy transfer between trophic levels involves metabolic losses, meaning secondary productivity is always lower than primary productivity. Thus, statement (C) is incorrect.
- Statement (D): Primary productivity varies strongly with solar irradiance, ambient temperature, water availability, and soil nutrient levels, as noted in the passage. Thus, statement (D) is incorrect.

Final Answer:
The correct statement is that the annual NPP of land area is higher than oceans, corresponding to option (A).

Quick Tip: Ecological Production Inequalities:
- \(\text{GPP} > \text{NPP}\) (always, because respiration \(R > 0\)).
- \(\text{Primary Productivity} > \text{Secondary Productivity}\) (thermodynamic loss).
- \(\text{Land NPP } (115\text{ B tons}) > \text{Ocean NPP } (55\text{ B tons})\).

Question 44:

Inorganic nutrients are released into the soil by the decomposition of dead organic matter through a process called as ..............

  • (A) Photosynthesis
  • (B) Mineralization
  • (C) Purification
  • (D) Respiration
Correct Answer: (B) Mineralization
View Solution

Concept:
Decomposition is an essential ecological process in which decomposers (bacteria and fungi) break down complex organic detritus into simpler inorganic substances.
The process comprises five distinct steps: fragmentation, leaching, catabolism, humification, and mineralization.

Step 1: The Stages of Decomposition:
1. Fragmentation: Detritivores (such as earthworms) break down dead plant and animal remains into smaller particles.
2. Leaching: Water-soluble inorganic nutrients percolate into soil horizons and precipitate as unavailable salts.
3. Catabolism: Fungal and bacterial extracellular enzymes degrade complex detritus into simpler organic molecules.
4. Humification: Decomposed matter is converted into humus, a dark, amorphous, colloidal substance that is highly resistant to microbial action and serves as a nutrient reservoir.
5. Mineralization: As stated directly in the passage, humus is further broken down over time by specialized soil microbes, releasing bound inorganic mineral nutrients (\(\text{NH}_4^+\), \(\text{NO}_3^-\), \(\text{HPO}_4^{2-}\), \(\text{K}^+\), \(\text{Ca}^{2+}\), \(\text{SO}_4^{2-}\)) into the soil solution.

Step 2: Conclusion:
The specific process that converts organic matter to release bioavailable inorganic ions into the soil is called mineralization.

Final Answer:
The release of inorganic nutrients through organic matter decomposition is mineralization, corresponding to option (B).

Quick Tip: Humification vs. Mineralization:
- Humification: Formation of dark, amorphous, non-soluble humus from detritus (slow decomposition).
- Mineralization: Enzymatic breakdown of humus to release inorganic mineral ions (\(\text{N}, \text{P}, \text{K}, \text{S}\)) into the soil.

Question 45:

Which of the following units can be appropriately used in the expression of Primary Productivity of an ecosystem?

  • (A) \(\text{g m}^2/\text{yr}\)
  • (B) \(\text{Kg/Km}^2/\text{yr}\)
  • (C) \(\text{g/yr}\)
  • (D) \(\text{g/m/yr}\)
Correct Answer: (B) \(\text{Kg/Km}^2/\text{yr}\)
View Solution

Concept:
In ecological energetics, productivity is defined as the rate of biomass or energy accumulation per unit surface area per unit time.
Dimensional consistency requires expressing productivity as:
\[ \text{Productivity Dimensions} = \frac{[\text{Mass}]}{[\text{Area}] \times [\text{Time}]} \quad \text{or} \quad \frac{[\text{Energy}]}{[\text{Area}] \times [\text{Time}]} \]

Step 1: Dimensional Analysis of the Standard Unit:
As noted in the comprehension text, primary productivity is commonly reported in:
\[ \text{g}\cdot\text{m}^{-2}\cdot\text{yr}^{-1} = \frac{\text{g}}{\text{m}^2\cdot\text{yr}} \] In base SI dimensions, this represents:
\[ [\text{Mass}] \cdot [\text{Length}]^{-2} \cdot [\text{Time}]^{-1} \]

