NCERT Solutions for Class 12 Chapter 13 Probability Exercise 13.3

Collegedunia Team logo

Collegedunia Team

Content Curator

Class 12 Maths NCERT Solutions Chapter 13 Probability Exercise 13.3 is based on Bayes’ Theorem also covering questions based on Bayes Theorem Formula.

Download PDF NCERT Solutions for Class 12 Maths Chapter 13 Probability Exercise 13.3

Check out the solutions of Class 12 Maths NCERT solutions Chapter 13 Probability Exercise 13.3

Read More: NCERT Solutions For Class 12 Mathematics Chapter 13 Probability

Also check other Exercise Solutions of Class 12 Maths Chapter 13 Probability

Also Read:

Also Read:

CBSE CLASS XII Related Questions

  • 1.
    Find:

    If \[ (3\hat{i}-2\hat{j}+5\hat{k})\times(4\hat{i}+p\hat{j}+q\hat{k})=\vec{0} \] then find the values of \(p\) and \(q\).

      • \(p = -\frac{2}{3}, \, q = \frac{5}{3}\)
      • \(p = -\frac{8}{3}, \, q = \frac{20}{3}\)
      • \(p = \frac{20}{3}, \, q = -\frac{8}{3}\)
      • \(p = 0, \, q = 0\)

    • 2.
      Find: \[ \int \frac{x^2}{(x^2-1)(x^2+4)}\,dx \]


        • 3.
          Find:

          The shortest distance between the lines: \[ \vec{r}=(4+\lambda)\hat{i}+(2\lambda-1)\hat{j}-3\lambda\hat{k} \] and \[ \vec{r}=(1+2\mu)\hat{i}+(4\mu-1)\hat{j}+(2-5\mu)\hat{k} \]


            • 4.

              Evaluate:
              \[ \int_{0}^{1} \frac{x \tan^{-1}x}{(1+x^2)^{3/2}}\,dx \]


                • 5.
                  Differentiate \( \tan^{-1}\left( \frac{\sqrt{1 + x^2} + \sqrt{1 - x^2}}{\sqrt{1 + x^2} - \sqrt{1 - x^2}} \right) \) with respect to \( \cos^{-1}(x^2) \).


                    • 6.
                      If \( xy = e^{x - y} \), then find \( \frac{dy}{dx} \).

                        CBSE CLASS XII Previous Year Papers

                        Comments


                        No Comments To Show