NCERT Solutions for Class 12 Chapter 9 Differential Equations Exercise 9.5 Solutions

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Class 12 Maths NCERT Solutions Chapter 9 Differential Equations Exercise 9.5 is provided in the article. Class 12 Chapter 9 Differential Equations Exercises provided in the chapter are based on Homogeneous Differential Equations.

Download PDF: NCERT Solutions for Class 12 Maths Chapter 9 Exercise 9.5

Also check other Exercise Solutions of Class 12 Maths Chapter 9 Differential Equations

Also Read:

Chapter 9 Differential Equations Important Topics
Differential Equations Applications	Difference between parametric and nonparametric	Partial Differential Equation
Ordinary differential equations	Differential Equations Formula	Differential Calculus
Partial Derivative	How to Solve Linear Differential Equation	Homogeneous Differential Equation

Also Read:

CBSE Class 12 Mathematics Study Guides
Algebra	Arithmetic	Calculus
Mensuration	Trigonometry	Geometry
Permutation and Combination	Math Study Notes	Math MCQs
NCERT Solutions for Class 12 Maths	Math Formula	Difference between in Maths

CBSE CLASS XII Related Questions

1.
Solve the following Linear Programming Problem graphically :
Maximize \( Z = \frac{2x}{5} + \frac{3y}{10} \)
subject to constraints
\( 2x + y \leq 1000 \)
\( x + y \leq 800 \)
\( x, y \geq 0 \).
View Solution
2.
A die is rolled. Consider events : \( A = \{1, 2, 5\} \), \( B = \{3, 5\} \), \( C = \{2, 3, 4, 5\} \). Find \( P(A \cap B|C) \) and \( P(A \cup B|C) \).
View Solution
3.
A box contains 6 cards numbered 1 to 6. A student is asked to pick up two cards, one by one after replacement and note down the numbers on the cards. Let A be the event of getting sum of the numbers on two cards as 10, and B, the event of a number other than 4 on the first card selected. Find \( P(A \text{ and } B) \) and find whether the events A and B are independent events or not.
View Solution
4.
Find the value of \( p \) if the shortest distance between the lines \( \vec{r} = (\hat{i} + 2\hat{j} + \hat{k}) + \lambda(\hat{i} - \hat{j} + \hat{k}) \) and \( \vec{r} = (p\hat{i} - \hat{j} - \hat{k}) + \mu(2\hat{i} + \hat{j} + 2\hat{k}) \) is \( \frac{3}{\sqrt{2}} \) units.
View Solution
5.
The volume of a wooden block in the shape of a cube increases at a constant rate as the air becomes moist during the rainy season. Show that the rate of change of its surface area varies inversely as the length of edge of the cube.
View Solution
6.
Sketch the graph defined by \( \left\{ (x, y) : \frac{x^2{25} + \frac{y^2}{25} = 1 \right\} \). Find the area of the region of minor segment cut off by the line \( x = \frac{5}{2} \), using integration.}
View Solution

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You can also check

NCERT Solutions for Class 12 Chapter 9 Differential Equations Exercise 9.5 Solutions

CBSE CLASS XII Related Questions

1.
Solve the following Linear Programming Problem graphically :
Maximize \( Z = \frac{2x}{5} + \frac{3y}{10} \)
subject to constraints
\( 2x + y \leq 1000 \)
\( x + y \leq 800 \)
\( x, y \geq 0 \).

2.
A die is rolled. Consider events : \( A = \{1, 2, 5\} \), \( B = \{3, 5\} \), \( C = \{2, 3, 4, 5\} \). Find \( P(A \cap B|C) \) and \( P(A \cup B|C) \).

4.
Find the value of \( p \) if the shortest distance between the lines \( \vec{r} = (\hat{i} + 2\hat{j} + \hat{k}) + \lambda(\hat{i} - \hat{j} + \hat{k}) \) and \( \vec{r} = (p\hat{i} - \hat{j} - \hat{k}) + \mu(2\hat{i} + \hat{j} + 2\hat{k}) \) is \( \frac{3}{\sqrt{2}} \) units.

5.
The volume of a wooden block in the shape of a cube increases at a constant rate as the air becomes moist during the rainy season. Show that the rate of change of its surface area varies inversely as the length of edge of the cube.

6.
Sketch the graph defined by \( \left\{ (x, y) : \frac{x^2{25} + \frac{y^2}{25} = 1 \right\} \). Find the area of the region of minor segment cut off by the line \( x = \frac{5}{2} \), using integration.}

Similar Mathematics Concepts

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NCERT Solutions for Class 12 Chapter 9 Differential Equations Exercise 9.5 Solutions

CBSE CLASS XII Related Questions

1.Solve the following Linear Programming Problem graphically : Maximize \( Z = \frac{2x}{5} + \frac{3y}{10} \) subject to constraints \( 2x + y \leq 1000 \) \( x + y \leq 800 \) \( x, y \geq 0 \).

2.A die is rolled. Consider events : \( A = \{1, 2, 5\} \), \( B = \{3, 5\} \), \( C = \{2, 3, 4, 5\} \). Find \( P(A \cap B|C) \) and \( P(A \cup B|C) \).

4.Find the value of \( p \) if the shortest distance between the lines \( \vec{r} = (\hat{i} + 2\hat{j} + \hat{k}) + \lambda(\hat{i} - \hat{j} + \hat{k}) \) and \( \vec{r} = (p\hat{i} - \hat{j} - \hat{k}) + \mu(2\hat{i} + \hat{j} + 2\hat{k}) \) is \( \frac{3}{\sqrt{2}} \) units.

5.The volume of a wooden block in the shape of a cube increases at a constant rate as the air becomes moist during the rainy season. Show that the rate of change of its surface area varies inversely as the length of edge of the cube.

6.Sketch the graph defined by \( \left\{ (x, y) : \frac{x^2{25} + \frac{y^2}{25} = 1 \right\} \). Find the area of the region of minor segment cut off by the line \( x = \frac{5}{2} \), using integration.}

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Solve the following Linear Programming Problem graphically :
Maximize \( Z = \frac{2x}{5} + \frac{3y}{10} \)
subject to constraints
\( 2x + y \leq 1000 \)
\( x + y \leq 800 \)
\( x, y \geq 0 \).

2.
A die is rolled. Consider events : \( A = \{1, 2, 5\} \), \( B = \{3, 5\} \), \( C = \{2, 3, 4, 5\} \). Find \( P(A \cap B|C) \) and \( P(A \cup B|C) \).

4.
Find the value of \( p \) if the shortest distance between the lines \( \vec{r} = (\hat{i} + 2\hat{j} + \hat{k}) + \lambda(\hat{i} - \hat{j} + \hat{k}) \) and \( \vec{r} = (p\hat{i} - \hat{j} - \hat{k}) + \mu(2\hat{i} + \hat{j} + 2\hat{k}) \) is \( \frac{3}{\sqrt{2}} \) units.

5.
The volume of a wooden block in the shape of a cube increases at a constant rate as the air becomes moist during the rainy season. Show that the rate of change of its surface area varies inversely as the length of edge of the cube.

6.
Sketch the graph defined by \( \left\{ (x, y) : \frac{x^2{25} + \frac{y^2}{25} = 1 \right\} \). Find the area of the region of minor segment cut off by the line \( x = \frac{5}{2} \), using integration.}