NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.6 (Optional)

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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.6 are provided in this article. Class 10 Maths Chapter 6 Triangles is included under the Unit Geometry of class 10 maths syllabus. This chapter contains a total of 6 exercises. Exercise 6.6 is an optional exercise which includes questions based on different concepts covered in the chapter.

Download PDF: NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.6 (Optional)

Check below the NCERT solutions pdf for Class 10 Maths Chapter 6 Exercise 6.6 (Optional)

Find below NCERT solutions of other exercises of class 10 maths chapter 6 Triangles:

Class 10 Chapter 6 Triangles Related Links:

Triangle Theorems	Types of Triangles	Triangles Important Questions
Triangles Revision Notes	MCQ on Triangles	Circles
Tangent to a Circle	Important Questions on Circles	Circles Revision Notes

Class 10 Maths Study Guides:

Math Study Material	Important Formulas in Maths	Difference Between in Maths
Class 10 Maths Notes	NCERT Solutions for Class 10 Maths	Mathematics Important Questions

CBSE X Related Questions

1.
In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.
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2.
Find the sum of first 20 terms of an A.P. whose n$^{th}$ term is given by $a_n = 5 + 2n$. Can 52 be a term of this A.P. ?
View Solution
3.
The perimeters of two similar triangles are 22 cm and 33 cm respectively. If one side of the first triangle is 9 cm, then find the length of the corresponding side of the second triangle.
View Solution
4.
Solve the following pair of linear equations by graphical method : $2x + y = 9$ and $x - 2y = 2$.
View Solution
5.
In $\triangle ABC, DE || BC$. If AE = (2x + 1) cm, EC = 4 cm, AD = (x + 1) cm and DB = 3 cm, then value of x is
- 1
- $\frac{1}{2}$
- --1
- $\frac{1}{3}$
View Solution
6.
In a trapezium $ABCD$, $AB \parallel DC$ and its diagonals intersect at $O$. Prove that \[ \frac{OA}{OC} = \frac{OB}{OD} \]
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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.6 (Optional)

CBSE X Related Questions

1.
In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.

2.
Find the sum of first 20 terms of an A.P. whose n\(^{th}\) term is given by \(a_n = 5 + 2n\). Can 52 be a term of this A.P. ?

3.
The perimeters of two similar triangles are 22 cm and 33 cm respectively. If one side of the first triangle is 9 cm, then find the length of the corresponding side of the second triangle.

4.
Solve the following pair of linear equations by graphical method : \(2x + y = 9\) and \(x - 2y = 2\).

5.
In \(\triangle ABC, DE || BC\). If AE = (2x + 1) cm, EC = 4 cm, AD = (x + 1) cm and DB = 3 cm, then value of x is

6.
In a trapezium \(ABCD\), \(AB \parallel DC\) and its diagonals intersect at \(O\). Prove that \[ \frac{OA}{OC} = \frac{OB}{OD} \]

Similar Mathematics Concepts

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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.6 (Optional)

CBSE X Related Questions

1.In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.

2.Find the sum of first 20 terms of an A.P. whose n\(^{th}\) term is given by \(a_n = 5 + 2n\). Can 52 be a term of this A.P. ?

3.The perimeters of two similar triangles are 22 cm and 33 cm respectively. If one side of the first triangle is 9 cm, then find the length of the corresponding side of the second triangle.

4.Solve the following pair of linear equations by graphical method : \(2x + y = 9\) and \(x - 2y = 2\).

5.In \(\triangle ABC, DE || BC\). If AE = (2x + 1) cm, EC = 4 cm, AD = (x + 1) cm and DB = 3 cm, then value of x is

6.In a trapezium \(ABCD\), \(AB \parallel DC\) and its diagonals intersect at \(O\). Prove that \[ \frac{OA}{OC} = \frac{OB}{OD} \]

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.

2.
Find the sum of first 20 terms of an A.P. whose n\(^{th}\) term is given by \(a_n = 5 + 2n\). Can 52 be a term of this A.P. ?

3.
The perimeters of two similar triangles are 22 cm and 33 cm respectively. If one side of the first triangle is 9 cm, then find the length of the corresponding side of the second triangle.

4.
Solve the following pair of linear equations by graphical method : \(2x + y = 9\) and \(x - 2y = 2\).

5.
In \(\triangle ABC, DE || BC\). If AE = (2x + 1) cm, EC = 4 cm, AD = (x + 1) cm and DB = 3 cm, then value of x is

6.
In a trapezium \(ABCD\), \(AB \parallel DC\) and its diagonals intersect at \(O\). Prove that \[ \frac{OA}{OC} = \frac{OB}{OD} \]