Step 2: Evaluating the Given Options:
- Option (A): \(\text{g m}^2/\text{yr} = [\text{Mass}] \cdot [\text{Length}]^2 \cdot [\text{Time}]^{-1}\). This multiplies mass by area rather than dividing by it, which is dimensionally incorrect.
- Option (B): \(\text{Kg/Km}^2/\text{yr} = \frac{\text{kg}}{\text{km}^2\cdot\text{yr}}\). This has the dimensions:
\[ \frac{[\text{Mass}]}{[\text{Area}] \times [\text{Time}]} = [\text{Mass}] \cdot [\text{Length}]^{-2} \cdot [\text{Time}]^{-1} \] Because kilograms (\(\text{kg}\)) represent mass, square kilometers (\(\text{km}^2\)) represent surface area, and years (\(\text{yr}\)) represent time, this formulation is dimensionally valid for landscape-scale productivity.
- Option (C): \(\text{g/yr} = [\text{Mass}] \cdot [\text{Time}]^{-1}\), which omits the unit area requirement.
- Option (D): \(\text{g/m/yr} = [\text{Mass}] \cdot [\text{Length}]^{-1} \cdot [\text{Time}]^{-1}\), which divides by linear distance rather than surface area.

Final Answer:
The dimensionally correct unit for primary productivity is \(\text{Kg/Km}^2/\text{yr}\), corresponding to option (B).

Quick Tip: Dimensional check for productivity:
Always verify: \(\frac{\text{Mass}}{\text{Area} \times \text{Time}}\) or \(\frac{\text{Energy}}{\text{Area} \times \text{Time}}\).
Valid units: \(\text{g/m}^2/\text{yr}\), \(\text{kg/km}^2/\text{yr}\), \(\text{kcal/m}^2/\text{yr}\).
Be alert to missing division signs or incorrect exponents.

​Comprehension Passage (Questions 46 to 50)
 



"Smog, a term coined 50 years ago, from the words "Smoke" and "fog" is a dirty yellow-brown cloudy formation in lower portion of troposphere near the ground. Smog, we are most familiar with are Los Angles and London smog. Former is a example of photochemical smog, and later is a classical smog which contained sulphur dioxide, sulphur trioxide, sulphuric acid, heavy suspended particles, and water vapours. Los Angles smog was formed by photochemical reactions among nitrogen oxides and volatile hydrocarbons in presence of sunlight. This type of smog contains ozone, PAN, formaldehyde, and causes eye irritation, impairs pulmonary functions and damage plants and crops."

​Question 46:
Choose the incorrect statement

  • (A) Smog is formed near the ground in the troposphere.
  • (B) Nitrogen oxides impart yellow-brown colour to smog.
  • (C) Photochemical somg formation is maximum when sun is overhead in the day.
  • (D) Photochemical smog formation is maximum in winter compared to summer season.
Correct Answer: (D) Photochemical smog formation is maximum in winter compared to summer season.
View Solution

Concept:
Smog is a form of air pollution that develops in the lower troposphere.
There are two major categories: classical (London-type) smog and photochemical (Los Angeles-type) smog.
Photochemical smog is driven by solar ultraviolet radiation and elevated ambient temperatures.

Step 1: Assessing the Conditions for Photochemical Smog Formation:
Photochemical smog formation begins with the photolysis of nitrogen dioxide (\(\text{NO}_2\)) by solar UV radiation (\(\lambda < 420\text{ nm}\)):
\[ \text{NO}_2 + h\nu \rightarrow \text{NO} + \text{O}(^3P) \] The liberated oxygen radical combines with diatomic oxygen to produce ground-level ozone:
\[ \text{O} + \text{O}_2 + M \rightarrow \text{O}_3 + M \] Secondary reactions between hydroxyl radicals, volatile organic compounds (VOCs), and \(\text{NO}_x\) yield peroxyacetyl nitrate (PAN) and aldehydes.
Because these photochemical chain reactions require intense solar insolation and warm temperatures, photochemical smog peaks during hot, sunny summer afternoons when the sun is directly overhead.

