The National Testing Agency (NTA) conducted the CUET PG 2026 Mathematics (SCQP19) examination on March 18, 2026, during Shift 2 from 12:30 PM to 02:00 PM.

Students who appeared for the exam reported that the overall difficulty level of the paper was moderate to difficult. CUET PG 2026 Mathematics Question Paper with Solutions PDF is available here for download. The marking scheme is +4 for correct answers and -1 for wrong answers, totaling 300 marks.

CUET PG 2026 Mathematics Question Paper with Solutions PDF

CUET PG 2026 Mathematics Question Paper with Answer Key Download PDF Check Solutions

Question 1:

What is the dimension of the vector space of all \( n \times n \) real symmetric matrices?

  • (A) \( n^2 \)
  • (B) \( \frac{n(n+1)}{2} \)
  • (C) \( \frac{n(n-1)}{2} \)
  • (D) \( 2n \)
Correct Answer: (B) \( \frac{n(n+1)}{2} \)
View Solution



Concept:
A real symmetric matrix satisfies: \[ A^T = A \]
This means the entries are symmetric about the main diagonal.

Step 1: Count diagonal elements

There are \( n \) diagonal elements: \[ a_{11}, a_{22}, \dots, a_{nn} \]

Step 2: Count off-diagonal elements

For \( i \neq j \), we have: \[ a_{ij} = a_{ji} \]
So each pair contributes only one independent element.

Number of such pairs: \[ \frac{n(n-1)}{2} \]

Step 3: Total independent elements
\[ n + \frac{n(n-1)}{2} = \frac{n(n+1)}{2} \]

Hence, the dimension is: \[ \frac{n(n+1)}{2} \] Quick Tip: Symmetric matrix dimension = diagonal + upper triangle
= \( n + \frac{n(n-1)}{2} = \frac{n(n+1)}{2} \)


Question 2:

If a function \( f(x) \) is continuous on a closed interval \( [a,b] \), is it necessarily uniformly continuous?

  • (A) Yes, always uniformly continuous
  • (B) No, never uniformly continuous
  • (C) Only if differentiable
  • (D) Only if bounded
Correct Answer: (A) Yes, always uniformly continuous
View Solution




Concept: Heine–Cantor Theorem

A very important result in real analysis states:

If a function is continuous on a closed and bounded interval \( [a,b] \),
Then it is uniformly continuous on that interval.


Step 1: Understand continuity vs uniform continuity


Continuity: For every point \(x\), we can find a \(\delta\) depending on \(x\).
Uniform continuity: A single \(\delta\) works for all \(x \in [a,b]\).


Step 2: Apply the theorem

Since the function is continuous on a closed interval \( [a,b] \), it satisfies: \[ Uniform continuity on [a,b] \]

Step 3: Why closed interval matters

Closed intervals are:

Bounded
Contain all limit points

This ensures no “escape” of function behavior at endpoints.


Conclusion: \[ The function is always uniformly continuous. \] Quick Tip: Continuous on closed interval \( \Rightarrow \) Uniformly continuous (Always true!)


Question 3:

What is the value of the limit \( \lim_{n \to \infty} \left(1 + \frac{1}{n}\right)^n \)?

  • (A) \(1\)
  • (B) \(0\)
  • (C) \(e\)
  • (D) \(\infty\)
Correct Answer: (C) \(e\)
View Solution




Concept: Definition of \(e\)

The number \(e\) is defined as: \[ e = \lim_{n \to \infty} \left(1 + \frac{1}{n}\right)^n \]

Step 1: Recognize the standard limit

The given expression is a direct standard limit used to define \(e\).

Step 2: Intuition behind the limit

This expression arises in:

Compound interest problems
Continuous growth models


As \(n\) increases, the quantity: \[ \left(1 + \frac{1}{n}\right)^n \]
approaches a fixed number.

Step 3: Numerical idea
\[ n=1 \Rightarrow 2,\quad n=2 \Rightarrow 2.25,\quad n=10 \Rightarrow 2.593,\quad n \to \infty \Rightarrow 2.718... \]

Step 4: Final value
\[ \lim_{n \to \infty} \left(1 + \frac{1}{n}\right)^n = e \approx 2.718 \]


Conclusion: \[ Limit value is e \] Quick Tip: Always remember: \[ \left(1 + \frac{1}{n}\right)^n \rightarrow e \] A standard and very important limit in calculus.


