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| Updated On - Nov 25, 2024
CUET Physics Question Paper 2024 (Set B) is available for download here. NTA conducted CUET 2024 Physics paper on 16 May in Shift 2A from 3 PM to 4 PM. CUET Physics Question Paper 2024 is based on objective-type questions (MCQs). Candidates get 60 minutes to solve 40 MCQs out of 50 in CUET 2024 question paper for Physics.
CUET Physics Question Paper 2024 (Set B) PDF Download
| CUET Physics Question Paper with Answer Key Set B |  Download |
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| Question | Answer | Detailed Solution |
|---|---|---|
| In an electromagnetic wave, the ratio of energy densities of electric and magnetic fields is: (1) 1:1 (2) 1:c (3) c:1 (4) 1:c² |
(1) 1:1 | In an electromagnetic wave, the energy densities of the electric and magnetic fields are equal. This is a fundamental property of electromagnetic waves. Therefore, the ratio of their energy densities is 1:1. |
| Match List-I (graphs showing variation of opposition to flow of AC versus frequency) with List-II (circuit characteristic). Choose the correct answer from the options given below: (1) (A)-(I), (B)-(II), (C)-(III), (D)-(IV) (2) (A)-(IV), (B)-(III), (C)-(II), (D)-(I) (3) (A)-(I), (B)-(II), (C)-(IV), (D)-(III) (4) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) |
(2) (A)-(IV), (B)-(III), (C)-(II), (D)-(I) | The correct matching is determined by analyzing the frequency response graphs in relation to the circuit characteristics (e.g., series resonance, parallel resonance). |
| In an electromagnetic wave, the ratio of energy densities of electric and magnetic fields is: (1) 1:1 (2) 1:c (3) c:1 (4) 1:c² |
(1) 1:1 | In an electromagnetic wave, the energy densities of the electric and magnetic fields are equal. This is a fundamental property of electromagnetic waves. Therefore, the ratio of their energy densities is 1:1. |
| Match List-I (graphs showing variation of opposition to flow of AC versus frequency) with List-II (circuit characteristic). Choose the correct answer from the options given below: (1) (A)-(I), (B)-(II), (C)-(III), (D)-(IV) (2) (A)-(IV), (B)-(III), (C)-(II), (D)-(I) (3) (A)-(I), (B)-(II), (C)-(IV), (D)-(III) (4) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) |
(2) (A)-(IV), (B)-(III), (C)-(II), (D)-(I) | The correct matching is determined by analyzing the frequency response graphs in relation to the circuit characteristics (e.g., series resonance, parallel resonance). |
CUET Previous Year Question Paper PDF
| CUET Physics Previous Year Question Papers | CUET Question Paper 2023 |
| CUET Question Paper 2022 | CUET Question Paper 2021 |
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CUET Questions
1. When a photon of energy hν falls on a photosensitive metallic surface (work function hν0), electrons are emitted from the metallic surface. It is possible to say that:
When a photon of energy hν falls on a photosensitive metallic surface (work function hν0), electrons are emitted from the metallic surface. It is possible to say that:
- All have the same K.E.=hν−hν$_0$
- Maximum K.E.=hν−hν$_0$
- Maximum K.E.=hν
- K.E.=hν$_0$
2. In a p-type semiconductor, the acceptor level is situated 50 meV above the valence band. The maximum wavelength of light required to produce a hole will be:
In a p-type semiconductor, the acceptor level is situated 50 meV above the valence band. The maximum wavelength of light required to produce a hole will be:
- $24.8 \times 10^{-5} \, \text{m} \\$
- $0.248 \times 10^{-5} \, \text{m} \\$
- $2.48 \times 10^{-5} \, \text{m} \\$
- $248 \times 10^{-5} \, \text{m}$
3. \( A \;pure \;silicon \;crystal \;with \; 5 \times 10^{28} \, \text{atoms/m}^3 \text{ has } n_i = 1.5 \times10^{16}\text{m}^{-3}.\text{ It is doped with a concentration of 1 in } 10^5 \text{ pentavalent atoms.}\text{The number density of holes (per m}^3\text{) in the doped semiconductor will be:}\)
\( A \;pure \;silicon \;crystal \;with \; 5 \times 10^{28} \, \text{atoms/m}^3 \text{ has } n_i = 1.5 \times10^{16}\text{m}^{-3}.\text{ It is doped with a concentration of 1 in } 10^5 \text{ pentavalent atoms.}\text{The number density of holes (per m}^3\text{) in the doped semiconductor will be:}\)
- \(\quad 4.5 \times 10^3 \\\)
- \(\quad 4.5 \times 10^8 \\\)
- \(\quad \left( \frac{10}{3} \right) \times 10^{12} \\\)
- \(\quad \left( \frac{10}{3} \right) \times 10^7\)
4. The study of radioactive decay results in the emission of particles, leading to four observations: (A) No change in atomic and mass number, (B) Atomic number decreases by 1, (C) Study of radioactive decay of unstable nuclei resulting in emission of a
particle leads us to four different observations listed below:
(A) Nochange in atomic number and mass number.
(B) Nochange in mass number but the atomic number decreases by 1.
(C) Nochange in mass number but the atomic number increases by 1.
(D) Atomic number decreases by 2 and the mass number decreases by 4.
Arrange the particles emitted in the above four cases in correct sequence:
The study of radioactive decay results in the emission of particles, leading to four observations: (A) No change in atomic and mass number, (B) Atomic number decreases by 1, (C) Study of radioactive decay of unstable nuclei resulting in emission of a
particle leads us to four different observations listed below:
(A) Nochange in atomic number and mass number.
(B) Nochange in mass number but the atomic number decreases by 1.
(C) Nochange in mass number but the atomic number increases by 1.
(D) Atomic number decreases by 2 and the mass number decreases by 4.
Arrange the particles emitted in the above four cases in correct sequence:
particle leads us to four different observations listed below:
(A) Nochange in atomic number and mass number.
(B) Nochange in mass number but the atomic number decreases by 1.
(C) Nochange in mass number but the atomic number increases by 1.
(D) Atomic number decreases by 2 and the mass number decreases by 4.
Arrange the particles emitted in the above four cases in correct sequence:
- Alpha particle, positron, electron, photon
- Alpha particle, electron, positron, photon
- Photon, positron, electron, alpha particle
- Alpha particle, positron, photon, electron
5. In an LCR series circuit, the source of emf is E=30sin(100t), R=120Ω, L=100mH, C=100μF.
(A) The numerical value of impedance
(B) The numerical value of resistance R
(C) The numerical value of capacitive reactance
(D) The numerical value of inductive reactance.
Arrange the values of quantities mentioned in (A, B, C, D) in increasing order.
In an LCR series circuit, the source of emf is E=30sin(100t), R=120Ω, L=100mH, C=100μF.
(A) The numerical value of impedance
(B) The numerical value of resistance R
(C) The numerical value of capacitive reactance
(D) The numerical value of inductive reactance.
Arrange the values of quantities mentioned in (A, B, C, D) in increasing order.
(A) The numerical value of impedance
(B) The numerical value of resistance R
(C) The numerical value of capacitive reactance
(D) The numerical value of inductive reactance.
Arrange the values of quantities mentioned in (A, B, C, D) in increasing order.
- (A), (B), (C), (D)
- (A), (C), (B), (D)
- (B), (A), (D), (C)
- (D), (C), (B), (A)
6. If the momentum of an electron is changed by P, then the de Broglie wavelength associated with it changes by\( 1\%\). The initial momentum of the electron will be:
If the momentum of an electron is changed by P, then the de Broglie wavelength associated with it changes by\( 1\%\). The initial momentum of the electron will be:
- 200 P
- 100 P
- 300 P
- 150 P
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