Step 2: Evaluating the Other Statements:
- Statement (A): Smog forms in the planetary boundary layer of the lower troposphere near the ground. (Correct)
- Statement (B): Nitrogen dioxide (\(\text{NO}_2\)) is a reddish-brown gas that imparts a characteristic yellow-brown haze to photochemical smog. (Correct)
- Statement (C): Smog production peaks around midday when solar insolation reaches its daily maximum. (Correct)
- Statement (D): Claiming that photochemical smog formation is higher in winter than in summer contradicts its reliance on solar insolation and warm temperatures. (Classical sulfurous smog occurs in cold, damp winter conditions, whereas photochemical smog develops in warm, sunny summer weather.)

Final Answer:
The incorrect statement is option (D).

Quick Tip: Contrasting Smog Types:
- Classical Smog (London): Cool, humid, winter mornings; high \(\text{SO}_2\) and smoke; reducing chemistry.
- Photochemical Smog (Los Angeles): Warm, dry, sunny summer afternoons; high \(\text{NO}_x\), VOCs, and \(\text{O}_3\); oxidizing chemistry.

Question 47:

Smog clouds of sulphur dioxide, water droplets and sulphuric acid droplets can be referred to as ..............

  • (A) Photochemical smog
  • (B) Oxidising smog
  • (C) Los Angles smog
  • (D) Reducing smog
Correct Answer: (D) Reducing smog
View Solution

Concept:
Smog types are classified based on their dominant chemical composition and overall oxidation-reduction behavior.
Atmospheric mixtures containing high concentrations of reducing agents behave differently from those dominated by strong chemical oxidants.

Step 1: Chemical Composition of Classical Smog:
As described in the passage, classical smog (exemplified by the Great London Smog of 1952) forms in cool, damp, foggy conditions where coal combustion releases large volumes of:
1. Sulphur dioxide (\(\text{SO}_2\))
2. Soot and fly-ash particulates
3. Sulphur trioxide (\(\text{SO}_3\))
4. Liquid droplets of sulphuric acid (\(\text{H}_2\text{SO}_4\)) formed by catalytic oxidation in fog droplets.

Step 2: Chemical Mechanism of Reducing Smog:
Because this smog contains elevated concentrations of sulphur dioxide, where sulfur exists in the intermediate \(+4\) oxidation state (\(\text{S}^{IV}\)), it readily acts as a chemical reducing agent by undergoing oxidation to sulphate (\(\text{S}^{VI}\)):
\[ \text{SO}_2 + \text{H}_2\text{O} \rightarrow \text{H}_2\text{SO}_3 \] \[ 2\text{H}_2\text{SO}_3 + \text{O}_2 \rightarrow 2\text{H}_2\text{SO}_4 \] Because reducing species dominate the mixture, classical sulfurous smog is chemically designated as reducing smog.
In contrast, photochemical smog contains high levels of ozone (\(\text{O}_3\)) and peroxides, making it an oxidising smog.

Final Answer:
Smog composed of sulphur dioxide, water droplets, and sulphuric acid is reducing smog, corresponding to option (D).

Quick Tip: Chemical Classification of Smog:
- London Smog = Classical Smog = Sulfurous Smog = Reducing Smog (dominated by \(\text{SO}_2\)).
- Los Angeles Smog = Photochemical Smog = Oxidising Smog (dominated by \(\text{O}_3\) and PAN).

Question 48:

Which of the following is not essentially required for photochemical smog formation?

