NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Exercise 10.3

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NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Exercise 10.3 is covered in this article with a detailed explanation. Chapter 10 Vector Algebra Exercise 10.1 covers basic concepts of the product of two vectors, multiplication of vector by a scalar, and projection of a vector on a line.

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Class 12 Chapter 10 Vector Algebra Topics:

Properties of scalar product of two vectors	Laws of Vector Addition	Vector Formula
Magnitude of a vector	Vector Projection Formula	Scalar triple product of vectors
Direction of a vector	Adjacency Matrix	Components of vector
Vector Space	Cross product	Vector Calculus

CBSE Class 12 Mathematics Study Guides:

NCERT Solutions for Class 12 Maths	Math Formula	Difference between in Maths
Math MCQs	Math Study Notes	Calculus
Mensuration	Arithmetic	Trigonometry

CBSE CLASS XII Related Questions

1.
Mother, Father and Son line up at random for a family picture. Let events \(E\): Son on one end and \(F\): Father in the middle. Find \(P(E/F)\).

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2.
Find : \[ \int \frac{2x+1}{\sqrt{x^2+6x}}\,dx \]

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3.
A line passing through the points \(A(1,2,3)\) and \(B(6,8,11)\) intersects the line \[ \vec r = 4\hat i + \hat j + \lambda(6\hat i + 2\hat j + \hat k) \] Find the coordinates of the point of intersection. Hence write the equation of a line passing through the point of intersection and perpendicular to both the lines.

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4.
Sports car racing is a form of motorsport which uses sports car prototypes. The competition is held on special tracks designed in various shapes. The equation of one such track is given as

(i) Find \(f'(x)\) for \(0<x>3\).
(ii) Find \(f'(4)\).
(iii)(a) Test for continuity of \(f(x)\) at \(x=3\).
OR
(iii)(b) Test for differentiability of \(f(x)\) at \(x=3\).

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5.
Smoking increases the risk of lung problems. A study revealed that 170 in 1000 males who smoke develop lung complications, while 120 out of 1000 females who smoke develop lung related problems. In a colony, 50 people were found to be smokers of which 30 are males. A person is selected at random from these 50 people and tested for lung related problems. Based on the given information answer the following questions:

(i) What is the probability that selected person is a female?
(ii) If a male person is selected, what is the probability that he will not be suffering from lung problems?
(iii)(a) A person selected at random is detected with lung complications. Find the probability that selected person is a female.
OR
(iii)(b) A person selected at random is not having lung problems. Find the probability that the person is a male.

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6.
Find the domain of \(p(x)=\sin^{-1}(1-2x^2)\). Hence, find the value of \(x\) for which \(p(x)=\frac{\pi}{6}\). Also, write the range of \(2p(x)+\frac{\pi}{2}\).

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NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Exercise 10.3

CBSE CLASS XII Related Questions

1.
Mother, Father and Son line up at random for a family picture. Let events \(E\): Son on one end and \(F\): Father in the middle. Find \(P(E/F)\).

2.
Find : \[ \int \frac{2x+1}{\sqrt{x^2+6x}}\,dx \]

6.
Find the domain of \(p(x)=\sin^{-1}(1-2x^2)\). Hence, find the value of \(x\) for which \(p(x)=\frac{\pi}{6}\). Also, write the range of \(2p(x)+\frac{\pi}{2}\).

Similar Mathematics Concepts

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NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Exercise 10.3

CBSE CLASS XII Related Questions

1.Mother, Father and Son line up at random for a family picture. Let events \(E\): Son on one end and \(F\): Father in the middle. Find \(P(E/F)\).

2.Find : \[ \int \frac{2x+1}{\sqrt{x^2+6x}}\,dx \]

6.Find the domain of \(p(x)=\sin^{-1}(1-2x^2)\). Hence, find the value of \(x\) for which \(p(x)=\frac{\pi}{6}\). Also, write the range of \(2p(x)+\frac{\pi}{2}\).

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Mother, Father and Son line up at random for a family picture. Let events \(E\): Son on one end and \(F\): Father in the middle. Find \(P(E/F)\).

2.
Find : \[ \int \frac{2x+1}{\sqrt{x^2+6x}}\,dx \]

6.
Find the domain of \(p(x)=\sin^{-1}(1-2x^2)\). Hence, find the value of \(x\) for which \(p(x)=\frac{\pi}{6}\). Also, write the range of \(2p(x)+\frac{\pi}{2}\).