Question 4:

How many elements of order 5 are there in a cyclic group of order 25?

  • (A) \(1\)
  • (B) \(4\)
  • (C) \(5\)
  • (D) \(10\)
Correct Answer: (B) \(4\)
View Solution




Concept: Order of elements in a cyclic group

In a cyclic group of order \( n \), the number of elements of order \( d \) (where \( d \mid n \)) is given by Euler’s totient function: \[ \phi(d) \]

Step 1: Identify the group order
\[ n = 25 = 5^2 \]

Step 2: Find valid divisors

Possible orders divide 25: \[ 1, 5, 25 \]

We need elements of order \(5\).

Step 3: Apply Euler's totient function
\[ \phi(5) = 5 - 1 = 4 \]

Step 4: Interpretation

There are exactly 4 generators of the subgroup of order 5.

Conclusion: \[ Number of elements of order 5 = 4 \] Quick Tip: In cyclic groups: Number of elements of order \(d\) = \( \phi(d) \)


Question 5:

If \( A \) is a \(3 \times 3\) matrix with eigenvalues \(1, 2, 3\), what is the determinant of \(A^2\)?

  • (A) \(6\)
  • (B) \(12\)
  • (C) \(18\)
  • (D) \(36\)
Correct Answer: (D) \(36\)
View Solution




Concept 1: Determinant and eigenvalues

The determinant of a matrix is equal to the product of its eigenvalues: \[ \det(A) = \lambda_1 \cdot \lambda_2 \cdot \lambda_3 \]

Step 1: Compute determinant of \(A\)

Given eigenvalues: \[ 1, 2, 3 \] \[ \det(A) = 1 \times 2 \times 3 = 6 \]

Concept 2: Determinant of powers

For any square matrix: \[ \det(A^k) = (\det A)^k \]

Step 2: Apply the formula for \(A^2\)
\[ \det(A^2) = (\det A)^2 = 6^2 = 36 \]

Step 3: Alternative understanding

Eigenvalues of \(A^2\) are: \[ 1^2, 2^2, 3^2 = 1, 4, 9 \] \[ \det(A^2) = 1 \times 4 \times 9 = 36 \]

Conclusion: \[ \det(A^2) = 36 \] Quick Tip: Two useful results: Product of eigenvalues = determinant \( \det(A^k) = (\det A)^k \)


Question 6:

Which theorem states that every bounded sequence in \( \mathbb{R}^n \) has a convergent subsequence?

  • (A) Mean Value Theorem
  • (B) Bolzano–Weierstrass Theorem
  • (C) Rolle’s Theorem
  • (D) Taylor’s Theorem
Correct Answer: (B) Bolzano–Weierstrass Theorem
View Solution




Concept: Bolzano–Weierstrass Theorem

This is a fundamental theorem in real analysis which states:

Every bounded sequence in \( \mathbb{R}^n \) has at least one convergent subsequence.


Step 1: Understand bounded sequence

A sequence \( \{x_n\} \) is bounded if: \[ \exists M > 0 such that \|x_n\| \leq M for all n \]

Step 2: Apply the theorem

If the sequence is bounded, then it cannot “escape to infinity,” so there exists a subsequence that converges.

Step 3: Conclusion
\[ Bolzano–Weierstrass Theorem guarantees convergence of a subsequence \] Quick Tip: Bounded sequence \( \Rightarrow \) Convergent subsequence (always!)


Question 7:

What is the radius of convergence of the power series \( \sum_{n=0}^{\infty} \frac{x^n}{n!} \)?

  • (A) \(0\)
  • (B) \(1\)
  • (C) \(\infty\)
  • (D) \(e\)
Correct Answer: (C) \(\infty\)
View Solution




Concept: Radius of convergence using Ratio Test

For a power series: \[ \sum a_n x^n \]
the radius of convergence \(R\) is found using: \[ \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| \]

Step 1: Identify coefficients
\[ a_n = \frac{1}{n!} \]

Step 2: Apply Ratio Test
\[ \left| \frac{a_{n+1}}{a_n} \right} = \frac{1}{(n+1)!} \cdot n! = \frac{1}{n+1} \]

Step 3: Take the limit
\[ \lim_{n \to \infty} \frac{1}{n+1} = 0 \]

Step 4: Interpretation

Since the limit is 0 for all \(x\), the series converges for all real \(x\).

