NCERT Solutions for Class 9 Maths Chapter 7: Triangles

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The NCERT Solutions for class 9 Maths Chapter 7 Triangles are included in the article below. A triangle is a closed shape with three angles, three sides, and three vertices. It has two basic formulas that help us to determine its area and perimeter.

Class 9 Maths Chapter 7 Triangles belong to Unit 4 Geometry which has a weightage of 27 marks in the Class 9 Maths Examination. Class 9 Maths Chapter 7 has the following important concepts: 

Download: NCERT Solutions for Class 9 Mathematics Chapter 7 pdf


NCERT Solutions for Class 9 Mathematics Chapter 7

The Chapter 7 Class 9 Maths are given below:

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Important Topics in Class 9 Maths Chapter 7 Triangles

Important Topics in Class 9 Maths Chapter 7 Triangles are elaborated below:

Area of Triangles

The area of a triangle is the space confined within the three sides of a triangle. For calculating its area, the base length and the height of the triangle are required.

Example: What is the formula to determine the area of a triangle?

Solution: The formula to determine the Area of a Triangle is:
Area of triangle = ½ (base x height) = ½ b x h

Perimeter of Triangles

The perimeter of a respective triangle can be defined as the sum of three sides of the triangle. For example, if a triangle has sides ABC, then the perimeter of it would be (AB + BC + AC).

  1. Perimeter of Scalene Triangle:  A + B + C
  2. Perimeter of Iosceles Triangle: 2A + B
  3. Perimeter of Equilateral Triangle: 3A

Congruency of Triangles

If two triangles have the same shape and size, then they are found congruent to one another.

Example: List all the followed criteria for congruency in a triangle.

Solution: The criteria of conguency in Triangles are: 

  • SSS (side-side-side) congruency
  • SAS (side-angle-side) congruency
  • ASA (angle-side-angle) congruency
  • AAS (angle-angle-side) congruency
  • RHS (right angle-hypotenuse-side) congruency

NCERT Solutions for Class 9 Maths Chapter 7 Exercises:

The detailed solutions for all the NCERT Solutions for Triangles under different exercises are:

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CBSE X Related Questions

  • 1.

    In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.


      • 2.
        If the mode of some observations is 10 and sum of mean and median is 25, then the mean and median respectively are

          • 12 and 13
          • 13 and 12
          • 10 and 15
          • 15 and 10

        • 3.
          Solve the following pair of linear equations by graphical method : \(2x + y = 9\) and \(x - 2y = 2\).


            • 4.
              Three coins are tossed together. The probability that at least one head comes up is

                • \(\dfrac{3}{8}\)
                • \(\dfrac{7}{8}\)
                • \(\dfrac{1}{8}\)
                • \(\dfrac{3}{4}\)

              • 5.

                There is a circular park of diameter 65 m as shown in the following figure, where AB is a diameter. An entry gate is to be constructed at a point P on the boundary of the park such that distance of P from A is 35 m more than the distance of P from B. Find distance of point P from A and B respectively.


                  • 6.
                    Find length and breadth of a rectangular park whose perimeter is \(100 \, \text{m}\) and area is \(600 \, \text{m}^2\).

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