NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.4

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Jasmine Grover

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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.4 are provided in this article. Class 10 Maths Chapter 6 Triangles is an important chapter included under the Unit Geometry of class 10 maths syllabus. This chapter covers important concepts related to triangles. Exercise 6.4 mainly includes questions based on areas of similar triangles.

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Check below the NCERT solutions pdf for Class 10 Maths Chapter 6 Exercise 6.4

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Find below NCERT solutions of other exercises of class 10 maths chapter 6 Triangles:


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CBSE X Related Questions

  • 1.
    If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then

      • \( \frac{a_1}{a_2} \neq \frac{b_1}{b_2} \)
      • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
      • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} \)
      • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)

    • 2.
      PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.


        • 3.
          If the quadratic equation \(9x^2 + 8kx + 16 = 0\) has real and equal roots, then the value of k is

            • 3
            • –3
            • –4
            • \(\pm 3\)

          • 4.
            Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
            Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

              • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
              • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
              • Assertion (A) is true, but Reason (R) is false.
              • Assertion (A) is false, but Reason (R) is true.

            • 5.
              The HCF of 960 and 432 is :

                • 48
                • 54
                • 72
                • 36

              • 6.
                The natural number 1 is :

                  • a prime number.
                  • a composite number.
                  • prime as well as composite.
                  • neither prime nor composite.

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