Conclusion: \[ R = \infty \] Quick Tip: \(\sum \frac{x^n}{n!} = e^x\)
Exponential series converges for all real numbers \(x\)


Question 8:

Is the set of all rational numbers \( \mathbb{Q} \) a countable or uncountable set?

  • (A) Finite set
  • (B) Countable set
  • (C) Uncountable set
  • (D) Empty set
Correct Answer: (B) Countable set
View Solution




Concept: Countability of sets

A set is called:

Countable if its elements can be put in one-to-one correspondence with \( \mathbb{N} \)
Uncountable if this is not possible


Step 1: Form of rational numbers

Every rational number can be written as: \[ \frac{p}{q}, \quad p \in \mathbb{Z},\; q \in \mathbb{N} \]

Step 2: Arrangement idea

We can arrange all such fractions in a grid and traverse them diagonally (Cantor’s method), ensuring every rational number is listed.

Step 3: Conclusion

Since all rational numbers can be listed in a sequence: \[ \mathbb{Q} is countable \] Quick Tip: Even though rationals are infinite, they are still countable!


Question 9:

If \( T: V \to W \) is a linear transformation, what is the relationship between rank(\(T\)), nullity(\(T\)), and dim(\(V\))?

  • (A) rank(\(T\)) + nullity(\(T\)) = dim(\(W\))
  • (B) rank(\(T\)) \(\times\) nullity(\(T\)) = dim(\(V\))
  • (C) rank(\(T\)) + nullity(\(T\)) = dim(\(V\))
  • (D) rank(\(T\)) = nullity(\(T\))
Correct Answer: (C) rank(\(T\)) + nullity(\(T\)) = dim(\(V\))
View Solution




Concept: Rank–Nullity Theorem

This is a fundamental theorem in linear algebra which states: \[ rank(T) + nullity(T) = \dim(V) \]

Step 1: Understand terms


Rank: Dimension of the image (range) of \(T\)
Nullity: Dimension of the kernel (null space) of \(T\)
dim(\(V\)): Dimension of domain space


Step 2: Interpretation

The theorem splits the domain space into:

Part mapped to zero (kernel)
Part mapped to image


Step 3: Conclusion
\[ rank(T) + nullity(T) = \dim(V) \] Quick Tip: Always remember: \[ Rank + Nullity = Dimension of domain \]


Question 10:

What is the condition for a group \( G \) to be Abelian based on the commutator subgroup?

  • (A) Commutator subgroup is equal to \(G\)
  • (B) Commutator subgroup is trivial
  • (C) Commutator subgroup is infinite
  • (D) Commutator subgroup is cyclic
Correct Answer: (B) Commutator subgroup is trivial
View Solution




Concept: Commutator Subgroup

The commutator of two elements \(a, b \in G\) is: \[ [a,b] = aba^{-1}b^{-1} \]

The commutator subgroup \(G'\) (or \([G,G]\)) is generated by all such commutators.

Step 1: Abelian group definition

A group is Abelian if: \[ ab = ba \quad \forall a,b \in G \]

Step 2: Effect on commutators

If \(ab = ba\), then: \[ [a,b] = e \]
(identity element)

Step 3: Conclusion

All commutators are identity \( \Rightarrow \) commutator subgroup is trivial: \[ G' = \{e\} \] Quick Tip: Group is Abelian \( \Leftrightarrow \) Commutator subgroup is trivial


Question 11:

What is the value of the integral \( \int_{-\infty}^{\infty} e^{-x^2} \, dx \)?

  • (A) \(0\)
  • (B) \(1\)
  • (C) \(\sqrt{\pi}\)
  • (D) \(\pi\)
Correct Answer: (C) \(\sqrt{\pi}\)
View Solution




Concept: Gaussian Integral

The integral: \[ \int_{-\infty}^{\infty} e^{-x^2} dx \]
is a standard result known as the Gaussian integral.

Step 1: Define the integral

Let: \[ I = \int_{-\infty}^{\infty} e^{-x^2} dx \]

Step 2: Square the integral
\[ I^2 = \left(\int_{-\infty}^{\infty} e^{-x^2} dx \right)\left(\int_{-\infty}^{\infty} e^{-y^2} dy \right) \]
\[ = \int_{-\infty}^{\infty} \int_{-\infty}^{\infty} e^{-(x^2+y^2)} dx\,dy \]

Step 3: Convert to polar coordinates
\[ x^2 + y^2 = r^2, \quad dx\,dy = r\,dr\,d\theta \]
\[ I^2 = \int_{0}^{2\pi} \int_{0}^{\infty} e^{-r^2} r\,dr\,d\theta \]

Step 4: Evaluate the integral
\[ \int_{0}^{\infty} e^{-r^2} r\,dr = \frac{1}{2} \]
\[ I^2 = 2\pi \cdot \frac{1}{2} = \pi \]

Step 5: Final result
\[ I = \sqrt{\pi} \] Quick Tip: \[ \int_{-\infty}^{\infty} e^{-x^2} dx = \sqrt{\pi} \] A very important standard result in probability and analysis.


