Algebra Formula: Important Formulas in Algebra & Solved Examples

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Anjali Mishra

Content Writer-SME

Algebra formulas are alphabetical notations in any equation of mathematics and science. It involves symbols called variables that represent quantities with no definite value. The most common letters used to express algebraic problems and equations are X, Y, A, and B. Just as an engineer's life mainly revolves around wires, gadgets, current and electricity, similarly, algebra formulas are important tool for a mathematician.

Real numbers, complex numbers, matrices, vectors, and other concepts are all part of algebra.​ Algebra formulas have a wide range of applications, which is why it is considered one of the important units of mathematics. In this article, we will cover all the important algebraic formulas which are used in all classes starting from class 8.

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What are Algebra Formulas?

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Inclusion of new topics in Mathematics is usually seen after class 8, depending on the type of board (CBSE or state or ICSE) and the books run by different schools. Before this, students may be aware of different types of numbers like real numbers, prime numbers etc. but after class 8, they are usually familiar with an important chapter “Algebra” which forms the basis of complex chapters like Trigonometry.

Algebra is a branch of mathematics that deals with both numbers and letters. The value of numbers is fixed and the letters or alphabets represent the unknown quantities in the algebra or algebraic formulaA combination of numbers, letters, factorials, matrices, etc. is used to form an algebraic equation or algebraic formula. 

Important Algebraic Expressions: 

Algebra formulas are mathematical equations that show how variables and constants relate to one another. Here is the list of all the important algebraic formulas

  1. (a+b)2 = a2 + 2ab + b2
  2. (a-b)2 = a2 – 2ab + b2
  3. (a+b)(a-b) = a2 – b2
  4. (x +a)(x+b) = x2 +(a+b)x +ab
  5. (x+a)(x-b) = x2 + (a-b)x – ab
  6. (x-a)(x+b) = x2 + (b-a)x – ab
  7. (x-a)(x-b) = x2 – (a+b)x +ab
  8. (a+b)3 = a3 + b3 + 3ab(a+b)
  9. (a-b)3 = a3 – b3 – 3ab (a-b)
  10. (x+y+z)2 = x2 + y2 +z2 + 2xy + 2yx + 2xz
  11. (x+y-z)2 = x2 + y2 +z2 + 2xy – 2yz – 2xz
  12. (x – y +z)2 = x2 + y2 +z2  - 2xy – 2yz +2xz 
  13. (x-y-z)2 = x2 + y2 +z2  - 2xy +2yz -2xz
  14. X3 + y3 +z3 – 3xyz = (x+y+z) (x2+ y2 +z2)
  15. (x+a)(a+b)(a+c) = x3 + (a+b+c) x2 + (ab +bc+ ca)x + abc
  16. X3 + y3 = (x+y) (x2 – xy + y2)
  17. X3 – y3 = (x- y) (x2 + xy + y2)
  18. X2 + y2 + z2 –xy – yz – zx = 12[(x-y)2 + (y-z)2 + (z-x)2
  19. X2 + y2 = ½[(x +y)2 + (x – y)2 ]
  20. a1/x = xa
  21. (a/b)x = a2/b2
  22. (ab)x = axbx
  23. (am)n = amn
  24. am/an = am-n
  25. Laws of Exponents am x an = am+n
  26. a8- b8 = (a4 + b4) (a2 +b2) (a+b)(a-b)
  27. a4 + a2 + 1 = (a2 + a +1)(a2-a + 1)
  28. a4 + a2b2 + b4 = (a2 + ab + b2 )(a2 –ab + b2)
Algebra Formula
Important Algebraic Formulas
Large complex mathematical calculations can be solved easily with the help of the above mentioned algebra formulas. The formulas can be applied in mensuration, calculus, equations of profit and loss etc. Moreover, these algebraic formulas also help in enhancing logic and reasoning skills.