  • (A) Nitrogen oxides
  • (B) Sunlight
  • (C) Water Vapour
  • (D) Volatile hydrocarbons
Correct Answer: (C) Water Vapour
View Solution

Concept:
Photochemical smog is a secondary atmospheric phenomenon formed through solar-driven reactions between primary vehicular emissions.
The essential chemical ingredients and physical conditions dictate whether photochemical smog can develop.

Step 1: The Essential Components of Photochemical Smog:
1. Nitrogen Oxides (\(\text{NO}_x\)): Primarily nitric oxide (\(\text{NO}\)) and nitrogen dioxide (\(\text{NO}_2\)) emitted by internal combustion engines. Photolysis of \(\text{NO}_2\) provides the oxygen atoms needed to generate ground-level ozone.
2. Volatile Hydrocarbons (VOCs): Unburned hydrocarbons emitted in vehicular exhaust and evaporated from industrial solvents. They react with hydroxyl radicals to produce peroxy radicals (\(\text{RO}_2^\bullet\)), which oxidize \(\text{NO}\) to \(\text{NO}_2\) without consuming ozone, allowing ozone levels to build up.
3. Sunlight (Ultraviolet Radiation): Solar photon flux (\(\lambda < 420\text{ nm}\)) drives the dissociation of \(\text{NO}_2\) and initiates the radical chain reactions.

Step 2: Role of Water Vapour:
While moisture is an essential component of classical London-type smog (where sulfur oxides dissolve into suspended fog droplets), it is not a prerequisite for photochemical smog.
Photochemical smog typically develops in arid, semi-arid, or dry Mediterranean basins (such as the Los Angeles basin, Mexico City, and Santiago) characterized by clear, sunny skies, low humidity, and stagnant atmospheric inversion layers.
High concentrations of water vapor are not required to drive the gas-phase photochemical chain reactions.

Final Answer:
Water vapour is not an essential requirement for photochemical smog formation, corresponding to option (C).

Quick Tip: Key Requirements for Photochemical Smog:
1. \(\text{NO}_x\) emissions (from vehicles).
2. Volatile Organic Compounds (VOCs).
3. Intense Sunlight (UV radiation).
4. Stagnant air / thermal inversion.
Fog and water vapor are required for classical smog, not photochemical smog.

Question 49:

Which of the following is not formed during Photochemical smog formation?

  • (A) Ozone
  • (B) Aldehydes
  • (C) Peroxy acetyl nitrate
  • (D) Sulphuric Acid
Correct Answer: (D) Sulphuric Acid
View Solution

Concept:
Photochemical smog is characterized by the production of toxic secondary oxidants through chemical reactions between nitrogen oxides and volatile organic compounds under solar irradiation.
In contrast, sulfurous smog is characterized by sulfur oxidation chemistry.

Step 1: Products of Photochemical Smog Reactions:
As described in the passage, photochemical reactions between \(\text{NO}_x\), hydrocarbons, and sunlight generate several characteristic secondary pollutants:
1. Ozone (\(\text{O}_3\)): Generated when atomic oxygen released from \(\text{NO}_2\) photolysis combines with molecular oxygen.
2. Peroxyacetyl Nitrate (PAN): Formed by the reaction of peroxyacetyl radicals (derived from hydrocarbon oxidation) with nitrogen dioxide:
\[ \text{CH}_3\text{C(O)OO}^\bullet + \text{NO}_2 \rightarrow \text{CH}_3\text{C(O)OONO}_2 \text{ (PAN)} \] 3. Aldehydes and Ketones: Incomplete oxidation of volatile hydrocarbons produces formaldehyde (\(\text{HCHO}\)) and acrolein (\(\text{CH}_2=\text{CHCHO}\)), both of which cause respiratory and eye irritation.

Step 2: Source of Sulphuric Acid:
Sulphuric Acid (\(\text{H}_2\text{SO}_4\)): Produced through the gas-phase and aqueous oxidation of sulphur dioxide (\(\text{SO}_2\)) emitted by coal combustion or smelters.
It is a primary constituent of classical reducing smog and acid precipitation, but is not a characteristic secondary product of the \(\text{NO}_x\)-hydrocarbon photochemical smog cascade described in the text.

