Re-NEET Answer Key 2026 Code 80 (Available): Download PDF

NEET Questions

• 1.

  For sound waves, if the number of nodes for the 5th harmonic of an open-ended pipe is \(n\) and that for the 9th harmonic of the same pipe with one of its ends closed is \(m\), the ratio \(n/m\) is:

  • \(\dfrac{3}{5}\)
  • \(\dfrac{9}{5}\)
  • \(\dfrac{5}{9}\)
  • \(1\)
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• 2.

  Consider the reversible processes for 1.0 mol of an ideal gas as shown in the figure. Processes 2 and 4 are adiabatic. \(w_1,w_2,w_3\) and \(w_4\) represent work done (in calories) in processes 1, 2, 3 and 4, respectively. \(\Delta U_2\) and \(\Delta U_4\) are changes in internal energy for processes 2 and 4, respectively. [Use \(R = 2\ \text{cal}\ \text{K}^{-1}\text{mol}^{-1}\)]
  

  

  • \(w_1+w_2+w_3+w_4=0\)
  • \(w_1+w_3=-2T_1\ln\left(\frac{V_2}{V_1}\right)-2T_2\ln\left(\frac{V_4}{V_3}\right)\)
  • \(w_2+w_4=\Delta U_2-\Delta U_4\)
  • \(w_1+w_2=2T_1\ln\left(\frac{V_2}{V_1}\right)\)
  View Solution

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• 3.

  A photon and an electron, each of \(10\,\text{eV}\) energy, move in free space. The ratio of linear momentum of electron \(P_e\) to that of photon \(P_{ph}\), \[ \frac{P_e}{P_{ph}} \] is :

  • \(275\)
  • \(\frac{2}{450}\)
  • \(\frac{1}{250}\)
  • \(225\)
  View Solution

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• 4.

  The current I in the circuit shown below is: (All diodes are ideal and identical)
  

  

  • 5/3 A
    
  • 5/9 A
    
  • 15/2 A
    
  • 1/3 A
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• 5.

  Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R. Assertion A : Generally, 3d transition metals have high melting points. Reason R : Involvement of 3d-electrons in addition to 4s-electrons in the interatomic metallic bonding. In the light of the above statements, choose the most appropriate answer from the options given below.

  • A is not correct but R is correct.
  • Both A and R are correct and R is the correct explanation of A.
  • Both A and R are correct but R is NOT the correct explanation of A.
  • A is correct but R is not correct.
  View Solution

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• 6.

  The numbers \(17.0145\) and \(21.0235\) were rounded to three figures after the decimal point. The resulting numbers, respectively, are

  • \(17.015\) and \(21.024\)
  • \(17.014\) and \(21.023\)
  • \(17.015\) and \(21.023\)
  • \(17.014\) and \(21.024\)
  View Solution