NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.3

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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.3 are provided in this article. Class 10 Maths Chapter 6 Triangles covers important concepts related to properties of triangles, the similarity between triangles and important theorems. Chapter 6 Exercise 6.3 includes questions mainly based on the congruence of triangles.

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Check below the NCERT solutions pdf for Class 10 Maths Chapter 6 Exercise 6.3

Check out NCERT solutions of other exercises of class 10 maths chapter 6 Triangles:

Class 10 Chapter 6 Triangles Related Links:

Triangles Revision Notes	MCQ on Triangles	Circles
Tangent to a Circle	Important Questions on Circles	Circles Revision Notes
Triangle Theorems	Types of Triangles	Triangles Important Questions

Class 10 Maths Study Guides:

Class 10 Maths Notes	NCERT Solutions for Class 10 Maths	Mathematics Important Questions
Math Study Material	Important Formulas in Maths	Difference Between in Maths

CBSE X Related Questions

1.
Find the H.C.F. and L.C.M. of 408 and 312.
View Solution
2.
In the given figure, two triangles ABC and PQR are shown such that \(\angle A = \angle P\) and \(\angle C = \angle R\). If \(AD \perp BC\) and \(PS \perp QR\), then prove that (i) \(\Delta ADB \sim \Delta PSQ\) (ii) \(AD \times QS = BD \times PS\).
View Solution
3.
In a circular museum hall of radius 14 m, some statues are displayed. Statues are kept inside the inner concentric circle of radius 7 m. One such statue lying in sector OAB, is fenced along line segments OA, AP, PB and BO where P is a point on outer circle. Based on above information, answer the following questions:

37(i) Find \(m\angle AOP\).
View Solution
4.
If 14th term of an A.P. is 4 and its 15th term is zero, then its first term is
- –48
- –56
- 56
- 48
View Solution
5.
Three coins are tossed together. The probability of getting exactly two tails is
- \(\frac{2}{8}\)
- \(\frac{1}{2}\)
- \(\frac{3}{8}\)
- 1
View Solution
6.
Prove that : \(\sqrt{\frac{1 - \cos A}{1 + \cos A}} = \frac{\tan A}{\sec A + 1}\).
View Solution

View All

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Triangles Important Questions: Important Similarity Concepts

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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.3

CBSE X Related Questions

1.
Find the H.C.F. and L.C.M. of 408 and 312.

2.
In the given figure, two triangles ABC and PQR are shown such that \(\angle A = \angle P\) and \(\angle C = \angle R\). If \(AD \perp BC\) and \(PS \perp QR\), then prove that (i) \(\Delta ADB \sim \Delta PSQ\) (ii) \(AD \times QS = BD \times PS\).

4.
If 14th term of an A.P. is 4 and its 15th term is zero, then its first term is

5.
Three coins are tossed together. The probability of getting exactly two tails is

6.
Prove that : \(\sqrt{\frac{1 - \cos A}{1 + \cos A}} = \frac{\tan A}{\sec A + 1}\).

Similar Mathematics Concepts

Comments

dOGVmW

NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.3

CBSE X Related Questions

1.Find the H.C.F. and L.C.M. of 408 and 312.

2.In the given figure, two triangles ABC and PQR are shown such that \(\angle A = \angle P\) and \(\angle C = \angle R\). If \(AD \perp BC\) and \(PS \perp QR\), then prove that (i) \(\Delta ADB \sim \Delta PSQ\) (ii) \(AD \times QS = BD \times PS\).

4.If 14th term of an A.P. is 4 and its 15th term is zero, then its first term is

5.Three coins are tossed together. The probability of getting exactly two tails is

6.Prove that : \(\sqrt{\frac{1 - \cos A}{1 + \cos A}} = \frac{\tan A}{\sec A + 1}\).

Similar Mathematics Concepts

Comments

dOGVmW

1.
Find the H.C.F. and L.C.M. of 408 and 312.

2.
In the given figure, two triangles ABC and PQR are shown such that \(\angle A = \angle P\) and \(\angle C = \angle R\). If \(AD \perp BC\) and \(PS \perp QR\), then prove that (i) \(\Delta ADB \sim \Delta PSQ\) (ii) \(AD \times QS = BD \times PS\).

4.
If 14th term of an A.P. is 4 and its 15th term is zero, then its first term is

5.
Three coins are tossed together. The probability of getting exactly two tails is

6.
Prove that : \(\sqrt{\frac{1 - \cos A}{1 + \cos A}} = \frac{\tan A}{\sec A + 1}\).