Linear Equation in Two Variables

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Algebra formulas are classified into two parts: basic and advanced algebra. Basic algebraic formulas are generally used by students up to class 10. Next, advanced algebraic equations are used to solve complex problems and write equations. Application of advanced level algebraic formulas is also seen in the engineering field.

An equation is said to be a linear equation in two variables if it is written in the form of ax + by + c = 0, where a, b & c are real numbers and the coefficients of x and y, i.e a and b respectively, are not equal to zero.

For example: 

  • a1x + b1y + c1 = 0
  • a2x + b2y + c2 = 0

Read More: Arithmetic Progressions Revision Notes


Algebraic Formulas for Quadratic Equations

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These formulas serve as the basis of algebra and are often used in geometry, physics, equation solving, and other mathematics-related subjects. For any quadratic equation, algebraic formula is given as: 

Let an algebraic equation, ax2 + bx + c = 0,

So, the formula for this quadratic equation will be: 

\((α,ß) =\) \(\frac {[(-b) ± √(b^2 – 4ac)]}{2a}\)
  • The quadratic equation will have two distinct real roots if b2- 4ac >0
  • The quadratic equation will have two imaginary roots if b2 – 4ac < 0
  • The quadratic equation has two real equivalent real roots if b2 – 4ac = 0

Arithmetic Progression Formulas

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Arithmetic Progression formulas are given below

  • The nth term of an arithmetic sequence (an) = a + (n-1)d
  • The sum of n terms in an arithmetic sequence (sn) = n/2 [2a + (n-1)d]
  • The nth term of a geometric sequence (an) = a.rn-1
  • The sum of n terms of a geometric sequence (sn) = a(1-rn)/(1-r)
  • The sum of infinite terms of a geometric sequence (s) = a/(1-r)

Things to Remember

  • A single equation without the equal sign is known as an algebraic expression whereas a set of equations with the equal sign is known as the algebraic equation.
  • An equation that has a mixture of variables and is only true for some value of x is known as an algebraic equation.
  • Large complex mathematical problems can be easily solved by algebra formulas.
  • A polynomial of 1 degree is known as linear, 2 degrees is known as quadratic, and degree 3 is known as a cubic polynomial.
  • A quadratic equation has 2-3 zeros which form the x coordinators of the points where the graph of y=p(x) intersects the x-axis.

Sample Questions

Ques. What is algebra? (1 Mark)

Ans. Algebra is the study of variables and the rules that govern their use in formulae.

Ques. William had a few chocolates with him. Jack came across and took away five of his chocolates. And then he had just seven chocolates remaining with him. How many chocolates did he have before Jack came to him? (2 Marks)

Ans. Let William have x chocolates with him, and Jack take away five of his chocolates, then

x − 5 = 7

Hence, we subtract five from x. Moreover, after all this, William was left with seven chocolates. This entire puzzle will then equal seven. 

x − 5 + 5 = 7 + 5

x = 12

Ques. 43 x 42 = ? (2 Marks)

Ans. Using the exponential formula (am)(an) = am+n
where a = 4
⇒ 43 x 42  
= 43+2
= 45
= 1024

Ques. Calculate: 172 – 42 (2 Marks)

Ans. We know that: 

a2 – b2 = (a+b)(a-b)

So, 

172 – 42 = (17+4)(17-4) 

= 13 x 21

=273

Ques. Simplify the expression: 12m2 -9m +5m -4m2 -7m +10 (2 Marks)

Ans. Given that: 

12m2 – 4m2 +5m -9m -7m +10

= (12-4)m2 + (5-9-7)m+10

=8m2 + (-4-7)m + 10

= 8m2 + 11m + 10

Ques. If the quadratic equation is mx(x-7) + 49 = 0. Find the value of m when the equation has two equal roots. (3 Marks)

Ans. mx (x-7)+49 = 0

mx2 – 7mx + 49 = 0

a= m, b= -7m, c = 49

D = b2 -4ac = 0

= (-7m)2 – 4 (m) (49) = 0

= 49m2 – 4m (49) = 0

= 49m (m-4) = 0

= 49m = 0 or m – 4 = 0

m = 0 (rejected) or m = 4

m= 4

Ques. If the quadratic equation is x2 – 3x – m (m +3 ) = 0 and the value of m is constant. Find the root of the equation. (3 Marks)

Ans. x2 – 3x – m(m+3) = 0

a = 1, b= -3, c = -m(m+3) 

D = (b2 – 4ac)

So,

D= (-3)2 -4 (1) = 9 +4m(m+3)

= 4m2 +12m +9

= (2m+3)2

(α,ß) = [-3±√(2m+3)2]/2x1x-m(m+3)

= (α,ß) = (m+3,-m)

Ques. The equation ay2+ay+3 = 0 and y2+y+b= 0 has the root 1. Calculate the value of ab. (3 Marks)

Ans. Given that: 

ay2+ay+3 = 0 … (i)

y2+y+b= 0 … (ii)

By putting the value of y = 1,

a(1)2 + a(1) +3 = 0

2a = -3

a = -3/2

by putting the value of y =1 in the equation y2 +y+b =0,

12 + 1+b = 0

b = -2

therefore, ab =(-3/2)(-2) = 3

Ques. Find the value of p if the quadratic equation px2 -(25 - √p)x + 15 = 0 which has two equal roots. (3 Marks)

Ans. px2 -25 - √px + 15 = 0

a = p , b = -25- √p , c = 15

D = 0 (for equal roots)

D = b2 – 4ac -0

0 = 4 x 5p2 – 60p

0 = 20p2 – 60p = 20p2 = 60p

p = 60p 20p = 3

Therefore, p = 3

Ques. Solve the equation: 5x +3y = 9 and 2x - 3y = 12. (3 Marks)

Ans. Given that: 

5x +3y = 9 … (i)

2x - 3y = 12 … (ii)

By adding equation (i) and (ii), we get

7x = 21

x = 3

By substituting the value of x in equation (i), we get

5 (3) + 3y = 9

15 + 3y = 9

3y = 9-15 = -6

Y = -2

Thus, (x,y) = (3,-2)

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CBSE X Related Questions

  • 1.
    In the given figure, \(\Delta ABC\) is a right-angled triangle with \(\angle A = 90^\circ\). AD is perpendicular to BC.

    35(a)(i) Prove that \(\Delta DBA \sim \Delta DAC\)


      • 2.
        In the given figure, PQ is a tangent to a circle with centre \(O(-5, 3)\). If coordinates of P and Q are \((3, 1)\) and \((0, 6)\) respectively, then using distance formula, show that \(PQ \perp OQ\).


          • 3.
            In a circular museum hall of radius 14 m, some statues are displayed. Statues are kept inside the inner concentric circle of radius 7 m. One such statue lying in sector OAB, is fenced along line segments OA, AP, PB and BO where P is a point on outer circle. Based on above information, answer the following questions:

            37(i) Find \(m\angle AOP\).


              • 4.
                In the given figure, two triangles ABC and PQR are shown such that \(\angle A = \angle P\) and \(\angle C = \angle R\). If \(AD \perp BC\) and \(PS \perp QR\), then prove that (i) \(\Delta ADB \sim \Delta PSQ\) (ii) \(AD \times QS = BD \times PS\).


                  • 5.
                    Seema daily goes to a park to exercise on machines available there. When Seema spent 15 minutes on exercise bicycle and 30 minutes on double cross walker, she received a message of burning 435 calories on her fitness watch. When she spent 30 minutes on exercise bicycle and 40 minutes on double cross walker, she received a message of burning 690 calories. Based on above information, answer the following questions:

                    38(i) Represent the above situation in terms of a pair of linear equations in two variables.


                      • 6.
                        \(17 \times 11 \times 13 + 11\) is

                          • a prime number.
                          • multiple of 17.
                          • a composite number.
                          • an odd number.

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