Final Answer:
Sulphuric acid is not a product of photochemical smog formation, corresponding to option (D).

Quick Tip: Photochemical Smog Reaction Products:
- Ozone (\(\text{O}_3\))
- Peroxyacetyl Nitrate (PAN)
- Formaldehyde and Acrolein (Aldehydes)
- Nitric acid (\(\text{HNO}_3\))
Sulphuric acid (\(\text{H}_2\text{SO}_4\)) is associated with coal-burning sulfurous smog and acid rain.

Question 50:

Choose the correct statement

  • (A) Ozone formed during photochemical smog protects us from UV radiations.
  • (B) Increase in tropospheric ozone can reduce food production.
  • (C) Photochemical smog formation is maximum in morning and evening due to heavy traffic hours.
  • (D) Vehicular exhaust does not contain any precursors of ozone formation in the troposphere.
Correct Answer: (B) Increase in tropospheric ozone can reduce food production.
View Solution

Concept:
Ground-level tropospheric ozone (\(\text{O}_3\)) is a harmful secondary pollutant and phytotoxin that damages plant tissues, inhibits photosynthesis, and harms human health.
Evaluating its environmental impacts requires distinguishing its tropospheric effects from its stratospheric UV-shielding role.

Step 1: Evaluating the Impact on Crop Yields (Statement B):
Tropospheric ozone enters plant leaves through open stomata during normal gas exchange.
Inside the leaf apoplast, it degrades into reactive oxygen species (ROS, including hydrogen peroxide and hydroxyl radicals) that induce oxidative stress.
This damages chloroplast thylakoid membranes, degrades the primary carbon-fixing enzyme RuBisCO, accelerates foliar senescence, and inhibits photosynthesis.
Agronomic studies show that elevated tropospheric ozone causes yield reductions of \(5-15\%\) in staple crops such as wheat, rice, and soybeans, directly reducing food production.
Hence, statement (B) is scientifically correct.

Step 2: Evaluating the Other Statements:
- Statement (A): While stratospheric ozone shields the biosphere from harmful solar UV-B radiation, ground-level ozone in photochemical smog is a toxic pollutant that does not provide useful UV shielding. Thus, statement (A) is incorrect.
- Statement (C): Morning and evening traffic emissions release precursor gases (\(\text{NO}\) and hydrocarbons), but photochemical smog peaks in the early afternoon (12:00 PM to 3:00 PM) when solar UV intensity is highest. Thus, statement (C) is incorrect.
- Statement (D): Internal combustion engines are the primary urban source of \(\text{NO}_x\) and VOC precursors that generate tropospheric ozone. Thus, statement (D) is incorrect.

Final Answer:
The correct statement is that an increase in tropospheric ozone can reduce food production, corresponding to option (B).

Quick Tip: Key Tropospheric Ozone Facts:
- Strong phytotoxin that enters stomata, damages RuBisCO, and reduces crop yields.
- Secondary pollutant formed by vehicular \(\text{NO}_x\) and VOCs in the presence of sunlight.
- Peaks in early-to-mid afternoon, not during morning rush hour.

CUET UG 2026 Exam Pattern

Parameter Details
Exam Name Common University Entrance Test (CUET UG) 2026
Conducting Body National Testing Agency (NTA)
Exam Mode Computer-Based Test (CBT)
Exam Duration 60 minutes per test
Total Sections 3 (Languages, Domain Subjects, General Test)
Question Type Multiple Choice Questions (MCQs)
Questions per Test 50 questions (all compulsory)
Marking Scheme +5 for correct, -1 for incorrect
Maximum Marks 250 marks per test
Maximum Subject Choices 5 subjects in total
Syllabus Base Class 12 NCERT (mainly for Domain Subjects)

CUET UG 2026 Paper Analysis