NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Exercise 10.2

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NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Exercise 10.2 is covered in this article with a detailed explanation. Chapter 10 Vector Algebra Exercise 10.2 covers basic concepts of addition of vectors, property of vector addition, and multiplication of a vector by a scalar.

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Check out other exercise solutions of Class 12 Maths Chapter 10 Vector Algebra

Class 12 Chapter 10 Vector Algebra Topics:

Types of vectors	Vector Calculus	Laws of Vector Addition
Negative of a vector	Vector Projection Formula	Vector Formula
Triangle law of vector addition	Direction of a vector	Components of vector
Vector Space	Cross product	Vector Calculus

CBSE Class 12 Mathematics Study Guides:

NCERT Solutions for Class 12 Maths	Math Formula	Difference between in Maths
Math Study Notes	Arithmetic	Trigonometry
Mensuration	Math MCQs	Calculus

CBSE CLASS XII Related Questions

1.
The integrating factor of the differential equation $ (x + 2y^3) \frac{dy}{dx} = 2y $ is:

$ e^{y^2} $
$ \frac{1}{\sqrt{y}} $
$ e^{-\frac{1}{y^2}} $
$ e^{y^2} $

View Solution

2.
If $ \mathbf{a} $ and $ \mathbf{b} $ are position vectors of two points $ P $ and $ Q $ respectively, then find the position vector of a point $ R $ in $ QP $ produced such that \[ QR = \frac{3}{2} QP. \]

View Solution

3.
A coin is tossed twice. Let $X$ be a random variable defined as the number of heads minus the number of tails. Obtain the probability distribution of $X$ and also find its mean.

View Solution

4.
If $ \int \frac{1}{2x^2} \, dx = k \cdot 2x + C $, then $ k $ is equal to:

$ -1 $
$ \log 2 $
$ -\log 2 $
$ 1/2 $

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5.
Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.

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6.
If $ \overrightarrow{a} + \overrightarrow{b} + \overrightarrow{c} = 0 $, $ |\overrightarrow{a}| = \sqrt{37} $, $ |\overrightarrow{b}| = 3 $, and $ |\overrightarrow{c}| = 4 $, then the angle between $ \overrightarrow{b} $ and $ \overrightarrow{c} $ is:

$ \frac{\pi}{6} $
$ \frac{\pi}{4} $
$ \frac{\pi}{3} $
$ \frac{\pi}{2} $

View Solution

NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Exercise 10.2

CBSE CLASS XII Related Questions

1.
The integrating factor of the differential equation \( (x + 2y^3) \frac{dy}{dx} = 2y \) is:

2.
If \( \mathbf{a} \) and \( \mathbf{b} \) are position vectors of two points \( P \) and \( Q \) respectively, then find the position vector of a point \( R \) in \( QP \) produced such that \[ QR = \frac{3}{2} QP. \]

3.
A coin is tossed twice. Let $X$ be a random variable defined as the number of heads minus the number of tails. Obtain the probability distribution of $X$ and also find its mean.

4.
If \( \int \frac{1}{2x^2} \, dx = k \cdot 2x + C \), then \( k \) is equal to:

5.
Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.

6.
If \( \overrightarrow{a} + \overrightarrow{b} + \overrightarrow{c} = 0 \), \( |\overrightarrow{a}| = \sqrt{37} \), \( |\overrightarrow{b}| = 3 \), and \( |\overrightarrow{c}| = 4 \), then the angle between \( \overrightarrow{b} \) and \( \overrightarrow{c} \) is:

Similar Mathematics Concepts

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NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Exercise 10.2

CBSE CLASS XII Related Questions

1.The integrating factor of the differential equation \( (x + 2y^3) \frac{dy}{dx} = 2y \) is:

2.If \( \mathbf{a} \) and \( \mathbf{b} \) are position vectors of two points \( P \) and \( Q \) respectively, then find the position vector of a point \( R \) in \( QP \) produced such that \[ QR = \frac{3}{2} QP. \]

3.A coin is tossed twice. Let $X$ be a random variable defined as the number of heads minus the number of tails. Obtain the probability distribution of $X$ and also find its mean.

4.If \( \int \frac{1}{2x^2} \, dx = k \cdot 2x + C \), then \( k \) is equal to:

5.Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.

6.If \( \overrightarrow{a} + \overrightarrow{b} + \overrightarrow{c} = 0 \), \( |\overrightarrow{a}| = \sqrt{37} \), \( |\overrightarrow{b}| = 3 \), and \( |\overrightarrow{c}| = 4 \), then the angle between \( \overrightarrow{b} \) and \( \overrightarrow{c} \) is:

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
The integrating factor of the differential equation \( (x + 2y^3) \frac{dy}{dx} = 2y \) is:

2.
If \( \mathbf{a} \) and \( \mathbf{b} \) are position vectors of two points \( P \) and \( Q \) respectively, then find the position vector of a point \( R \) in \( QP \) produced such that \[ QR = \frac{3}{2} QP. \]

3.
A coin is tossed twice. Let $X$ be a random variable defined as the number of heads minus the number of tails. Obtain the probability distribution of $X$ and also find its mean.

4.
If \( \int \frac{1}{2x^2} \, dx = k \cdot 2x + C \), then \( k \) is equal to:

5.
Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.

6.
If \( \overrightarrow{a} + \overrightarrow{b} + \overrightarrow{c} = 0 \), \( |\overrightarrow{a}| = \sqrt{37} \), \( |\overrightarrow{b}| = 3 \), and \( |\overrightarrow{c}| = 4 \), then the angle between \( \overrightarrow{b} \) and \( \overrightarrow{c} \) is: