NCERT Solutions for Class 12 Chapter 9 Differential Equations Exercise 9.5 Solutions

Collegedunia Team logo

Collegedunia Team

Content Curator

Class 12 Maths NCERT Solutions Chapter 9 Differential Equations Exercise 9.5 is provided in the article. Class 12 Chapter 9 Differential Equations Exercises provided in the chapter are based on Homogeneous Differential Equations.

Download PDF: NCERT Solutions for Class 12 Maths Chapter 9 Exercise 9.5

Read More: NCERT Solutions For Class 12 Mathematics Chapter 9 Differential Equations

Also check other Exercise Solutions of Class 12 Maths Chapter 9 Differential Equations

Also Read:

Also Read:

CBSE CLASS XII Related Questions

  • 1.
    Find:

    The principal value of \[ \sec^{-1}(\sqrt{2})+2\csc^{-1}(-2) \] is:

      • \(-\frac{\pi}{2}\)
      • \(-\frac{\pi}{4}\)
      • \(\frac{\pi}{4}\)
      • \(\frac{\pi}{2}\)

    • 2.
      Find:

      If the function \[ f(x)= \begin{cases} \frac{\sin x}{x}+\cos x, & x\neq0\\ k, & x=0 \end{cases} \] is continuous at \(x=0\), then find the value of \(k\).

        • \(0\)
        • \(-2\)
        • \(-1\)
        • \(2\)

      • 3.

        An NGO organises a charity event in which they decide to distribute woollen caps to protect children from winter. The caps to be distributed are in three separate boxes, Box I has 30 red caps, Box II has 20 red and 10 green caps, and Box III has 30 green caps. The probability that a Box i is selected and a cap picked out is i/6, where i = 1, 2, 3.  
        Based on the above information, answer the following questions :


          • 4.

            Evaluate:
            \[ \int_{0}^{1} \frac{x \tan^{-1}x}{(1+x^2)^{3/2}}\,dx \]


              • 5.
                A relation $R$ on set $A=\{1,2,3\}$ defined as $R=\{(1,2),(2,1),(2,2)\}$ is

                  • Reflexive only
                  • Reflexive and Transitive
                  • Symmetric and Transitive
                  • Symmetric only

                • 6.
                  Find:

                  The shortest distance between the lines: \[ \vec{r}=(4+\lambda)\hat{i}+(2\lambda-1)\hat{j}-3\lambda\hat{k} \] and \[ \vec{r}=(1+2\mu)\hat{i}+(4\mu-1)\hat{j}+(2-5\mu)\hat{k} \]

                    CBSE CLASS XII Previous Year Papers

                    Comments


                    No Comments To Show