NEET PYQs for Ionic Equilibrium in Solution with Solutions: Practice NEET Previous Year Questions

Select Goal &

City

Select Goal

Write a ReviewGet Upto ₹300*

Collegedunia Medicine Team

Updated on - Jan 19, 2026

Ionic Equilibrium in Solution is an important topic in the Chemistry section in NEET exam. Practising this topic will increase your score overall and make your conceptual grip on NEET exam stronger.

This article gives you a full set of NEET PYQs for Ionic Equilibrium in Solution with explanations for effective preparation. Practice of NEET Chemistry PYQs including Ionic Equilibrium in Solution questions regularly will improve accuracy, speed, and confidence in the NEET 2026 exam.

NEET PYQs for Ionic Equilibrium in Solution with Solutions

1.
The ionisation constant of ammonium hydroxide is $ 1.77 \times 10^{-5} $ at $298\, K.$ Hydrolysis constant of ammonium chloride is
- $ 5.65 \times 10^{-10} $
- $ 6.50 \times 10^{-12} $
- $ 5.65 \times 10^{-13} $
- $ 5.65 \times 10^{-12} $
View Solution
2.
The ionic product of water at $25^{\circ} C$ is $10^{-14}$. Its ionic product at $90^{\circ} C$ will be
- $1 \times 10^{-14}$
- $1 \times 10^{-12}$
- $1 \times 10^{-20}$
- $1 \times 10^{-16}$
View Solution
3.
The molar solubility of CaF$_2$ (K$_{sp}$ = 5.3 × 10$^{-11}$) in 0.1 M solution of NaF will be
- 5.3 × 10$^{-11}$ mol L$^{-1}$
- 5.3 × 10$^{-8}$ mol L$^{-1}$
- 5.3 × 10$^{-9}$ mol L$^{-1}$
- 5.3 × 10$^{-10}$ mol L$^{-1}$
View Solution

View more NEET Questions

Fees Structure

Structure based on different categories

Categories	State
General	1700
sc	1000
pwd	1000

Note: EWS and OBC Category Fees- INR 1600

In case of any inaccuracy, Notify Us!

Comments

No Comments To Show

SUBSCRIBE TO OUR NEWS LETTER

COLLEGE NOTIFICATIONS

EXAM NOTIFICATIONS

NEWS UPDATES

Download the Collegedunia app on

NEET PYQs for Ionic Equilibrium in Solution with Solutions

1.The ionisation constant of ammonium hydroxide is $ 1.77 \times 10^{-5} $ at $298\, K.$ Hydrolysis constant of ammonium chloride is

2.The ionic product of water at $25^{\circ} C$ is $10^{-14}$. Its ionic product at $90^{\circ} C$ will be

3.The molar solubility of CaF$_2$ (K$_{sp}$ = 5.3 × 10$^{-11}$) in 0.1 M solution of NaF will be

Fees Structure

Structure based on different categories

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
The ionisation constant of ammonium hydroxide is $ 1.77 \times 10^{-5} $ at $298\, K.$ Hydrolysis constant of ammonium chloride is

2.
The ionic product of water at $25^{\circ} C$ is $10^{-14}$. Its ionic product at $90^{\circ} C$ will be

3.
The molar solubility of CaF$_2$ (K$_{sp}$ = 5.3 × 10$^{-11}$) in 0.1 M solution of NaF will be