NCERT Solutions for class 10 Science chapter 5: Periodic Classification of Elements

NCERT Solutions for Class 10 Science Chapter 5 Periodic Classification of Elements is provided in this article. Some of the important topics of Periodic classification of elements include:

  1. Periodic Classification of Elements
  2. Newland’s Law of Octaves: Advantages
  3. Periodic Classification of Elements Important Questions
  4. Periodic Classification of Elements Revision Notes

Expected no of questions: 2 to 3 questions for a total of 5 marks

Download: NCERT Solutions for Class 10 Science Chapter 5 pdf


NCERT Solutions for Class 10 Science Chapter 5

NCERT Solutions for Class 10 Science Chapter 5 Periodic Classification of Elements is given below.

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Class 10 Science Chapter 5 Periodic Classification of Elements – Important Topics

Periodic classification of elements have been done inorder to classify the elements according to their properties. Some of the periodic classification theories and tables include:

  • Newland’s law of octaves
  • Dobereiner Triad
  • Mendeleev’s periodic table

Newland’s law of Octaves: According to Newland’s law, when the elements are managed according to aggregate atomic masses, the physical and chemical properties of every 8th element are the same as that of the first. 

Dobereiner Triad: Dobereiner identified a group of 3 elements with similar chemical and physical properties in the order of aggregate atomic masses and called it a triad. 

Mendeleev’s Law: Madeleev’ law stated that the chemical properties and physical properties of elements are periodic purposes of their atomic masses. 

The Modern Periodic Law states that- “ Properties of elements are a periodic function of their atomic number.” In the Modern Periodic Table, the elements are characterised in the form of Periods and Groups.

Some of the trends in periodic table include:

  • Metallic character
  • Non metallic character
  • Metalloids
  • Variation of atomic size
  • Electronegativity

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CBSE X Related Questions

  • 1.

    (i) Study the diagram and name the parts marked as A, B, C, and D. 
    (ii) Write the function of A and C.

     


      • 2.
        A tall pea plant with round seeds (TTRR) is crossed with a short pea plant with wrinkled seeds (ttrr). The \( F_1 \) generation will be:

          • 25% tall with round seeds
          • 50% tall with wrinkled seeds
          • 75% tall with wrinkled seeds
          • 100% tall with round seeds

        • 3.
          Juice of tamarind turns blue litmus to red. It is because of the presence of a chemical compound called:

            • Acetic acid
            • Methanoic acid
            • Oxalic acid
            • Tartaric acid

          • 4.
            In human alimentary canal, the digestive juice secreted by the gastric glands are:

              • Bile, Trypsin, Pepsin
              • Hydrochloric acid, Pepsin, Mucus
              • Lipase, Bile, Mucus
              • Salivary amylase, Pepsin, Bile

            • 5.
              Which one of the following is not an excretory product in plants?

                • \(CO_2\)
                • Starch
                • Resins and gums
                • Dead cells

              • 6.
                In a bisexual flower the male gametes are present in the :

                  • anther
                  • ovary
                  • stigma
                  • filament

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