Question 12:

In a metric space, is every Cauchy sequence necessarily a convergent sequence?

  • (A) Yes, always
  • (B) No, not always
  • (C) Only in finite spaces
  • (D) Only for bounded sequences
Correct Answer: (B) No, not always
View Solution




Concept: Cauchy sequence and completeness


A sequence is Cauchy if its terms get arbitrarily close to each other.
A sequence converges if it approaches a limit in the space.


Step 1: Key idea

In general metric spaces: \[ Cauchy sequence \not\Rightarrow convergent \]

Step 2: Special case

If the space is complete, then: \[ Every Cauchy sequence converges \]

Step 3: Example

In \( \mathbb{Q} \), a Cauchy sequence may converge to an irrational number, which is not in \( \mathbb{Q} \), so it does not converge in that space.

Conclusion: \[ Not every Cauchy sequence is convergent (unless space is complete) \] Quick Tip: Cauchy \( \Rightarrow \) Convergent only in complete spaces


Question 13:

What are the possible values for the rank of a \(4 \times 3\) matrix?

  • (A) \(0,1,2,3,4\)
  • (B) \(1,2,3,4\)
  • (C) \(0,1,2,3\)
  • (D) Only \(3\)
Correct Answer: (C) \(0,1,2,3\)
View Solution




Concept: Rank of a matrix

The rank of a matrix is the maximum number of linearly independent rows or columns.

Step 1: General rule

For an \(m \times n\) matrix: \[ rank \leq \min(m,n) \]

Step 2: Apply to given matrix

Matrix size: \[ 4 \times 3 \] \[ \min(4,3) = 3 \]

Step 3: Possible values

Rank can be any integer from \(0\) up to \(3\): \[ 0,1,2,3 \]

Step 4: Interpretation


Rank \(0\): zero matrix
Rank \(3\): full column rank


Conclusion: \[ Possible ranks = 0,1,2,3 \] Quick Tip: Rank of \(m \times n\) matrix \( \leq \min(m,n)\)


Question 14:

What is the order of the group of permutations \( S_3 \)?

  • (A) \(3\)
  • (B) \(6\)
  • (C) \(9\)
  • (D) \(12\)
Correct Answer: (B) \(6\)
View Solution




Concept: Symmetric Group

The symmetric group \( S_n \) consists of all permutations of \( n \) elements.

Step 1: Formula for order
\[ |S_n| = n! \]

Step 2: Apply for \(S_3\)
\[ |S_3| = 3! = 3 \times 2 \times 1 = 6 \]

Step 3: Interpretation

There are 6 possible ways to arrange 3 distinct elements.

Conclusion: \[ |S_3| = 6 \] Quick Tip: Order of symmetric group \(S_n = n!\)


Question 15:

Which partial differential equation represents the Laplace equation in two dimensions?

  • (A) \( \frac{\partial u}{\partial x} + \frac{\partial u}{\partial y} = 0 \)
  • (B) \( \frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = 0 \)
  • (C) \( \frac{\partial^2 u}{\partial t^2} = c^2 \frac{\partial^2 u}{\partial x^2} \)
  • (D) \( \frac{\partial u}{\partial t} = k \frac{\partial^2 u}{\partial x^2} \)
Correct Answer: (B) \( \frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = 0 \)
View Solution




Concept: Laplace Equation

The Laplace equation is a second-order partial differential equation widely used in physics and engineering.

Step 1: Standard form in two dimensions
\[ \frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = 0 \]

Step 2: Interpretation

It describes:

Steady-state heat distribution
Electrostatic potential
Fluid flow


Step 3: Identify correct option

Option (B) matches the standard Laplace equation.

Conclusion: \[ Laplace equation in 2D is \frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = 0 \] Quick Tip: Laplace equation = sum of second partial derivatives equals zero

 

CUET PG 2026 Mathematics Preparation