NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.6 (Optional)

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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.6 are provided in this article. Class 10 Maths Chapter 6 Triangles is included under the Unit Geometry of class 10 maths syllabus. This chapter contains a total of 6 exercises. Exercise 6.6 is an optional exercise which includes questions based on different concepts covered in the chapter.

Download PDF: NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.6 (Optional)

Check below the NCERT solutions pdf for Class 10 Maths Chapter 6 Exercise 6.6 (Optional)

Find below NCERT solutions of other exercises of class 10 maths chapter 6 Triangles:

Class 10 Chapter 6 Triangles Related Links:

Triangle Theorems	Types of Triangles	Triangles Important Questions
Triangles Revision Notes	MCQ on Triangles	Circles
Tangent to a Circle	Important Questions on Circles	Circles Revision Notes

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Math Study Material	Important Formulas in Maths	Difference Between in Maths
Class 10 Maths Notes	NCERT Solutions for Class 10 Maths	Mathematics Important Questions

CBSE X Related Questions

1.
Assertion (A) : H.C.F. $(36 m^{2}, 18 m) = 18 m$, where $m$ is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.
- Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
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2.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.
View Solution
3.
Prove that :
$\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$.
View Solution
4.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.
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5.
Two water taps together can fill a tank in $8\frac{8}{9}$ hours. The tap of larger diameter takes 4 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.
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6.
A kite is flying at a height of $60 \text{ m}$ above the ground level. Ravi, standing at the roof of the house is holding the string straight and observes the angle of elevation of kite as $30^{\circ}$. From the bottom of the same building, the angle of elevation of kite is $45^{\circ}$. Find the length of the string and height of roof from the ground. (Use $\sqrt{3} = 1.73$)
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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.6 (Optional)

CBSE X Related Questions

1.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

2.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

3.
Prove that :
\(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).

4.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.

5.
Two water taps together can fill a tank in $8\frac{8}{9}$ hours. The tap of larger diameter takes 4 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.

Similar Mathematics Concepts

Comments

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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.6 (Optional)

CBSE X Related Questions

1.Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number. Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

2.Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

3.Prove that : \(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).

4.A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.

5.Two water taps together can fill a tank in $8\frac{8}{9}$ hours. The tap of larger diameter takes 4 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

2.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

3.
Prove that :
\(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).

4.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.

5.
Two water taps together can fill a tank in $8\frac{8}{9}$ hours. The tap of larger diameter takes 4 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.